php shell_exec return null - php

I want run php ../cat1/index.php gr_s2/3/gr-n40 1200 command by php.
The shell_exec return NULL as result but when I try that command on cmd, output was shown correctly.
What happen in php and shell_exec ?!
Note: The command with different parameters (Like: php ../cat1/index.php gr_s2/3/gr-n40 800) works correctly in both (php and cmd).

There is a note in php manual page of shell_execute:
Note: This function can return NULL both when an error occurs or the
program produces no output. It is not possible to detect execution
failures using this function. exec() should be used when access to the
program exit code is required.
Source: http://php.net/manual/en/function.shell-exec.php
So your code running with error. Try with exec.
If you want, insert your code (or blocks) to be checked.

This is fixed by adding user used by web-server to sudoer and run the php command with
sudo php ..........
To start run this command sudo visudo
Add the following line at the end of sudoer file opened
www-data ALL=NOPASSWD: /usr/bin/php
But if you whant to execute all commad from php add this line instead of the above www-data ALL=NOPASSWD: ALL which is not recommended
and the run your commands with sudo php /path/to/you/file.php
For my case I was running ubuntu 14.04
Have fun please

Related

PHP shell_exec which mysqld refuses to work

I attempt to run the command echo shell_exec('which mysqld'); in PHP which yields nothing.
I manually go to the terminal and run $ which mysqld which yields the answer.
I run the command echo shell_exec('whoami'); in PHP which gives me user.
I go back to the terminal and run $ which mysqld as the user PHP is running as and get the answer.
How do I force PHP to return echo shell_exec('which mysqld'); whether it "feels" like it or not?
Yes, the database is running.
It sounds like php doesn't know what the executable is, it's possible it doesnt know what the command is (it might not be in your $PATH), or it's a shell builtin, you may be better off running a command with bash -c "which mysql", or something of that nature, to force your script to run it in the context of an actual shell session.

PHP exec on local script

Hello i have a PHP script, and its added to cron, it is possible to execute from this script shell command (with exec() or something) without enabling it on php.ini? I don't want to enable exec on my site
It's called PHP CLI, check here
Usually when you install php, there's option to install php_cli too.
So long you can run php on shell prompt, then it can work.
Open bash (or other shell), try this:
php -v
If the version printed, then it's working.
Then you can
php -f phpfile
or put
#!/usr/bin/php
At the beginning of your php file as a line, and chmod +x file.php, and then
./file.php
#or
/path/to/file.php
to run it.
(Note /usr/bin/php is the usual place of php executable, it might change, eg in unix is ually /bin/php. Use whereis php to check its place.)

SuiteCRM Database Scheduler

I installed SuiteCRM and while trying to run the code below for for the Scheduler...
php.exe -f cron.php
I get the error:
Call to undefined function mysqli_connect()
Can anyone help?
Have you checked the mysqli PHP extension is installed? try viewing the phpinfo, either from a php phpifno(); or from the command line php -i.
If this wasn't installed it would effect the whole installation rather than just the scheduler.
Looks like your command line PHP ( PHP CLI ) refers to seperte location than your PHP.
Get path of php.ini for your command line and then uncomment this line.
extension=mysqli
The cron.php is run from the scheduler, but sometimes I have to run the code to make sure is working properly.
php cron.php all -F -vvv
where
the “all” command will execute all the tasks
The “-F” option forces all the tasks to be executed.
The “-vvv” option sets the output verbosity level to maximum.
If I need to edit my web server user's crontab file, I use this command:
sudo crontab -e -u username
If I need to find out the username the cron job is running on, I use the browser
domain.com/get_current_user.php
assuming I already created the get_current_user.php file.

CLI php run php in command prompt

I have installed PHP CLI to execute php commands from console.
I have installed PHP CLI using this command -
sudo apt-get install php5-cli
When I run this
$vr=3; echo $vr;
Result :-
=3: command not found
If I run echo "test";
Result :- test
displays..
Can anyone tell why "command not found" displays..
The "echo "test" line is working because echo is a bash command.
You have to write your own php script, the run it by command line like this:
$ php myscript.php
In alternative, you can run php from your command line, then directly write or paste your script.
Then press CTRL+D to run it. Remember the at the beginning and at the end.
As third option, you can write a php script, putting in the first line this code:
#!/usr/bin/php
Obviously the php executable path must match the one in your system.
This way, you can chmod +x the script, then run it directly like this:
$ ./myscript.php
The fourth option is the interactive shell:
$ php -a
Interactive shell
php > echo 5+8;
13
[$ in front of commands means a command run by user]
You are entering PHP code into the Unix shell (e.g. bash). The Unix shell does not understand PHP code, so you have to run php first.
To run your PHP code from the command line:
$ php -r '$vr=3; echo $vr, "\n";'
3
To run your PHP code from the PHP interactive shell (which may or may not be compiled into PHP):
$ php -a
Interactive shell
php > $vr=3; echo $vr, "\n";
3
php >
(Hit Ctrl+D or type exit to get out of the PHP shell.)
To run your PHP code from a file named prog.php (which contains <?php before the code):
$ php prog.php
3
It seems you want something like this: http://www.php.net/manual/en/features.commandline.interactive.php
This gives you an interactive mode, where you can type PHP code and have it executed directly.

Bash script to run php script

I have a php script that I want to be run using a bash script, so I can use Cron to run the php script every minute or so.
As far as I'm aware I need to create the bash script to handle the php script which will then allow me to use the Cron tool/timer.
So far I was told I need to put:
#!/pathtoscript/testphp.php
at the start of my php script. Im not sure what to do from here...
Any advice? Thanks.
If you have PHP installed as a command line tool (try issuing php to the terminal and see if it works), your shebang (#!) line needs to look like this:
#!/usr/bin/php
Put that at the top of your script, make it executable (chmod +x myscript.php), and make a Cron job to execute that script (same way you'd execute a bash script).
You can also use php myscript.php.
Sometimes PHP is placed in non standard location so it's probably better first locate it and then try to execute.
#!/usr/bin/env bash
PHP=`which php`
$PHP /path/to/php/file.php
A previous poster said..
If you have PHP installed as a command line tool… your shebang (#!) line needs to look like this: #!/usr/bin/php
While this could be true… just because you can type in php does NOT necessarily mean that's where php is going to be... /usr/bin/php is A common location… but as with any shebang… it needs to be tailored to YOUR env.
a quick way to find out WHERE YOUR particular executable is located on your $PATH, try..
➜which -a php ENTER, which for me looks like..
php is /usr/local/php5/bin/php
php is /usr/bin/php
php is /usr/local/bin/php
php is /Library/WebServer/CGI-Executables/php
The first one is the default i'd get if I just typed in php at a command prompt… but I can use any of them in a shebang, or directly… You can also combine the executable name with env, as is often seen, but I don't really know much about / trust that. XOXO.
You just need to set :
/usr/bin/php path_to_your_php_file
in your crontab.
I'm pretty sure something like this is what you are looking for:
#!/bin/sh
php /pathToScript/script.php
Save that with your desired script name (such as runPHP.sh) and give it execution rights, then you can use it however you want.
Edit: You might as well not use a bash script at all and just add the "php ..." command to the crontab, if I'm not mistaken.
Good luck!
The bash script should be something like this:
#!/bin/bash
/usr/bin/php /path/to/php/file.php
You need the php executable (usually found in /usr/bin) and the path of the php script to be ran. Now you only have to put this bash script on crontab and you're done!
a quick way to find out WHERE YOUR particular executable is located on your $PATH, try.
Even quicker way to find out where php is ...
whereis php
I'm running debian and above command showing me
php: /usr/bin/php /usr/share/php /usr/share/man/man1/php.1.gz
Hope that helps.
If you don't do anything in your bash script than run the php one, you could simply run the php script from cron with a command like /usr/bin/php /path/to/your/file.php.
I found php-cgi on my server. And its on environment path so I was able to run from anywhere. I executed succesfuly file.php in my bash script.
#!/bin/bash
php-cgi ../path/file.php
And the script returned this after php script was executed:
X-Powered-By: PHP/7.1.1
Content-type: text/html; charset=UTF-8
done!
By the way, check first if it works by checking the version issuing the command php-cgi -v
Create file.php with first line in files: file.php(#!/bin/php) file.sh(#!/bin/bash).
Check installed php.Run command in terminal:
which php
If set there will be an answer:
/usr/bin/php
Run file.php with command:
php file.php
if the file has started then you can write this command to file.sh:
#!/bin/bash
run_php=`php file.php`
echo $run_php
Be careful ' and ` different!!!

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