Creating and using magic methods within PHP - php

I am trying to get to grips with PHP's magic methods, and for this I am creating a test class that looks as follows:
<?php
class overload
{
protected $lastCalledParam;
public $param;
public function __construct()
{
return $this->switchConstruct(func_get_args());
}
protected function switchConstruct(array $args)
{
switch (count($args))
{
case 0:
return print "0 params<br />";
case 1:
return call_user_func_array(array($this, 'constr1'), $args);
case 2:
return call_user_func_array(array($this, 'constr2'), $args);
}
die("Invalid number of args");
}
protected function constr1($a)
{
print "constr1 called<br />";
}
protected function constr2($a, $b)
{
print "constr2 called<br />";
}
public function __get($name)
{
$this->lastCalledParam = $name;
return $this->{$name};
}
public function __set($name, $value)
{
$this->lastCalledParam = $name;
$this->{$name} = $value;
}
protected function lastCalled()
{
if (func_num_args() == 1)
{
$args = func_get_args();
$this->lastCalledParam = $args[0];
}
return $this->lastCalledParam;
}
public function __toString()
{
return $this->lastCalledParam == null ? "No data found" : $this->lastCalledParam;
}
}
And called as such:
<?php
require_once 'clib/overload.php';
$c = new overload();
print $c->__toString();
print "<br />";
$c->param = "Hello";
print $c->__toString();
?>
The behaviour that I am expecting is that on the first __toString() call, there will be:
0 params
No data found
Hello
But what I get is:
0 params
No data found
No data found
I have come to a major sticking point with this and cannot see why it is not doing the work to set the lastCalledParam property!
I am getting a grand total of 0 errors and 0 warnings with full error and warning reporting turned on so I do no understand what is not being called, where/why.

__set is only invoked if the parameter cannot be reached normally. Your public $param would need to be protected at least for __set to be invoked.
__set() is run when writing data to inaccessible properties.
http://php.net/manual/en/language.oop5.overloading.php#object.set (emphasis mine)

Related

How to check returned value to which function it belogns

Say I have to similar function :
public function auth(){
return $someResponse;
}
public function collect(){
return $someOtherResponse
}
Question : When one of the response get passed to another class, is there any way to check which function returned the response ?
In a purely object-oriented way, wanting to attach information to a value is akin to wrapping it into a container possessing context information, such as:
class ValueWithContext {
private $value;
private $context;
public function __construct($value, $context) {
$this->value = $value;
$this->context = $context;
}
public value() {
return $this->value;
}
public context() {
return $this->context;
}
}
You can use it like this:
function auth()
{
return new ValueWithContext($someresponse, "auth");
}
function collect()
{
return new ValueWithContext($someotherrpesonse, "collect");
}
This forces you to be explicit about the context attached to the value, which has the benefit of protecting you from accidental renamings of the functions themselves.
As per my comment, using arrays in the return will give you a viable solution to this.
It will allow a way to see what has been done;
function auth()
{
return (array("auth" => $someresponse));
}
function collect()
{
return (array("collect" => $someotherrpesonse));
}
class myClass
{
function doSomething($type)
{
if (function_exists($type))
{
$result = $type();
if (isset($result['auth']))
{
// Auth Used
$auth_result = $result['auth'];
}
else if (isset($result['collect']))
{
// Collect used
$collect_result = $result['collect'];
}
}
}
}
It can also give you a way to fail by having a return array("fail" => "fail reason")
As comments say also, you can just check based on function name;
class myClass
{
function doSomething($type)
{
switch ($type)
{
case "auth" :
{
$result = auth();
break;
}
case "collect" :
{
$result = collect();
break;
}
default :
{
// Some error occurred?
}
}
}
}
Either way works and is perfectly valid!
Letting the two user defined functions auth() & collect() call a common function which makes a call to debug_backtrace() function should do the trick.
function setBackTrace(){
$backTraceData = debug_backtrace();
$traceObject = array_reduce($backTraceData, function ($str, $val2) {
if (trim($str) === "") {
return $val2['function'];
}
return $str . " -> " . $val2['function'];
});
return $traceObject;
}
function getfunctionDo1(){
return setBackTrace();
}
function getfunctionDo2(){
return setBackTrace();
}
class DoSomething {
static function callfunctionTodo($type){
return (($type === 1) ? getfunctionDo1() : getfunctionDo2());
}
}
echo DoSomething::callfunctionTodo(1);
echo "<br/>";
echo DoSomething::callfunctionTodo(2);
/*Output
setBackTrace -> getfunctionDo1 -> callfunctionTodo
setBackTrace -> getfunctionDo2 -> callfunctionTodo
*/
The above function would output the which function returned the response

PHP __set variable while __get passes by reference

I think its quite a simple question but not sure.
I have a class:
<?PHP
class PropertyTest {
private $data = array();
public function __set($name, $value) {
$this->data[$name] = $value;
}
public function __get($name) {
if (array_key_exists($name, $this->data)) {
return $this->data[$name];
}
$trace = debug_backtrace();
trigger_error(
'Undefined property via __get(): ' . $name .
' in ' . $trace[0]['file'] .
' on line ' . $trace[0]['line'],
E_USER_NOTICE);
return null;
}
public function __isset($name) {
echo "Is '$name' set?\n";
return isset($this->data[$name]);
}
public function __unset($name) {
echo "Unsetting '$name'\n";
unset($this->data[$name]);
}
public function getHidden() {
return $this->hidden;
}
}
?>
Not sure why but the 'code' block is annoying as hell, anyway.
Just the basic magic get set really. But when I change the __get to pass by reference I cant do this anymore:
$object->$variableName = $variableValue;
I'm not sure why although I assume because it checks if it exists but since it has to return something by reference it will fail to do so if it doesn't exists to begin with. The set function wont be called probably and even if I return a fake value it would never call the set function cause it 'already exists/has a value'.
Am I understanding this correctly? If so, Is there a work around? If not how does it work and is there a workaround?
Unless I'm missing something it's working fine for me
<?php
class PropertyTest
{
private $data = array();
public function __set($name, $value)
{
$this->data[$name] = $value;
}
public function &__get($name)
{
if(array_key_exists($name, $this->data))
return $this->data[$name];
return null;
}
public function __isset($name)
{
return isset($this->data[$name]);
}
public function __unset($name)
{
unset($this->data[$name]);
}
public function getHidden()
{
return $this->hidden;
}
}
$oPropTest = new PropertyTest();
$sField = 'my-field';
$oPropTest->$sField = 5;
var_dump($oPropTest);
Outputs:
bash-3.2$ php test-get-set.php
object(PropertyTest)#1 (1) {
["data":"PropertyTest":private]=>
array(1) {
["my-field"]=>
int(5)
}
}
One tweak I'd suggest for your __get implementation is to leverage the __isset method rather than re-implement the check (doing it 2 different ways as you are)
public function __get($name)
{
if($this->__isset($name))
return $this->data[$name];
return null;
}
Regarding the idea of return-by-reference from __get; it will work, but be useless on anything but public attributes, since private and protected attributes won't be settable directly through a reference outside the class scope.
$oPropTest = new PropertyTest();
$sField = 'my-field';
$oPropTest->$sField = 5; // sets $oPropTest->my-field to 5 (effectively)
$iRef = $oPropTest->$sField; // $iRef is a reference to $oPropTest->my-field
$iRef = 6; // this will not set $oPropTest->my-field since it's private

Questions abt PHP Magic Methods & Delegating

i was wanting to wrap an object in another - favoring composition over inheritance. but i am not sure i am doing it right tho there are no errors.
i created a class Wrapped thats is wrapped by Wrapper. i made it such that when a method/property is called on $wrapper, if it exists in the class, Wrapper, it will be returned else, it will delegate to the $wrapped object. i wonder apart from the fact i didnt check if the method/property exists, what have i done wrong? can some1 explain __callStatic() too?
class Wrapped {
protected $wrappedProp1 = 'Wrapped: Property 1';
protected $wrappedProp2 = 'Wrapped: Property 2';
function method1($arg1, $arg2) {
echo "Called Wrapped::method1() with the following parameters: $arg1, $arg2";
}
static function sMethod2() {
echo 'Called a static method in wrapped';
}
function __get($name) {
return $this->$name;
}
function __set($name, $val) {
$this->$name = $val;
}
}
class Wrapper {
protected $wrapperProp1 = 'Wrapper: Property 1';
protected $wrapped;
function __construct($wrapped) {
$this->wrapped = $wrapped;
}
function wrapperMethod() {
echo 'In wrapper method';
}
function __get($name) {
if (property_exists($this, $name)) {
return $this->$name;
}
return $this->wrapped->$name;
}
function __set($name, $val) {
if (property_exists($this, $name)) {
$this->$name = $val;
}
$this->wrapped->$name = $val;
}
function __call($name, $args = array()) {
call_user_func_array(array($this->wrapped, $name), $args);
}
static function __callStatic($name, $args = array()) {
call_user_func_array(array('Wrapped', $name), $args);
}
}
$wrapper = new Wrapper(new Wrapped);
// testing normal methods
$wrapper->wrapperMethod();
echo $wrapper->wrapperProp1;
$wrapper->wrapperProp1 = 'New Wrapper Prop 1';
echo $wrapper->wrapperProp1;
// testing delegates
$wrapper->method1('hello', 'world'); //delegated to Wrapped::method1()
$wrapper->sMethod2(); // delegated to static Wrapped::sMethod2() ... what is callStatic for then
echo $wrapper->wrappedProp2;
Wrapper::sMethod2();
As it seems - it's all ok.
About __callStatic() - it allows you to workaround undefined static functions in class.
Example:
<?php
class Foo {
static function __callStatic($name, $args = array()) {
echo "Called static function $name with arguments ". print_r($args, true);
}
}
Foo::Bar('test');
// will output "Called static function Bar with arguments Array ( 0 => test );"

PHP OOP, perform a function once a certain variable has been set

How can i perform a function once a variable's value has been set?
say like
$obj = new object(); // dont perform $obj->my_function() just yet
$obj->my_var = 67 // $obj->my_function() now gets run
I want the object to do this function and now having to be called by the script.
Thanks
EDIT
my_var is predefined in the class, __set is not working for me.
Use a private property so __set() is invoked:
class Myclass {
private $my_var;
private $my_var_set = false;
public function __set($var, $value) {
if ($var == 'my_var' && !$this->my_var_set) {
// call some function
$this->my_var_set = true;
}
$this->$var = $value;
}
public function __get($var, $value) {
return $this->$name;
}
}
See Overloading. __set() is called because $my_var is inaccessible and there is your hook.
I'd recommend to create a setter function for $obj and include the relevant function call there. So basically your code would look somehow like this:
$obj = new ClassOfYours();
$obj->setThatValue("apple");
Of course you would have to take care that all assignments to ThatValue need to be
done through that setter in order make it work properly. Assuming that you're on php5 I'd set that property to private, so all direct assignments will cause an runtime error.
A good overview about OOP in php can be found in this article on devarticles.com.
HTH
To acheive exactly what you describe, you'd have to use a magic setter.
class ObjectWithSetter {
var $data = array();
public function my_function() {
echo "FOO";
}
public function __set($name, $value) {
$this->data[$name] = $value;
if($name == 'my_var') {
$this->my_function();
}
}
public function __get($name) {
if (array_key_exists($name, $this->data)) {
return $this->data[$name];
}
$trace = debug_backtrace();
trigger_error(
'Undefined property via __get(): ' . $name .
' in ' . $trace[0]['file'] .
' on line ' . $trace[0]['line'],
E_USER_NOTICE);
return null;
}
/** As of PHP 5.1.0 */
public function __isset($name) {
return isset($this->data[$name]);
}
public function __unset($name) {
unset($this->data[$name]);
}
}
Assuming you want to call my_function() once you set a value, that case you can encapsulate both the operations into one. Something like you create a new function set_my_var(value)
function set_my_var(varvalue)
{
$this->my_var = varvalue;
$this->my_function();
}

PHP: How do I check if all public methods of two classes return the same values?

In effect, if I have a class c and instances of $c1 and $c2
which might have different private variable amounts but all their public methods return the same values I would like to be able to check that $c1 == $c2?
Does anyone know an easy way to do this?
You can also implement a equal($other) function like
<?php
class Foo {
public function equals($o) {
return ($o instanceof 'Foo') && $o.firstName()==$this.firstName();
}
}
or use foreach to iterate over the public properties (this behaviour might be overwritten) of one object and compare them to the other object's properties.
<?php
function equalsInSomeWay($a, $b) {
if ( !($b instanceof $a) ) {
return false;
}
foreach($a as $name=>$value) {
if ( !isset($b->$name) || $b->$name!=$value ) {
return false;
}
}
return true;
}
(untested)
or (more or less) the same using the Reflection classes, see http://php.net/manual/en/language.oop5.reflection.php#language.oop5.reflection.reflectionobject
With reflection you might also implement a more duck-typing kind of comparision, if you want to, like "I don't care if it's an instance of or the same class as long as it has the same public methods and they return the 'same' values"
it really depends on how you define "equal".
It's difficult to follow exactly what you're after. Your question seems to imply that these public methods don't require arguments, or that if they did they would be the same arguments.
You could probably get quite far using the inbuilt reflection classes.
Pasted below is a quick test I knocked up to compare the returns of all the public methods of two classes and ensure they were they same. You could easily modify it to ignore non matching public methods (i.e. only check for equality on public methods in class2 which exist in class1). Giving a set of arguments to pass in would be trickier - but could be done with an array of methods names / arguments to call against each class.
Anyway, this may have some bits in it which could be of use to you.
$class1 = new Class1();
$class2 = new Class2();
$class3 = new Class3();
$class4 = new Class4();
$class5 = new Class5();
echo ClassChecker::samePublicMethods($class1,$class2); //should be true
echo ClassChecker::samePublicMethods($class1,$class3); //should be false - different values
echo ClassChecker::samePublicMethods($class1,$class4); //should be false -- class3 contains extra public methods
echo ClassChecker::samePublicMethods($class1,$class5); //should be true -- class5 contains extra private methods
class ClassChecker {
public static function samePublicMethods($class1, $class2) {
$class1methods = array();
$r = new ReflectionClass($class1);
$methods = $r->getMethods();
foreach($methods as $m) {
if ($m->isPublic()) {
#$result = call_user_method($m->getName(), $class1);
$class1methods[$m->getName()] = $result;
}
}
$r = new ReflectionClass($class2);
$methods = $r->getMethods();
foreach($methods as $m) {
//only comparing public methods
if ($m->isPublic()) {
//public method doesn't match method in class1 so return false
if(!isset($class1methods[$m->getName()])) {
return false;
}
//public method of same name doesn't return same value so return false
#$result = call_user_method($m->getName(), $class2);
if ($class1methods[$m->getName()] !== $result) {
return false;
}
}
}
return true;
}
}
class Class1 {
private $b = 'bbb';
public function one() {
return 999;
}
public function two() {
return "bendy";
}
}
class Class2 {
private $a = 'aaa';
public function one() {
return 999;
}
public function two() {
return "bendy";
}
}
class Class3 {
private $c = 'ccc';
public function one() {
return 222;
}
public function two() {
return "bendy";
}
}
class Class4 {
public function one() {
return 999;
}
public function two() {
return "bendy";
}
public function three() {
return true;
}
}
class Class5 {
public function one() {
return 999;
}
public function two() {
return "bendy";
}
private function three() {
return true;
}
}
You can define PHP's __toString magic method inside your class.
For example
class cat {
private $name;
public function __contruct($catname) {
$this->name = $catname;
}
public function __toString() {
return "My name is " . $this->name . "\n";
}
}
$max = new cat('max');
$toby = new cat('toby');
print $max; // echoes 'My name is max'
print $toby; // echoes 'My name is toby'
if($max == $toby) {
echo 'Woohoo!\n';
} else {
echo 'Doh!\n';
}
Then you can use the equality operator to check if both instances are equal or not.
HTH,
Rushi
George: You may have already seen this but it may help: http://usphp.com/manual/en/language.oop5.object-comparison.php
When using the comparison operator (==), object variables are compared in a simple manner, namely: Two object instances are equal if they have the same attributes and values, and are instances of the same class.
They don't get implicitly converted to strings.
If you want todo comparison, you will end up modifying your classes. You can also write some method of your own todo comparison using getters & setters
You can try writing a class of your own to plugin and write methods that do comparison based on what you define. For example:
class Validate {
public function validateName($c1, $c2) {
if($c1->FirstName == "foo" && $c2->LastName == "foo") {
return true;
} else if (// someother condition) {
return // someval;
} else {
return false;
}
}
public function validatePhoneNumber($c1, $c2) {
// some code
}
}
This will probably be the only way where you wont have to modify the pre-existing class code

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