Insert directory path of images in a table with FK [MySQL] - php

Question

I'm trying to insert directory path of images in a table with FK (MySQL) using PHP-PDO, but I'm receiving this error:
SQLSTATE[23000]: Integrity constraint violation: 1452 Cannot add or update a child row: a foreign key constraint fails (bd-veiculos.fotos, CONSTRAINT fk_fotos_veiculos FOREIGN KEY (veiculos_idveiculos) REFERENCES mydb.veiculos (idveiculos) ON DELETE NO ACTION ON UPDATE NO ACTION)
This is my table:
I'm building a CRUD in php, I've got a table with informations of cars as below:
I've got a submit button called 'AddImages' When I click it, I'm sending via POST the ID of car that I want to change, this is the php page that I send...
uploadimageform.php:
after that I choose some images then I click submit and send the informations to the next php code:
<?php
include "dbconfig.php";
if(isset($_POST['submit'])){
$id = trim(strip_tags($_POST['id']));
# INFO IMAGEM
$file = $_FILES['img'];
$numFile = count(array_filter($file['name']));
# PASTA
$folder = 'uploads';
# REQUISITOS
$permite = array('image/jpeg', 'image/png');
$maxSize = 1024 * 1024 * 5;
# MENSAGENS
$msg = array();
$errorMsg = array(
1 => 'O arquivo no upload é maior do que o limite definido em upload_max_filesize no php.ini.',
2 => 'O arquivo ultrapassa o limite de tamanho em MAX_FILE_SIZE que foi especificado no formulário HTML',
3 => 'o upload do arquivo foi feito parcialmente',
4 => 'Não foi feito o upload do arquivo'
);
if($numFile <= 0)
echo 'Selecione uma Imagem!';
else{
for($i = 0; $i < $numFile; $i++){
$name = $file['name'][$i];
$type = $file['type'][$i];
$size = $file['size'][$i];
$error = $file['error'][$i];
$tmp = $file['tmp_name'][$i];
$extensao = #end(explode('.', $name));
$novoNome = rand().".$extensao";
if($error != 0)
$msg[] = "<b>$name :</b> ".$errorMsg[$error];
else if(!in_array($type, $permite))
$msg[] = "<b>$name :</b> Erro imagem não suportada!";
else if($size > $maxSize)
$msg[] = "<b>$name :</b> Erro imagem ultrapassa o limite de 5MB";
else{
if(move_uploaded_file($tmp, $folder.'/'.$novoNome)):
$msg[] = "<b>$name :</b> Upload Realizado com Sucesso!";
$imgpath[] = $folder.'/'.$novoNome;
else:
$msg[] = "<b>$name :</b> Desculpe! Ocorreu um erro...";
endif;
}
foreach($msg as $pop)
echo $pop.'<br>';
}
}
try
{
$sql = "INSERT INTO fotos (tbl_imagecar) VALUES ";
foreach ($imgpath as $path)
{
$sql .= " ('$path'),";
}
$sql = substr ($sql,0,strlen ($sql)-1);
$result = $DB_con->exec($sql);
echo "Dados criados com sucesso.<br><br>";
}
catch(PDOException $e)
{
echo $e->getMessage();
}
}
?>
<br><br>
INDEX
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Here's the query that I'm trying use to put the informations in the DB:
INSERT INTO fotos SET `tbl_imagecar` = 'uploads/19350.JPG', `veiculos_idveiculos` = (SELECT idveiculos FROM veiculos WHERE idveiculos = 3
from there I can not progress in my code. (Sorry for my bad English)

Answer 1

You are getting database foreign key voilation error. To fix this
Your field
mydb.veiculos (idveiculos)
needs to be first inserted/updated with same value(for example 13232) ,
which you are trying to insert into table field
bd-veiculos.fotos.veiculos_idveiculos