Check if filename from directory exists as a value in database - php

Question

I have a bunch of .png's in a directory that are named the same as the values in the database. I would like to do a check if the filename (without '.png') exists in the database or not.
At the moment I am using this code to display the flags those are in the database
<?php
$result = mysql_query("SELECT `country` FROM `countries`");
while($row = mysql_fetch_array($result)) {;
?>
<img src="images/countries/<?php echo $row['country']?>.png" />
<?php }; ?>
Since there are only 3 countries in the column it's displayed as:
I would like to display the flags that are not in the database as well, but then in greyscale.
I came up wit this code to get all the flags from the directory
<?php
$directory = "images/countries/";
$images = glob($directory . "*.png");
foreach($images as $image)
{
echo '<image src="'.$image.'" class="flaginactive"/>'; //show all flags as inactive
echo basename($image, '.png'); //get file name with .png
}
?>
But somehow I am stuck and clueless how I could get them both in an if statement.
Can someone advise me how I can solve this the best way. I am aware I am using the old mySQL functions.

Answer 1

There are many ways to achieve this. I will relate one.
First load the names in the database in to an array. Then check the existence of the enumerated file names of the directory in the array to decide the class of the element.
Elements are shown inactive if a file in the directory is not found in the database.
<?php
$directory = "images/countries/";
//Lets save all the file names in the database to an array
$dbImages = array();
$result = mysql_query("SELECT `country` FROM `countries`");
while($row = mysql_fetch_array($result)) {
array_push($dbImages, $directory . $row['country'] . '.png');
}
//Lets go through all the files in the directory and see if they are in the $dbImages array
$images = glob($directory . "*.png");
foreach($images as $image)
{
//Decide the class attribute based on the existence of the file name in $dbImages array
if (in_array($image, $dbImages))
$classAttribute = '';
else
$classAttribute = 'class="flaginactive"'
echo '<image src="'.$image.'" ' . $classAttribute . ' />';
}
?>

Answer 2

You can file_exists() function like this
<?php
$directory = "images/countries/";
$images = glob($directory . "*.png");
foreach($images as $image)
{
if(file_exists($_SERVER['DOCUMENT_ROOT'] . $directory . $image . '.png')) //Files exists goes here
{
echo '<image src="'.$image.'" class="flaginactive"/>'; //show all flags as inactive
echo basename($image, '.png'); //get file name with .png
}
}
?>