I want to be able to calculate the days that post was created and compare with today to echo "Today/ Yesterday/ Last Week/ Last Month". The date format I get from get_the_date() is "December 1, 2015" so I'm wondering if I need to use a different function that I don't know about.
You just need to the get_the_date() function;
Now Date Should In YYYY-MM-DD Format
for that
$date1 = date('Y-m-d', strtotime(get_the_date())) ;
$current_date1 = date('Y-m-d', time()) ;
Now use this function
function dateDifference($date_1 , $date_2 )
{
$datetime1 = date_create($date_1);
$datetime2 = date_create($date_2);
$interval = date_diff($datetime1, $datetime2);
return $interval->format('%a');
}
//call above function
echo $days = dateDifference($date1, $current_date1);
I'm not sure if there is any WordPress function but you can get your values using built in PHP functions.
Yesterday:
date('Y-m-d', strtotime("-1 day"));
Last week
date('Y-m-d', strtotime("-1 week +1 day"));
Last month
date('Y-m-'.1, strtotime("-1 month")); //First day of -1 month
You can read more about strtotime here http://php.net/manual/en/function.strtotime.php
Here is also a link to the date function, if you havent had any experience with it before: http://php.net/manual/en/function.date.php
You would want to use Y-m-d format for wordpress querys read more about that here: http://php.net/manual/en/function.date.php
Related
I have an issue.I need to calculate the time difference but here the date_create function is not showing any output in php.I am explaining my code below.
while($row=mysqli_fetch_assoc($orderqry)){
$exit_date=$row['delivered_datetime'];
if($exit_date!=='0000-00-00 00:00:00'){
$deldate=date_create($exit_date);
$today=date_create(date('Y-m-d H:i:s'));
echo $today;exit;
$interval = date_diff($deldate, $today);
$hours = $interval->format('%h');
}
}
Here i am trying to echo $today but its not giving any result.Here i need to calculate the time difference in hour.In my DB i have existing time in the format of date('Y-m-d H:i:s').Please help me.
$today is DateTime instance. To echo it you need to call its format() method.
echo $today->format('Y-m-d H:i:s');
date_create is an alias of: DateTime::__construct(). see below example, I have assigned 6 Hour ago date in $exit_date. so ideally difference from current date should be 6 Hour.
$exit_date = date('Y-m-d H:i:s', strtotime('-6 Hours'));
$deldate=date_create($exit_date); //returns datetime class object
$today=date_create(date('Y-m-d H:i:s'));
$interval = date_diff($deldate, $today);
echo $hours = $interval->format('%h'); // output 6 hours
If you want to print date from $today variable then use:
echo $today->format('Y-m-d H:i:s'); //output: today's date in Y-m-d H:i:s format
for more detail have a look at http://php.net/manual/en/book.datetime.php
I can add x week to my date
//$ultima_azione <--- 2015/07/15
//$data['intervallo'] <---- 5
$mydate = date("Y-m-d",strtotime($ultima_azione." +".$data['intervallo']." weeks"));
now how can i give a day starting from that week
example:
//$mydate + "next Monday" -----> final date
and this ve to work like, if today is Monday and i add weeks to jump to an other Monday and then i select the next Monday the week don't ve to change
The simplest way would be to use strtotime. It can do date calculations based on a textual representation of the delta:
$mydate = strtotime('+3 weeks');
It also accepts a second parameter, which is a timestamp to start from when doing the calculation, so after you get the offset in weeks, you can pass the new date to a second calculation:
// Get three weeks from 'now' (no explicit time given)
$mydate = strtotime('+3 weeks');
// Get the Monday after that.
$mydate = strtotime('next Monday', $mydate);
See strtotime documentation for more examples of notations that you can use.
I would highly recommend using PHP's built-in DateTime class for any date and time logic. It's a much better API than the older date and time functions and creates much cleaner and easier to read code.
For example:
// Current date and number of weeks to add
$date = '2015/07/15';
$weeks = 3;
// Create and modify the date.
$dateTime = DateTime::createFromFormat('Y/m/d', $date);
$dateTime->add(DateInterval::createFromDateString($weeks . ' weeks'));
$dateTime->modify('next monday');
// Output the new date.
echo $dateTime->format('Y-m-d');
References:
DateTime.
DateTime::createFromFormat
DateTime::add
DateTime::modify
DateInterval::createFromDateString
DateTime::format
Are you looking for something like this?
$today = time();
$weeks = 2;
// timestamp 2 weeks from now
$futureWeeks = strtotime("+ ".$weeks." weeks");
// the next monday after the timestamp date
$futureMonday = strtotime("next monday",$futureWeeks);
echo date("Y-m-d", $futureMonday);
// or in one line
echo date("Y-m-d", strtotime("next monday", strtotime("+ ".$weeks." weeks")));
PHP is using an unix timestamp for date calculations. Functions as date() and strtotime() using a timestamp as an optional second parameter. This is used a reference for formatting and calculations. If no timestamp is passed to the function the current timestamp is used (time()).
I have the answer here. This will show the next wednesday every 2 weeks and the first date to start from would be the 10th.
I have also added in an estimated delivery which would be 6 weeks after that date.
We will be placing our next order for this on:
<?php
$date = '2020/05/26';
$weeks = 2;
$dateTime = DateTime::createFromFormat('Y/m/d', $date);
$dateTime->add(DateInterval::createFromDateString($weeks . ' weeks'));
$dateTime->modify('wednesday');
echo $dateTime->format('d/m/Y');
?>
Expected delivery for the next order will be:
<?php
$date = '2020/05/26';
$weeks = 2;
$dateTime = DateTime::createFromFormat('Y/m/d', $date);
$dateTime->add(DateInterval::createFromDateString($weeks . ' weeks'));
$dateTime->modify('+42 days next wednesday');
echo $dateTime->format('d/m/Y');
?>
If anyone can confirm this is correct that would be great.
I want to find the next occurrence of date from the current date.
For example, imagine I want to find 20th of the month from current date
If current date is 10th october then return the result 2014-10-20 (Y-m-d)
If current date is 22nd october then return the result 2014-11-20 (Y-m-d)
I created a solution just now using a while loop.
$oldd= "2014-06-20";
$newdate = date("Y-m-d",strtotime($oldd."+1months"));
while(strtotime($newdate) <= strtotime(date("Y-m-d")))
{
$newdate = date("Y-m-d",strtotime($newdate."+1months"));
}
echo $newdate;
manually and pass that to strtotime(). The time information you need to extract from the reference time string. Like this:
$refdate = '2014-02-25 10:30:00';
$timestamp = strtotime($refdate);
echo date('Y-m-d H:i:s',
strtotime("next Thursday " . date('H:i:s', $timestamp), $timestamp)
);
same results could be achieved using string concatenation:
echo date('Y-m-d', strtotime("next Thursday", $timestamp)
. ' ' . date('H:i:s', $timestamp);
another way, you can use methods of DateTime object, PHP has really rich API in dealing with date time.
$current_date = new DateTime('2014-06-20');
if ($current_date->format('d') >= 20) {
// $current_date->modify('last day of this month')->modify("+20 days");
$current_date->modify('first day of next month')->modify("+19 days");
}else{
$current_date->modify('first day of this month')->modify("+19 days");
}
echo $current_date->format("Y-m-d");
http://php.net/manual/en/datetime.modify.php
http://php.net/manual/en/datetime.formats.relative.php
I am generating next date using the following code:
$s1=date('d/M/Y', strtotime('+1 day'));
echo $s1;
for ex: Assume current date is 26/Aug/2014.
so above code generates 27/Aug /2014 and storing in varible $s1.
By using the varible s1 i want to create 28/Aug/2014. how to create?
I dont want to use '+2 day' in STRTOTIME function. I want to generate next day based on variable $s1.
You can do it all with strtotime() but you have to remember that strtotime assumes a USA date format when it see's a / forward slash as a seperator.
So before using $s1 you need to convert the / to a - so it assumes a sensible data format is being used.
$s1=date('d/M/Y', strtotime('+1 day'));
echo $s1.PHP_EOL;
// change date format as strtotime assumes USA dates
$date = strtotime( '+1 day', strtotime( str_replace('/','-',$s1) ) );
echo date('d/M/Y', $date);
When run on 26/Aug/2014 the result would be
27/Aug/2014
28/Aug/2014
The best way (using strtotime):
$tomorrow = strtotime('+1 day');
$twoDaysHence = strtotime('+1 day', $tomorrow);
echo date('d/M/Y', $tomorrow);
echo date('d/M/Y', $twoDaysHence);
In other words, leave your date variables in the form of UNIX timestamps as returned by strtotime until you need to display them. Because you can do calculations directly with them in this format. Once you format that to a date string, you'll have to convert them back into a malleable form first. strtotime doesn't recognise the format d/M/Y automatically, so that makes that all the harder. You should use DateTime in that case:
$tomorrow = date('d/M/Y', strtotime('+1 day'));
$timestamp = DateTime::createFromFormat('d/M/Y', $tomorrow);
$timestamp->modify('+1 day');
echo $timestamp->format('d/M/Y');
You can use something like following:
$newvariable = strtotime ('+2 day' , $s1);
this is a very simple part
$s1=date('d/M/Y', strtotime('+2 day'));
echo $s1;
and if you want then copy the value of $s1 in another variable
function date_addDate($text, $da=0, $ma=0, $ya=0, $ha=0)
{
$h=date('H',strtotime($text));
$d=date('d',strtotime($text));
$m=date('m',strtotime($text));
$y=date('Y',strtotime($text));
$fromTime =date("Y-m-d H:i:s", mktime($h+$ha, 0, 0, $m+$ma, $d+$da, $y+$ya));
return $fromTime;
}
$date = date("Y-m-d H:i:s");
// $da days
// $ma months
// $ya years
// $ha hours
echo date_addDate($date, $da=0, $ma=0, $ya=0, $ha=0);
//out put : current date
echo date_addDate($date, $da=2, $ma=0, $ya=0, $ha=0);
//out put : As you want
Try this
$s1=date('d/M/Y', strtotime('+1 day'));
echo $s1; echo "<br/>";
$date = strtotime(strtotime($s1). ' + 2 days');
$s2 = date('d/M/Y', $date);
echo $s2;
Now it's edited!! Check it!
What about using DateTime ?
$d1 = new DateTime(date('Y-m-d'));
$d1->format('d/m/Y'); // 26/08/2014
$d1->modify('+1 day');
$d1->format('d/m/Y'); // 27/08/2014
Given a time, how can I find the time one month ago.
strtotime( '-1 month', $timestamp );
http://php.net/manual/en/function.strtotime.php
In php you can use strtotime("-1 month"). Check out the documentation here: http://ca3.php.net/strtotime
We can achieve same by using PHP's modern date handling. This will require PHP 5.2 or better.
// say its "2015-11-17 03:27:22"
$dtTm = new DateTime('-1 MONTH', new DateTimeZone('America/Los_Angeles')); // first argument uses strtotime parsing
echo $dtTm->format('Y-m-d H:i:s'); // "2015-10-17 03:27:22"
Hope this adds some more info for this question.
<?php
$date = new DateTime("18-July-2008 16:30:30");
echo $date->format("d-m-Y H:i:s").'<br />';
date_sub($date, new DateInterval("P1M"));
echo '<br />'.$date->format("d-m-Y").' : 1 Month';
?>
PHP 5.2=<
$date = new DateTime(); // Return Datetime object for current time
$date->modify('-1 month'); // Modify to deduct a month (Also can use '+1 day', '-2 day', ..etc)
echo $date->format('Y-m-d'); // To set the format
Ref: http://php.net/manual/en/datetime.modify.php
This code is for getting 1 month before not 30 days
$date = "2016-03-31";
$days = date("t", strtotime($date));
echo date("Y-m-d", strtotime( "-$days days", strtotime($date) ));
These answers were driving me nuts. You can't subtract 31 days and have a sane result without skipping short months.
I'm presuming you only care about the month, not the day of the month, for a case like filtering/grouping things by year and month.
I do something like this:
$current_ym = date('ym',strtotime("-15 days",$ts));