When I write the code out without a function it works, otherwise I get a 500 connection error. Not sure what error I'm making. Here is my code:
$date = "2016-01-12";
$date = date("Y-m-d", strtotime($date));
$sql = 'INSERT INTO `campaigns` (campaign_id, campaign_date) VALUES (9001, "' . $date . '")';
$result = $link->query($sql);
if ($result) {
echo "database updated";
} else {
echo $link->error;
}
function insertIntoDB($mysqli, $date) {
$sql = 'INSERT INTO `campaigns` (campaign_id, campaign_date) VALUES (9001, "' . $date . '")';
$result = $mysqli->query($sql);
if ($result) {
echo "database updated";
} else {
echo $mysqli->error;
}
}
insertIntoDB($link, $date);
The function works properly when I call it above defining it. Dunno.
Related
I tried to update a row in table showtable
Bugupdate
By using the php code below, binding a bugID to a SQL UPDATE statement to update the row I want to but it doesn't seem to work, is it the problem lie in my SQL statement ?
$id = $_GET['update'];
$games = htmlentities($_POST['games']);
$version = htmlentities($_POST['version']);
$platform = htmlentities($_POST['platform']);
$frequency = htmlentities($_POST['frequency']);
$proposal = htmlentities($_POST['proposal']);
$SQLstring2 = "UPDATE " .$TableName. " SET Game=?,Version=?,Platform=?,Frequency=?,Proposed solution=? WHERE BugID= " .$id;
if ($stmt = mysqli_prepare($DBconnect, $SQLstring2)) {
mysqli_stmt_bind_param($stmt,'sssss', $games, $version, $platform, $frequency, $proposal);
$QueryResult2 = mysqli_stmt_execute($stmt);
if ($QueryResult2 === FALSE) {
echo "<p>Unable to execute the query.</p>"
. "<p>Error code "
. mysqli_errno($DBconnect)
. ": "
. mysqli_error($DBconnect)
. "</p>";
} else {
echo "<h1> Thank you for your contribution";
}
mysqli_stmt_close($stmt);
}
mysqli_close($DBconnect);
Try to rename Proposed solution column to Proposed_solution and adapte the sql query like this :
$SQLstring2 = "UPDATE " .$TableName. " SET Game=?,Version=?, Platform=?, Frequency=?, Proposed_solution=? WHERE BugID= " .$id;
Can someone help me to debug this
<?php
$file_name = basename(__FILE__,'.php');
include("conf.php");
include("XMLSoccer.php");
$years = 1; ///<-------NUMBER OF YEARS TO GO BACK
$leagueretrive = 3; ///<--------THE LEAGUE ID TO RETRIEVE DATA FOR
$date1 = date('y', strtotime("-$years years"));
$date2 = date("y");
//CHECKING IF TABLE EXIST IF NOT CREATE NEW
$table = $file_name;
$query = "SELECT ID FROM " . $table;
$resultat = mysqli_query($conn,$query);
if(empty($resultat)) {
echo "<p>" . $table . " table does not exist</p>";
$query = mysqli_query($conn,"CREATE TABLE IF NOT EXISTS $file_name (
Id int NOT NULL PRIMARY KEY,
HomeGoalDetails varchar(800) NOT NULL,
)CHARACTER SET utf8 COLLATE utf8_general_ci");
}
else {
echo "<p>" . $table . "table exists</p>";
} // else
/////GETING THE DATA FROM SERVICE
try {
$soccer = new XMLSoccer($api_key);
$soccer->setServiceUrl("http://www.xmlsoccer.com/FootballDataDemo.asmx");
$results = $soccer->GetHistoricMatchesByLeagueAndSeason(array("league"=>$leagueretrive,"seasonDateString"=>"$date1$date2"));
print_r($results);
} catch (XMLSoccerException $e) {
echo "XMLSoccerException: " . $e->getMessage();
}
foreach ($results->Match as $team) {
$id = $team->Id;
$homeGoalDetails = $team->HomeGoalDetails;
///INSERTING DATA INTO THE TABLE
$sql = "INSERT INTO $file_name (HomeGoalDetails)
VALUES ('$homeGoalDetails')
on duplicate key update HomeGoalDetails='$homeGoalDetails'";
}
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
?>
The response what i get
Error: INSERT INTO testing2 (HomeGoalDetails) VALUES ('35': Stefan
Johansen;4': penalty Leigh Griffiths;') on duplicate key update
HomeGoalDetails='35': Stefan Johansen;4': penalty Leigh Griffiths;'
You have an error in your SQL syntax; check the manual that
corresponds to your MariaDB server version for the right syntax to use
near ': Stefan Johansen;4': penalty Leigh Griffiths;') on duplicate
key update HomeGo' at line 2 Process finished with exit code 0
You've got unescaped quotes in your query.
Try:
<?php
$file_name = basename(__FILE__,'.php');
include("conf.php");
include("XMLSoccer.php");
$years = 1; ///<-------NUMBER OF YEARS TO GO BACK
$leagueretrive = 3; ///<--------THE LEAGUE ID TO RETRIEVE DATA FOR
$date1 = date('y', strtotime("-$years years"));
$date2 = date("y");
//CHECKING IF TABLE EXIST IF NOT CREATE NEW
$table = $file_name;
$query = "SELECT ID FROM " . $table;
$resultat = mysqli_query($conn,$query);
if(empty($resultat)) {
echo "<p>" . $table . " table does not exist</p>";
$query = mysqli_query($conn,"CREATE TABLE IF NOT EXISTS $file_name (
Id int NOT NULL PRIMARY KEY,
HomeGoalDetails varchar(800) NOT NULL,
)CHARACTER SET utf8 COLLATE utf8_general_ci");
}
else {
echo "<p>" . $table . "table exists</p>";
} // else
/////GETING THE DATA FROM SERVICE
try {
$soccer = new XMLSoccer($api_key);
$soccer->setServiceUrl("http://www.xmlsoccer.com/FootballDataDemo.asmx");
$results = $soccer->GetHistoricMatchesByLeagueAndSeason(array("league"=>$leagueretrive,"seasonDateString"=>"$date1$date2"));
print_r($results);
} catch (XMLSoccerException $e) {
echo "XMLSoccerException: " . $e->getMessage();
}
foreach ($results->Match as $team) {
$id = $team->Id;
$homeGoalDetails = $team->HomeGoalDetails;
///INSERTING DATA INTO THE TABLE
$sql = "INSERT INTO $file_name (HomeGoalDetails)
VALUES ('".mysqli_real_escape_string($conn,$homeGoalDetails)."')
on duplicate key update HomeGoalDetails='".mysqli_real_escape_string($conn,$homeGoalDetails)."'";
}
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
?>
This is cancel_order function,that also in it will call the increase_gameamount() function, i am trying to call increament_gameamount() function it works but when I try to call it from while loop nothing changes in database.
//cancel function
function cancel_order($ord) {
global $conn;
$bqty = 0;
$gqty = 0;
$res = array();
echo "entered cancel function " . $ord . "<br>";
$st = "select (B_qty+G_qty) newqt, B_GM_ID from tb_basket b, tb_game g
where b.B_GM_ID = g.G_ID
and B_O_ID='$ord' ";
$sql = $conn->prepare($st);
$sql->execute();
$sql->bind_result($newqt, $gid);
$i = 0;
while($row = $sql->fetch()) {
$res[$i][0] = $newqt;
$res[$i][1] = $gid;
$i++;
}
$j = 0;
$sql->free_result();
$sql->close();
while($j < sizeof($res)) {
echo $gd = $res[$j][0] . "<br>";
echo $qty = $res[$j][1] . "<br>";
increament_gameamount($gd, $qty);
$j++;
}
}
//increament function
function increament_gameamount($gameid, $new_qty) {
global $conn;
echo "entered increament_gameamount function";
echo $gameid;
echo $new_qty;
$varupdateqty = $conn->prepare("update tb_game set G_qty=? where G_ID=?");
$varupdateqty->bind_param("ss", $new_qty, $gameid);
$varupdateqty->execute();
echo "Prepare failed: (" . $conn->errno . ") " . $conn->error;
}
As I stated in the comments I think you are failing on the WHERE of your query because
echo $gd=$res[$j][0]."<br>";
is making $gd a string like 125<br> and the DB cannot find that.
Also, this would cause an error but if the type of your column is int and you pass:
echo $qty=$res[$j][1]."<br>";
again you make $qty something like 1000<br> and that would fail again this would be an error the above for ID check would not.
UPDATE
Just realized I did not specifially state the resolution. Set the variables then echo them and you should be all good.
$gd=$res[$j][0];
$qty=$res[$j][1];
echo $gd . "<br>" . $qty . "<br>";
When I print my code it only prints the question and description of id = 1 but not the rest of the table.
here is my code.
Please show me how to print my entire table which has like 20 questions or so...and also please show me how to make it so that the questions stay on the browser (even when I refresh the page) because currently the data does not stay on the browser when i refresh the page.
Thanks So Much!
<?php
require_once "connection.php";
if(isset($_POST['submit'])) {
$conn = new mysqli(DB_HOST, DB_USER, DB_PASS, DB_NAME );
if($conn->connect_error) {
die("connection error: " . $conn->connect_error);
} else {
echo "Submit button connected to database!";
}
$question = $_POST['question'];
$description = $_POST['description'];
$sql = " INSERT INTO `ask` (question_id, question, description) VALUES
(NULL, '{$question}', '{$description}' ) ";
if($conn->query($sql)) {
echo "it worked";
} else {
echo "error: " . $conn->error;
exit();
}
$query = "SELECT * FROM `ask` ";
if( $result = $conn->query($query)) {
$fetch = $result->fetch_assoc();
echo "<p>{$fetch['question']}</p>";
echo "<p>{$fetch['description']}</p>";
} else {
echo "failed to fetch array";
}
}
?>
You need a for each loop:
<?php
require_once "connection.php";
if(isset($_POST['submit'])) {
$conn = new mysqli(DB_HOST, DB_USER, DB_PASS, DB_NAME );
if($conn->connect_error) {
die("connection error: " . $conn->connect_error);
} else {
echo "Submit button connected to database!";
}
$question = $_POST['question'];
$description = $_POST['description'];
$sql = " INSERT INTO `ask` (question_id, question, description) VALUES
(NULL, '{$question}', '{$description}' ) ";
if($conn->query($sql)) {
echo "it worked";
} else {
echo "error: " . $conn->error;
exit();
}
$query = "SELECT * FROM `ask` ";
if( $result = $conn->query($query)) {
$fetch = mysql_fetch_array($result, MYSQL_ASSOC);
foreach($fetch as $ques) {
echo "<p>" . $ques['question'] . "</p>";
echo "<p>" . $ques['description'] . "</p>";
}
} else {
echo "failed to fetch array";
}
}
?>
All I've done there is change:
$fetch = $result->fetch_assoc();
echo "<p>{$fetch['question']}</p>";
echo "<p>{$fetch['description']}</p>";
to:
$fetch = mysql_fetch_array($result, MYSQL_ASSOC);
foreach($fetch as $ques) {
echo "<p>" . $ques['question'] . "</p>";
echo "<p>" . $ques['description'] . "</p>";
}
fetch_assoc() — Fetch a result row as an associative array
so it gets only 1 row you need to loop through the rest of the rows check the examples reference from php docs
I am trying to execute the function below but does not display anything.
function displayNr($x){
$sql="SELECT D4741 FROM table_x WHERE D4711='".$x."';
if (!$result = odbc_exec($pconn, $sql)) {
echo "Query error! ODBC: ", odbc_error();
} else {
while ($row = odbc_fetch_array($result)) {
echo $row["D4741"] . "\n";
}
}
}
displayNr('name');
However, if I remove the function it works correctly:
x='name';
$sql="SELECT D4741 FROM table_x WHERE D4711='".$x."';
if (!$result = odbc_exec($pconn, $sql)) {
echo "Query error! ODBC: ", odbc_error();
} else {
while ($row = odbc_fetch_array($result)) {
echo $row["D4741"] . "\n";
}
}
What could be the problem?
$pconn is not set in the function.
in the function, $pconn is a new local variable (with a scope of the function) and is not the same $pconn defined outside the function. pass it in as a parameter:
function displayNr($x,$pconn){
$sql="SELECT D4741 FROM table_x WHERE D4711='".$x."';
if (!$result = odbc_exec($pconn, $sql)) {
echo "Query error! ODBC: ", odbc_error();
} else {
while ($row = odbc_fetch_array($result)) {
echo $row["D4741"] . "\n";
}
}
}
displayNr('name');
watch out for SQL injection!!! your code is a perfect example of what not to do!!:
$sql="SELECT D4741 FROM table_x WHERE D4711='".$x."';
see this: SQL Injection or just google it
function displayNr($x, $pconn)
{
$sql = "SELECT D4741 FROM table_x WHERE D4711='" . $x . "'"; //here " is remaining
if (!$result = odbc_exec($pconn, $sql)) {
echo "Query error! ODBC: ", odbc_error();
} else {
while ($row = odbc_fetch_array($result)) {
echo $row["D4741"] . "\n";
}
}
}
displayNr('name');