I want to fetch data of row buy clicking "apply" button in another page.
Which code should I use for hyberlink on the row?
also which code should I use for the another page which will show the row date?
This is the code I use:
<?php
/////// Update your database login details here /////
$dbhost_name = "localhost:1234"; // Your host name
$database = $CONFIG->dbname; // Your database name
$username = $CONFIG->dbuser; // Your login userid
$password = $CONFIG->dbpass; // Your password
$conn = mysql_connect($dbhost_name, $username, $password);
if(! $conn ) {
die('Could not connect: ' . mysql_error());
}
$sql = 'SELECT * FROM jobs';
mysql_select_db($database);
$retval = mysql_query( $sql, $conn );
if(! $retval ) {
die('Could not get data: ' . mysql_error());
}
?>
<?php
while($row = mysql_fetch_array($retval, MYSQL_ASSOC)) {
?>
<table border="2">
<thead>
<tr>
<td><?php echo $row['jobid']; ?></td>
<td><?php echo $row['title']; ?></td>
<td><?php echo $row['company']; ?></td>
<td>
<form name="search" action="submit.php" method="POST">
<?php echo $row['jobid']; ?>
<input type="submit" value="apply" name="submit" />
</form>
</td>
</tr>
</tbody>
</table>
<?php
}
mysql_close($conn);
?>
If you want to send data from database to submit.php use hidden input type and and echo your data in the value section. Eg:
<form name="search" action="submit.php" method="POST">
<input type="hidden" name="jobid" value="<?php echo $row['jobid']; ?>" />
<input type="hidden" name="title" value="<?php echo $row['title']; ?>" />
<input type="hidden" name="company" value="<?php echo $row['company']; ?>" />
<input type="submit" value="apply" name="submit" />
And in processing page that is your submit.php use $_POST to fetch the data eg:
<?php
$jobid = $_POST['jobid'];
?>
How ever you are using mysql_* which is clearly outdated and removed from new php vevrsion. I recommend to use mqsqli or PDO. And start using prepare statements to remove the risk of sql injection.
You are describing something called AJAX. Don't be worried, it is actually quite easy.
See this example for an overview of what you want to do.
See this answer for some simple examples of AJAX to get you started.
Note that the PHP page with the AJAX javascript code, and the PHP page the AJAX sends data to, cannot be the same page. Although that is possible with <form> constructs, it is not possible with AJAX. (Instead of receiving the desired output, you will receive back the full HTML of the page)
Related
Why the database isn't displayed without send form?
when I submit using the form, all the data is displayed, but when I open this page at new, it doesn't display table of database, even when refreshed.
all codes are in a page
SQL, connect
<?php
include '../../database/db.php';
if(isset($_POST['submit'])){
$title = $_POST['title'];
$sort = $_POST['sort'];
$result = $conn->prepare("INSERT INTO menu SET title=?, sort=?");
$result->bindValue(1, $title);
$result->bindValue(2, $sort);
$result->execute();
$all = $conn->prepare("SELECT *FROM menu");
$all->execute();
$menus = $all->fetchAll(PDO::FETCH_ASSOC);
}
?>
form
<form method="POST">
<input type="text" name="title">
<input type="number" name="sort">
<input type="submit" name="submit" value="save">
</form>
show database
<?php
foreach ($menus as $menu){ ?>
<tr>
<td><?php echo $menu['title']; ?></td>
<td><?php echo $menu['sort']; ?></td>
</tr>
<?php } ?>
enter image description hereI'm new to PHP so please don't judge :D
I'm trying to make table with edit option. No matter in which row I click "Edit" button, only data from last row of the page gets loaded. What should I do?
$sql = "SELECT * FROM countries LIMIT " . $this_page_first_result . ',' . $results_per_page;
$result = $connection-> query($sql);
echo '<div style="text-align:center; font-weight: bold;">';
for ($page=1; $page<=$num_of_pages; $page++){
echo '' . $page . ' ';
}
echo '<div><br>';
if($result-> num_rows > 0){
while($row = mysqli_fetch_assoc($result)){
$id = $row['id'];
$Name = $row['Name'];
$Area = $row['Area'];
$Population = $row["Population"];
$Phone_code = $row["Phone_code"];
echo "<tr><td><a href='cities.php?id={$row['id']}'>".$row['Name']."</a></td><td>". $row["Area"] ."</td><td>"
. $row["Population"] ."</td><td>". $row["Phone_code"] ."</td><td><button id='update-button' onclick='openEdit()'>Update</button></td><td><button id='delete-button'>Delete</button></td></tr>";
}
print_r($row);
}
else{
echo "</table><h2 style='text-align:center'>There are no countries in the database..</h2>";
}
$connection-> close();
?>
</table>
<br>
<div style="text-align:center">
<button type="button" id="close-button-edit" onclick="closeEdit()" style="display:none">Close</button>
<div id="edit_form" style="display:none; text-align:left">
<form action="edit_country.php" method="POST" class="forms">
<input type="hidden" name="id" value="<?php echo $id; ?>">
<p>Name: <input type="text" name="name" required value="<?php echo $Name; ?>"></p>
<p>Area: <input type="text" name="area" required value="<?php echo $Area; ?>"></p>
<p>Population: <input type="text" name="population" required value="<?php echo $Population; ?>"></p>
<p>Phone code: <input type="text" name="phone_code" required value="<?php echo $Phone_code; ?>"></p>
<input type="submit" name="update" value="Update">
</form>
</div>
There are two strategies that can be used for this problem: all php or using JavaScript.
PHP Only
This requires a submission to pre-fill the edit form. Each update button sends the id as a GET request (it is requesting information, not changing information, so use GET), in the form of an ordinary link, which the php script uses to populate the edit form.
<?php
// always start with php stuff and don't issue any html until you're done
// initialization
$sortDirection = 'asc';
if(isset($_REQUEST['sortDirection'])) {
// this decouples the value from user input. It can only be 'Asc' or 'Desc'
$sortDirection = $_REQUEST['sortDirection'] == 'asc' ? 'Asc' : 'desc';
}
$rowToEdit = '';
$pdo = new PDO( ... );
// Using PDO because it is more standard
// Leaving connection details to user. See https://phpdelusions.net/pdo_examples/connect_to_mysql for tutorial
// $pdo is assumed to be the pdo object
// deal with row delete. Destructive, so will be post, and delete button will be set
if(isset ($_POST['delete']) ) {
// delete from countries where id = ?
//redirect back to self (Post, Redirect, Get pattern).
// Always do this when done working with POST submissions!
header('Location: /countries.php');
exit;
}
// deal with row update. This changes data, so use POST
if(isset($_POST['id'])) {
// update countries set ...
// redirect back to self
header('Location: /countries.php');
exit;
}
// deal with request for row to edit, use GET for info requests
if(array_key_exists('id', $_GET) {
$rowToEdit = $pdo->prepare("select * from countries where id = ?");
$rowToEdit->execute([$id]);
// fall through to show page
}
// get all country rows (Note, OK to use $sortDirection here because it is decoupled from user input)
$country = $pdo->query("SELECT * FROM countries ORDER BY NAME $sortDirection")->fetchAll(PDO::FETCH_GROUP);
// got all our data, dealt with user input, now we can present the view
?>
<html>
<head>
</head>
<body>
<h1>Countries</h1>
Sort Asc
Sort Desc
<table>
<tr>
<th>Name</th>
<th>Area</th>
<th>Population</th>
<th>Phone</th>
<th></th>
<th></th>
</tr>
<?php foreach( $country as $row): ?>
<tr>
<td><a href='cities.php?country_id=<?=$row['id']?>'><?=$row['Name']?></a></td>
<td><?=$row["Area"]?></td>
<td><?=$row["Population"]?></td>
<td><?=$row["Phone_code"]?></td>
<td> <a href='countries.php?id=<?=$row['id']?>'>Update</a> </td>
<td>
<form method="post">
<input type="hidden" name="id" value="<?=$row['id']?>" />
<button id='delete-button'>Delete</button>
</form>
</td>
</tr>
</table>
<?php if($rowToEdit): ?>
<div style="text-align:center">
<form action="countries.php" method="POST" class="forms">
<input type="hidden" name="id" value="<?= rowToEdit ['id']?>">
<input type="hidden" name="sortDirection" value="<?= $sortDirection?>">
<p>Name: <input type="text" name="name" required value="<?= $rowToEdit['Name']?>"></p>
<p>Area: <input type="text" name="area" required value="<?= $rowToEdit['Area']?>"></p>
<p>Population: <input type="text" name="population" required value="<?= $rowToEdit["Population"]?>"></p>
<p>Phone code: <input type="text" name="phone_code" required value="<?= $rowToEdit["Phone_code"]?>"></p>
<input type="submit" name="update" value="Update">
</form>
</div>
<?php endif; ?>
</body>
</html>
I am trying to figure out how to display all the rows of a database table in one page, all the values to be editable, and for there to be a single submit button at the end of it. I got half the equation figured out, but for some reason it is still not working.
What I currently have is a table displaying all the contents of a MYSQL table and all fields are editable. There is a submit button for all each field (which is not what I want, but willing to settle if I have to), but upon editing something from the database fields, it brings me to a page that gives me a syntax error:
"Error updating record: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE idnum = '0000'' at line 1"
The following is from FORM.PHP
<?php
include('config.php');
$result = mysqli_query($connect,"SELECT * FROM table123");
?>
<html>
<table>
<?php while ($res = mysqli_fetch_array($result)) { ?>
<tr>
<form action="test.php" method="post">
<td><input type="text" name="ret" value="<?php echo $res['ret']; ?>"></td>
<td><input type="text" name="code" value="<?php echo $res['code']; ?>"></td>
<td><input type="text" name="status" value="<?php echo $res['status']; ?>"></td>
<td><input type="hidden" name="idnum" value="<?php echo $res['idnum']; ?>"></td>
<td><input type="submit" name="update" value="Submit"></td>
</form>
</tr>
<?php } ?>
</table>
</html>
The following is from TEST.PHP
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "database";
$connect = mysqli_connect($servername, $username, $password, $dbname);
if (!$connect) {
die("Connection failed: " . mysqli_connect_error());
}
if (isset($_POST['update'])) {
$sql = "UPDATE ssoretailerlist SET ret = '$_POST[ret]', code = '$_POST[code]', status = '$_POST[status]', WHERE idnum = '$_POST[idnum]'";
} else {
echo "Nothing was posted";
}
if (mysqli_query($connect, $sql)) {
echo "Record updated successfully";
} else {
echo "Error updating record: " . mysqli_error($connect);
}
mysqli_close($connect);
Syntax error is because you have an extra comma. Remove the comma before WHERE and you should be fine.
$sql = "UPDATE ssoretailerlist
SET ret = '$_POST[ret]', code = '$_POST[code]', status = '$_POST[status]'
WHERE idnum = '$_POST[idnum]'";
There is a submit button for all each field. Instead of creating a new form and submit for every row inside the loop, one them each once manually outside the loop.
<?php
include('config.php');
$result = mysqli_query($connect, "SELECT * FROM table123");
?>
<html>
<table>
<form action="test.php" method="post">
<?php while ($res = mysqli_fetch_array($result)) { ?>
<tr>
<td><input type="text" name="ret" value="<?php echo $res['ret']; ?>"/></td>
<td><input type="text" name="code" value="<?php echo $res['code']; ?>"/></td>
<td><input type="text" name="status" value="<?php echo $res['status']; ?>"/></td>
<td><input type="hidden" name="idnum" value="<?php echo $res['idnum']; ?>"/></td>
</tr>
<?php } ?>
</table>
<input type="submit" name="update" value="Submit"/>
</form>
</html>
You may want to also handle the output you're inserting into the form. If the data has double quotes in it, it may break your HTML. Check out htmlspecialchars(). Based on your column titles I don't think it would, but always good to keep in mind.
However, every single row has the exact same input names. This is a problem. How will it know which ret, code, status, or idnum to choose and associate together? First you want to turn the names into arrays. Then you want to loop through the idnum array and do multiple UPDATE queries accessing the same key location in the other arrays. Post a new question if you get stuck working on that.
And finally your config.php file is pretty necessary. You may want to read this thread about require_once() vs include(). It's good to throw an error and handle it if the include fails instead of continuing to process the rest of the script.
im currently displaying all the information from the table product in a tabular format, i have a button ADD which when click should add only the id, name and price from the table product to the table product_add in the same database. but my problem is that when i click on the button ADD, nothing is entered in the product_add table.
<?php
include'connect.php';
$image =$_GET['image'];
$id =$_GET['id'];
$name =$_GET['name'];
$price=$_GET['price'];
$sql="SELECT * FROM product";
$result = mysql_query($sql);
if($result>0)
{
?>
<form method="post" id="form" name="form">
<table border='1'>
<?php
while ($row = mysql_fetch_array($result))
{
extract($row);
?>
<tr>
<td><?php echo $row['id']?></td>
<td><img src=<?php echo $row['image'] ?> /></td>
<td><?php echo $row['name']?></td>
<td><?php echo $row['price']?></td>
<td><input type='button' value='ADD' id="insert" name="insert"/></td>
</tr>
<?php
}
?>
</table>
</form>
<?php
}
if(isset($_REQUEST['insert']))
{
$insert = "INSERT INTO product_add(id, name, price)
VALUES ('$row[id]','$row['name']','$row['price']')";
$insertQuery=mysql_query($insert);
}
?>
</body>
</html>
I have updated the codes as shown below but the last row from the table product is being added to the table product_add. I want to add only a specific row when i click on the button submit.
<?php
include'connect.php';
$image = isset($_GET['image']) ? $_GET['image'] : "";
$id = isset($_GET['id']) ? $_GET['id'] : "";
$name = isset($_GET['name']) ? $_GET['name'] : "";
$price= isset($_GET['price']) ? $_GET['price'] : "";
$sql="SELECT * FROM product";
$result = mysql_query($sql);
if($result>0){
?>
<form method="POST" id="form" name="form">
<table border='1'>
<tr>
<th>Id</th>
<th>Image</th>
<th>Name</th>
<th>Price MUR</th>
</tr>
<?php
while ($row = mysql_fetch_array($result)){
extract($row);
?>
<tr>
<td><input name="id" value="<?php echo htmlspecialchars($row['id']); ?>">
</td>
<td><img src=<?php echo $row['image'] ?> width='120' height='100'/></td>
<td><input name="name" value="<?php echo htmlspecialchars($row['name']);
?>"></td>
<td><input name="price" value="<?php echo htmlspecialchars($row['price']);
?>"></td>
<td>
<input id="submit" type="submit" name="submit" value='Add to cart' />
</td>
</tr>
<?php
}
?>
</table>
</form>
<?php
}
if (isset($_REQUEST['submit']))
{
$insert = "INSERT INTO product_add(id, name, price) VALUES ('$id',
'$name','$price')";
$insertQuery=mysql_query($insert);
}
?>
Apart from the method (if your form uses POST, you should use $_POST in php), you do not have any form fields.
For example:
<?php echo $row['id']?>
Should be something like:
<input type="hidden" name="id" value="<?php echo $row['id']; ?>">
and:
<?php echo $row['name']?>
should be:
<input name="name" value="<?php echo htmlspecialchars($row['name']); ?>">
etc.
You should also switch to PDO or mysqli and prepared statements as the code you have now is vulnerable to sql injection. And ID's in html need to be unique.
One point is, you have multiple
<input type='button' ...>
with the same id="insert". ids must be unique within a web page.
The other thing is, you need a submit input to send the form
<input type="submit" ...>
From Submit Button state (type=submit)
The input element represents a button that, when activated, submits the form.
With <input type='button' ...> nothing happens, because it has no default action, see Button state (type=button)
The input element represents a button with no default behavior.
If you want an <input type='button' ...> to submit the form, you must do so by using some Javascript code.
One idea is to load content once the button is clicked.
js
$("#button").click(function() {
$("#holder").load("insert.php");
});
insert.php
$db->query("INSERT INTO table VALUES('one','two','three')");
I wasn't sure what else to call the title...I have a PHP page that accesses a certain MySQL database, pulls the values from the table, and places them in an HTML form (POST method - PHP_SELF). The user can then view the values, alter them as they wish, and submit them. The page then takes those values and updates the MySQL database. Everything works perfectly except that when the user submits and the page goes to show the new updated variables, it still shows the old values. The user is forced refresh the page before the new variables show up. I thought that PHP was perhaps not deleting the variables, so I unset all stored variables after the script was over and it's still not working. I ever tried putting a sleep timer before the script started, and that didn't work either. I'd appreciate any suggestions. Here is my script just for reference:
<html>
<body>
<?php
$sql = "SELECT * FROM lease";
$result = mysql_query($sql);
?>
<form id="lease_update" method="post" action="<?php echo htmlentities($PHP_SELF); ?>">
<table>
<tr>
<th>Account</th>
<th>Car Lease</th>
<th>Radio Lease</th>
<th>Misc. Charges</th>
</tr>
<?php
while($rows = mysql_fetch_array($result)){
?>
<tr>
<td><input type="text" name="account[]" value="<?php echo $rows['accnt']; ?>" /></td>
<td><input type="int" name="car_lease[]" value="<?php echo $rows['car']; ?>" /></td>
<td><input type="int" name="radio_lease[]" value="<?php echo $rows['radio']; ?>" /> </td>
<td><input type="int" name="misc_lease[]" value="<?php echo $rows['misc']; ?>" /></td>
<input type="hidden" name="lease_ID[]" value="<?php echo $rows['ID']; ?>" />
</tr>
<?php
}
?>
</table>
<input type="submit" value="Update" name="lease_update" />
<?php
if(isset($_POST['lease_update'])){
$account = $_POST['account'];
$car_lease = $_POST['car_lease'];
$radio_lease = $_POST['radio_lease'];
$misc_lease = $_POST['misc_lease'];
$lease_ID = $_POST['lease_ID'];
//Get Array Lengths For Each Section
$A = count($lease_ID);
//Update Lease Information
$i = 0;
while($i < $A){
if(!mysql_query('UPDATE lease SET accnt = "' .$account[$i]. '", car = "' .$car_lease[$i]. '", radio = "' .$radio_lease[$i]. '", misc = "' .$misc_lease[$i]. '" WHERE ID = ' .$lease_ID[$i]))
die('Error: ' .mysql_error());
$i++;
}
unset($_POST);
unset($rows);
unset(result);
}
?>
</body>
</html>
You are displaying the data from the database before you update it.
It is normally good practice to do all your database connectivity at the top of the page, then display the results.
In your code (even if a user has submitted an update), you query the data, pull it from database and display it, then run the update with what the user submitted.
Changing your code to this should do the trick (Do read the note below though):
<html>
<body>
<?php
if(isset($_POST['lease_update'])){
$account = $_POST['account'];
$car_lease = $_POST['car_lease'];
$radio_lease = $_POST['radio_lease'];
$misc_lease = $_POST['misc_lease'];
$lease_ID = $_POST['lease_ID'];
//Get Array Lengths For Each Section
$A = count($lease_ID);
//Update Lease Information
$i = 0;
while($i < $A){
if(!mysql_query('UPDATE lease SET accnt = "' .$account[$i]. '", car = "' .$car_lease[$i]. '", radio = "' .$radio_lease[$i]. '", misc = "' .$misc_lease[$i]. '" WHERE ID = ' .$lease_ID[$i]))
die('Error: ' .mysql_error());
$i++;
}
unset($_POST);
unset($rows);
unset(result);
}
$sql = "SELECT * FROM lease";
$result = mysql_query($sql);
?>
<form id="lease_update" method="post" action="<?php echo htmlentities($PHP_SELF); ?>">
<table>
<tr>
<th>Account</th>
<th>Car Lease</th>
<th>Radio Lease</th>
<th>Misc. Charges</th>
</tr>
<?php
while($rows = mysql_fetch_array($result)){
?>
<tr>
<td><input type="text" name="account[]" value="<?php echo $rows['accnt']; ?>" /></td>
<td><input type="int" name="car_lease[]" value="<?php echo $rows['car']; ?>" /></td>
<td><input type="int" name="radio_lease[]" value="<?php echo $rows['radio']; ?>" /> </td>
<td><input type="int" name="misc_lease[]" value="<?php echo $rows['misc']; ?>" /></td>
<input type="hidden" name="lease_ID[]" value="<?php echo $rows['ID']; ?>" />
</tr>
<?php
}
?>
</table>
<input type="submit" value="Update" name="lease_update" />
</body>
</html>
Bad note - your code is wide open to injection attacks. You are using form data with no verification. That's a big red flag. Secondly, you are using deprecated mysql_* functions. Your code should be using mysqli_* functions or better yet move to PDO. It is much safer and you will be able to do a lot more with it.
Edit 2: The page IS being updated after the user submits the form, but the page you display to the user is querying the database before you update it - and using that to display the page to the user.