Notice: Undefined index: id [duplicate] - php

Question

This question already has answers here:
"Notice: Undefined variable", "Notice: Undefined index", "Warning: Undefined array key", and "Notice: Undefined offset" using PHP
(29 answers)
Closed 7 years ago.
I have used a prepared statement to define the id index however, it is telling me that it is undefined for some reason, where and what do i change for this to work?
<?php
$db_username='student';
$db_password='student';
$db = new PDO ('mysql:host=192.168.56.2;dbname=Assessment', $db_username, $db_password);
$result = $db ->prepare("SELECT * FROM Jobs WHERE jobname='".$_GET['id']."' ");
$result->execute();

Answer 1

Try this:
<?php
$db_username='student';
$db_password='student';
$db = new PDO ('mysql:host=192.168.56.2;dbname=Assessment', $db_username, $db_password);
if(isset($_GET['id'])) {
$result = $db ->prepare("SELECT * FROM Jobs WHERE jobname=?");
$result->execute(array($_GET['id']);`enter code here
}
else {echo('$_GET["id"] not set');}

Answer 2

First, verify that $_GET['id'] has a value. Second, for security, change some lines:
$result = $db ->prepare("SELECT * FROM Jobs WHERE jobname=:id");
$result->execute(array(':id' => $_GET['id']));