Create a dropdown for months using a php function. - php

Question

I am using this function to create a dropdown for months.
function formMonth(){
$month = strtotime(date('Y').'-'.date('m').'-'.date('j').' - 12 months');
$end = strtotime(date('Y').'-'.date('m').'-'.date('j').' + 0 months');
while($month < $end){
$selected = (date('F', $month)==date('F'))? ' selected' :'';
echo '<option'.$selected.' value="'.date('F', $month).'">'.date('F', $month).'</option>'."\n";
$month = strtotime("+1 month", $month);
}
}
My problem is I need to use numeric values of 1 to 12 for option values.
At this time it use month name for value options like this.
<select size="1" name="month">
<option selected value="January">January</option>
<option value="February">February</option>
<option value="March">March</option>
<option value="April">April</option>
<option value="May">May</option>
<option value="June">June</option>
<option value="July">July</option>
<option value="August">August</option>
<option value="September">September</option>
<option value="October">October</option>
<option value="November">November</option>
<option value="December">December</option>
</select>
Can anybody tell me how to modify this function.
Thank you.

Answer 1

Try below code:
<select name="month" size='1'>
<?php
for ($i = 0; $i < 12; $i++) {
$time = strtotime(sprintf('%d months', $i));
$label = date('F', $time);
$value = date('n', $time);
echo "<option value='$value'>$label</option>";
}
?>
</select>

Answer 2

If you take a look at the documentation for date(), you'll see under "Format" that you can use n for numeric representation of months, from 1 to 12. (You can also use m for having leading zeroes (01-12)).
This means that you basically only have to change
echo '<option'.$selected.' value="'.date('F', $month).'">'.date('F', $month).'</option>'."\n";
to
echo '<option'.$selected.' value="'.date('n', $month).'">'.date('F', $month).'</option>'."\n";
in your current code, provided that it otherwise works as expected (all I did there was replace date('F', $month) in the values-attribute to date('n', $month).

Answer 3

try this :your problem sloved.
<?php
function formMonth(){
$month = strtotime(date('Y').'-'.date('m').'-'.date('j').' - 12 months');
$end = strtotime(date('Y').'-'.date('m').'-'.date('j').' + 0 months');
$val=1;
echo "<select>";
while($month < $end){
$selected = (date('F', $month)==date('F'))? ' selected' :'';
echo '<option'.$selected.' value='.$val.'>'.date('F', $month).'</option>'."\n";
$month = strtotime("+1 month", $month);
$val++;
}
echo "</select>";
}
formMonth();
?>

Answer 4

Here is your answer:-
<?php
function months($selctedMonth='january'){
$months='<select name="month" size="1">';
for ($i = 12; $i > 0; $i--) {
$time = strtotime(sprintf('-%d months', $i));
$label = date('F', $time);
$selctedM = strtolower($selctedMonth) == strtolower($label) ? 'selected' : '';
$months.="<option value='$label' $selctedM >$label</option>";
}
$months.="</select>";
return $months;
}
echo months();
?>
By default, January will be displayed as selected.
if you write <?php echo months('march'); ?> then march will be selected by default.

Answer 5

<select size="1" name="month">
<option selected value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
<option value="6">6</option>
<option value="7">7</option>
<option value="8">8</option>
<option value="9">9</option>
<option value="10">10</option>
<option value="11">11</option>
<option value="12">12</option>
</select>
If thats what you want.
Enjoy!

Answer 6

<div class="form-group">
<label>Month:</label>
<select id="month" name="month" class="form-control select2" style="width: 100%;">
<option value=""></option>
<?php
$monthArray = range(1, 12);
foreach ($monthArray as $month) {
$monthPadding = str_pad($month, 2, "0", STR_PAD_LEFT);
$fdate = date("F", strtotime("2015-$monthPadding-01"));
echo '<option value="'.$monthPadding.'">'.$fdate.'</option>';
}?>
</select>
</div>
For more deail click here

Answer 7

<select name="month">
<?php
foreach (['January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December'] as $monthNumber => $month) {
echo "<option value='$monthNumber'>{$month}</option>";
}
?>
</select>

Answer 8

I tried some of the answers here, and they have not given me the right solution to display an array of months.
For example, the #Kausha Mehta solution outputted this one.
<select name="month" size="1">
<option value="7">July</option>
<option value="8">August</option>
<option value="10">October</option>
<option value="10">October</option>
<option value="12">December</option>
<option value="12">December</option>
<option value="1">January</option>
<option value="3">March</option>
<option value="3">March</option>
<option value="5">May</option>
<option value="5">May</option>
<option value="7">July</option>
</select>
Which seems to skip some months and duplicating some months.
But this work as expected.
<select id="month" name="month" autocomplete='off'>
<?php
// Create a dropdown for months using a php foreach.
$monthArray = range(1, 12);
//::::
foreach ($monthArray as $month):
$monthCode = str_pad($month, 2, "0", STR_PAD_LEFT);
$selected = ($monthCode === date('m')) ? 'selected' : '';
//All months start with 1
$date = new DateTime(date("Y-").$monthCode."-01");
print '<option '.$selected.' value="'.$monthCode.'">'.$date->format('F').'</option>';
endforeach;
?>
</select>

Answer 9

for($i=1; $i<=12; $i++)
{
echo '<option value="'.date('m', strtotime('2020-'.$i.'-01')).'">'.date('M', strtotime('2020-'.$i.'-01')).'</option>';
}