Can not update database when missing field in json - php

I am making an api that can help user update their info follow the input data. But when in input json have field "password" it will update successfully but when json don't have this field i can not update data in database. This is code i used to update data:
public function updateUserInfo(Request $request){
$postData = $request->all();
$data = json_decode($postData['postData'], true);
if(isset($data['password'])){
$data['password'] = bcrypt($data['password']);
}
$popData = $data['UserId'];
unset($data['UserId']);
$updateInfo = array();
foreach($data as $info){
if($info != null){
$updateInfo[] = $info;
}
}
$result = DB::update(GeneralFunctions::makeUpdateString($data, 'User', ' UserId = '.$popData), $updateInfo);
if($result != null && $result == true){
return response()->json(['success'=>true, 'data'=>'Update Successful']);
}else{
return response()->json(['success'=>false, 'error'=>'We have encountered an error, try again later!']);
}
}
This is the json when everything work fine:
$postData = '{ "UserId" : "1", "password":"12345", "UserName": "minhkhang", "Address": "11/200" }'
This is the json which will cause error because it is missing password field:
$postData = '{ "UserId" : "1", "UserName": "minhkhang", "Address": "11/200" }'
This is code i used to make update string follow input json:
public static function makeUpdateString($keyvalarr, $table, $where){
$stringSQL = 'UPDATE '.$table. ' SET ' ;
foreach($keyvalarr as $fieldname => $updateval){
if($updateval != null){
$stringSQL .= $fieldname.' = ? , ';
}
}
$stringSQL = substr($stringSQL, 0, -2);
if($where != null){
$stringSQL .= 'WHERE '.$where;
}
return $stringSQL;
}
Thank you.

The code in question here is:
if(isset($data['password'])){
$data['password'] = bcrypt($data['password']);
}
Check to see what
isset($data['password'])
is returning outside the if statement, if it is true for password being present in the JSON and not giving you an issue that sounds like what you'd expect, however check to see if that statement by itself is false without the if statement, make sure it isn't still jumping into that, it seems to be the only place your looking for 'password'

Related

PHP update json from received input and write back to same file

I have a json file stored on server & it looks like below:
{
"support_link":"#",
"support_link_2":"#",
"packs":[
{
"identifier":1,
"viewCount":0,
"downloadCount":0
},
{
"identifier":2,
"viewCount":0,
"downloadCount":0
}
]
}
By using PHP, I want to update the viewCount & downloadCount of some of the arrays inside packs.
But the thing is the data is received via a POST method to the server which contains another json with info. of which identifier to update & what param to update, & I am not able to update the existing file & save it back.
Received Json format:
{
"impressions": [
{
"identifier": "1",
"impressionCount": 2
},
{
"identifier": "100",
"impressionCount": 2
},
{
"identifier": "1000",
"impressionCount": 2000
}
],
"downloads": [
{
"identifier": "1",
"downloadCount": 10
}
]
}
What I've tried to do so far:
$json = file_get_contents('php://input');
if ($json != '') {
$properJsonFormatted = json_decode($json, true);
$impressions = $properJsonFormatted['impressions'];
$downloads = $properJsonFormatted['downloads'];
$testConfig =
$json = file_get_contents('php://input');
if ($json != '') {
$properJsonFormatted = json_decode($json, true);
$impressions = $properJsonFormatted['impressions'];
$downloads = $properJsonFormatted['downloads'];
$testConfig = json_decode(file_get_contents("test_config.json"),true);
$packs = $testConfig['packs'];
foreach ($packs as &$pack) {
$packIdentifier = $pack['identifier'];
foreach ($impressions as $impression) {
$impressionIdentifier = $impression['identifier'];
if ($packIdentifier == $impressionIdentifier) {
$pack['viewCount'] += $impression['impressionCount'];
$newCount = $pack['viewCount'];
print("Id: $packIdentifier, ViewCount: $newCount\n");
}
}
}
put_file_contents("test_config.json" , $testConfig);
// print_r($testConfig);
// Save back the updated test_config.json
}
}
UPDATE
Seem to have misinterpreted the question. The actual problem seems to be much simpler.
Change this:
put_file_contents("test_config.json" , $testConfig);
To this:
file_put_contents('test_config.json', json_encode($testConfig));
Also change this:
$packs = $testConfig['packs'];
To this:
$packs = &$testConfig['packs'];
As it seems you forgot to assign that by reference, while you correctly did that in the foreach.

What's a better way to make this insert more secure and safe from injection and manipulation

I've been trying to put together functions in a more secure way that keeps us safe from injection or manipulating inserts by calling different columns to be updated. In your opinion, is this function safe at all, and if not what would you suggest is a better way to do it, and why.
This function is called when a user updates their profile, or specific parts of their profile, as you can see I've made an array with items which is all they can update in that table. Also, the user_id I am getting is from the secure encrypted JSON token that's attached to their session, they are not sending that. Thanks for your time.
function updateProfile( $vars, $user_id ) {
$db = new Database();
$update_string = '';
$varsCount = count($vars);
$end = ',';
$start = 1;
$safeArray = array( "gradYear", "emailAddress", "token", "iosToken", "country",
"birthYear", "userDescription" );
foreach($vars as $key => $value) {
if(in_array( $key, $safeArray )) {
if($start == $varsCount) {
$end = '';
}
$update_string .= $key . '=' . '"' . $value . '"' . $end;
}
$start++;
}
if($start > 0) {
$statement = "update users set " . $update_string . " where userId = '$user_id'";
$query = $db->updateQuery( $statement );
if($query) {
$response = array( "response" => 200 );
} else {
$response = array( "response" => 500, "title" => "An unknown error occured,
please try again");
}
}
As the comments above suggest, it's worth using query parameters to protect yourself from SQL injection.
You asked for an example of how anything malicious could be done. In fact, it doesn't even need to be malicious. Any innocent string that legitimately contains an apostrophe could break your SQL query. Malicious SQL injection takes advantage of that weakness.
The weakness is fixed by keeping dynamic values separate from your SQL query until after the query is parsed. We use query parameter placeholders in the SQL string, then use prepare() to parse it, and after that combine the values when you execute() the prepared query. That way it remains safe.
Here's how I would write your function. I'm assuming using PDO which supports named query parameters. I recommend using PDO instead of Mysqli.
function updateProfile( $vars, $userId ) {
$db = new Database();
$safeArray = [
"gradYear",
"emailAddress",
"token",
"iosToken",
"country",
"birthYear",
"userDescription",
];
// Filter $vars to include only keys that exist in $safeArray.
$data = array_intersect_keys($vars, array_flip($safeArray));
// This might result in an empty array if none of the $vars keys were valid.
if (count($data) == 0) {
trigger_error("Error: no valid columns named in: ".print_r($vars, true));
$response = ["response" => 400, "title" => "no valid fields found"];
return $response;
}
// Build list of update assignments for SET clause using query parameters.
// Remember to use back-ticks around column names, in case one conflicts with an SQL reserved keyword.
$updateAssignments = array_map(function($column) { return "`$column` = :$column"; }, array_keys($data));
$updateString = implode(",", $updateAssignments);
// Add parameter for WHERE clause to $data.
// This must be added after $data is used to build the update assignments.
$data["userIdWhere"] = $userId;
$sqlStatement = "update users set $updateString where userId = :userIdWhere";
$stmt = $db->prepare($sqlStatement);
if ($stmt === false) {
$err = $db->errorInfo();
trigger_error("Error: {$err[2]} preparing SQL query: $sqlStatement");
$response = ["response" => 500, "title" => "database error, please report it to the site administrator"];
return $response;
}
$ok = $stmt->execute($data);
if ($ok === false) {
$err = $stmt->errorInfo();
trigger_error("Error: {$err[2]} executing SQL query: $sqlStatement");
$response = ["response" => 500, "title" => "database error, please report it to the site administrator"];
return $response;
}
$response = ["response" => 200, "title" => "update successful"];
return $response;
}
In addition to the excellent Bill's answer, one little suggestion: always make your methods to do one thing at a time. If a method's job is to update a database, then it should only update a database and nothing else, the HTTP interaction included. Imagine this method could be used in non-AJAX context or without a web-server at all but from a command line utility. Those HTTP codes and JSON responses would look completely off the track. So have two classes: one to update the database and one to interact with the client. It will make your code much cleaner and reusable.
Also, never create a new connection to the database for the every query. Instead, have a ready made connection and use it for all database interactions.
function updateProfile($db, $vars, $userId )
{
$safeArray = array( "gradYear", "emailAddress", "token", "iosToken", "country",
"birthYear", "userDescription" );
// let's check if all columns are safe
if (array_diff(array_keys($vars), $safeArray)) {
throw new InvalidArgumentException("Unknown columns provided");
}
$updateAssignments = array_map(function($column) {
return "`$column` = :$column"; }, array_keys($vars)
);
$updateString = implode(",", $updateAssignments);
$vars["userIdWhere"] = $userId;
$sqlStatement = "update users set $updateString where userId = :userIdWhere";
$db->prepare($sqlStatement)->execute($vars);
}
See, it makes your code slim and readable. And, above all - reusable. You don't have to make your methods bloated. PHP is a very concise language, if used properly

zend update is deleting old values

I am doing update in zend which in some cases doesn't update all the fields, the fields that are not updated become null as if we are doing an add.
This is the code from the Controller
$result = $theuserModel->updateUserTest(
$id,
$this->getRequest()->getPost('user_name'),
/*some code*/
$this->getRequest()->getPost('user_postee')
);
if ($result) {
$this->view->notif = "Successfull Update";
return $this->_forward('index');
}
The corresponding model
public function updateUserRest($id, $nom,$poste)
{
$data = array(
'user_name' => $nom,
'user_postee' => $poste
);
$result=$this->update($data, 'user_id = '. (int)$id);
return $result;
}
I do an update for user_name only I found that the old value of user_postee got deleted and replaced by the default value (initial value which we get at the time of creation) for example null.
Thanks in advance!
I have done this changes (bad solution) If anyone has another one optimised
->Controller
if($this->getRequest()->getPost('user_name')){
$resultname=$userModel->updateUserName($id,$this-
>getRequest()->getPost('user_name'));
}
if($this->getRequest()->getPost('user_postee')){
$resultpostee=$userModel->updateUserPoste($id,$this-
>getRequest()->getPost('user_postee'));
}
if ($resultname|| $resultpostee){
$this->view->notif = "Mise à jour effectuée";
return $this->_forward('index');
}
-> Model
public function updateUserName($id, $name)
{
$data = array(
'user_name' => $name
);
$result=$this->update($data, 'user_id = '. (int)$id);
return $result;
}
public function updateUserPostee($id, $postee)
{
$data = array(
'user_postee' => $poste
);
$result=$this->update($data, 'user_id = '. (int)$id);
return $result;
}
that is complete correct response of update in Zend Db Table.
I believe your assumption is if the value of 'user_postee' is null then it should not be updated into the database, am I correct.
The answer is they will update the new value of "NULL" into the database.
To avoid it , what you should do is
using fetchrow() to get the value of the line by id
foreach user_name and user_postee check if the value of them matching the array value your fetched , if nothing changed or Null, then use the old value from array , if new value exist use new value insert into the array , finally use update to update the new array into database
Assume your Table Column is also "user_name" and "user_postee"
public function updateUserRest($id, $nom,$poste)
{
$row = $this->fetchRow('user_id = '. (int)$id);
if(!empty($nom) && $row['user_name'] != trim($nom)){
$row['user_name'] = $nom;
}
if(!empty($poste) && $row['user_poste'] != trim($poste)){
$row['user_poste'] = $poste;
}
$result=$this->update($row, 'user_id = '. (int)$id);
return $result;
}

MySQL Update with field being a concatenated string

function updateUser($userData, $statsID) {
$fields = '';
$config = 0;
while(list($key,$val)= each($userData)) {
if($config++ != 0){
$fields .= ' , ';
}
$col = $key;
$val = $val;
$fields .= "$col='$val'";
}
//echo $fields;
global $dbhandle;
$query = mysqli_query($dbhandle, "UPDATE data SET $fields WHERE statsID = '$statsID'");
echo var_export($query); <--returns NULL
In this code, I pass in an array as noted below:
$sendData = array('name'=>$name,'race'=>$race,'rank'=>$rank,'highestRank'=>$highestRank,'commander'=>$commander,'atkSld'=>$atkSld,'atkMerc'=>$atkMerc,'defSld'=>$defSld,'defMerc'=>$defMerc,'untSld'=>$untSld,'untMerc'=>$untMerc,'spies'=>$spies,'sentries'=>$sentries,'morale'=>$morale,'tff'=>$tff,'strike'=>$strike,'strikeRank'=>$strikeRank,'defense'=>$defense,'defenseRank'=>$defenseRank,'spy'=>$spy, 'spyRank'=>$spyRank, 'sentry'=>$sentry, 'sentryRank'=>$sentryRank, 'fort'=>$fort,'siege'=>$siege,'economy'=>$economy,'tech'=>$tech,'conscription'=>$conscription,'gold'=>$gold,'tbg'=>$tbg,'gameTurns'=>$gameTurns,'covertLvl'=>$covertLvl);
I have confirmed all the data is set and correct. The statsID passes in correctly and when I echo field, it gives me exactly what is required to fulfill my query and in the correct format (key='value' , key ='value' , key ='value etc)
EDIT: Problem solved, I have updated my code to reflect the solution. For some reason I had to call global $dbhandle prior to the query string. If someone could tell me why that would be great!

Cant pass array value from codeigniter controller to view

Inside my controller, I have a line that needs to pass $content['pass_check'] to the view. It is inside an if statement that checks for validation. This I have found causes it to break. Once I move the $content['pass_check'] outside of any if statement, it works just fine passing to the view. All of the other values are passed (accounts, expense_accounts, vendors, terms). What must I do to get it to pass within this if statement. I've even tried moving it outside of the validation and it still wont set.
function create() {
require_permission("INVOICE_EDIT");
$this->load->library("form_validation");
$this->form_validation->set_rules("invoice_number", "Invoice Number", "required");
if($this->form_validation->run() !== false) {
$post = $this->input->post();
$this->session->set_userdata("create_invoice_vendor", $post['vendor_id']);
$this->session->set_userdata("create_invoice_date", $post['invoice_date']);
$invoice_number_exists = $this->invoices->count(array("invoice_number" => $post['invoice_number'])) > 0;
$post['invoice_date'] = date("Y-m-d", strtotime($post['invoice_date']));
$post['due_date'] = date("Y-m-d", strtotime($post['due_date']));
$post['date_entered'] = "now()";
$id = $this->invoices->insert_invoice($post);
$this->load->model("vendors");
if(isset($post['invoice_number'])){
$string_check= $post['invoice_number'];
$string_check= preg_replace('/\d/', '#', $string_check);
$string_check= preg_replace('/\w/', '#', $string_check);
$invoice_pattern=array();
$invoice_pattern = $this->db->select("invoice_pattern")->where("vendor_id",
$post['vendor_id'])->get("vendors")->result();
$invoice_pattern=$invoice_pattern[0]->invoice_pattern;
* //// THIS IS WHERE I NEED HELP ///////
if($invoice_pattern == $string_check){
***$content['post_check'] = 1;***
$this->invoices->flag_invoice($id);
};
};
$history = array(
"type" => "invoice_entered",
"comments" => "Invoice was entered",
"link" => $id,
"admin_id" => $this->user->admin_id,
"date" => "now()",
);
$this->vendors->insert_history($post['vendor_id'], $history);
if($post['flagged'] == 1) {
$this->invoices->flag_invoice($id);
}
if($invoice_number_exists) {
redirect("invoices/confirm_invoice/".$id);
} else {
// redirect("invoices/view/".$id);
redirect("invoices/create");
}
}
$content['accounts'] = $this->db->get("acct_chart_of_accounts")->result();
$content['expense_accounts'] = $this->db->get("invoice_expense_accounts")->result();
$content['vendors'] = $this->db->select("vendor_id, name, terms, override, invoice_pattern")
->order_by("name ASC")->get("vendors")->result();
$content['terms'] = $this->db->query("SELECT DISTINCT(terms) FROM vendors")->result();
}
}
$this->template['sub_heading'] = "Create";
$this->template['content'] = $this->load->view("invoices/create", $content, true);
$this->template['sidebar'] = $this->load->view("invoices/sidebar", array(), true);
$this->template['scripts'] = array("codeigniter/javascript/invoices/create.js");
$this->template['styles'][] = "codeigniter/styles/invoices/create.css";
$this->display();
}
Obviously it won't pass it to the view if the condition doesn't match, because you're only declaring the variable within the condition if it matches.
Just create $content['pass_check'] with an initial value of 0 or whatever before the conditional check first.
function create() {
...snip...
$content['pass_check'] = 0;
if($invoice_pattern == $string_check) {
$content['post_check'] = 1;
$this->invoices->flag_invoice($id);
};
...snip...
}
Let me know if this works or not please.

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