I have 3 tables:
MySQL: I need to link these tables and extracted sum of one of the column per row in the resulting table
tblRedemption
+---------------------+
| OrderID | OrderDesc |
+---------------------+
| 1000001 | aaaa |
| 1000002 | bbbb |
| 1000003 | cccc |
| 1000004 | dddd |
+---------------------+
tblLink
+------------------------+
| SubmissionID | OrderID |
+------------------------+
| 201 | 1000001 |
| 202 | 1000002 |
| 203 | 1000003 |
| 204 | 1000004 |
+------------------------+
tblSubmissions
+-------------------------------------------+
| SubmissionID | Name | Mobile | Amount |
+-------------------------------------------+
| 150 | Amy | 1111111111 | 10 |
| 200 | Bob | 2222222222 | 20 |
| 201 | Carl | 3333333333 | 30 |
| 202 | Dave | 4444444444 | 10 |
| 203 | Carl | 3333333333 | 25 |
| 204 | Fin | 5555555555 | 35 |
+-------------------------------------------+
Expected Results:
+---------------------------------------------------------------------+
| SubmissionID | Name | mobile | OrderDesc | Amount | TotalAmount |
+---------------------------------------------------------------------+
| 201 | Carl | 3333333333 | aaaa | 30 | 55 |
| 203 | Carl | 3333333333 | bbbb | 25 | 55 |
| 204 | Fin | 5555555555 | cccc | 35 | 35 |
| 202 | Dave | 4444444444 | dddd | 10 | 10 |
+---------------------------------------------------------------------+
Number of tblSubmission is a bigger list than the tblredemption.
There are customers with multiple entries tblSubmission identified by their mobile (see Carl).
The table tbLink joins the 2 tblSubmission and tblRdemption.
The resulting table also needs a new column which holds the total amount for each particular customer (by mobile).
The expected results needs to include:
The SubmissionID and OrderDesc from the "tblRedemption" table.
The Name, Mobile and Amount from the tblSubmissions table.
All my queries ether gives me a small subset or just one row, or "multiple rows returned".
Any ideas?
Try this:
select l.submissionid, s.name, s.mobile, s.amount, t.totalamount
from tbllink l
inner join tblsubmissions s on l.submissionid = s.submissionid
inner join (
select `name`, sum(amount) as totalamount
from tblsubmissions
group by `name`
) t on s.`name` = t.`name`
Example: http://sqlfiddle.com/#!9/2ea56a/5
Same query totalled by mobile number
select l.submissionid, s.name, s.mobile, s.amount, t.totalamount
from tbllink l
inner join tblsubmissions s on l.submissionid = s.submissionid
inner join (
select mobile, sum(amount) as totalamount
from tblsubmissions
group by mobile
) t on s.mobile = t.mobile
EDIT:
Including order desc is relatively easy also. Let's see:
select l.submissionid, s.name, s.mobile, r.orderdesc, s.amount, t.totalamount
from tbllink l
inner join tblredemption r on l.orderid = r.orderid
inner join tblsubmissions s on l.submissionid = s.submissionid
inner join (
select `name`, sum(amount) as totalamount
from tblsubmissions
group by `name`
) t on s.`name` = t.`name`
Example: http://sqlfiddle.com/#!9/63540/2
Tables
create table tblredemption (orderid int, orderdesc varchar(100));
insert into tblredemption values (1000001, 'aaaa'), (1000002, 'bbbb'), (1000003, 'cccc'), (1000004, 'dddd');
create table tbllink (submissionid int, orderid int);
insert into tbllink values (201,1000001), (202,1000002), (203,1000003), (204,1000004);
create table tblsubmissions (
submissionid int,
`name` varchar(20),
mobile varchar(20),
amount int
);
insert into tblsubmissions values
( 150 , 'Amy' , '1111111111', 10 ),
( 200 , 'Bob' , '2222222222' , 20 ),
( 201 , 'Carl' , '3333333333' , 30 ),
( 202 , 'Dave' , '4444444444' , 10 ),
( 203 , 'Carl' , '3333333333' , 25 ),
( 204 , 'Fin' , '5555555555' , 35 );
Results:
| submissionid | name | mobile | orderdesc | amount | totalamount |
|--------------|------|------------|-----------|--------|-------------|
| 201 | Carl | 3333333333 | aaaa | 30 | 55 |
| 203 | Carl | 3333333333 | cccc | 25 | 55 |
| 202 | Dave | 4444444444 | bbbb | 10 | 10 |
| 204 | Fin | 5555555555 | dddd | 35 | 35 |
Related
Here i have one table for purchase.
| Invoice No | Customer | Amount | Invoice Date(mm-dd-yy) |
| 101 | ABC | 1000 | 01-01-2020 |
| 102 | XYZ | 1000 | 01-01-2020 |
| 103 | ABC | 1000 | 02-01-2020 |
| 104 | XYZ | 1000 | 03-01-2020 |
| 105 | PQR | 1000 | 01-01-2020 |
| 106 | ABC | 1000 | 03-01-2020 |
Now I have to make Customer wise report.
so grouping will be on Customer which will be like this.
$sql->group(customer);
So after this table will generate like below..
| Invoice No | Customer | Amount | Invoice Date(mm-dd-yy) |
| 106 | ABC | 3000 | 03-01-2020 |
| 104 | XYZ | 2000 | 03-01-2020 |
| 105 | PQR | 1000 | 01-01-2020 |
I also have to make summary for this as like.
| Invoice Amount | Total Count |
| 5000 | 5 |
above all things are done, but the problem is i also have to generate Date Wise summary
So how i get Date Wise summary?
SELECT
`t`.*,
FORMAT(SUM(COALESCE(t.Total_Purchase_Amount_fororder, 0.00)), 2) AS Total_Purchase_Amount
FROM
(
SELECT
`invoice_item`.*,
`sr`.*,
cust_comp.name AS cust_name,
cust_comp.id AS cust_id,
MAX(FROM_UNIXTIME(invoice.date, '%Y')) AS `Transaction_Year`,
MAX(FROM_UNIXTIME(invoice.date, '%m')) AS `Transaction_Month`,
MAX(FROM_UNIXTIME(invoice.date, '%m-%Y')) AS `Transaction_Month_Year`,
FORMAT(COALESCE(COUNT(invoice.to_type_id), 0.00), 2) AS `Total_Purchases`,
COUNT(invoice.to_type_id) AS `Total_Purchases_forsummary`,
FORMAT(COALESCE(SUM(invoice_item.amountAfterDiscount) - COALESCE(total_return, 0.00) , 0.00), 2) AS `Total_Purchase_Amount`,
SUM(invoice_item.amountAfterDiscount) - COALESCE(total_return, 0.00) AS `Total_Purchase_Amount_fororder`,
FORMAT(COALESCE(MAX(invoice_item.amountAfterDiscount) - COALESCE(total_return, 0.00) , 0.00), 2) AS `Max_Purchase_Amount`
FROM
`invoice`
INNER JOIN
`cust_comp`
ON cust_comp.id = invoice.to_type_id
INNER JOIN
(
SELECT
SUM(amountWithTax) AS `amountWithTax`,
SUM(amountAfterDiscount) AS `amountAfterDiscount`,
FORMAT(sum(tax_amount), 2) AS `tax_amount`,
`invoice_item`.`invoice_id`,
`invoice_item`.`invoice_item_inventory_id`
FROM
`invoice_item`
WHERE
(
invoice_item.item_status NOT IN
(
8
)
)
GROUP BY
`invoice_item`.`invoice_id`
)
AS `invoice_item`
ON invoice_item.invoice_id = invoice.invoice_id
LEFT JOIN
(
SELECT
`sr`.`sales_return_id`,
`sr`.`invoice_id` AS `return_invoice_id`,
SUM(COALESCE(return_amountAfterDiscount, 0.00)) AS total_return,
`sri`.*
FROM
`sales_return` AS `sr`
INNER JOIN
(
SELECT
`sri`.`sales_return_id` AS `item_sales_return_id`,
COALESCE(amountAfterDiscount, 0.00) AS `return_amountAfterDiscount`
FROM
`sales_return_item` AS `sri`
)
AS `sri`
ON sri.item_sales_return_id = sr.sales_return_id
WHERE
(
sr.invoice_id = invoice_id
)
GROUP BY
`sr`.`invoice_id`
)
AS `sr`
ON sr.return_invoice_id = invoice.invoice_id
WHERE
(
invoice.invoice_status NOT IN
(
8,
6
)
)
AND
(
invoice.date >= 1596240000
)
GROUP BY
`invoice`.`to_type_id`
)
AS `t`
Expected Result for date wise summary is:
| Invoice Amount| Total Count | Invoice Date |
| 3000 | 3 | 01-01-2020 |
| 1000 | 1 | 02-01-2020 |
| 2000 | 2 | 03-01-2020 |
Items Table
+----+------+
| id | name |
+----+------+
| 1 | abc |
| 2 | def |
| 3 | ghi |
+----+------+
Buy Table
+------+-------------+-------+---------+
| b_id | b_date | b_qty | b_itmid |
+------+-------------+-------+---------+
| 1 | 2020-05-01 | 10 | 1 |
| 2 | 2020-05-01 | 20 | 1 |
| 3 | 2020-05-02 | 5 | 2 |
| 3 | 2020-05-03 | 10 | 3 |
+------+-------------+-------+---------+
Rent Table
+------+-------------+-------+---------+
| r_id | r_date | r_qty | r_itmid |
+------+-------------+-------+---------+
| 1 | 2020-05-03 | 5 | 2 |
| 2 | 2020-05-03 | 10 | 2 |
| 3 | 2020-05-04 | 15 | 3 |
+------+-----------+---------+---------+
Sell Table
+------+-------------+-------+---------+
| s_id | s_date | s_qty | s_itmid |
+------+-------------+-------+---------+
| 1 | 2020-05-03 | 10 | 1 |
| 2 | 2020-05-05 | 20 | 3 |
| 3 | 2020-05-06 | 5 | 3 |
+------+-----------+---------+---------+
And I'm trying to get outputs with php foreach something like this ...
$trans_date
$buy_qty
$rent_qty
$sell_qty
$item
In case item id 1
+-------------+--------------+---------------+---------------+------+
| trans_date | buy_qty | rent_qty | sell_qty | item |
+-------------+--------------+---------------+---------------+------+
| 2020-05-01 | 30 | 0 | 0 | abc |
| 2020-05-02 | 0 | 0 | 0 | abc |
| 2020-05-03 | 0 | 0 | 10 | abc |
| 2020-05-04 | 0 | 0 | 0 | abc |
| 2020-05-05 | 0 | 0 | 0 | abc |
| 2020-05-06 | 0 | 0 | 0 | abc |
+-------------+--------------+---------------+---------------+------+
This is the query I've come for one table (b_date column has timestamp value)...
$query = $this->db->query("
SELECT FROM_UNIXTIME(b_date,'%d %M') AS date_b
, SUM(b_qty) AS qty_b
FROM buytable
WHERE b_itmid = 1
AND MONTH(FROM_UNIXTIME(b_date)) = MONTH(CURDATE())
GROUP
BY DATE(FROM_UNIXTIME(b_date))
");
if ($query->num_rows() > 0) {
foreach ($query->result() as $data) {
$result[] = $data;
}
return $result;
}
Finally I've found the correct answer https://stackoverflow.com/a/61875506/7554875
select d.date, b.qty_buy, r.qty_rent, s.qty_sell, i.name
from items i
cross join (
select b_date as date from buy
union all select r_date as date from rent
union all select s_date as date from sell
) d
left join (select b_date as date, b_itmid, sum(b_qty) qty_buy
from buy group by date, b_itmid) b
on b.date = d.date and b.b_itmid = i.id
left join (select r_date as date, r_itmid, sum(r_qty) qty_rent
from rent group by date, r_itmid) r
on r.date = d.date and r.r_itmid = i.id
left join (select s_date as date, s_itmid, sum(s_qty) qty_sell
from sell group by date, s_itmid) s
on s.date = d.date and s.b_itmid = i.id
where i.id = 1 and d.date >= date_format(curent_date, '%Y-%m-01')
order by d.date
I have following tables, i want to fetch the purchase_order and his order_quantity and sum of received quantity for each purchase_order. i know how to sum the quantity from single table but from multiple tables, it is confusing me a lot...
mysql> select * from purchase_order;
+-------------------+-------------------------+-------+---------------------+
| purchase_order_id | purchase_order | cost | created_on |
+-------------------+-------------------------+-------+---------------------+
| 1 | Dell Computer 000001256 | 10000 | 2015-02-19 22:14:52 |
| 2 | HP Computer 000001256 | 50000 | 2015-02-19 22:14:52 |
+-------------------+-------------------------+-------+---------------------+
2 rows in set (0.00 sec)
mysql> select * from purchase_order_detail;
+--------------------------+-------------------+---------+------------------+
| purchase_order_detail_id | purchase_order_id | item_id | ordered_quantity |
+--------------------------+-------------------+---------+------------------+
| 1 | 1 | 279 | 100 |
| 2 | 1 | 286 | 100 |
| 3 | 2 | 279 | 200 |
| 4 | 2 | 286 | 300 |
+--------------------------+-------------------+---------+------------------+
4 rows in set (0.00 sec)
mysql> select * from delivery_order;
+-------------------+--------------------------+-------------------+---------------------+
| delivery_order_id | purchase_order_detail_id | recieved_quantity | recieved_on |
+-------------------+--------------------------+-------------------+---------------------+
| 1 | 1 | 50 | 2015-02-19 22:22:51 |
| 2 | 2 | 50 | 2015-02-19 22:24:59 |
| 3 | 1 | 50 | 2015-02-19 22:34:14 |
| 4 | 3 | 70 | 2015-02-20 11:11:31 |
| 5 | 4 | 150 | 2015-02-20 11:11:31 |
| 6 | 3 | 90 | 2015-02-20 11:12:20 |
| 7 | 4 | 100 | 2015-02-20 11:12:20 |
| 8 | 3 | 40 | 2015-02-20 11:12:55 |
| 9 | 4 | 50 | 2015-02-20 11:12:55 |
+-------------------+--------------------------+-------------------+---------------------+
So far, i have this query, but id doesn't returns correct record..
SELECT po.purchase_order_id, SUM(pod.ordered_quantity) AS Sum_of_ordered_quantity, SUM(dor.recieved_quantity) AS Sum_of_recieved_quantity
FROM purchase_order AS po
INNER JOIN purchase_order_detail AS pod ON po.purchase_order_id = pod.purchase_order_id
INNER JOIN delivery_order AS dor ON dor.purchase_order_detail_id = pod.purchase_order_detail_id
GROUP BY po.purchase_order_id
it returns this,
+-------------------+-------------------------+--------------------------+
| purchase_order_id | Sum_of_ordered_quantity | Sum_of_received_quantity |
+-------------------+-------------------------+--------------------------+
| 1 | 300 | 150 |
| 2 | 1500 | 500 |
+-------------------+-------------------------+--------------------------+
you can see in the question that , purchase_order_id 1 has 200 ordered quantity and 150 received quantity while purchase_order_id 2 has 500 ordered_quantity and 500 received quantity.
Please try this code:
SELECT po.purchase_order_id,
SUM(pod.ordered_quantity) AS Sum_of_ordered_quantity,
(SELECT `mySelect`.`desired_sum` FROM
(SELECT B.`purchase_order_id` AS myID, SUM( `A`.`recieved_quantity` ) AS desired_sum
FROM `delivery_order` AS A
LEFT JOIN `purchase_order_detail` AS B ON A.purchase_order_detail_id = B.purchase_order_detail_id
GROUP BY B.`purchase_order_id` ) AS mySelect
WHERE `mySelect`.`myID` = `po`.`purchase_order_id`) AS Sum_of_received_quantity
FROM purchase_order AS po
INNER JOIN purchase_order_detail AS pod ON po.purchase_order_id = pod.purchase_order_id
GROUP BY po.purchase_order_id
This is usual while doing aggregate sum function with multiple many-to-many tables with different joining condition.
One way is to use correlated subquery to get the aggregate value and then do the join. Something as
select
po.purchase_order_id,
pod.Sum_of_ordered_quantity,
do.Sum_of_received_quantity
from purchase_order po
join
(
select purchase_order_id,sum(ordered_quantity) as Sum_of_ordered_quantity
from purchase_order_detail
group by purchase_order_id
)pod on pod.purchase_order_id = po.purchase_order_id
join
(
select
t1.purchase_order_id,
sum(t2.recieved_quantity) as Sum_of_received_quantity
from purchase_order_detail t1
join delivery_order t2 on t1.purchase_order_detail_id = t2.purchase_order_detail_id
group by t1.purchase_order_id
)do on do.purchase_order_id = po.purchase_order_id
DEMO
This is my table. I want to select distinct 'bill_no' with only first related row.
+--------------+--------------+-------+------------+
| id | bill_no | product_name | tax | total |
+--------------+-------+------+-------+------------+
| 1 | 12 | Hairgel | 10 | 241 |
| 2 | 12 | Spiker gel | 10 | 300 |
| 3 | 13 | Wokzem amba | 12 | 450 |
| 4 | 13 | test prod | 1 | 145 |
| 5 | 14 | wokk | 3 | 55 |
| 6 | 14 | Kamer hyp | 11 | 46 |
| 7 | 15 | Xyombokx | 2 | 220 |
+--------------+-------+------+-------+------------+
I want data to be displayed like the below table having only distinct "bill_no" -
Output-
+--------------+--------------+-------+------------+
| id | bill_no | product_name | tax | total |
+--------------+-------+------+-------+------------+
| 1 | 12 | Hairgel | 10 | 241 |
| 3 | 13 | Wokzem amba | 12 | 450 |
| 5 | 14 | wokk | 3 | 55 |
| 7 | 15 | Xyombokx | 2 | 220 |
+--------------+-------+------+-------+------------+
Use group by
select * from youtable group by bill_no
select t1.*
from your_table t1
join
(
select min(id) as id
from your_table
group by bill_no
) t2 on t1.id = t2.id
You can use GROUP BY clause.GROUP BY clause always return first row with related group by cloumn name.
SELECT * FROM `table_1` group by `bill_no`
I want to three table union to one query like a pivot table.
My main table name is products and two support tables name are code_keys and code_values
I have a main table name: products
+------------------+
| Field |
+------------------+
| productid |
| catpath |
| da |
| l0 |
| ig |
| des |
| notes |
| wire |
| lmm |
+------------------+
example data:
+-----------+------+------+------+
| productid | da | ig | des |
+-----------+------+------+------+
| 5 | 78 | 33 | 23 |
| 8 | 88 | 13 | 21 |
+-----------+------+------+------+
and 2 conf table names: code_keys. Store code structure.
+--------+
| Field |
+--------+
| codeid |
| title |
| codekey|
| format |
+--------+
example data:
+--------+----------------+
| codeid | title |
+--------+----------------+
| 2 | St Code |
| 3 | Rear Les |
+--------+----------------+
code_values
+-------+
| Field |
+-------+
| id |
| pid | -> Product ID
| codeid|
| value |
+-------+
and finally example data:
+----+------+--------+--------------+
| id | pid | codeid | value |
+----+------+--------+--------------+
| 9 | 5 | 2 | ST 102 200 R |
| 10 | 5 | 3 | 12 000 33 |
| 11 | 6 | 2 | ST 343 432 R |
| 12 | 6 | 3 | 34 343 24 |
| 15 | 8 | 2 | ST 100 101 R |
| 16 | 8 | 3 | 11 223 34 |
| 17 | 0 | 2 | ST 343 432 R |
| 18 | 0 | 3 | 34 343 24 |
+----+------+--------+--------------+
I want to show like this into one query:
Product Columns | *code_keys rows > columns* |
+-----------+------+------+------+--------------+----------+
| productid | da | ig | des | St Code | Rear Les |
+-----------+------+------+------+--------------+----------+
| 5 | 78 | 33 | 23 | ST 102 200 R | 12 000 33|
| 8 | 88 | 13 | 21 | ST 100 101 R | 11 223 34|
+-----------+------+------+------+--------------+----------+
Any ideas?
You can do this using CASE statement:
SELECT p.productid, p.da, p.ig, p.des
,GROUP_CONCAT(CASE WHEN ck.title = 'St Code'
THEN cv.value ELSE NULL END) AS 'St Code'
,GROUP_CONCAT(CASE WHEN ck.title = 'Rear Les'
THEN cv.value ELSE NULL END) AS 'Rear Les'
FROM Products p
JOIN code_values cv ON p.productid = cv.pid
JOIN code_keys ck ON cv.codeid = ck.codeid
GROUP BY p.productid;
If you have unknown number of code_keys you can try this dynamic query:
SET #sql = NULL;
SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'GROUP_CONCAT(CASE WHEN `title` = ''',
`title`,
''' THEN cv.value ELSE NULL END) AS `',
`title`, '`'
)
) INTO #sql
FROM code_keys ck JOIN code_values cv ON cv.codeid = ck.codeid;
SET #sql = CONCAT('SELECT p.productid, p.da, p.ig, p.des, ', #sql,'
FROM Products p
JOIN code_values cv ON p.productid = cv.pid
JOIN code_keys ck ON cv.codeid = ck.codeid
GROUP BY p.productid
');
PREPARE stmt FROM #sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
Output:
| PRODUCTID | DA | IG | DES | ST CODE | REAR LES |
--------------------------------------------------------
| 5 | 78 | 33 | 23 | ST 102 200 R | 12 000 33 |
| 8 | 88 | 13 | 21 | ST 100 101 R | 11 223 34 |
See this SQLFiddle