Hy I have 2 table
1.application
id | name | status
====================
1 | morvick | complete
2 | siti | prosess
3 | boby | complete`
2.application_test
id | application_id | test_id | result
======================================
1 | 1 | 1 | 70
2 | 1 | 2 | 80
3 | 1 | 3 | 90
4 | 2 | 1 | 60
5 | 2 | 2 | 80
6 | 2 | 3 | 70
7 | 3 | 1 | 90
8 | 3 | 2 | 70
9 | 3 | 3 | 60
10| 3 | 4 | 80
my Question is :
==================
1. how to find the maximum value at each test_id
2. how I can to get or total applicant_id where status complete
for example to be like this :
test_id | result_max | total_applicant_status(complete)
1 | 90 | 2
2 | 80 | 2
3 | 90 | 2
4 | 80 | 1
SELECT MAX(value) FROM table WHERE test_id = 1;
or perhaps SELECT value, test_id FROM table ORDER BY value DESC;
and for the next part, this may give what you want.
SELECT at.test_id, MAX(at.result), COUNT(IF(status='complete', 1, 0)) FROM application a LEFT JOIN application_test at ON a.id = at.application_id GROUP BY application_id;
Related
I have 2 tables (docs & doc_process):
docs
id | content | status
------------------------
1 | content 1 | 1
2 | content 2 | 2
doc_process
id | doc_id | user | status
---------------------------
1 | 1 | 1 | 2
2 | 1 | 2 | 2
3 | 1 | 3 | 2
4 | 2 | 1 | 1
5 | 2 | 2 | 2
6 | 2 | 3 | 1
How can I select the status when all doc_id = 1 have a value of 2
doc_id | status
---------------
1 | 2
doc_id 2 not filter because id = 4, id = 6 are not equal 2
Use a conditional aggregation
select doc_id
from your_table
group by doc_id
having sum(status <> 2) = 0
Hy I have 2 table
1.application
id | name | status
====================
1 | morvick | complete
2 | siti | prosess
3 | boby | complete`
2.application_test
id | application_id | test_id | result
======================================
1 | 1 | 1 | 70
2 | 1 | 2 | 80
3 | 1 | 3 | 90
4 | 2 | 1 | 60
5 | 2 | 2 | 80
6 | 2 | 3 | 70
7 | 3 | 1 | 90
8 | 3 | 2 | 70
9 | 3 | 3 | 60
10| 3 | 4 | 80
my Question is :
==================
1. how I can to get sum(result) on each test_id where status complete
2. how I can to get sum(result) on each test_id where status prosess
for example to be like this :
test_id | SUM(result = complete) | SUM(result = proses) |
1 | 90 | 50
2 | 80 | 40
3 | 90 | 60
4 | 80 | 70
Try below query-
SELECT test_id,
SUM(IF(app.status='complete',apt.result,0)) AS complete_sum,
SUM(IF(app.status='process',apt.result,0)) AS process_sum
FROM application_test AS apt
JOIN application AS app ON app.id=apt.application_id
GROUP BY apt.test_id
You can try two query to get sum of result
SELECT test_id , SUM (result)
FROM application a
JOIN application_test t
ON t.test_id = a.id
WHERE a.status = 'complete'
GROUP BY test_id
SELECT test_id , SUM (result)
FROM application a
JOIN application_test t
ON t.test_id = a.id
WHERE a.status = 'prosess'
GROUP BY test_id
if you want in one query
SELECT test_id,
SUM(IF(a.status='complete',result,0)) Completed ,
SUM(IF(a.status='process',result,0)) Process
FROM application a
JOIN application_test t
ON a.id=t.application_id
GROUP BY t.test_id
i have 3 table user, products and sales
user
UID | NAME
1 | agent1
2 | agent2
3 | agent3
4 | agent4
5 | agent5
products
PID | PNAME
1 | P1
2 | P2
3 | P3
sales
SID | UID | PID | SALES_CREATED
1 | 3 | 1 | 2013-07-13 01:15:04
2 | 1 | 1 | 2013-07-13 01:25:34
3 | 3 | 1 | 2013-07-13 02:01:34
4 | 3 | 1 | 2013-07-13 02:45:34
5 | 5 | 1 | 2013-07-13 02:56:34
6 | 5 | 1 | 2013-07-13 03:21:34
7 | 2 | 3 | 2013-07-13 03:38:34
8 | 3 | 2 | 2013-07-13 03:51:34
9 | 4 | 2 | 2013-07-13 04:25:34
10 | 3 | 1 | 2013-07-13 04:45:04
11 | 1 | 3 | 2013-07-13 04:55:34
12 | 2 | 2 | 2013-07-13 05:01:34
13 | 1 | 3 | 2013-07-13 05:15:34
14 | 5 | 3 | 2013-07-13 05:36:34
15 | 5 | 3 | 2013-07-13 06:21:34
where the results of sales per agent is: (sort by user UID)
user | P1 | P2 | P3 |
agent1 | 1 | 0 | 2 |
agent2 | 0 | 1 | 1 |
agent3 | 4 | 1 | 0 |
agent4 | 0 | 1 | 0 |
agent5 | 2 | 0 | 2 |
now, i want a result to sort user that has a greatest sale by P1 and a minimum of 3 result only, and the result will be like this
user | P1 | P2 | P3 |
agent3 | 4 | 1 | 0 |
agent5 | 2 | 0 | 2 |
agent1 | 1 | 0 | 2 |
can you guys give me a best mysql_query to show that result?
Oh, something like this...
SELECT uid
, SUM(pid=1) p1
, SUM(pid=2) p2
, SUM(pid=3) p3
FROM sales
GROUP
BY uid
ORDER
BY p1 DESC
, p2 DESC
, p3 DESC;
+-----+------+------+------+
| uid | p1 | p2 | p3 |
+-----+------+------+------+
| 3 | 4 | 1 | 0 |
| 5 | 2 | 0 | 2 |
| 1 | 1 | 0 | 2 |
| 2 | 0 | 1 | 1 |
| 4 | 0 | 1 | 0 |
+-----+------+------+------+
If handling the display logic at the application level, then your query can be simplified to something more scalable, like this...
SELECT uid
, pid
, COUNT(*)
FROM sales
GROUP
BY uid,pid;
I am only answering because (1) I am bored, and (2) I wanted a brain teaser exercise. I typically do not like to answer when people post and run (don't respond to anyone's comments/posts), or provide what they have tried (no query).
If you want better/more help on SO in the future, it would be beneficial to post the query that you have tried, and when using complex/diverse data like this to create a sqlfiddle - http://sqlfiddle.com/
So with that caveat, here is how you can get your desired results
SELECT
user.NAME as user,
SUM(PID=1) as P1,
SUM(PID=2) P2,
SUM(PID=3) P3
FROM
sales
LEFT JOIN
user
ON
user.UID = sales.UID
GROUP BY
sales.UID
HAVING
P1+P2+P3 >= 3
ORDER BY
P1 DESC, P2 DESC, P3 DESC;
and here is the sqlfiddle example that shows it in action - http://sqlfiddle.com/#!2/d3405/8
I have a database table campaign_data. I need to select the customer_id where in the campaign there is difference in tariff. How can i do that with MySQL query. Here is some sample data.
SQL Fiddle Schema
| CAMPAIGN_ID | CUSTOMER_ID | CAMPAIGN_NAME | TARIFF |
---------------------------------------------------------
| 1 | 1 | Richmond | 100 |
| 2 | 1 | Sutton Coldfield | 75 |
| 3 | 1 | Putney | 100 |
| 4 | 1 | Kentish Town | 100 |
| 5 | 1 | Woking | 100 |
| 6 | 2 | Chiswick | 90 |
| 7 | 2 | Ealing | 100 |
| 8 | 2 | Camden | 100 |
| 9 | 3 | Croydon | 75 |
| 10 | 3 | Croydon1 | 100 |
| 11 | 3 | Archway | 100 |
| 12 | 4 | Ealing0 | 100 |
| 13 | 4 | Ealing01 | 100 |
| 14 | 4 | Ealing02 | 100 |
| 15 | 4 | Chingford | 100 |
| 16 | 4 | chingford01 | 100 |
Now as you can see customer id 1 , and 3 has different tariffs. I want to select them and leave the customer id 4 because it has campaigns with same tariffs.
Desired Output
| CUSTOMER_ID |
---------------
| 1 |
| 2 |
| 3 |
For clearification you can see customer 1 has 5 records. If in his 5 records the tariff is same (100) i want to avoid but if the tariff is not some as 4 records have 100 and one has 75, i want to select.
SELECT customer_id, count(DISTINCT tariff) as tariffs
FROM campaign_data
GROUP BY customer_id
HAVING tariffs > 1
you looking for this maybe
SELECT customer_id
FROM campaign_data
GROUP BY customer_id
HAVING count(DISTINCT tariff) > 1
http://sqlfiddle.com/#!2/48b6e/31
select
customer_id,
tariff
from campaign_data
group by customer_id
having sum(tariff)/count(tariff) <> tariff;
tbl_pack_service;
+-------+---------+------------+
| ps_id | pack_id | service_id |
+-------+---------+------------+
| 1 | 1 | 1 |
| 2 | 1 | 2 |
| 3 | 2 | 1 |
| 4 | 2 | 2 |
| 5 | 2 | 3 |
| 6 | 2 | 4 |
| 7 | 2 | 5 |
| 8 | 3 | 1 |
| 9 | 3 | 2 |
| 10 | 3 | 3 |
| 11 | 3 | 4 |
+-------+---------+------------+
ps_id is primary key
i am tying to make dynamic select list in php
i want a mysql query that can give service id which do not match with particular pack_id
like i have service_id 1,2,3,4,5
when i should select pack_id=1 then 3,4,5 should be displayed
and when i should select pack_id=2 then nothing should be displayed as it has all the 5 services.
thanks..
There are a few ways to handle this. The easiest is with a NOT IN subquery:
SELECT DISTINCT service_id
FROM
tbl_pack_service
WHERE service_id NOT IN (SELECT service_id FROM tbl_pack_service WHERE pack_id = 1)