How can i variable add new charcter another string? [closed] - php

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Hi guy can you help me i have problem sometimes variable.
<?php
$ns = "test";
echo $ns;
print test but I don't want this.
output
t:e:s:t
please help?

Use chunk_split()
chunk_split() function splits the function.
In our case, it splits by every 1 character.
And adds a new character :.
We do not need last : character so, we are using rtrim().
<?php
$ns = "test";
$n = chunk_split($ns, 1, ':');
echo rtrim($n, ":");
?>
Demo

Please try below code :
$ns = "test";
$array = str_split($ns);
echo implode(":", $array);

<?php $ns = "test";
echo substr(chunk_split($ns, 1, ':'), 0, -1);
?>

Related

How to exchange numbers in string? [closed]

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can you please help me with finding right function for exchanging numbers in string? Numbers are separated with ":".
For example
"2:0" to "0:2"
"101:50" to "50:101"
Thank you.
There are many ways to do it, you can try the any of the ways here.
<?php
//using regex
$re = '/(\d+):(\d+)/i';
$str = '50:101';
$subst = '$2:$1';
$result = preg_replace($re, $subst, $str);
echo "The string $str after exchange is ".$result;
echo PHP_EOL;
// concatenating parts after explode
$parts = explode(':',$str);
echo "The string $str after exchange is $parts[1]:$parts[0]";
echo PHP_EOL;
//using explode, array_reverse and implode
$str = '50:101';
$result = implode(':', array_reverse(explode(':',$str)));
echo "The string $str after exchange is ".$result;
?>
DEMO: https://3v4l.org/OkY18
Simply explode() the string and then reform it.
$str = '100:200';
$bits = explode(':',$str);
echo $bits[1] . ':' . $bits[0];
RESULT
200:100

Extract texts on strings PHP [closed]

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Hey i wanna know how i can extract this data and do a echo
Example of echo:
Item: D608
Time: 17011511
Same with the another line after ,
$strings = "D608-1-1-17011511-0,D832-1-1-17011511-0";
Thanks you!
If -1-1- and -0 will be always same then you can do it via str_replace
Working example
$strings = "D608-1-1-17011511-0,D832-1-1-17011511-0";
$strings = explode(',', $strings);
foreach ($strings as $item)
{
$item = str_replace( array('-1-1-', '-0'), array('-', ''), $item);
$item = explode('-', $item);
echo "Item: <b>".$item[0]."</b> ";
echo "Time: <b>".$item[1]."</b><br>";
}
Output:
Item: D608 Time: 17011511
Item: D832 Time: 17011511
If you know the length/content of the string, you can use explode().
$strings = "D608-1-1-17011511-0,D832-1-1-17011511-0";
$exploded_string = explode(',',$string);
foreach ($exploded_string as $string) {
echo explode('-',$string)[0].' '.explode('-',$string)[3];
}

How to Delete Last Word of variable in php [closed]

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How to last word from our Variable for example
$name = "Salman Khan";
And I want ans in only because i want tp remove n in my string
$words = explode(' ',$name); // Break words into array
$noofwords = count($words); // Find out how many
unset($words[$noofwords-1]); // remove the last one (-1 because of zero-index)
$newstring = implode(' ',$words); //put back together
$newstring = substr($name, 0, strlen($name)-1);
Do you mean remove the last letter?
echo substr($name, 0, -1);
Or the last word?
echo explode(' ', $name)[0];
echo rtrim($name,"n");
OR
echo substr($name,0,-1);
OR
echo substr($name,0,strlen($name)-1);
Output
salman kha
Try out this one.
$name = 'salman khan';
$length = strlen($name);
$char = $name[$length-1];
echo rtrim($name,$char);

Using PHP how do I test a string for a pattern then alter it? [closed]

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In PHP given this string:
$string = '/sometext?123#abc/moretext';
How can I test for the existence of the pattern "?123#abc/" which will always be enclosed by "?" and "/" but have varying inner-text that may include any text and symbols? The text outside of the pattern will also be different. I need to do this:
if ($string includes pattern ?*/) {
//load the inner value into a variable
//then remove the entire patern including the leading "?" and trailing "/" and replace with a single "/"
}
How do I do this?
<?php
$string = '/sometext?123#abc/moretext';
$pattern = '/\\?(.*?)\\//';
if( $pieces = preg_split($pattern, $string, Null, PREG_SPLIT_DELIM_CAPTURE)) {
echo($pieces[1] . "\n");
unset($pieces[1]);
echo(implode("/", $pieces) . "\n");
}
?>
--output:--
~/php_programs$ php 1.php
123#abc
/sometext/moretext
Try this
$s = '/sometext?123#abc/moretext';
$matches = array();
$t = preg_match('#\?(.*?)\/#s', $s, $matches);
if($matches[1])
echo "match";
else
echo "not";
Output
match
Codepad

How can I explode the following parameters into an array in PHP? [closed]

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I have the following parameters for example:
max_image_width=100,max_image_height=200,image_proportion=1.75
I want to get an array with:
array('max_image_width'=>100,'max_image_height'=>200,'image_proportion'=175);
$str = 'max_image_width=100,max_image_height=200,image_proportion=1.75';
$cfg = parse_ini_string(
str_replace(',', "\n", $str)
);
print_r($cfg);
5.4
$a=[];foreach(explode(',',$i)as$b){$a[explode('=',$b)[0]]=explode('=',$b)[1];}
$output = array();
parse_str(str_replace(',', '&', 'max_image_width=100,max_image_height=200,image_proportion=1.75'), $output);
E.g. by using preg_match_all.
<?php
$t = 'max_image_width=100,max_image_height=200,image_proportion=1.75';
preg_match_all('!([^=]+)=([^,]+)!', $t, $m);
$x = array_combine($m[1], $m[2]);
var_export($x);
prints
array (
'max_image_width' => '100',
',max_image_height' => '200',
',image_proportion' => '1.75',
)
( though there are tons of other ways to do it without regular expressions ;-) )

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