How to compare different arrays? - php

Question

I need to show the email address, first and last names of users who are not registered in my new database.
I selected three columns of my old database and three columns of my new database. I created two arrays and each receives the result of the query.
But when the comparing is displaying all users, the comparison is not made.
Check my code:
while($array = $resultado->fetch_array(MYSQLI_NUM)){
$portal_old[] = $array;
}
while($array2 = $resultado2->fetch_array(MYSQLI_NUM)){
$portal_new[] = $array2;
}
foreach ($portal_old as $portal) {
if(!in_array($portal, $portal_new)){
$result[] = $portal;
}
}

Answer 1

Assuming email address should be able to uniquely identify a registered user, you can use email address as a key as you build your array of results from each database.
while($array = $resultado->fetch_array(MYSQLI_ASSOC)){
$portal_old[$array['email']] = $array;
}
while($array2 = $resultado2->fetch_array(MYSQLI_ASSOC)){
$portal_new[$array2['email']] = $array2;
}
In order for this to work, you will need to either use MYSQLI_ASSOC instead of MYSQLI_NUM when fetching, and specify the name of the email column when building your array, or if you are using MYSQLI_NUM, specify the numeric index of the email column.
Then you can use array_diff_key to easily find the result you are looking for.
$result = array_diff_key($portal_old, $portal_new);

Answer 2

This works, John Smith here gets in $result while Joe Black doesn't:
<?php
$name = array(0 => 'john', 1 => 'smith');
$portal_old[] = $name;
$name = array(0 => 'joe', 1 => 'black');
$portal_old[] = $name;
//print_r($portal_old);
//shows: Array ( [0] => Array ( [0] => john [1] => smith ) [1] => Array ( [0] => joe [1] => black ) )
$name = array(0 => 'jason', 1 => 'mill');
$portal_new[] = $name;
$name = array(0 => 'joe', 1 => 'black');
$portal_new[] = $name;
//print_r($portal_new);
//shows: Array ( [0] => Array ( [0] => jason [1] => mill ) [1] => Array ( [0] => joe [1] => black ) )
foreach($portal_old as $key=>$value) {
if(!in_array($value[0], $portal_new[0]) && !in_array($value[1], $portal_new[1])) {
$result[] = $value;
}
}
print_r($result);
//shows: Array ( [0] => Array ( [0] => john [1] => smith ) )
?>
It's because the results of $portal_old and $portal_new are multidimensional arrays, you need to compare by looking inside the arrays of the arrays.

Answer 3

This will work for you :
$i = $j = 0;
while($array = $resultado->fetch_array(MYSQLI_NUM)){
$portal_old[$i][$array['0'].' | '.$array['1'].' | '.$array['2']] = $array;
}
while($array2 = $resultado2->fetch_array(MYSQLI_NUM)){
$portal_new[$j][$array2['0'].' | '.$array2['1'].' | '.$array2['2']] = $array2;
}
// Get only array keys
$old_arr_key = array_keys($portal_old[0]);
$new_arr_key = array_keys($portal_new[0]);
// Result
$result = array_diff($new_arr_key,$old_arr_key);
print_r($result);