i'm saving time for first login ,now when user logs in i enter time using NOW() function, that saves time in this format (data type is DATETIME.
2015-12-24 15:47:30
Now logic is like every login is first login so i've to check if there already exists an entry for today to check that i fetch time explode it and get time like this
$logintime= mysqli_query($connection,"SELECT loggedin from employees");
$loggedin_time= mysqli_fetch_assoc($logintime);
$Date = $loggedin_time['loggedin'];
$loggedin_time_converted= explode(" ",$yourDate) ;
$ConvertedDate = $loggedin_time_converted[0];
last line returns 2015-12-24 now i've date
$today= time();
$DateToday= date("Y-m-d",$today);
$DateToday also returns me same format and same date now i need your help me to compare these dates , if they are equel i dont uopdate database if they are not i will , Pleas help me how do i compare these values
You can do the test in MySQL
$result = mysqli_query($connection, "SELECT DATE(loggedin) = CURDATE() AS logged_in_today FROM employees");
$row = mysqli_fetch_assoc($result);
if (!$row['logged_in_today']) {
// code to update database
}
Wow, you've done all the hard stuff to get the problem to the point of being a simple comparison of 2 strings. This is all you need to do to get over the finish line ...
if ($ConvertedDate !== $DateToday) {
// update the database
}
You can use Php Built In function "Date Difference."
Code Seems Like As Follow:-
$today= time();
$DateToday= date("Y-m-d",$today);
$diff = date_diff($today,$DateToday);
echo "$diff days";
This will return values something like +12 days or something else.
Related
I have in my MSSQL database a column with datatype of datetime which contains some dates in this format 2021-01-11 19:58:04.277.
This is a voting system, the idea is that the users can only vote once every 24 hours.
Every time they vote this table is updated with a new record and a new date is added with the corresponding user.
I want to display a message that says how many hours left to place the next vote.
This is the code I am trying to use:
/**
* Get Votes Time
*
*/
public function getVoteRemainingTime($account) {
date_default_timezone_get();
$currentTime = date('Y-m-d H:i:s');
$sql = "SELECT VoteDate FROM dbo.vote WHERE Account = :account ORDER BY logid DESC";
$query = $this->db->prepare($sql);
$query->execute(array(':account' => $account));
$voteDate = $query->fetch(PDO::FETCH_OBJ);
$timeLeftVote = strtotime($currentTime) - strtotime($voteDate->VoteDate);
if($timeLeftVote > 86400) {
return '<strong>Vote Available!</strong>';
} else {
return $timeLeftVote;
}
}
But it is displaying the wrong information. What I am doing wrong? I would appreciate your help.
Thanks!
you need declare format parameter of the date() like date('Y-m-d H:i:s')
date_default_timezone_get();
$currentTime = date('Y-m-d H:i:s');
$timeLeftVote = strtotime($currentTime) - strtotime('2021-01-11 19:58:04.277');
if($timeLeftVote > 86400){
echo 'Vote available';
}else{
echo $timeLeftVote;
}
Instead of SELECT VoteDate FROM dbo.vote
Can you do the calculation on the time difference at source in the database using
SELECT VoteDate, DATEDIFF(HOUR, VoteDate, GETDATE()) as HourDifference from dbo.vote
As I cannot check your database query, I only checked the rest of the code and it seems to work (as Fikri F mentioned in the comments of this post) if I replace $voteDate->VoteDate by a static date.
So please provide more information. You could output the current time and the previous vote time from the database as strings, and for both dates as well the result of strtotime, and in the end the result of the method. Then please explain, what the wrong behaviour is. By this, we can narrow down the problem either to the DB query or to the PHP code.
(I would write this as a comment, but I have not enough reputation.)
I'm writing a time logging programme for a client who is a piano tuner, and I've written the following PHP code to give a record a status of 'to do':
$last_tuned = '2017-01-05';
$tuning_period = 3;
$month_last_tuned = date('Y-m', strtotime(date('Y-m-d', strtotime($last_tuned))));
$next_tuning = date('Y-m', strtotime($month_last_tuned.(' +'.$tuning_period.' months')));
if (time() > strtotime($next_tuning.' -1 months')) {
if (time() > strtotime($next_tuning)) {
return 'late';
} else {
return 'upcoming';
}
}
As you can see, the $last_tuned variable is of the date(YYYY-MM-DD) format. This is then converted to a (YYYY-MM) format.
Once convered, an additional number of months, identical to $tuning_period is then added to the $month_last_tuned variable giving us a month and year value for when we need to add a new record.
If the current time (found with time()) is greater than the $next_tuning variable - 1 month, it returns that the task is upcoming. If it's after the $next_tuning variable, it returns that the task is late.
I now have to write a MySQL query to list the items that would return as upcoming or late.
How would I write this in MySQL? I'm not very good with MySQL functions, and some help would be much appreciated.
My attempt at the logic is:
SELECT * FROM records
// The next lines are to get the most recent month_last_tuned value and add the tuning_period variable
WHERE
NOW() > (SELECT tuning_date FROM tunings ORDER BY tuning_date ASC LIMIT 1)
+
(SELECT tuning_period FROM records WHERE records.id = INITIAL CUSTOMER ID)
I know that that is completely wrong. The logic is pretty much there though.
My database schema is as follows:
I expect the rows returned from the query to be on-par with the 'late' or 'upcoming' values in the PHP Code above. This means that the rows returned will be within 1 months of their next tuning date (calculated from last tuning plus tuning period).
Thanks!
You'd probably be better off with using the DateTime object instead of manipulating date strings.
$last_tuned = '2017-01-05';
$tuning_period = 3; // months
$dt_last_tuned = DateTimeImmutable::createFromFormat('Y-m-d',$last_tuned);
$dt_next_tuning = $dt_last_tuned->add(new DateInterval('P3M'));
$dt_now = new DateTimeImmutable();
$dt_tuning_upcoming = $dt_next_tuning->sub(new DateInterval('P1M'));
if( $dt_now > $dt_next_tuning) {
return 'late';
}
if( $dt_now > $dt_tuning_upcoming) {
return 'upcoming';
}
You can also use these DateTime objects in your MySQL queries, by building the query and passing through something like $dt_next_tuning->format('Y-m-d H:i:s'); as needed.
Given your table structure, however, it may be easier to just get all the relevant records and process them. It's a little difficult to tell exactly how the pieces fit together, but generally speaking MySQL shouldn't be used for "processing" stuff.
I need to create a script that compares one field in the database (has a date stored, it's type is "TEXT" and cannot be changed DATE) to the current server date.
The dates are encoded like this "1380571547", so i need to use strftime() to decode them. This field for example, decoded with strftime corresponds to this "Sep-30-2013, 22:05"
What I need is to compare those fields with the current date, and according to that condition, write something like "Expired" in another field.
To achieve this, I made this block of code:
<?php
require("connection.php");
$today = strftime('%b-%d-%Y, %H:%M');
$exp_date = mysql_query("SELECT numbers FROM date");
while($row = mysql_fetch_array($exp_date))
{
echo (strftime ( '%b-%d-%Y, %H:%M', $row ['numbers'])). "<br />";
}
if ($exp_date < $today) {
$sql = "INSERT INTO date (changed) VALUES ('EXPIRED')";
$result = mysql_query($sql);
echo "ADDED!";
}
?>
However, this code is not working, can someone help me ?
PHP is not my strong point but it looks to me like you condition is doing a comparison on an array,
IE:
if ($exp_date < $today) // will always be false.
Your code would probably have to look something more like this.
while($row = mysql_fetch_array($exp_date))
{
if ($row[0] < $today)
{
$sql = "Update date set changed = VALUE where rowid = rowid";
$result = mysql_query($sql);
echo "ADDED!";
}
}
having said that i would probably do the comparison and update in SQL using a case statement,
Update Date
set changed = case when number > ExpiryDate
then "Expired"
else "Current"
end
You can do all this in a single query:
UPDATE `date` set `changed`='Expired' where date(now()) > date(from_unixtime(`numbers`))
But this is not what your code is attempting to do. Your second block seems to be inserting the word Expired in new rows, rather than updating anything.
Note that the table name date should be wrapped in backticks to avoid any possible clash with MySQL keywords
I don't understand the second block of code with the insert. I would do an update inside the loop. but if your going to do that, it could probably be done in one combined update statement.
this has held me up all day i have a column called hours where i add up hours (not clock time) I have a method which takes one date from the other (starttime -endtime) but when i try and update a entry with the hours it wont work bellow is my code.
private function calculatedifference($starttime,$endtime) // delete checkin time from checkouttime
{
$diff= abs(strtotime($starttime) - strtotime($endtime));
return date("H:i:s",$diff);
}
i then proceed to try and update a row based on a users email and their starttime. but it doesnt work? below are my methods in my model to update the entry and the line of code i use to call that method.
function update_daily_row($email,$date,$data)//update existing row.
{
$this->db->where('email', $email);
$this->db->where('starttime', time($date));
$this->db->update('dailyinfo', $data);
}
here is where i call the method.
$hours=$this->calculatedifference(date("Y-m-d H:i:s",
$this->session->userdata
('last_activity')),date("Y-m-d H:i:s"));
$data =array("hours"=>$hours,"endtime"=>date("Y-m-d H:i:s"));
$this->dbaccess->update_daily_row
($this->cdata['email'],
date("Y-m-d H:i:s",
$this->session->userdata('last_activity')),$data);
any help would be appreciated as ive actually gone blind from looking at the thing
update: so i checked the query using this command
$this->db->last_query();
returned the query the email address missing? that means active record probably doesnt like the format of the email address. is there anyway around this?
my query returns after using this method as
UPDATE `dailyinfo` SET `endtime` = '2013-10-02 21:14:02',
`hours` = '00:00:03' WHERE `email` = ''AND `starttime` = '2013-10-02 21:13:59'
so the email is always blank. not sure how to fix this???
Trying to figure out why my code isn't working. Basically I have an elseif statment like so:
mysql_connect("localhost","xxxx","xxxxx");
mysql_select_db("xxxxxx");
$sql = "SELECT COUNT(DATE) FROM calendar";
$result = mysql_query($sql);
$row = mysql_fetch_assoc($result);
$checkdate = $row['DATE'];
$DATEFROM = $_POST['DATEFROM'];
$DAYCOUNT = $_POST['DAYCOUNT'];
$DAYS = $_POST['DAYS'];
if ( $DAYCOUNT < $DAYS ) {
header( 'Location: request_go_fail.php' );
}
else if ( $checkdate == $DATEFROM ) {
echo "FAIL!";
}
else {
It doesn't work, the first check (to see if the DAYCOUNT is less than DAYS works fine, but when comparing to entries in the DB it doesn't seem to do it. Seems to be some issue with finding the already existing data, as when I change $checkdate to an entry that's already in the database it works great.
Any help is most appreciated :)
SELECT COUNT(DATE) FROM calendar doesn't return a field called date, print_r the $row variable to confirm that. Best solution is to change the statement to something like SELECT COUNT(DATE) AS datecount FROM calendar and then do $checkdate = $row['datecount'];
But while rereading your code fragment, I'm not sure that you really want the count of DATE's in the calendar table, and what exactly the intention is, is hard to determine from the code fragment.
Also, DATE is a reserved word in SQL, not the optimal choice for a column name!
Did you try printing $checkdate? I suspect it's null if that is indeed the SQL you're using.
Should be $row['COUNT(DATE)'] I believe, or you can use mysql_fetch_array and $row[0] instead, or use an AS in your SQL or
$checkdate = mysql_result($result, 0);
And skip the fetch call all together.
COUNT(DATE) will return the number of non-null DATE fields in your DB btw, is that really what you want?
You don't have a DATE key in the $row variable because of the sql command. Use this instead, it's called Alias:
SELECT COUNT(DATE) AS DATE_COUNT FROM calendar
Now you have a key DATE_COUNT which will contains value.
$checkdate = $row['DATE_COUNT'];