file_get_contents on local wamp server not working - php

I simply cant wrap my head around why this simple code won't work on my local wamp server where i have other sites running.
<?php
$file = file_get_contents('C:\Users\Computer\input.txt', true);
echo $file;
?>
The file is where it should be.
I get the following error:
Warning: file_get_contents(C:\Users\Computer\input.txt): failed to open stream: No such file or directory in C:\Users\Computer\Dropbox\htdocs\ny\www\php\day2\code.php on line 3
But the file is exactly where it should be.
The file has all possible permissions to true (read, write ect.) in windows except for "special permissions".
What is not working correctly?
Regards,
Patrick

The solution was the extension. It was not correctly parsed. This was checked by using #VolkerK suggesting to check
Does the output of var_export(glob('C:\Users\Computer*')); contain
input.txt? Or is it false/null?
Thanks to #VolkerK for the help solving the problem.

Since I incorrectly said that it might be because of backslash escaping, I guess I need to redeem by saying something useful :)
So try:
$file = 'C:\Users\Computer\input.txt';
if(is_file($file))
{
$string = file_get_contents($file);
}
else
{
die("Uh oh! Seems like $file has got problems!");
}
Also, you are passing the second argument as true for searching the include path. Since your filepath is absolute, I suspect if you need this argument to be passed at all.

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I don't have enough reputation to post more then 8 lines so everything is on pastebin Here. The main aprt is...
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https://pastebin.com/Z321R76z
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Here is a snippet of what I'm trying to do:
$file = fopen($path, "wb");
fwrite($file, $data);
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Simple enough.
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But I've clearly specified I want binary mode. Maybe my brain isn't functioning right or something, so.. Anyone got a solution?
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If you are defining the $path with a dynamic file name, use / before the file name. For example, $var = "/var/www/html/projectFolder/folderFile/". "Filename.fileformat"
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You're making the classic mistake of confusing data with the representation of that data.
Let's say you have a text file. If you open it in Notepad, you'll see the following:
$str = "Hello world!";
echo bin2hex($str); // output: 48656c6c6f20776f726c6421
$file = fopen($path, "wb");
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how to open a file while inside a foreach(glob....PHP

I have a small number of image files and text files. They have the same file name with different extensions. I need to read the image files and for each image I need to read some (tool top) text from the corresponding text file. The problem is the file open inside the "foreach( glob("inserts/*.png")" loop fails. I have output the filename and the fopen works fine. I thought it may be you are unable to open two file concurrently in PHP but I could find nothing about it when I googled
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$insertpath=substr($filename, 0, -3)."txt";
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$rec=fread($myfile,filesize($insertpath));
fclose($myfile);
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}
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I am writing some php script to update the code on my sites. In order to do that I have written the following lines which checks for the update version and bring the name from where I use to distribute my updates ans then creates the link of that name. I have done something like this.
$filename = "http://www.hf-live.com/codeupdate/Get_Files_Name.php";
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echo $contents;
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failed to open stream: No such file or directory.
Even though the file is present still I am getting the same error. I have turned on my allow_url_fopen to on. The above code is working from my local host but not from the server. I have to update a major bug fix and I am stuck.. Please someone help me soon..
remove extra .php from url
$filename = "http://www.hf-live.com/codeupdate/Get_Files_Name.php";
You will get error if you are doing this way...
$filename = "marynyhof.com/Info.php"; // will give you error, which exactly you are getting
use full url like this
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PHP - Failed to open stream: no such file or directory - for existing file

I'm writing a PHP application and in my code i want to create create and return images to the browser. However, sometimes i'm getting some weird results where the image cannot be created since the file does not seem to exist.
Here is a sample error message I get and the code in a nutshell. I do know that the image exists, but still the method sometimes fails, and sometimes it succeeds, even for the same file.
The error:
Warning: imagecreatefrompng(path/to/image.png) [function.imagecreatefrompng]: failed to open stream: No such file or directory in file test.php on line 301
The code:
if (file_exists($filename)) {
$image = imagecreatefrompng($filename);
}
I would greatly appreciate any hints or tips of what might be wrong and how I can improve the code to be more stabile.
I suggest you use is_readable
if (is_readable($filename)) {
$image = imagecreatefrompng($filename);
}
The file may "exist" but is the file accessible? what does file_exists actually do?
if it opens the file and then closes it make sure that the file is actualy closed and not locked before imagecreatedfrompng fires.
it would be a good idea to try catching the error in a loop and make 4 or 5 attempts before handing back a controlled error.
maybe try is_readable() or is_writable() instead?
Have you considered checking for the correct permissions? If the file cannot be read, but the directory can, you would get file_exists(...) = true, but would not be able to open a handle to the file.
Use is_readable() to check whatever you have permission to access that file.
You can try GD :
IF($img = #GETIMAGESIZE("testimage.gif")){
ECHO "image exists";
}ELSE{
ECHO "image does not exist";
}
bro check for white spaces in your filepath. I recently had this issue while i was tring to include a file from a module i was creating for an app. Other modules included well when called but one didnt. It turned out that there was a white space in the filepath. I suggest u try php trim() function. If this works holla.

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