How to append the two lines string in php json response - php

Question

{
"employees": [{
"name": "Chicken Shawarma",
"price": "510.00",
"nutrients": "A
B "
}]
}
this is the my json response , In My app i setup a two line record for "nutrients". Ex :
A
B
this vale saved in database without any issue (My SQL), now i want display the "nutrients" data as a two line record. but its displaying below error
SyntaxError: unterminated string literal
if you have any idea please share with me.
this is the my server side code
if ($itemInfo->num_rows() == 1) {
$row = $itemInfo->row_array();
$json_arr = $_GET['callback'] . '(' .
"{'name' : '" . $row['name'] . "',"
. "'nutrients' : '" . $row['nutrients'] . "',"
. "'img' : '" . $row['img'] . "'}" . ')';
} else {
$json_arr = json_encode(array('status' => 'N'));
}
echo $json_arr;
this is the my client side code
$http.jsonp(full_url).success(function (data) {
$scope.item = data ;
});

Answer 1

Your main problem is making a JSON response by concatenating strings. In such case you miss required encodings/escaping and so on. So, first of all you should create an associative array and then do $json_arr = $_GET['callback'].'('.json_encode($your_json_like_array).')'; exactly like in the else clause.
Resulting code should look like this:
$json_arr = array(
'name' => $row['name'],
...,
'nutrients' => $row['nutrients']
);
$json_arr = $_GET['callback'].'('.json_encode($json_arr).')';