I'm hoping someone could help me finish off some php code (the avon guy already kindly helped me with this but I'm still struggling with the last bit).
All it is, is I have a form where I have 10 particular sequences of digits, which if entered, allows the form to redirect to the following page. If anything else is entered I want the page to deny access with some kind of error prompt.
At top of the php, in the part before any php is printed, avon guy suggested an array to check the 10 correct sequences against.
$possibles = array('rva858', 'anothersequence', 'andanother');
$match = $_POST['nextpage'];
if (array_search($match, $possibles) != false) {
//match code in here
} else {
// fail code in here
}
I'm not sure what to put in the //match code in here AND the //fail code in here, bits. Can someone help me with this last bit please?
Many thanks
Jon
If you are just trying to redirect to another page using php, you can use header('Location: mypage.php');. More information on header here.
So for your code example (edited based on comment):
invitation.php
<?php
//invitation.php
$possibles = array('rva858', 'anothersequence', 'andanother');
$match = $_POST['nextpage'];
if (array_search($match, $possibles) === false)
{
//If fail
header('Location: formpage.php?errorMessage=Incorrect code!');
exit();
}
//If success:
//All of the invitation.php html and success code below
formpage.php
<?php
//formpage.php
if(!empty($_GET['errorMessage'])){
echo '<span>' . $_GET['errorMessage'] . '</span>';
}
?>
<form action="invitation.php" method="post">
<input name="rsvp" type="text" />
<input type="submit" value="Submit" name="submit" />
</form>
Related
I am having a problem with simple PHP app where a user has to enter a correct answer from a list of available options. And that options are stored in an array. The problem is that i cannot use the options anytime in the script other than the array declaration point. I might sound dumb...and i am, believe me. Lets say this is the array:
$hobbyChoices = array("Movie","Music","Games","Books","Sports","Sleeping");
Now there is a text box in my script and $_POST method is used to submit the form. The correct choice which i have selected is 'Sports'. Now there are 4 possibilities a user might click submit, they are listed below.
A user clicks the submit button without entering any text in the textbox.
A user guesses the wrong choice which is from the $hobbyChoices but not 'Sports'.
A user guesses a choice which is not from the array. i.e anything other than what is in the array.
Finally, the user enters the correct choice that is 'Sports'.
This might seem pretty easy but the problem is that i cant use the names of the hobbies anywhere in the script, as mentioned before, other than the array declaration. Can i please get help? Also, when i tried to do one of the 4 possibilities, i encountered a problem with the uppercase and lowercase. This is seriously getting irritating, any help would be greatly appreciated.
Thanks!
If I am understanding your question correctly, the following is what you are looking for:
<?php
$hobbyChoices = array("Movie","Music","Games","Books","Sports","Sleeping");
if (isset($_POST['answer'])) {
$answer = mysql_real_escape_string($_POST['answer']);
$correct_answer = $hobbyChoices[4];
$response = "Your answer is not one of the answers listed!";
foreach ($hobbyChoices as $value) {
if (strtolower($answer) == strtolower($value) && (strtolower($answer) != strtolower($correct_answer))) {
$response = "You selected the wrong answer from the list of options!";
}
else if (strtolower($answer) == strtolower($value) && (strtolower($answer) == strtolower($correct_answer))) {
$response = "You have answered correctly!";
}
}
print $response;
}
?>
<form name="form" method="post">
<table>
<tr>
<td>What is baseball?
</td>
<td><input type="text" name="answer" />
</td>
</tr>
<tr>
<td colspan="2"><input type="submit" value="submit" />
</td>
</tr>
</table>
</form>
strtolower is a function in php that converts strings to lowercase and would help you compare your two values.
Hi I am a newbie learning PHP ( & on stackoverflow too)- I am trying to solve a simple problem but unable to do. I hae already searched on google and stackoverflow before posting a question as I didnt want to waste other time but for a week now am unable to solve this issue.
I am writing a simple program in php that lets user input a number and checks if the value entered is 5. If true it echo's "you win" else "try again". I am able to do this
The tricky part for me is I want to give him only 10 chances and try as I might using basic PHP am unable to do this. Have tried using if, for, do while but am unable to "loop the html"..I dont know jquery etc and am trying to accomplish this with PHP only. I havent yet progessed to learning sessions etc. Thanks in advance
<html>
<body>
TRY AND GUESS THE NUMBER
<br/>
<br/>
<form method="POST" action="gullible.php">
Please enter any number :<input type="text" name="num">
<input type="hidden" name="cnt" value=<?php $cnt=0 ?>>
<input type="submit" name="go">
</body>
</html>
<?php
$i=0;
if ($_POST['num']!=5)
{
$i++;
echo $i;
echo " Please try again";
}
else
echo "You win the game";
?>'
You need to store the variable in some manner such that it persists. in your script, you are setting $i to 0 each time it runs. Plus you are setting the value incorrectly in your hidden input.
One way of doing this is using a Session variable, such as $_SESSION['cnt']
My PHP is a bit rusty, but here's an example using Session variables:
$max_guesses = 10;
if( !isset($_SESSION['cnt']) ){
$_SESSION['cnt'] = 0;
}
if( $_SESSION['cnt']++ > $_max_guesses ){
echo "Maximum tries exceeded";
} else {
echo "Try again";
}
If you don't want to, or can't use a session variable, you could use the hidden input field, like you tried to:
<?php
if( !isset($_POST['cnt']) ){
$cnt = 0;
} else {
$cnt = $_POST['cnt'];
}
if( $cnt++ > $_max_guesses ){
echo "Maximum tries exceeded";
} else {
echo "Try again";
}
?>
<input type='hidden' name='cnt' value='<?php echo $cnt ?>' />
(Note if your form uses GET instead, just replace $_POST with $_GET or you can use $_REQUEST if you're not sure, but probably better not to.
After successful login of the user set the chances variable to 10 like this.
$_SESSION['nofchances']=10;
After setting this flag on the successful authentication page. Redirect to your PLAIN html code.
EDITED :
question.html
<html>
<body>
TRY AND GUESS THE NUMBER
<br/>
<br/>
<form method="POST" action="gullible.php">
Please enter any number :<input type="text" name="num">
<input type="submit" name="go">
</body>
</html>
gullible.php
<?php
if($_SESSION['nofchances']!=0)
{
if ($_POST['num']!=5)
{
$_SESSION['nofchances'] = $_SESSION['nofchances'] - 1;
echo "You have ".$_SESSION['nofchances']." no of chances to try";
echo "<br>Please try again";
header("location:question.html");
}
else
{
echo "You won the game";
$_SESSION['nofchances']=10; // resetting back
}
}
else
{
echo "Your chances expired";
}
?>
You can call a function in onBlur/onChange
<script>
function test()
{
var count=<?php echo $count;?>;
var guess=parseInt($('#hid_num').val())+1;
if(guess>count)
{
alert('Your chances over!');
}
else
{
$('#hid_num').val(guess);
}
}
</script>
<input type="text" onblur="test();" id="chk_estimate" />
<input type="hidden" value="0" id="hid_num" /></body>
If you dont want to use sessions yet you could define a hidden input field which stores the current try then incriment "+1" it whenever the submit is pressed / the site is reloaded. Something like:
if( isset($_POST['try']) ) {
$try = $_POST['try'];
$try += 1;
} else {
$try = 0;
}
add the hidden field in your form like:
$hiddenTry = '<input type="hidden" value="'. $try .'" name="try"/>';
and add a if clause to when to show the form like:
if ( $try <= 10 ) {
//your form
}
i made this for you i hope it can help you learn something new (i edited it a couple of times to make variable names easier to understand make sure you check it again - i added a cheat also :) )
<?php
session_start(); // with this we can use the array $_SESSION to store values across page views of a user.
mt_srand(time()); // this is to ensure mt_rand function will produce random values. just ignore it for now. it's another story :)
$max_tries = 10; // limit of guesses
$_SESSION['the_magic_number']=!isset($_SESSION['the_magic_number'])?mt_rand(0,100):$_SESSION['the_magic_number'];
// the previous line is a one-liner if then else statement. one-liners works like this:
// $my_name_will_be=($isBoy==true)?"George":"Mary";
if(isset($_POST['num'])) // if this pageview is from a valid POST then...
{
$_SESSION['current_try']=isset($_SESSION['current_try'])?$_SESSION['current_try']+1:1;
// one-line if then else again. This increases the try user is now, or resets it to one
}
?>
<html>
<body>
TRY AND GUESS THE NUMBER
<br/>
<br/>
<?php
if ($_SESSION['current_try']<=$max_tries) // if user has more tries available
{
if(intval($_POST['num'])==$_SESSION['the_magic_number']) // did he found it?
{
echo "You found it! Gongratulations! Click <a href=''>here</a> to try again!";
// oh and do not forget to reset the variables (you found this bug, well done!)
$_SESSION['current_try']=1;
$_SESSION['the_magic_number']=NULL;
}
else
{
// if he didn't found it, display the status of tries left, and the form to try again
echo "This is your try ".($_SESSION['current_try'])." of ".$max_tries." Good Luck!";
?>
<form method="POST" action="mygame.php">
Please enter any number :
<input type="text" name="num"/>
<input type="hidden" name="tries" value="<?php echo (isset($_POST['tries']))?$_POST['tries']-1:$max_tries; ?>"/>
<input type="submit" name="go"/>
</form>
<span style="color:white;background-color:white;"><?php echo "You bloody cheater! The magic number is ".$_SESSION['the_magic_number'];?></span>
<?php
}
}
else
{
// here we are if no tries left! An empty href to reload the page, and we resetting our variables.
// the_magic_number gets NULL so at the start of script it will be "not set" and will get a mt_rand(0,100) value again
echo "You lost! Sorry! Click <a href=''>here</a> to try again!";
$_SESSION['current_try']=1;
$_SESSION['the_magic_number']=NULL;
}
?>
</body>
</html>
the span at the end is a cheat ;) press ctrl+a to use it !!!
I'm developing a custom package that accepts a form input, compares it against a table and display the relevant information on the screen, I have the transport and schema setup correctly (I hope! I followed the guide at BobsGuides.com) and I can read back from the table without issue. My problems began when I started implementing the form input.
Basically the session variables I am posting never seem to get recieved so the isset never evaluates to true and I just see the form over and over again.
I've only just begun with PHP and am a complete newb when it comes to xPDO so I accept theres probably more than a few things I havn't noticed but if someone could point me in the right direction I'd be extremely grateful.
<?php
$path = MODX_CORE_PATH . 'components/dataease/';
var_dump($_POST['submit']);
var_dump($_POST['accNo']);
// get POST variable this is captured
$accNo = $_POST['accNo'];
$output = '';
// Check if form has been submitted
if (isset($_POST['submit'])) {
// Get info from the database
$query = $modx->newQuery('accno');
$query->select($modx->getSelectColumns('Dataease','Dataease','',array('*')));
$query->where(array('accNumber:LIKE' => '$accNo'));
var_dump($query);
// Place it into a variable for output
if (!$query) {
return "Query failed";
} else {
$dataease = $modx->getCollection('Dataease',$query);
// Count the returned rows, should only ever be 1
$output .= '<p>Total: '. count($dataease) . '</p>';
// Show the found data
foreach($dataease as $sql) {
$fields = $sql->toArray();
$output .= $modx->getChunk('showData', $fields);
}
}
return $output;
} else {
// Get the form chunk
$form = $modx->getChunk('dataEntryForm');
return $form;
}
This is my form chunk
<h2>Enter Account Number:</h2>
<form method="POST" action="">
<input name="accNo" type="text"/>
<input name="submit" type="submit" value="submit" />
</form>
Give this a try to see if there has been a post submission
if($_SERVER['REQUEST_METHOD'] == "POST")
and/or give your form a hidden submit field, some browsers [at least some used to] not post the submit field if you just hit return when the submit button is not in focus. Test for that as well.
Do you trying http://rtfm.modx.com/display/ADDON/Rowboat for work with your tables?
I am having problems figuring out how to retain users data when the validation fails. I am somewhat new to PHP so I might be making some huge mistakes in my logic.
Currently if the validation fails all the fields are wiped clean and $_Post data is also gone.
Here is some code assuming the user enters an invalid email I want the Name field to be retained. This code is not working.
<?php
if($_POST['doSubmit'] == 'Submit') {
$usr_name = $data['Name'];
$usr_email = $data['Email'];
if (isEmail($usr_email)==FALSE){
$err = "Email is invalid.");
header("Location: index.php?msg=$err");
exit();
}
//do whatever with data
}
if (isset($_GET['msg'])) {
$msg = mysql_real_escape_string($_GET['msg']);
echo "<div class=\"msg\">$msg</div><hr />";
}
if (isset ($_POST['Name'])){
$reusername = $_POST['Name'];}
else{$reusername = "NOTHING";}//to test
?>
<form action="index.php" method="post" >
<input name="UserName" type="text" size="30" value="<?echo $reusername;?>">
<input name="Email" type="text" size="30">
<input name="doSubmit" type="submit" value="submit">
</form>
}
You can use AJAX to submit your form data to your PHP script and have it return JSON data that specifies whether the validation was successful or not. That way, your fields won't be wiped clean.
Another way is to send back the recorded parameters to the posting page, and in the posting page, populate the fields using PHP.
However, I think the first solution is better.
UPDATE
The edit makes your code clearer and so I noticed something. Your input field is called UserName in the HTML, but you are referring to Name in PHP. That's probably why it's not working. Is your field always being filled with the value NOTHING? Make sure the name of the input field and the subscript you are using in $_POST are the same.
Also, there's no need to redirect to another page (using header) if you have an error. Maintain an $errors array or variable to print error messages in the same page. But like I mentioned before, it's probably better to use the JSON approach since then you can separate your view layer (the html) from the PHP (controller layer). So you'd put your HTML in one file, and your PHP in another file.
EDIT:
Vivin had commented that my assumption regarding the header was incorrect and he was right in that. Further more it looks like what the OP is doing is essentially what i layed out below albeit in a less structured fashion. Further Vivin - caught what is likely the actual problem here - the html name and the array key $_POST do not match.
Its wiped clean because you are using header to redirect to another page. Typicaly you would have a single page that validates the data and if ok does something with it and returns a success view of some sort, or that returns an error view directly showing the form again. By using header youre actually redirecting the browser to another page (ie. starting up an entirely new request).
For example:
// myform.php
if(strtolower($_SERVER['REQUEST_METHOD']) == 'get')
{
ob_start();
include('form.inc.php'); // we load the actual view - the html/php file
$content = ob_get_clean();
print $content; // we print the contents of the view to the browser
exit;
}
elseif(strtolower($_SERVER['REQUEST_METHOD']) == 'post')
{
$form = santize($_POST); // clean up the input... htmlentities, date format filters, etc..
if($data = is_valid($form))
{
process_data($data); // this would insert it in the db, or email it, etc..
}
else
{
$errors = get_errors(); // this would get our error messages associated with each form field indexed by the same key as $form
ob_start();
include('form.inc.php'); // we load the actual view - the html/php file
$content = ob_get_clean();
print $content; // we print the contents of the view to the browser
exit;
}
}
so this assumes that your form.inc.php always has the output of error messages coded into it - it just doesnt display them. So in this file you might see something like:
<fieldset>
<label for="item_1">
<?php echo isset($error['item_1']) ? $error['item_1'] : null; ?>
Item 1: <input id="item_1" value="<?php echo $form['item_1'] ?>" />
</label>
</fieldset>
Could do something similar to if failed then value=$_POST['value']
But vivin's answer is best. I don't know much about AJAX and wouldn't be able to manage that.
Ok, firstly header("Location: index.php?msg=$err"); is not really required. It's best practice not to redirect like this on error, but display errors on the same page. Also, redirecting like this means you lose all of the post data in the form so you can never print it back into the inputs.
What you need to do is this:
<input name="Email" type="text" size="30" value="<?php print (!$err && $usr_email ? htmlentities($usr_email, ENT_QUOTES) : '') ?>">
Here I'm checking whether any errors exist, then whether the $usr_email variable is set. If both these conditions are matched the post data is printed in the value attribute of the field.
The reason I'm using the function htmlentities() is because otherwise a user can inject malicious code into the page.
You appear to be processing the post on the same page as your form. This is an OK way to do things and it means you're nearly there. All you have to do is redirect if your validation is successful but not if it fails. Like this
<?php
if( isset( $_POST['number'] ) ) {
$number = $_POST['number'];
// validate
if( $number < 10 ) {
// process it and then;
header('Location: success_page.php');
} else {
$err = 'Your number is too big';
}
} else {
$number = '';
$err = '';
}
?>
<form method="POST">
Enter a number less than 10<br/>
<?php echo $err ?><br/>
<input name="number" value="<?php echo $number ?>"><br/>
<input type="submit">
</form>
I've just discovered the email-address-saving form on my website does not work on Opera and Internet Explorer (7 at any rate), and possibly other browsers. Works fine with Firefox. Unfortunately I'm not a developer and no longer have any contact with the guy who wrote the code for the form so I've no idea how to fix it. I assume the problem has something to do with the code below:
<?php
$str = '';
if (isset($_POST['submit']))
{
if(!eregi("^[[:alnum:]][a-z0-9_.-]*#[a-z0-9.-]+\.[a-z]{2,4}$", $_POST['email'])) {
$str = "<span style='color: red'>Not a valid email address</span>";
} else {
$file = 'emails.txt';
$text = "$_POST[email]\n";
if (is_writable($file)) {
if (!$fh = fopen($file, 'a')) {
exit;
}
if (fwrite($fh, $text) === FALSE) {
exit;
}
fclose($fh);
}
header('Location: thankyou.html');
}
}
?>
and then the body bit:
<form action="index.php" method="post">
<input type="text" name="email" style="width: 250px;" />
<input type="image" src="img/button-submit.png" name="submit" value="Submit" style="position: relative; top: 5px; left: 10px" />
</form>
<?php echo $str ?>
Anybody feeling pity for a helpless non-dev and have an idea what's not working here?
This is being caused by the fact that the submit input is of type 'image'. On submit, IE7 only returns the x and y coords of the click.
This should do the trick:
Replace:
if (isset($_POST['submit']))
With:
if (isset($_POST['submit']) || isset($_POST['submit_x']))
It is a browser based issue
in your form, you have used <input type="image" />
IE doesn't pass name/value pairs for image type input, instead it only sends the key_x/value_x and key_y/value_y pairs
you probaly want to use <input type="submit" /> as replacement/addition, since this is completely supported on all types of browsers (think also about text browsers please, i still use them.)
Unfortunately, the error, if any at all, is going to be between the Browser and the server, not PHP. If you could provide some details like the HTML form that isn't working in IE7, then we may be able to help out more.
Your form element is self-closed. Remove the trailing / in the opening tag and it should work. (Er, it might work. Either way, there shouldn't be a trailing slash.)
Assuming that the php in your code is in the same file as the form ... you might try adding the name of your php file to the form's action.
<form action="" method="post">
... becomes ...
<form action="name_of_php_file" method="post">
Include a hidden field in your form that will only be valid and present if you submit the form. Something like:
<input type="hidden" name="checkemail" value="1" />
Then, in your PHP, change the if-condition to check for this particular variable:
<?php
$str = '';
if (isset($_POST["checkemail"]))
{
//-- rest of your code
}
?>
This will allow you to keep the image as the submit button and work across browsers which differ in how they send the value, if at all, of the name of image type buttons.
I know this doesn't fix your problem, but I don't like the line:
$text = "$_POST[email]\n";
Is that not bad practice? I haven't used PHP for years, but I think you should change it to
$text = $_POST['email'] . "\n";
or something like that. Using $_POST[email] without the quotes around the array key causes PHP to first look for a constant named 'email'. Only after not finding it will it convert email to a string and then pull the value out of the associative array. Just wasted CPU power.