In phalcon you can get uploaded file with this piece of code
//Check if the user has uploaded files
if ($this->request->hasFiles() == true) {
//Print the real file names and their sizes
foreach ($this->request->getUploadedFiles() as $file){
echo $file->getName(), " ", $file->getSize(), "\n";
}
}
each $file is an Phalcon\Http\Request\File instance.
But what if I want to create an file instance from an existing file on the server, how can I do that?
What I tried is this:
new Phalcon\Http\Request\File(array($fileDir));
But it returns an instance with empty properties.
any help would be appreciated :D
As per the documentation of that class I think the constructor does not expect an array. So just leave out the array( ) that you are passing to the constructor and you should be fine. Disclaimer: I did not check out the code and rely on the documentation being proper here.
Code example:
new Phalcon\Http\Request\File($fileDir);
But what if I want to create an file instance from an existing file on the server, how can I do that?
This class is designed to work with $_FILES superglobal, so as for me you are using wrong tool. I would create your own wrapper for using files that are already on server, or go for SplFileObject.
Anyway, how should parameter array look like you may be able to anderstand from here starting at line 74+ and it pretty reflects $_FILES structure.
Related
I want to know if you do the following in my code below how do you check if the file exists e.g
{
$file = Storage::disks('local')->get($file);
// then test if $file exists
}
You can check the existence of the file with the code below for your local storage,
$file_exists = Storage::disk('local')->exists($file);
You can read more about storage on Laravel Document at Laravel Filesystem.
Note: in the document you will check disk('s3'). It depends on what connection we are using defined in config/filesystem.php(the configuration file for the filesystem in laravel).
OR simply you can use check the condition by
if(Storage::disk('local')->exists($file)) {
}
It will also work for you.
There's a clear example in the docs, if you take a look.
$exists = Storage::disk('s3')->exists('file.jpg');
The project I am working on requires creating .tar.gz archives and feeding it to an external service. This external service works only with .tar.gz so another type archive is out of question. The server where the code I am working on will execute does not allow access to system calls. So system, exec, backticks etc. are no bueno. Which means I have to rely on pure PHP implementation to create .tar.gz files.
Having done a bit of research, it seems that PharData will be helpful to achieve the result. However I have hit a wall with it and need some guidance.
Consider the following folder layout:
parent folder
- child folder 1
- child folder 2
- file1
- file2
I am using the below code snippet to create the .tar.gz archive which does the trick but there's a minor issue with the end result, it doesn't contain the parent folder, but everything within it.
$pd = new PharData('archive.tar');
$dir = realpath("parent-folder");
$pd->buildFromDirectory($dir);
$pd->compress(Phar::GZ);
unset( $pd );
unlink('archive.tar');
When the archive is created it must contain the exact folder layout mentioned above. Using the above mentioned code snippet, the archive contains everything except the parent folder which is a deal breaker for the external service:
- child folder 1
- child folder 2
- file1
- file2
The description of buildFromDirectory does mention the following so it not containing the parent folder in the archive is understandable:
Construct a tar/zip archive from the files within a directory.
I have also tried using buildFromIterator but the end result with it also the same, i.e the parent folder isn't included in the archive. I was able to get the desired result using addFile but this is painfully slow.
Having done a bit more research I found the following library : https://github.com/alchemy-fr/Zippy . But this requires composer support which isn't available on the server. I'd appreciate if someone could guide me in achieving the end result. I am also open to using some other methods or library so long as its pure PHP implementation and doesn't require any external dependencies. Not sure if it helps but the server where the code will get executed has PHP 5.6
Use the parent of "parent-folder" as the base for Phar::buildFromDirectory() and use its second parameter to limit the results only to "parent-folder", e.g.:
$parent = dirname("parent-folder");
$pd->buildFromDirectory($parent, '#^'.preg_quote("$parent/parent-folder/", "#").'#');
$pd->compress(Phar::GZ);
I ended up having to do this, and as this question is the first result on google for the problem here's the optimal way to do this, without using a regexp (which does not scale well if you want to extract one directory from a directory that contains many others).
function buildFiles($folder, $dir, $retarr = []) {
$i = new DirectoryIterator("$folder/$dir");
foreach ($i as $d) {
if ($d->isDot()) {
continue;
}
if ($d->isDir()) {
$newdir = "$dir/" . basename($d->getPathname());
$retarr = buildFiles($folder, $newdir, $retarr);
} else {
$dest = "$dir/" . $d->getFilename();
$retarr[$dest] = $d->getPathname();
}
}
return $retarr;
}
$out = "/tmp/file.tar";
$sourcedir = "/data/folder";
$subfolder = "folder2";
$p = new PharData($out);
$filemap = buildFiles($sourcedir, $subfolder);
$iterator = new ArrayIterator($filemap);
$p->buildFromIterator($iterator);
$p->compress(\Phar::GZ);
unlink($out); // $out.gz has been created, remove the original .tar
This allows you to pick /data/folder/folder2 from /data/folder, even if /data/folder contains several million OTHER folders. It then creates a tar.gz with the contents all being prepended with the folder name.
I have a blob resource from my db. I want to wrap temporaly this file into Symfony File object because I want to use specific methods like the extension guesser, and apply symfony file validators.
I want to store this temporary file into memory, because the blobs are small files and i dont want to create a file in disk in every request.
I tried to do this in that way:
$file = new File ('php://temp');
but symfony throws an error that says 'The file "php://temp" does not exist'. Looking at File source, the error is caused by a "is_file($path)" check that is made in the constructor, and I can invalidate this putting false in the second argument. But, if I do:
$file = new File ('php://temp', false);
the File is created, but then the error comes back later, e.g. when i use the guesser:
$file->guessExtension($file)
because in Symfony/Component/HttpFoundation/File/MimeType/MimeTypeGuesser.php:
public function guess($path)
{
if (!is_file($path)) {
throw new FileNotFoundException($path);
}
(...)
Ok. Then my question is: There is a way to load a 'php://temp' or 'php://memory' within a File object?
Pretty sure php://temp writes to memory until it is full and then writes to a file, whereas php://memory ensures only in memory with no fall back.
This likely happens because php://temp and php://memory are non-reusable, so once you've written to it the content may not still be there when you next want it. From the PHP manual:
php://memory and php://temp are not reusable, i.e. after the streams have been closed there is no way to refer to them again.
file_put_contents('php://memory', 'PHP');
echo file_get_contents('php://memory'); // prints nothing
How are you writing to php://temp to begin with? That will be the more important issue rather than with Symfony's File class. I suspect that by the time you are creating a File instance that php://temp has already gone.
It's worth noting that using php://temp will create a file on disk in the temporary location, so you might as well use write to a tempnam() handle anyway. At least then you will have a reference to a physical (but temporary) file.
I suggested to allow passing the file contents (instead of the path) to Symfony's MIME type guesser, to enable guessing "on-the-fly": https://github.com/symfony/symfony/issues/40916
Here's how I do it right now:
use Symfony\Component\Mime\MimeTypes;
$tmpFilename = tempnam(sys_get_temp_dir(), 'guessMimeType_');
file_put_contents($tmpFilename, $content);
$mimeTypes = new MimeTypes();
$guessedMimeType = $mimeTypes->guessMimeType($tmpFilename);
unlink($tmpFilename);
The first line is taken from https://www.php.net/manual/en/function.tempnam.php#93256
I have made a class file which are running on my server.I am using it as a API.my some client will use it.In their program i have to create an object remotely of this class.
How will use my class file as RMI that object can create easily on other server.
Thanks
I don't think anything close to Java's RMI (as far as I understand it) can be done in PHP.
The best thing that comes to my mind is
Create an object in the remote script
Serialize that object
Return the serialized data to the calling script
Unserialize the data back into an object (note that all class definitions must be present locally for this to work!)
Note that things like active database connections, file handles and so on can not be transferred this way.
Whether this is a good - and fast enough - way to do what you want is hard to say. Maybe it helps.
To connect as a user other than 'anonymous', you need to specify the username (and possibly password) within the URL, such as 'ftp://user:password#ftp.example.com/path/to/file'. (You can use the same sort of syntax to access files via HTTP when they require Basic authentication.)
<?php
$file = fopen ("ftp://ftp.example.com/incoming/outputfile", "w");
if (!$file) {
echo "<p>Unable to open remote file for writing.\n";
exit;
}
/* Write the data here. */
fwrite ($file, $_SERVER['HTTP_USER_AGENT'] . "\n");
fclose ($file);
?>
http://php.net/manual/en/features.remote-files.php
include ("ftp://username:password#ftp.example.com/public_html/example.php");
$class = new Ford();
$dataRow = $class->consulta();
var_dump($conexion);
I was wondering how to basically edit a .swf file using php, to change a single variable or to change more. How would I go about doing this? Is there a way to edit it without knowing machine code?
If there is an example of how to do this, where can I find it?
Thanks!
Or, if there is an easier way to go about doing this, please let me know!
take a look at libming
php documentation at http://docs.php.net/manual/en/book.ming.php
With Actionscript, it's very simple to load external data: XML and JSON are two standardized ways to do it, and both are easily generated by PHP. What exactly are you trying to do?
The question is old, but since it happens to coincide with what I've been working on, I figured I would put something together in case others find it useful. The solution works for AS3 only. It let you to change the values of instance variables and constants.
Suppose you have the following class:
package pl.krakow.rynek {
import flash.display.Sprite;
public class Advertisement extends Sprite {
private var title:String = 'Euro 2012 LIVE!';
/* ... */
}
}
You want the var title to be something else. The code for doing so is as follow:
<?php
require_once 'flaczki/classes.php';
// parse the SWF file, decoding only those tags needed by the injector
$input = fopen("input.swf", "rb");
$parser = new SWFParser;
$injector = new AS3ConstantInjector;
$swfFile = $parser->parse($input, $injector->getRequiredTags());
$classConstants = array(
'pl.krakow.rynek.Advertisement' => array(
'title' => 'Free Beer!'
)
);
// inject the values and reassemble the file
$injector->inject($swfFile, $classConstants);
$output = fopen($outPath, "wb");
$assembler = new SWFAssembler;
$assembler->assemble("output.swf", $swfFile);
?>
The code should be self-explanatory. The SWF file is first parsed, modifications are made, and the in-memory structure is saved to file. AS3ConstantInjector.inject() expects as the second argument an array of arrays keyed by the qualified names of the classes you wish to modify. The arrays themselves hold the new values for each class, with the key as the variable/constant name.
To see The variables in a SWF file, use AS3ConstantExtractor:
<?php
require_once 'flaczki/classes.php';
$input = fopen("button.swf", "rb");
$parser = new SWFParser;
$extractor = new AS3ConstantExtractor;
$swfFile = $parser->parse($input, $extractor->getRequiredTags());
$classConstants = $extractor->extract($swfFile);
print_r($classConstants);
?>
The Flaczki classes can be downloaded at http://code.google.com/p/flaczki/downloads/list
You can find out more about the Flaczki framework at the project development blog at http://flaczkojad.blogspot.com/
check out the SWF-library in php
Instead of thinking how to generate swf files, do the opposite and let the internal behavior depend on external logic in a php script. This way you never need to (re)compile your swf.