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I am trying to run a sum from numbers taken from a database. However i can't seem to get it to work.
Does anyone have any ideas as to why i keep getting 0 instead of a percentage? if so could you guide me in the right direction.
PHP:
//SQL Original Goal
$goal = "SELECT * FROM login WHERE username = '$login'";
$goalquery = mysql_query($goal);
$goalarray = mysql_fetch_array($goalquery);
$endgoal = $goalarray['goal'];
//Latest Weight
$latestweightarray = mysql_fetch_array($latestweightq);
$currentweight = $latestweightarray['weight'];
//First Weight Recorded
$firstweightarray = mysql_fetch_array($firstweightq);
$firstweight = $firstweightarray['weight'];
$percent = "100";
$progress = (($firstweight - $currentweight) / ($firstweight - $endgoal)) * $percent;
Print Result:
<?php
echo $progress
?>
This just gives: 0
Rookie Error, i had updated the database twice in one day which conflicted the results somehow, changed one of the dates in the database and this solved the problem
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<?php
$income = array(19500, 22000, 85205, 110000, 26568, 12000, 37500, 50900, 28000, 32430);
$percentage = 0.09;
foreach($income as $integers)
{
echo ("$integers <br/>");
}
if ($integers < 26568);
{
echo "$integers = Pay back £0 per year";
}
?>
outcome below
19500
22000
85205
110000
26568
12000
37500
50900
28000
32430
32430 = Pay back £0 per year
If it is lower than 26568 then next to the number I want it to say "Pay back £0 per year" but if it's more than 26568 I need to calculate 9 percentage and add how much is paid back next to the number. Is this possible?
I tried the above and keep getting the same output, I need to be able to calculate the 9 percent and add this next to the number.
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Closed 2 years ago.
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I want to Select one record from a table Named 'sms_students' by using Student Id or Student Telephone
Here is My Code
$student_rand_id=$_GET['std_rand'];
$std_tell=$_GET['std_tell'];
$view_student = $config->prepare("SELECT * FROM sms_students WHERE st_rand = :random_id || st_tel =: st_tel");
$view_student->execute(['random_id' => $student_rand_id]);
$view_student->execute(['st_tel' => $std_tell]);
$row = $view_student->fetch();
Since you call execute twice, this executes twice, both times with an incomplete set of arguments. It's an easy fix though:
$view_student = $config->prepare("SELECT * FROM sms_students WHERE st_rand = :random_id OR st_tel = :st_tel");
$view_student->execute(['random_id' => $_GET['std_rand'], 'st_tel' => $_GET['std_tell'] ]);
$row = $view_student->fetch();
Try and get rid of single-use variables, they're almost always unnecessary, and do try and steer towards having names that match precisely. Seeing st_tel and std_tell together is a sign something's not quite right. Get your code to agree on names and stick with them.
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I'm having problems with a query that should "rank an user to 3" but instead in the MySQL it gives to the user X rank 0.
Here is the code
if($_POST['rank'] == '3')
{
mysql_query("UPDATE users SET rank='3' AND LPT='1' where username='".$_post['u_name']."' LIMIT 1")or die(mysql_error());
$query = true;
}
Waiting for answers
Use comma instead of AND when updating multiple columns:
UPDATE users
SET rank='3',
LPT='1'
where username= ?
You should:
Use parametrized query instead of concatenating SQL string
$_post is a superglobal and must be in uppercase $_POST
Reference: http://php.net/manual/en/language.variables.superglobals.php
Additional reference:
UPDATE http://dev.mysql.com/doc/refman/5.7/en/update.html
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Closed 8 years ago.
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SOLVED
Rows 1, 4, and 10 have a field with a single quote character in them, so I was SQL injecting myself. More reason to switch to prepared statements!
I have a very simple bulk UPDATE query sent from my PHP form which, oddly enough, only affects certain rows. Rows 1, 4, and 10 doesn't get updated; but all other rows get updated.
Here is the query:
$query = "SELECT * FROM SkillDescriptions";
$result = mysql_query($query);
for ($i=1; $i<=mysql_num_rows($result); $i++){
$skillKey = 'Skill' . (string)$i;
$categoryKey = 'Category' . (string)$i;
$descriptionKey = 'Description' . (string)$i;
$sql="UPDATE SkillDescriptions SET
Skill='$_POST[$skillKey]',
Category='$_POST[$categoryKey]',
Description='$_POST[$descriptionKey]'
WHERE id='$i'
";
$result2=mysql_query($sql);
}
I've got a parallel form that does the exact same PHP form processing as this one but has a different database table, which works properly: so the problem most likely lies in the database table (configuration?) and not the code.
Why do only certain rows get updated, in a seemingly random pattern?
UPDATE
Before:
http://i.stack.imgur.com/2hk2l.png
After: (I appended test to the columns)
http://i.stack.imgur.com/ObMn5.png
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I am using Yii, I want to select all records of a model except the last 2 records, but I got an error that there is syntax error, here is my code:
$c = new CDbCriteria();
$c->select = "*";
$c->condition = "idNewsEvents!=(SELECT MAX(idNewsEvents) FROM newsevents) AND idNewsEvents!=(SELECT MAX(idNewsEvents)-1 FROM newsevents))";
$model2 = Newsevents::model()->findAll($c);
This one considers, that idNewsEvents might not be sequential (due to deletes or whatever).
$c = new CDbCriteria();
$c->select = "*";
$c->condition = "idNewsEvents NOT IN (SELECT idNewsEvents FROM newsevents ORDER BY idNewsEvents DESC LIMIT 2)";
$model2 = Newsevents::model()->findAll($c);
P.S.: Not sure if this is correct yii syntax, I'm not familiar with it, but I'm very familiar with MySQL. Anyway, you get the idea I hope.
Two checking can be done in a single checking
$c->condition ="idNewsEvents < (SELECT MAX(idNewsEvents)-1 FROM newsevents)";
Example query
SELECT * FROM `users` WHERE user_id < (SELECT MAX(user_id)-1 FROM users)
it should be:
$c->condition = "idNewsEvents!=(SELECT MAX(idNewsEvents)
FROM newsevents) AND idNewsEvents!=(SELECT MAX(idNewsEvents)-1 FROM newsevents)";
There were just an extra bracket at end and a very tired eyes to notice that :( .