Hello awesome people on the internet! I need some help :)
I have a php rcon script, this script saves the result of the rcon to a variable named results, this is an example.
results = Showing 2 tracked objective(s) for lluiscab:- rcon: 4 (rcon)- test: 5555 (test)
I want to set a variable like rcon to 4 and test to 5555.
I used explode and other thinks that I found on the web, but I can't make it work. Does someone know how to do it?
Edit: This variable changes, so, sometimes I can have rcon, test and coins and sometime only rcon
You can use a regular expression for this.
preg_match('/rcon:\s*(\d+).*test:\s*(\d+)/', $line, $match);
$rcon = $match[1];
$test = $match[2];
\d+ matches a sequence of numbers, and putting () around it makes it a capture group. $match contains the parts of the input line that were matched by the regular expression, and $match[N] contains the Nth capture group.
If you need to capture anything that looks like word: number, you can use preg_match_all and an associative array.
preg_match_all('/(\w+):\s*(\d+)/', $line, $matches, PREG_SET_ORDER);
$results = array();
foreach ($matches as $match) {
$results[$match[1]] = intval($match[2]);
}
For the example input, this will create
$results = array(
'rcon' => 4,
'test' => 5555
);
DEMO
Related
I have a server application which looks up where the stress is in Russian words. The end user writes a word жажда. The server downloads a page from another server which contains the stresses indicated with apostrophes for each case/declension like this жа'жда. I need to find that word in the downloaded page.
In Russian the stress is always written after a vowel. I've been using so far a regex that is a grouping of all possible combinations (жа'жда|жажда'). Is there a more elegant solution using just a regex pattern instead of making a PHP script which creates all these combinations?
EDIT:
I have a word жажда
The downloaded page contains the string жа'жда. (notice the
apostrophe, I do not before-hand know where the apostrophe in the
word is)
I want to match the word with apostrophe (жа'жда).
P.S.: So far I have a PHP script creating the string (жа'жда|жажда') used in regex (apostrophe is only after vowels) which matches it. My goal is to get rid of this script and use just regex in case it's possible.
If I understand your question,
have these options (d'isorder|di'sorder|dis'order|diso'rder|disor'der|disord'er|disorde'r|disorder') and one of these is in the downloaded page and I need to find out which one it is
this may suit your needs:
<pre>
<?php
$s = "d'isorder|di'sorder|dis'order|diso'rder|disor'der|disord'er|disorde'r|disorder'|disorde'";
$s = explode("|",$s);
print_r($s);
$matches = preg_grep("#[aeiou]'#", $s);
print_r($matches);
running example: https://eval.in/207282
Uhm... Is this ok with you?
<?php
function find_stresses($word, $haystack) {
$pattern = preg_replace('/[aeiou]/', '\0\'?', $word);
$pattern = "/\b$pattern\b/";
// word = 'disorder', pattern = "diso'?rde'?r"
preg_match_all($pattern, $haystack, $matches);
return $matches[0];
}
$hay = "something diso'rder somethingelse";
find_stresses('disorder', $hay);
// => array(diso'rder)
You didn't specify if there can be more than one match, but if not, you could use preg_match instead of preg_match_all (faster). For example, in Italian language we have àncora and ancòra :P
Obviously if you use preg_match, the result would be a string instead of an array.
Based, on your code, and the requirements that no function is called and disorder is excluded. I think this is what you want. I have added a test vector.
<pre>
<?php
// test code
$downloadedPage = "
there is some disorde'r
there is some disord'er in the example
there is some di'sorder in the example
there also' is some order in the example
there is some disorder in the example
there is some dso'rder in the example
";
$word = 'disorder';
preg_match_all("#".preg_replace("#[aeiou]#", "$0'?", $word)."#iu"
, $downloadedPage
, $result
);
print_r($result);
$result = preg_grep("#'#"
, $result[0]
);
print_r($result);
// the code you need
$word = 'also';
preg_match("#".preg_replace("#[aeiou]#", "$0'?", $word)."#iu"
, $downloadedPage
, $result
);
print_r($result);
$result = preg_grep("#'#"
, $result
);
print_r($result);
Working demo: https://eval.in/207312
Here's the deal, I am handling a OCR text document and grabbing UPC information from it with RegEx. That part I've figured out. Then I query a database and if I don't have record of that UPC I need to go back to the text document and get the description of the product.
The format on the receipt is:
NAME OF ITEM 123456789012
OTHER NAME 987654321098
NAME 567890123456
So, when I go back the second time to find the name of the item I am at a complete loss. I know how to get to the line where the UPC is, but how can I use something like regex to get the name that precedes the UPC? Or some other method. I was thinking of somehow storing the entire line and then parsing it with PHP, but not sure how to get the line either.
Using PHP.
Get all of the names of the items indexed by their UPCs with a regex and preg_match_all():
$str = 'NAME OF ITEM 123456789012
OTHER NAME 987654321098
NAME 567890123456';
preg_match_all( '/^(.*?)\s+(\d+)/m', $str, $matches);
$items = array();
foreach( $matches[2] as $k => $upc) {
if( !isset( $items[$upc])) {
$items[$upc] = array( 'name' => $matches[1][$k], 'count' => 0);
}
$items[$upc]['count']++;
}
This forms $items so it looks like:
Array (
[123456789012] => NAME OF ITEM
[987654321098] => OTHER NAME
[567890123456] => NAME
)
Now, you can lookup any item name you want in O(1) time, as seen in this demo:
echo $items['987654321098']; // OTHER NAME
You can find the string preceding a value you know with the following regex:
$receipt = "NAME OF ITEM 123456789012\n" .
"OTHER NAME 987654321098\n" .
"NAME 567890123456";
$upc = '987654321098';
if (preg_match("/^(.*?) *{$upc}/m", $receipt, $matches)) {
$name = $matches[1];
var_dump($name);
}
The /m flag on the regex makes the ^ work properly with multi-line input.
The ? in (.*?) makes that part non-greedy, so it doesn't grab all the spaces
It would be simpler if you grabbed both the name and the number at the same time during the initial pass. Then, when you check the database to see if the number is present, you already have the name if you need to use it. Consider:
preg_match_all('^([A-Za-z ]+) (\d+)$', $document, $matches, PREG_SET_ORDER);
foreach ($matches as $match) {
$name = $match[1];
$number = $match[2];
if (!order_number_in_database($number)) {
save_new_order($number, $name);
}
}
You can use lookahead assertions to match string preceding the UPC.
http://php.net/manual/en/regexp.reference.assertions.php
By something like this: ^\S*(?=\s*123456789012) substituting the UPC with the UPC of the item you want to find.
I'm lazy, so I would just use one regex that gets both parts in one shot using matching groups. Then, I would call it every time and put each capture group into name and upc variables. For cases in which you need the name, just reference it.
Use this type of regex:
/([a-zA-Z ]+)\s*(\d*)/
Then you will have the name in the $1 matching group and the UPC the $2 matching group. Sorry, it's been a while since I've used php, so I can't give you an exact code snippet.
Note: the suggested regex assumes you'll only have letters or spaces in your "names" if that's not the case, you'll have to expand the character class.
I am going to parse a log file and I wonder how I can convert such a string:
[5189192e][game]: kill killer='0:Tee' victim='1:nameless tee' weapon=5 special=0
into some kind of array:
$log['5189192e']['game']['killer'] = '0:Tee';
$log['5189192e']['game']['victim'] = '1:nameless tee';
$log['5189192e']['game']['weapon'] = '5';
$log['5189192e']['game']['special'] = '0';
The best way is to use function preg_match_all() and regular expressions.
For example to get 5189192e you need to use expression
/[0-9]{7}e/
This says that the first 7 characters are digits last character is e you can change it to fits any letter
/[0-9]{7}[a-z]+/
it is almost the same but fits every letter in the end
more advanced example with subpatterns and whole details
<?php
$matches = array();
preg_match_all('\[[0-9]{7}e\]\[game]: kill killer=\'([0-9]+):([a-zA-z]+)\' victim=\'([0-9]+):([a-zA-Z ]+)\' weapon=([0-9]+) special=([0-9])+\', $str, $matches);
print_r($matches);
?>
$str is string to be parsed
$matches contains the whole data you needed to be pared like killer id, weapon, name etc.
Using the function preg_match_all() and a regex you will be able to generate an array, which you then just have to organize into your multi-dimensional array:
here's the code:
$log_string = "[5189192e][game]: kill killer='0:Tee' victim='1:nameless tee' weapon=5 special=0";
preg_match_all("/^\[([0-9a-z]*)\]\[([a-z]*)\]: kill (.*)='(.*)' (.*)='(.*)' (.*)=([0-9]*) (.*)=([0-9]*)$/", $log_string, $result);
$log[$result[1][0]][$result[2][0]][$result[3][0]] = $result[4][0];
$log[$result[1][0]][$result[2][0]][$result[5][0]] = $result[6][0];
$log[$result[1][0]][$result[2][0]][$result[7][0]] = $result[8][0];
$log[$result[1][0]][$result[2][0]][$result[9][0]] = $result[10][0];
// $log is your formatted array
You definitely need a regex. Here is the pertaining PHP function and here is a regex syntax reference.
<?php
$string = "Movies and Stars I., 32. part";
$pattern = "((IX|IV|V?I{0,3}[\.]))";
if(preg_match($pattern, $string, $x) == false)
{
print "NAPAKA!";
}
else
{
print_r($x);
}
?>
And the response is:
Array ( [0] => I. [1] => I. )
I should get only 1 response... Why do I get multiple responses?
The element at index 0 is the whole matched string. The element at index 1 is the contents of the first capture group, i.e. the content inside the parenthesis. In this case, they just happen to be the same. Just use $x[0] to get the value you're looking for.
The nested parenthesis should, in this instance, be a "non-capturing" subpattern.
$pattern = "~((?:IX|IV|V?I{0,3}[\.]))~";
Try that. It will tell the regex compiler to not capture the results of those parenthesis into the array.
In fact, looking at your regex, you don't even need those parenthesis. Make your regex this:
$pattern = "~IX|IV|V?I{0,3}[\.]~";
That should also work.
Your pattern has multiple groups in it -> the () brackets tell you what to capture in your match.
Try this:
$pattern = "(IX|IV|V?I{0,3}[\.])";
If you have a hard time identifying the wanted groups in the result you can name them as specified in the php.net documentation.
That would look something like this:
$pattern = "(?P<groupname>IX|IV|V?I{0,3}[\.])";
You get 0-indexed for all mathced string and result for every paretness (). it's helpful to get groups i.e
preg_match('~([0-9]+)([a-z]+)','12abc',$x);
$x is ([0]=>12abc [1]=>12 [2]=>abc)
In your case you can simply delete () (1 pair ot them, 1 pair is used as delimiters)
i have a file out of which i want a specific data below is the sample data
moduleHelper.addModule('REC');
moduleHelper.addModule('TOP');
What i want is
anything.anything('x');i.e.
moduleHelper.addModule('');
The above is what i want to be returned .
i just dont want the 'x' part exclusive of single quote.
i tried by my self and wrote a regex which is below.
/(.*)\.(.*)\(\'[^.*]\'\)/mi
it gives me nothing according to the PCRE manual the ^ inside the [ ] does negation ??
It could be done with preg_replace_callback if you feel like figuring out how all that backreferencing works, but i think this is a bit easier:
// the regex
$regex = "/(?P<FIRST>.+)?\.(?P<SECOND>.+)\('(?P<PARAM>.+)?\'\)?/mi";
$subject = <<<EOB
moduleHelper.addModule('REC');
moduleHelper.addModule('TOP');
EOB;
$matches = array();
$numberOfMatches = preg_match_all($regex, $subject, $matches, PREG_SET_ORDER);
$results = array();
foreach($matches as $match)
{
array_push($results, sprintf("%s.%s('')", $match['FIRST'], $match['SECOND']));
}
print_r($results);
// result:
Array
(
[0] => moduleHelper.addModule('')
[1] => moduleHelper.addModule('')
)
Try using the following
/^([^.]+)\.([^\(]+)/
If ^ is the first character in [ ] then it negates the other characters in the set. Where [ab] accepts either a or b, [^ab] accepts any character that is not a nor b.
Also I'm not sure what you want. You state that you do not want the 'x', but what exactly do you want?
It does do negation. [^.*], in this case, means "get on character that is not . or *. I think you want below, but I can't totally tell.
preg_match_all( "/(\w+\.\w+)(?=\([\"']\w+[\"']\);)/i", $string, $matches);
Try this one:
/([^.]*)\.([^.]*)\(.*\)/