i want to get datas from a mySQL table and want to insert every row (that my query get) into another table.
With following code i get my Datas:
$cart = new Dbconn();
$query = new Dbconn();
if ($cart->pdo()) {
$cart->stmt("SELECT id, product FROM cart WHERE uid =:uid");
$cart->bindParam(':uid', Session::get('uid'));
$cart->exe();
}
After i get the data i want to insert it, with a while loop
while ($rowPay = $cart->fetch()) {
if ($query->pdo()) {
$query->stmt('INSERT INTO orders (products_id, order_id) VALUES(:uid, :products)');
$query->bindParam(':user_id', Session::get('uid'));
$query->bindParam(':products', $rowPay['product']);
$query->exe();
}
}
He get all Datas but insert only the first entry. Where is my mistake?
Greetings
If it insert only the first entry, then there is a problem with the parameters you try to insert.
You probably try to insert several rows with the same primary key.
I need to know where is the primary key in each table in order to help you more.
$payCart->fetch() fetches single row and $payCart->fetchAll() fetches all rows.
Try as this
while ($rowPay = $payCart->fetchAll(PDO::FETCH_ASSOC)) {
if ($query->pdo()) {
$query->stmt('INSERT INTO orders'
.'(products_id, order_id)'
.'VALUES(:uid, :products)');
$query->bindParam(':user_id', Session::get('uid'));
$query->bindParam(':products', $rowPay['product']);
$query->exe();}}
Related
Bit new to MYSQL and PHP - I have the following code that will create a new record in multiple tables that I have setup however I need to merge the following code together somehow as it creates separate rows instead of one record
$sql .=("INSERT INTO orders (customer_id) SELECT customer_id FROM
customer_details;");
foreach($result as $item){
$mysql_desc = $item['product_description'];
$mysql_mode = $item['delivery_mode'];
$mysql_cost = $item['course_cost'];
$sql .=("INSERT INTO orders(product_description, delivery_mode, course_cost) VALUES('$mysql_desc', '$mysql_mode', '$mysql_cost');");
}
The result I'm getting:
Based on your data I assume that you want to insert the customer id and the values from php into the same record. In this case you need to combine them into the same insert ... select ... statement:
$sql .=("INSERT INTO orders(customer_id, product_description, delivery_mode, course_cost) select customer_id, '$mysql_desc', '$mysql_mode', '$mysql_cost' from customer_details;");
Couple of things to note:
This insert ... select ... statement will insert the same records for all customers in the customer details table. I'm not sure if this is your ultimate goal.
Pls consider the advices made in the comments regarding the old mysql API and the use of prepared statements.
To put this more into what I would expect to happen, something along the lines of - prepare statement, then loop through each item and add in new row...
$insert = $connection->prepare("INSERT INTO orders (customer_id,product_description, delivery_mode, course_cost)
VALUES (?,?,?,?)");
foreach($result as $item){
$customerID = 1; // Have to ensure this is what your after
$mysql_desc = $item['product_description'];
$mysql_mode = $item['delivery_mode'];
$mysql_cost = $item['course_cost'];
$insert->execute([customerID,mysql_desc,mysql_mode,mysql_cost]);
}
I have the following two tables
Table player:
player_id (int)(primary)
player_name (varchar)
player_report_count (int)
Table report:
report_id (int)(primary)
player_id
report_description
report_location
Firstly I ask the user for the player_name and insert it into the player database. From here the player is given an id.
Then I tried to grab the value of the players report count and increment the current value by one (which isn't working).
This is followed by grabbing the playerId from the player table and then inserting into the corresponding column from the report table (also does not work).
When I insert some values into the database, the names, description and report are added to the database however the playerID remains at 0 for all entries and the player_report_count remains at a consistent 0.
What is the correct way to make these two features function? And also is there a more efficient way of doing this?
<?php
$records = array();
if(!empty($_POST)){
if(isset($_POST['player_name'],
$_POST['report_description'],
$_POST['report_location'])){
$player_name = trim($_POST['player_name']);
$report_description = trim($_POST['report_description']);
$report_location = trim($_POST['report_location']);
if(!empty($player_name) && !empty($report_description) && !empty($report_location)){
$insertPlayer = $db->prepare("
INSERT INTO player (player_name)
VALUES (?)
");
$insertPlayer->bind_param('s', $player_name);
$reportCount = $db->query("
UPDATE player
SET player_report_count = player_report_count + 1
WHERE
player_name = $player_name
");
$getPlayerId = $db->query("
SELECT player_id
FROM player
WHERE player_name = $player_name
");
$insertReport = $db->prepare("
INSERT INTO report (player_id, report_description, report_location)
VALUES (?, ?, ?)
");
$insertReport->bind_param('iss', $getPlayerId, $report_description, $report_location);
if($insertPlayer->execute()
&& $insertReport->execute()
){
header('Location: insert.php');
die();
}
}
}
Main issue here is you are getting player details before inserting it. $getPlayerId will return empty result always.
Please follow the order as follows.
Insert player details in to player table and get payerid with mysql_insert_id. After binding you need to execute to insert details to the table.
Then bind and execute insert report .
Then update the player table by incrementing report count with playerid which you got in step 1.
Note : use transactions when inserting multiple table. This will help you to rollback if any insert fails.
MySQL Query will return result object. Refer it from here https://stackoverflow.com/a/13791544/3045153
I hope it will help you
If you need to catch the ID of the last insterted player, This is the function you need if you're using PDO or if it's a custom Mysql Class, you need the return value of mysql_insert_id() (or mysqli_insert_id()) and then directly use it in the next INSERT INTO statement
I have a form button that I need to do two different things, based on user input and whether that input already exists in my database. If the input DOES NOT exist, then the button will create a new record. If it DOES exist, then the existing record will be updated.
Here's my PDO query as it stands now:
/* First, we need to discover whether the Proposal No. entered already exists in the
database. If it doesn't, then a new record will be created. If
it does, then an existing record will be updated. */
$pNoExists = $con->prepare("SELECT ProposalNo FROM ptfp1");
$pNoExists->execute();
$row = $pNoExists->fetch(PDO::FETCH_ASSOC);
When I run $row = $pNoExists->fetch(PDO::FETCH_ASSOC); through a while loop, all of the values for the field are present. Now I just need some guidance on how to use that in my button setup. This is what I want to do:
if($_POST['ButtonPush'] && input doesn't exist) {
Create new record;
}
else {
Update existing record;
}
Simple, right? But it's eluding me.
Given what you have, I would do:
if($_POST['ButtonPush'] && array_search($all_values, $input_value)) {
Create new
}
else {
Update
}
However, like the comment above, you may want to simply add a where clause to your "SELECT" statement so you are not grabbing the entire database table contents every time. And, one could even convert the SELECT in to a SELECT COUNT to bring down the amount of data being requested.
You could use SELECT count(*) FROM ptfp1 WHERE ProposalNo = :input
Than check if the value you get is bigger than one. If it is, update it:
UPDATE ptfp1 set ... where ProposalNo = :input
else
INSERT INTO ptfp1(...) VALUES (...)
Assuming ProposalNo has a unique index in the table, you can do it all in one query:
INSERT INTO ptfp1 (ProposalNo, colA, colB, colC, ...)
VALUES (:ProposalNo, :colA, :colB, :colC, ...)
ON DUPLICATE KEY
UPDATE colA = VALUES(colA), colB = VALUES(colB), colC = VALUES(colC), ...
Documentation
Figured out an answer. Just use the user's input (stored in a session variable) in my SELECT statement:
$pNoExists = $con->prepare("SELECT ProposalNo FROM ptfp1 WHERE ProposalNo =
'".$_SESSION['ProposalNo']."'");
$pNoExists->execute();
$row = $pNoExists->fetch(PDO::FETCH_ASSOC);
And the button:
if($_POST['ButtonPush'] && !$row['ProposalNo']) {
Write new record;
}
else {
Update existing record;
}
Hiding in plain sight!
If I have two different MySQL insert functions in a document going to two different tables, how can I get the id of one record and place it in the other table?
After the first insert you can pickup the id via mysql_insert_id
tru something like this
function insert1()
{
mysql_query("INSERT .....");
return myqsl_insert_id();
}
function insert2()
{
$id1 = insert1(); // the id you want
mysql_query("INSERT ..... $id1 ");
}
you can get the last insert id by mysql_insert_id() function and then use it.
For example your first Insert query is
$insertqry1 = mysql_query("insert into tbl_name values(..,...,..)");
$lastinsertid = myqsl_insert_id();
Your second Query will be
$insertqry2 = mysql_query("insert into tbl_name(id) values('$lastinsertid')");
I'm new to php. So, please forgive me if this seems like a dumb question.
Say i have a MySQL insert statement insert into table (a,b) values (1,2),(3,4),(5,6). table 'table' has a auto increment field called 'id'.
how can I retrieve all the ids created by the insert statement above?
It will be great if i get an example that uses mysqli.
You can't. I would suggest that you maintain your own ids (using guid or your own auto-increment table) and use it when you insert into the table.
But it's possible to get the auto-increment value for the last inserted using LAST_INSERT_ID():
http://dev.mysql.com/doc/refman/5.0/en/getting-unique-id.html
AngeDeLaMort's answer is almost right. Certainly, the most appropriate way to deal with the problem is to insert one row at a time and poll the insert_id or generate the sequence elsewhere (which has additional benefits in terms of scalability).
I'd advise strongly against trying to determine the last insert_id and comparing this the most recent insert_id after the insert - there's just too may ways this will fail.
But...an alternative approach would be:
....
"INSERT INTO destn (id, data, other, trans_ref)
SELECT id, data, other, connection_id() FROM source";
....
"SELECT id FROM destn WHERE trans_ref=connection_id()";
....
"UPDATE destn SET trans_ref=NULL where trans_ref=connection_id()";
The second query will return the ids generated (note that this assumes that you use the same connection for all 3 queries). The third query is necessary because connection ids to go back into the pool when you disconnect (i.e. are reused).
C.
In some cases, if you have another identifier of sort such as a UserID, you could filter your query by UniqueID's greater than or equal to mysql_insert_id(), limit by the number of affected rows and only display those by the user. This would really only work inside of a transaction.
$SQL = "INSERT INTO Table
(UserID, Data)
VALUES
(1,'Foo'),
(1,'Bar'),
(1,'FooBar')";
$Result = mysql_query($SQL);
$LastID = mysql_insert_id();
$RowsAffected = mysql_affected_rows();
$IDSQL = "SELECT RecordID
FROM Table
WHERE UserID = 1
AND RecordID >= '$LastID'
LIMIT '$RowsAffected'";
$IDResult = mysql_query($IDSQL);
as a follow up to AngeDeLaMort:
You could seperate your inserts and do it something like this:
$data = array (
array(1,2),
array(3,4),
array(5,6)
);
$ids = array();
foreach ($data as $item) {
$sql = 'insert into table (a,b) values ('.$item[0].','.$item[1].')';
mysql_query ($sql);
$id[] = mysql_insert_id();
}
Now all your new id's are in the $id array.
Maybe I can do this
$insert = "insert into table (a,b) values (1,2),(3,4),(5,6)";
$mysqli->query($insert);
$rows_to_be_inserted=3;
$inserted_id = $mysqli->insert_id // gives me the id of the first row in my list
$last_row_id = ($inserted_id+$rows_to_be_inserted)-1;
$mysql->query("select * from table where id between $inserted_id and $last_row_id");
what to you guys say?