I need to find out unique value. So I tried bellow code. It is through undefined variable error.
Controller:
$employee = Employee::all();
Return view ('page', compact('employee'));
Page view:
$uniqueEmpLoc = $employee->unique('location')->values()->list('location')->toArray();
#Foreach($uniqueEmpLoc as $empLoc)
{{ $empLoc }}
//this is select box used for search
#endforeach
//Display Entire data
#foreach($employee as #employee)
//Display all value
#endforeach
But I got an uniqueEmpLoc is undefined error. I'm using LARAVEL 5.1. Please help me to solve this problem.
There are some errors in your code:
I don't think compact(employee) would work. Shouldn't that suppose to be compact('employee') ?
In Blade, there is no need of putting curly braces at all. Remove them.
Try out the following:
$employees = Employee::unique('locations')->values()->list('location')->toArray();
return view('page', compact('employees'));
And then in your view:
#foreach($employees as $employee)
{{ $employee }}
#endforeach
Use this query in controller
$employees = Employee::distinct()->list('location')->toArray();
return view('page', compact('employees'));
In view
#foreach($employees as $employee)
{{ $employee }}
#endforeach
I agree with the other answers here, this code should be in the controller. You shouldn't be doing logic in the views.
In the controller do:
$uniqueEmpLoc = $employee->unique('location')->values()->list('location')->toArray();
$employee = Employee::all();
Return view ('page', compact('employee', 'uniqueEmpLoc'));
The reason your code isn't working is the line that defines $uniqueEmpLoc is interpreted by blade as text, not code.
If you really want to do that in the view, you need to wrap it in #php tags.
#php
$uniqueEmpLoc = $employee->unique('location')->values()->list('location')->toArray();
#endphp
#Foreach($uniqueEmpLoc as $empLoc)
{{ $empLoc }}
//this is select box used for search
#endforeach
Related
What is the most effective way for returning data from two tables in on view?
Like an employee check the vehicle for each order.
Route::get('orderVehicle',"adminController#orderVehicle");
public function orderVehicle(Request $reques){
$orders = new Order;
$vehicles = new Vehicle; $orders->id; $vehicles->id; return view('adminVeiw.orderVehicle',compact('orders','vehicles')); }
#foreach($orders as $or) {{ $or->id }} #endforeach {{ $vehicles->id }}
And the error is
"Trying to get property 'id' of non-object (View:
/var/www/html/full-Restaurant-App-Using-Laravel/resources/views/adminVeiw/orderVehicle.blade.php)"
So any suggestions?
do this if you don't wanna change your code in controller
#foreach($orders as $or)
#if(!empty($or->id))
{{ $or->id }}
#endif
#endforeach
#if(!empty($vahicles->id))
{{ $vehicles->id }}
#endif
in this case you won't get error but i don't know how you wanna this works for you,
i hope it helps
public function orderVehicle()
{
$orders = Order::create();
$vehicles = Vehicle::create();
return view('adminVeiw.orderVehicle', compact('orders', 'vehicles'));
}
Was wondering if someone could check this out and let me know what I'm doing wrong. I'm trying to use paginate on a database query and render it in my view.
Is my DB query incorrect? I was following the docs to create it. Also read that I needed to remove ->get() when using paginate.
This is what is giving the error on my view: {{$item->paginate(4)}}, same happens if I use {{$item->links(4)}}
Everything renders fine if I remove paginate from the query in the controller..?
Here is what I'm working with.
Controller:
public function index()
{
// $news = DB::table('news')->orderBy('id', 'DESC')->paginate(4);
$news = DB::table('news')->select('id','title','description','listing_image','created_at','updated_at')->orderBy('id', 'DESC')->paginate(4);
return view('news.index',compact('news'));
}
View: (Getting error: Call to undefined method stdClass::paginate())
#if ($news->count())
#foreach($news as $item)
...html
#if ($item->listing_image)
...more html
#else
#endif
... more html
#endforeach
{{$item->paginate(4)}}
#endif
change {{$item->paginate(4)}} to {{ $news->links() }}
i'm new in laravel, i have some problem to make database as variable to be shown on blade template,
example i want to get any data from database :
{{$get = DB::table('perangkat')->get()}}
then:
#foreach ($get as $got)
{{$got->jabatan}}
#endforeach
if the result of the $got->jabatan is kepala, But i want the result is Change To "Kepala Desa", How can i do ??
Please Help Mee ...
Write database related stuff in model or controller in a method and pass that value to view. It will be very neat and clear
public function getData(){
$get = DB::table('perangkat')->get();
return view('myblade', ['data' => $get]);
}
In your view
#foreach ($data as $got)
{{$got->jabatan}} Desa
#endforeach
Also can you update where you get Desa .so i can update answer according to that.
Updated
you keep different roles in array and do some think like this
<?php
$role=['a'=>'operator','b'=>'admin'] ; ?>
#foreach ($data as $got)
<?php $result = isset($role[$got->jabatan]) ? $role[$got->jabatan] : null; ?>
{{$result}}
#endforeach
company.php
function showdata{
$sql= "this syntax sql";
}
//show data
$company = new company();
#foreach ($company->showdata() as $got)
{{$got->jabatan}}
#endforeach
I am trying to make foreach loop in laravel to list all users but when I use the code that laravel suggested I get this error:
Undefined variable: users (View: /home/vagrant/Code/SimFly/resources/views/profile.blade.php)
The code causing the error is:
#foreach ($users as $user)
<p>This is user {{ $user->id }}</p>
#endforeach
Please can someone help me.
To use users variable in a view you need to pass it from a controller first:
$users = User::all();
return view('profile', compact('users'));
Its also a great practice to check state (isset, count for example) of the array/variable before looping through it, to protect any unforeseen errors.
As per the suggestions above, the problem is that the view was not being passed the variable.
To catch this in the blade template use something like a #forelse instead of a #foreach
ProfileController
$users = User::all();
return view('profile', [
'users' => $users
]);
Profile Blade
#forelse
<p>This is user {{ $user->id }}</p>
#empty
<p>There are no users</p>
#endforelse
I use Laravel with foreach in a blade.php
{{ $users = App\User::where('user_id', $post->user_id)->get() }}
and I got the result of this which show on the page
[{"user_id":"123","email":"123#com","password":"1234","first_name":"Tony"}]
But I want to get "Tony" only, how can I call?
{{ ($users = App\User::where('user_id', $post->user_id)->first())->first_name }}
Or better in sense of performance, if you select posts with user:
{{ $post->user->first_name }}
But it is better to prepare necessary data in controller.
get() returns an array, you should use first()
{{ ($users = App\User::where('user_id', $post->user_id)->first())->first_name }}
Since you said you are using foreach in blade. Try something like this
#foreach($user as $u)
{{$u->first_name}}
#endforeach
This will give you first_name for all users