How to join 2 tables no foreignkey but same data's? - php

Question

Is it possible to join to tables like in the following picture
There are no foreign key in svotes but there are the same records. In the select option tag I putted the school_year and the option are 2015-2016,2016-2017. If I click the 2016 it should that the other table svotes can display the year of 2016 can it be possible? and how?
Here's my code:
<select name="sy_no" onchange="getyr(this.value)">
<option></option>
<?php
include('../connect.php');
$sql2 = mysql_query("SELECT * FROM school_year");
while ($row1=mysql_fetch_array($sql2)) {
echo "<option value=".$row1['syearid'].">".$row1['from_year'].'-'.$row1['to_year']."</option>";
}
?>
</select>
get_winner.php
<?php
include('../connect.php');
$no = $_GET['no'];
//this is where I get the year
$stud = mysql_query("SELECT * FROM studentvotes,school_year WHERE school_year.from_year = studentvotes.year AND studentvotes.year = '$no' ") or die(mysql_error());
echo"<center>";
echo "<form action='' method='POST' enctype='multipart/form-data' >";
echo " <table class='table table-striped table-bordered table-hover' id='dataTables-example'>";
echo "<tr>";
echo "<th>IDno</th>";
echo "<th>Action</th>";
echo "</tr>";
while ($row=mysql_fetch_array($stud)) {
$result = mysql_query("SELECT * FROM studenvotes,school_year WHERE studenvotes.year = school_year.from_year") or die(mysql_error());
$r1 = mysql_fetch_assoc($result);
?>
<tr class="headings">
<?php
}
?>

Answer 1

Try this join query
<select name="sy_no" onchange="getyr(this.value)">
<option></option>
<?php
include('../connect.php');
$sql2 = mysql_query("SELECT school_year.*,svotes.* FROM school_year JOIN svotes ON , svotes.year = school_year.from_year ");
while ($row1=mysql_fetch_array($sql2)) {
echo "<option value=".$row1['syearid'].">".$row1['from_year'].'-'.$row1['to_year']."</option>";
}
?>
</select>