I am using below jQuery:
$rezultat = "SELECT sum(vrednost) as vrednost FROM vrednosti WHERE username = '$username' AND cas between '".date("Y-".(date("m")-1)."-01")."' AND '".date("Y-".(date("m")-1)."-31 23:59:59")."' ";
This works fine, where previous month is in the same year as current date.
But now I run into trouble, because can't echo december, which is different year (2015) than january (2016).
Is there any elegant solution?
You can use strtotime function to get previous month date, pass that time value to date function as second argument like date("Y-m-d", strtotime("today -1 month")), also to get the last date of any month by changing the date format in date function argument, e.g. to get last date of previous month you can use date("Y-m-t", strtotime("today -1 month")).
So, in your case, try this:
$rezultat = "SELECT sum(vrednost) as vrednost FROM vrednosti WHERE username = '$username' AND cas between '". date("Y-m-01", strtotime("today -1 month")) ."' AND '".date("Y-m-t", strtotime("today -1 month")) ."' ";
$rezultat = "SELECT sum(vrednost) as vrednost FROM vrednosti WHERE username = '$username' AND cas between '".date("Y-m-01", mktime(23, 59, 59, date("n")-1, date("j"), date("Y")))."' ";
Related
I'm am writing a PHP program that will get all of the dates for the current work week (excluding Monday). My code is as follows:
//Get Year
$sql = "SELECT YEAR(CURDATE()) AS CurYear";
$result = mysqli_query($db, $sql);
$row = mysqli_fetch_array($result,MYSQLI_ASSOC);
$curyear = $row['CurYear'];
//Get Week
$sql = "SELECT WEEK(CURDATE()) AS CurWeek";
$result = mysqli_query($db, $sql);
$row = mysqli_fetch_array($result,MYSQLI_ASSOC);
$curweek = $row['CurWeek'];
//Get Date of Tuesday
$sql = "SELECT STR_TO_DATE('$curyear$curweek Tuesday', '%X%V %W') AS TueDate";
$result = mysqli_query($db, $sql);
$row = mysqli_fetch_array($result,MYSQLI_ASSOC);
$tuedate = $row['TueDate'];
It works and will return the date of this Tuesday, but is there a more efficient way of doing this, and moreover doing it for the following 3 days?
As explained here: How to find the day of week from a date using PHP?
you can use the date command:
$time = time(); // present time
$day = 3; //the day of the week we are looking for 0: sunday, 1 monday and so on
$dayofweek = date('w', $time); //current day week number
$result = date('Y-m-d', strtotime(($day - $dayofweek).' day', $time));
I'm not sure if you have a requirement of using MySQL, but I would do this in PHP directly. Below is a sample of how you could approach it. Once the variable $TuesTS is set, you can figure out the next day by adding (24*60*60) or 86400 to it, which is the number of seconds in a day.
<?php
$ts = time();
$todayNum = date('N');
if ( ($todayNum >= 2) && ($todayNum<=5)){
$offset = $todayNum - 2; // number of days after Tuesday;
$TuesTS = $ts-($offset*24*60*60);
echo "Tuesday : ".date('Y-m-d', $TuesTS);
}
?>
I need to check date + 1 month from DB with correct date. I try:
$todayDate = date("Y-m-d");
$dateOneMonthAdded = strtotime(date("Y-m-d", strtotime($todayDate)) . "+1 month");
$result = mysql_query('SELECT UNIX_TIMESTAMP("date") AS date FROM followform WHERE id = "28"') or die(mysql_error());
$date = mysql_fetch_assoc($result);
if ($dateOneMonthAdded == $date['date']) echo 'nice';
But $date['date'] == 0
If I use - mysql_query('SELECT date FROM followform WHERE id = "28"')
$date['date'] == 2012-08-13
Where is my mistake?
UNIX_TIMESTAMP("date") should be UNIX_TIMESTAMP(date). With the quotes in there, it's trying to convert the literal string "date" to a timestamp.
Remove double quotes " from unix_timestamp function in your query. It should be:
SELECT UNIX_TIMESTAMP(date) AS date FROM followform WHERE id = "28"
I'm trying to develop a simple php based schedule ...
This is my database table:
Let's say that current time/date is: 2012-03-21 02:00:00
PHP script should echo: Meeting 2
I have a part of the script, but no idea what to do next
<?php
$con = mysql_connect("localhost","root","");
if (!$con){die('Could not connect: ' . mysql_error());}
mysql_select_db("schedule", $con);
$current_time = date("Y-m-d H:i:s");
$result = mysql_query("SELECT * FROM events");
while($row = mysql_fetch_array($result)){
echo $row['Subject'];
}
mysql_close($con);
?>
How to filter query, to mach current time and scheduled subject? Thank you!
(if current_time is between StartTime and EndTime - echo it's Subject)
Try this query
SELECT * FROM events WHERE NOW() BETWEEN StartTime AND EndTime
Try select * from events where StartTime <= NOW() and EndTime >= NOW()
NOW() will give you current time in mysql.
Please try the following query
select * from events where current_time between startTime and endTime
Your query should like this
$result = mysql_query("SELECT * FROM events WHERE current_time between startTime and endTime);
The mysql BETWEEN operator may be of some use.
$startDate = gmdate('Y/m/d/ H:i:s','2012-03-21 02:00:00');
$endDate = gmdate('Y/m/d/ H:i:s','2012-03-21 02:23:59');
$sql = 'select subject from events
where startTime between "'.gmdate("Y/m/d H:i:s", $startDate) .
'" and "' . gmdate("Y/m/d H:i:s", $endDate).'") ';
Firstly, you're going to have to convert your StartTime and EndTime into a timestamp using strtotime so you can compare it to the current time (same thing goes for current time):
http://php.net/manual/en/function.strtotime.php
Then just say if current_time > StartTime AND current_time < EndTime echo Subject.
Something like this should work:
while($row = mysql_fetch_array($result)){
$startTime = strtotime($row['StartTime']);
$endTime = strtotime($row['StartTime']);
if (strtotime($current_time) > $startTime && strtotime($current_time) < $endTime
echo $row['Subject'];
}
putenv("TZ=Asia/Calcutta"); // To Set TimeZone
$now = date("Y-m-d H:i:s");
$sql = "select * from events where '$now' between StartTime and EndTime";
in my code below i subtract the previous date of the user john in the field name date_time
from the current date CURRENT_TIMESTAMP the variable $newdate echo the answer in seconds only how can i make it to display from seconds to minutes from minutes to hours then hours to days
$query1 = "
SELECT (CURRENT_TIMESTAMP - date_time) AS dnew, date_time
FROM user
WHERE name = 'john'
";
$result1 = mysql_query ($query1) or die('query error2');
$line = mysql_fetch_assoc($result1);
$newdate = $line[dnew];
echo "$newdate";
$query1 = "
SELECT (CURRENT_TIMESTAMP - date_time) * 60 AS dnew, date_time
FROM user
WHERE name = 'john'
";
use math ( * 60)
I'm trying to select records which have a recdate within the past year
$goodate = date('Y-m-d h:i:s', mktime(0, 0, 0, date("m"), date("d"), date("Y")-1));
$sqlstmt = "SELECT * FROM #__mytable WHERE id=".$uid." AND recdate > ".$goodate.'"' ;
but I'm getting no records.
What am I doing wrong?
$sqlstmt = "SELECT * FROM #__mytable
WHERE id=".$uid."
AND recdate > ADDDATE(CURDATE(), INTERVAL -1 YEAR)";
If you want to do this programmatically, the DateTime object is a great tool.
$date = new DateTime();
$gooddate = $date->sub(DateInterval::createFromDateString('1 year'));
$sql = "SELECT * FROM #__mytable WHERE id=".$uid." AND recdate > ".$goodate->format('Y-m-d').'"';
This is assuming your date field is mysql type DATE. If not, there are similar DateTime methods for outputting unix timestamps, and the format() method accepts any formatting string that date() does.
$sql = "
select *
from #__mytable
where
id = $uid
and
date_format(recdate, '%Y') = date_format(adddate(curdate(), interval -1 year), '%Y')
"