function duration($day, $date)
{
$date1 = $date;
//$date2 = date_create("Y/m/d");
//$date1 = date_create("Y/m/d", strtotime($date));
//echo $date1;
//echo $date2;exit;
$date1 = date_create($date);
$date2 = date_create(date('Y-m-d'));
$diff = date_diff($date1, $date2);
return $diff->format("%a");
}
I want difference between days ex. I have entered 10 days and date is 17-12-2015 than I must want 27-12-2015 so how to get it?
Hello Please try this,
$date = date_create('2000-01-01');
date_add($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
this will help you to add number of days, month etc to date.
Thanks
Amit
Related
i need to get immediate date like if i select date is 05 then output will be 2017-07-05 cause select date already passed
if i select 12 then output will be 2017-06-12 cause this date future date
final if i select previous date of current month then output will be next month same date and if i select future date of current month then output will be same month
i have tired but not working this
$today = date("Y-m-d");
$next_payment_date = date('Y-m-d', strtotime('+1 month', $today));
or
$time = time();
date("Y-m-d", mktime(0,0,0,date("n", $time),date("j",$time)- 1 ,date("Y", $time)));
thanks in your advance
One more option:
https://3v4l.org/Me2Kh
$input = 12;
$day = date("d");
if ($input > $day){
$date = date("Y-m-"). str_pad($input,2,"0", STR_PAD_LEFT);
}else{
$date = date("Y-m-",strtotime("+1 month")). str_pad($input,2,"0", STR_PAD_LEFT);
}
echo $date;
I use str_pad to keep two digit day number.
Try this -
<?php
$day = '05';
$today = date('Y-m-d');
$supplied = date('Y-m-'.$day);
if($today>$supplied){
$final = date('Y-m-d', strtotime("+1 months", strtotime($supplied)));
}
else{
$final = $supplied;
}
echo $today;
echo '<br />';
echo $supplied;
echo '<br />';
echo $final;
What I'm doing here -
Comparing the current and supplied date
Based on comparison, if supplied date is smaller, I'm adding 1 month else dislpaying the supplied date.
use this,
$today = date('Y-m-d');
$nextDate = date('Y-m-d', strtotime('+1 month'));
or $nextDate = date('Y-m-d', strtotime('+1 month', strtotime($today));
I think this may help.
I would consider using DateTime and it's add method for a DateInterval.
$date = new \DateTime('now', new \DateTimeZone('America/New_York'));
$interval = new \DateInterval('P1M');
$date->add($interval);
Here are the supported DateTimeZone values. Make sure to set that to the applicable time zone.
Edit:
DateTime is mutable, so please keep that in mind.
Try this code :
<?php
$selected_date = '2017-06-05';
$current = date('Y-m-d');
//echo $current;
if($selected_date < $current)
{
$newDate = date('Y-m-d',strtotime($selected_date."+1 month"));
echo $newDate; // gives 2017-07-05
}else if($selected_date > $current)
{
$newDate = $current;
echo $newDate; // gives 2017-06-07
}
?>
From what you described in the points at beginning of the question, you could achieve it this way:
$selectedDate = new DateTime('2016-06-05 00:00:00');
$now = new DateTime('now');
$now->setTime(0, 0, 0);
if ($selectedDate < $now) { // Selected date is in past
// Set month and year to current
$selectedDate->setDate(
date('Y'),
date('m'),
$selectedDate->format('d')
);
// Add 1 month
$selectedDate->add(new DateInterval('P1M'));
}
// If selected date is current or in future we do nothing
echo $selectedDate->format('Y-m-d');
For input 2017-06-05 it will return 2017-07-05 as expected, and for current or future date will return the date that was selected. Works also for any past date like 2016-04-05
I'm trying to subtract 1 month from a date.
$today = date('m-Y');
This gives: 08-2016
How can I subtract a month to get 07-2016?
<?php
echo $newdate = date("m-Y", strtotime("-1 months"));
output
07-2016
Warning! The above-mentioned examples won't work if call them at the end of a month.
<?php
$now = mktime(0, 0, 0, 10, 31, 2017);
echo date("m-Y", $now)."\n";
echo date("m-Y", strtotime("-1 months", $now))."\n";
will output:
10-2017
10-2017
The following example will produce the same result:
$date = new DateTime('2017-10-31 00:00:00');
echo $date->format('m-Y')."\n";
$date->modify('-1 month');
echo $date->format('m-Y')."\n";
Plenty of ways how to solve the issue can be found in another thread: PHP DateTime::modify adding and subtracting months
Try this,
$today = date('m-Y');
$newdate = date('m-Y', strtotime('-1 months', strtotime($today)));
echo $newdate;
Depending on your PHP version you can use DateTime object (introduced in PHP 5.2 if I remember correctly):
<?php
$today = new DateTime(); // This will create a DateTime object with the current date
$today->modify('-1 month');
You can pass another date to the constructor, it does not have to be the current date. More information: http://php.net/manual/en/datetime.modify.php
I used this to prevent the "last days of month"-error. I just use a second strtotime() to set the date to the first day of the month:
<?php
echo $newdate = date("m-Y", strtotime("-1 months", strtotime(date("Y-m")."-01")));
if(date("d") > 28){
$date = date("Y-m", strtotime("-".$loop." months -2 Day"));
} else {
$date = date("Y-m", strtotime("-".$loop." months"));
}
$lastMonth = date('Y-m', strtotime('-1 MONTH'));
First change the date format m-Y to Y-m
$date = $_POST('date'); // Post month
or
$date = date('m-Y'); // currrent month
$date_txt = date_create_from_format('m-Y', $date);
$change_format = date_format($date_txt, 'Y-m');
This code minus 1 month to the given date
$final_date = new DateTime($change_format);
$final_date->modify('-1 month');
$output = $final_date->format('m-Y');
Try this,
$effectiveDate = date('2018-01'); <br>
echo 'Date'.$effectiveDate;<br>
$effectiveDate = date('m-y', strtotime($effectiveDate.'+-1 months'));<br>
echo 'Date'.$effectiveDate;
$currentMonth = date('m', time());
$currentDay = date('d',time());
$currentYear = date('Y',time());
$lastMonth = $currentMonth -1;
$one_month_ago=mkdate(0,0,0,$one_month_ago,$currentDay,$currentYear);
This could be rewritten more elegantly, but it works for me
I realize this is an old post, but I've been solving the same issue, and here is what I came up with to account for all the variability. This function is just trying to get relative dates, so same day of prior month, or last day of month if you are on the last day, regardless of exactly how many days a month has. So goal is given '2010-03-31' and subtract a month, we should output '2010-02-28'.
private function subtractRelativeMonth(DateTime $incomingDate): DateTime
{
$year = $incomingDate->format('Y');
$month = $incomingDate->format('m');
$day = $incomingDate->format('d');
$daysInOldMonth = cal_days_in_month(CAL_GREGORIAN, $month, $year);
if ($month == 1) { //It's January, so we have to go back to December of prior year
$month = 12;
$year--;
} else {
$month--;
}
$daysInNewMonth = cal_days_in_month(CAL_GREGORIAN, $month, $year);
if ($day > $daysInNewMonth && $month == 2) { //New month is Feb
$day = $daysInNewMonth;
}
if ($day > 29 && $daysInOldMonth > $daysInNewMonth) {
$day = $daysInNewMonth;
}
$adjustedDate = new \DateTime($year . '-' . $month . '-' . $day);
return $adjustedDate;
}
I need help to subtract 2 times in PHP.
Example:
$date1 = 02:40;
$date2 = 00:00;
$finaldate = $date1 - $date2;
the correct answer will be 21:20.
Check it out:
if use $date2 as 24:00
$date1 = new DateTime('02:40');
$date2 = new DateTime('24:00');
$finaldate = $date2->diff($date1);
echo $finaldate->format('%h:%i'); // 21:20
But if use $date2 as 00:00
$date1 = new DateTime('02:40');
$date2 = new DateTime('00:00');
$finaldate = $date2->diff($date1);
echo $finaldate->format('%h:%i'); //02:40
use strtotime() and subtract both the times ...
<?php
$date1=strtotime("02:40");
$date2=strtotime("00:00");
$diff= date('H:i', $date2-$date1);
echo "Time Difference : ".$diff;
?>
This will output:
Time Difference : 21:20
I'm coding a script where I require to save the current date, and the date 1 month from that date. I am pretty sure that the time() variable works, but I am not sure how to +1 month onto that?
Any ideas, suggestions. Cheers!
Try this
$today = date("Y-m-d");
$date = date('Y-m-d', strtotime('+1 month', $today));
or use DateTime()
$dt1 = new DateTime();
$today = $dt1->format("Y-m-d");
$dt2 = new DateTime("+1 month");
$date = $dt2->format("Y-m-d");
$time = strtotime("2010-12-11");
$final = date("Y-m-d", strtotime("+1 month", $time));
(OR)
strtotime( "+1 month", strtotime( $time ) );
this returns a timestamp that can be used with the date function
Use this:
Current Date:
echo "Today is " . date("Y/m/d");
1 Month to the Current Date:
$time = strtotime(date("Y/m/d"));
$final = date("Y-m-d", strtotime("+1 month", $time));
<?php
$current_time = date("Y-M-d h:i:s",time()); // Getting Current Date & Time
print $current_time; // Current Date & Time Printing for display purpose
$future_timestamp = strtotime("+1 month"); // Getting timestamp of 1 month from now
$final_future = date("Y-M-d h:i:s",+$future_timestamp); // Getting Future Date & Time of 1 month from now
print $final_future; // Printing Future time for display purpose
?>
shorter : $today=date("Y-m-d"); $date=
This one liner worked for me:
$monthFromToday = date("Y-m-d", strtotime("+1 month", strtotime(date("Y/m/d"))));
The given answers may not give you the results you might expect or desire.
Consider:
$today = "29Jan2018";
$nextMonth = date('dMY', strtotime('+1 month', (strtotime($today))));
echo $today // yields 29Jan2018
echo $nextMonth // yields 01Mar2018
$today = date("Y-m-d");
$enddate = date('Y-m-01',strtotime($today. ' + 1 months'));
You could also consider using the Carbon package.
The solution would look like this:
use Carbon\Carbon
$now = Carbon::now;
$now->addMonth();
Here is the link for reference https://carbon.nesbot.com/docs/
How can I get the timestamp of 12 o'clock of today, yesterday and the day before yesterday by using strtotime() function in php?
12 o'clock is a variable and would be changed by user.
$hour = 12;
$today = strtotime($hour . ':00:00');
$yesterday = strtotime('-1 day', $today);
$dayBeforeYesterday = strtotime('-1 day', $yesterday);
strtotime supports a number of interesting modifiers that can be used:
$hour = 12;
$today = strtotime("today $hour:00");
$yesterday = strtotime("yesterday $hour:00");
$dayBeforeYesterday = strtotime("yesterday -1 day $hour:00");
echo date("Y-m-d H:i:s\n", $today);
echo date("Y-m-d H:i:s\n", $yesterday);
echo date("Y-m-d H:i:s\n", $dayBeforeYesterday);
It works as predicted:
2011-01-24 12:00:00
2011-01-23 12:00:00
2011-01-22 12:00:00
OO Equivalent
$iHour = 12;
$oToday = new DateTime();
$oToday->setTime($iHour, 0);
$oYesterday = clone $oToday;
$oYesterday->modify('-1 day');
$oDayBefore = clone $oYesterday;
$oDayBefore->modify('-1 day');
$iToday = $oToday->getTimestamp();
$iYesterday = $oYesterday->getTimestamp();
$iDayBefore = $oDayBefore->getTimestamp();
echo "Today: $iToday\n";
echo "Yesterday: $iYesterday\n";
echo "Day Before: $iDayBefore\n";
You can easily find out any date using DateTime object, It is so flexible
$yesterday = new DateTime('yesterday');
echo $yesterday->format('Y-m-d');
$firstModayOfApril = new DateTime('first monday of april');
echo $firstModayOfApril->format('Y-m-d');
$nextMonday = new DateTime('next monday');
echo $nextMonday->format('Y-m-d');
to get start of day yesterday
$oDate = new DateTime();
$oDate->modify('-1 day');
echo $oDate->format('Y-m-d 00:00:00');
result
2014-11-05 00:00:00
All the answers here are too long and bloated, everyone loves one-lines ;)
$yesterday = Date('Y-m-d', strtotime('-1 day'));
(Or if you are American you can randomize the date unit order to m/d/y (or whatever you use) and use Cups, galloons, feet and horses as units...)
As of PHP 7 you can write something like this:
$today = new \DateTime();
$yesterday = (clone $today)->modify('-1 day');
$dayBefore = (clone $yesterday)->modify('-1 day');
// Then call ->format('Y-m-d 00:00:00'); on each objects
you can also use new DateTime("now") for today new DateTime("1 day ago") for yesterday or all can be parse by strtotime php function.
Then format as you want.
$timeStamp = time();
// $timeStamp = time() - 86400;
if (date('d.m.Y', $timeStamp) == date('d.m.Y')) {
echo 'Today';
} elseif (date('d.m.Y', $time) == date('d.m.Y', strtotime('-1 day'))) {
echo 'Yesterday';
}