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I am having trouble getting my for loop to work in php. I am trying to make my code loop the time ten times with my css formating
<html>
<head>
<meta charset="UTF-8">
<title></title>
<link rel="stylesheet" type="text/css" href="clockloop.css">
</head>
<body>
<div id="bodycontainer">
<h1> Clock Loop </h1><hr>
<?php for($i=0;$i<=10;$i++){
<div id="border">
<span id = "font">
<?php
echo date("G:i:s")
?>
</span>
</div>
<h3> Today is
<?php
echo date("F,j,Y")
?>
</h3>
}
?>
</div>
</body>
</html>
You messed up your php tags opening and closing in the wrong places
<html>
<head>
<meta charset="UTF-8">
<title></title>
<link rel="stylesheet" type="text/css" href="clockloop.css">
</head>
<body>
<div id="bodycontainer">
<h1> Clock Loop </h1><hr>
<?php for($i=0;$i<=10;$i++){?>
<div id="border">
<span id = "font">
<?php
echo date("G:i:s")
?>
</span>
</div>
<h3> Today is
<?php
echo date("F,j,Y")
?>
</h3>
<?php
}
?>
</div>
</body>
</html>
CONVERSELY .. You said you wanted 10 times .. This will output 11, as 0 is still a quantifiable number ..
You cannot just output HTML in PHP like that. You can echo or you can jump in and out like this:
<html>
<head>
<meta charset="UTF-8">
<title></title>
<link rel="stylesheet" type="text/css" href="clockloop.css">
</head>
<body>
<div id="bodycontainer">
<h1> Clock Loop </h1><hr>
<?php for($i=0;$i<=9;$i++){ ?><!-- note the closing PHP tag -->
<div id="border">
<span id = "font">
<?php
echo date("G:i:s")
?>
</span>
</div>
<h3> Today is
<?php
echo date("F,j,Y")
?>
</h3>
<?php } ?><!-- note the opening PHP tag -->
</div>
</body>
</html>
If you want 10 repeats you should end your count at 9 because 0 will be your first record. You could also start with $i = 1; and use 10 as the count to number.
Add error reporting to the top of your file(s) right after your opening <?php tag error_reporting(E_ALL); ini_set('display_errors', 1);this will reveal when you have errors in your syntax and alert you on where you should start debugging.
<html>
<head>
<meta charset="UTF-8">
<title></title>
<link rel="stylesheet" type="text/css" href="clockloop.css">
</head>
<body>
<div id="bodycontainer">
<h1> Clock Loop </h1><hr>
<?php for($i=0;$i<10;$i++){ ?> => look at this line
<div id="border">
<span id = "font">
<?php
echo date("G:i:s")
?>
</span>
</div>
<h3> Today is
<?php
echo date("F,j,Y")
?>
</h3>
<?php => look at this line
}
?>
</div>
Related
This question already has answers here:
PHP parse/syntax errors; and how to solve them
(20 answers)
Closed 1 year ago.
I have no idea what's going on, I have looked over the code and it just wont pull up the webpage. I need help figuring out what is going on with this code.
<?php
include ('config.php');
require('db.php');
$query = "SELECT * FROM salerecords";
$result = mysqli_query($conn, $query);
echo $result;
$posts = mysqli_fetch_all($result, MYSQLI_ASSOC);
mysqli_free_result($result);
mysqli_close($conn);
?>
<html>
<?php include('header.php'); ?>
<head>
<link rel="stylesheet" href="style.css" type="text/css">
<link rel="stylesheet" type="text/css"
href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css">
<title>PHP Stores</title>
</head>
<main>
<div id="user_select">
<div id="options">
<div id="view">
<a href="displayRecs.php"><input type="submit" value="View" class="menu-
chosen">
</a>
</div>
</div>
</div>
</main>
<body>
<header>Manage Sales Records</header>
<h1>salesrecords</h1>
<?php foreach($posts as $vaule) : ?>
<div class="well">
<h3><?php echo $vaule['size']; ?>
</h3>
<small>Created on <?php echo $vaule['color'];?> by <?php echo $vaule['price']; ?>
</small>
<p><?php echo $vaule['Description']; ?>
</p>
</div>
</body>
</html>
The error "unexpected end of file" means that when PHP was reading through your code, it was expecting to get to something, but never did. Often, it means you have mismatched brackets, quote marks, etc - you've indicated the start of something, and PHP is waiting for you to indicate the end.
In this case, you have a foreach(): which needs to be paired with an endforeach;
This question already has answers here:
How to fix "Headers already sent" error in PHP
(11 answers)
Closed 5 years ago.
IK this is prob a dupe, but I cant find any solutions to my code what so ever, no matter what code i add/change, it just wont budge... (NOTE im not using normal php, using a friends version, which yes, is fine and dandy)
<?php
include($_SERVER['DOCUMENT_ROOT'].'/phpAlphaDB/core.php');
?>
<html>
<head>
<link rel="icon" type="image/png" href="../logo.png">
<title> Xenoz Web - Users </title>
<link rel="stylesheet" type="text/css" href="../css/style.php" />
<meta http-equiv="content-type" content="text/html; charset=utf-8">
</head>
<?php
if ($role==0) {
header('Location: http://xenozweb.tk/index.php');
} else {
echo '<script>alert("Hello, '.$username.'. Welcome to the userlist...");</script>';
}
?>
<body>
<div class="navigation">
<div class="navitem"> Home </div>
<div class="navitem"> Register </div>
<div class="navitem"> Login </div>
<div class="navitem"> Users </div>
<div class="navitem"> Jukebox </div>
</div>
</div>
<div class="pagecontent">
<div class="userblock">
<?php
$results = db_read('xenozweb-users', '', 'username');
foreach ($results as $result) {
$u_name = db_column($result, 0);
echo '<div class="users">',$u_name,'</div>';
}
?>
</div>
</div>
</body>
</html>
You're returning a partial response before you set the header. Headers must be sent before a response is sent back to the browser.
Try moving the header('Location: ') function call into the top <?php enclosure like so:
<?php
include($_SERVER['DOCUMENT_ROOT'].'/phpAlphaDB/core.php');
if ($role==0) {
header('Location: http://xenozweb.tk/index.php');
}
?>
<html>
<head>
<link rel="icon" type="image/png" href="../logo.png">
<title> Xenoz Web - Users </title>
<link rel="stylesheet" type="text/css" href="../css/style.php" />
<meta http-equiv="content-type" content="text/html; charset=utf-8">
<?php
if ($role != 0) {
echo '<script>alert("Hello, '.$username.'. Welcome to the userlist...");</script>';
}
?>
</head>
<body>
You've already sent data to the browser. you cannot send header() info properly once you've already started to send data payload.
I need help for something please. I'm working on my structure, but I've some problems...
I created a page called "page-container.php" and the content is:
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title><?= $page_title; ?></title>
<link href="css/style.css" rel="stylesheet">
<link href="css/fonts/font-awesome/4.5.0/css/font-awesome.min.css" rel="stylesheet">
<link href="https://fonts.googleapis.com/css?family=Patrick+Hand" rel="stylesheet">
</head>
<body id="<?= $page_id; ?>">
<?php include "includes/header.php"; ?>
<div class="wrapper">
<div class="page-content">
<?php if(isset($sidebar)): ?>
<div class="main-container">
<div class="main-content">
<?php endif; ?>
<h1 class="page-title"><?= $page_title; ?></h1>
I WANT TO HAVE MY CONTENT HERE FOR ALL MY PAGES
</div>
</div>
</body>
</html>
You can see the "I WANT TO HAVE MY CONTENT HERE FOR ALL MY PAGES".
What I mean is that when I write the content in my other pages (for example, my registration page), I want that all the content is placed at this location, like this:
http://prntscr.com/a3oz5k
All my other pages are like this (exemple with index.php):
<?php
$page_title = "Home";
$page_id = "home";
?>
<?php require "includes/page-container.php"; ?>
If I want to write some content in this page, I need to do like this:
<?php
$page_title = "Home";
$page_id = "home";
?>
<?php require "includes/page-container.php"; ?>
<div id="mycontent">
<p>Heellloo</p>
</div>
But look the result: http://prntscr.com/a3p32y
In the code source this is not normal... http://prntscr.com/a3p3kg
My content is below the html and body tag and I want it to be placed just below my h3 title. How can I do please?
Simple example using ob_start(), ob_get_clean().
<?php
ob_start();
?>
<div id="mycontent">
<p>Hello</p>
</div>
<?php
$page = ob_get_clean();
require "includes/page-container.php";
?>
And then in page-container.php just do echo $page;.
Your code will be still formatted as HTML in your editor instead if it would be in a variable.
You can also split your page-container.php into two parts and include the first part before the content and the second one after.
Reference: ob_start(), ob_get_clean()
You can keep another vartiable say $page_content and use as below :
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title><?= $page_title; ?></title>
<link href="css/style.css" rel="stylesheet">
<link href="css/fonts/font-awesome/4.5.0/css/font-awesome.min.css" rel="stylesheet">
<link href="https://fonts.googleapis.com/css?family=Patrick+Hand" rel="stylesheet">
</head>
<body id="<?= $page_id; ?>">
<?php include "includes/header.php"; ?>
<div class="wrapper">
<div class="page-content">
<h1 class="page-title"><?= $page_title; ?></h1>
<?= $page_content; ?>
</div>
</div>
</body>
</html>
And for some content in another page
<?php
$page_title = "Home";
$page_id = "home";
$page_content = "content";
?>
<?php require "includes/page-container.php"; ?>
`
I am trying to create a very simple web application, basically to understand the best practices of coding in HTML5, CSS and JavaScript.
My application has 3-4 pages and each one is using same menu header. So I want to make it reusable by writing it in a separate file (either PHP or HTML).
head.php (it is to be made reusable):
<!DOCTYPE html>
<html>
<head>
<link href="../../css/headermenu.css" rel="stylesheet" type="text/css"/>
</head>
<body>
<ul id="menu">
<li>Home<span></span></li>
</ul>
<p>
</p>
</body>
</html>
front.php:
<?php
include ("$_SERVER[DOCUMENT_ROOT]/page/common/head.php");
?>
HTML markup (dirty code):
<!DOCTYPE html>
<html>
<head>
<!DOCTYPE html>
<html>
<head>
<link href="../../css/headermenu.css" rel="stylesheet" type="text/css"/>
</head>
<body>
<ul id="menu">
<li>Home<span></span></li>
</ul>
<p>
</p>
</body>
</html></head>
<body>
<div>
</div>
<p>
</p>
</body>
</html>
I have following questions:
head.php has both <body> and <head> tag. So where should I write these PHP lines to include it? (in <head> or <body>) (I don't want to have multiple <head>s and <body>s in the final page)
What are the other best practice I should follow? (any link to references welcome)
I have already read w3schools.
In my opinion it would be a good idea to read about templating systems or have a look how frameworks/CMS handle this.
Doing it your way, you can't completly avoid repeating e.g. the closing head tag </head> in every content.php.
So this is just an idea:
head.php
<?php
// Some other includes / requires,
// code snippets...
?>
<!DOCTYPE html>
<html>
<head>
<!-- site-wide stylesheets -->
<!-- & js-files -->
<link href="css/main.css" rel="stylesheet" type="text/css"/>
<script type="text/javascript" src="my/global/scripts.js"></script>
content.php
<?php
include ($_SERVER['DOCUMENT_ROOT'] . '/page/common/head.php');
?>
<!-- put page specific scripts &
<!-- styles here -->
<link href="my/pages/css/style.css" rel="stylesheet" type="text/css"/>
<script type="text/javascript" src="my/pages/js/scripts.js"></script>
</head>
<body>
<div id="container">
<!-- content start -->
<div id="content">
<h1>title</h1>
<p>Your content</p>
</div>
<!-- end of content div -->
<?php
include ($_SERVER['DOCUMENT_ROOT'] . '/page/common/foot.php');
foot.php
<div id="foot">
copyright etc
</div>
</div> <!-- end of container div -->
</body>
</html>
php is rendering html and if you have in both files header of course it will be printed twice
you should separate in includes but don't write in both files tag
example
<header>
<?php
// this file should not include <head> taf
include ($_SERVER[DOCUMENT_ROOT] . '/page/common/header.php);
?>
</header>
BODY
<header>
<?php
include ($_SERVER[DOCUMENT_ROOT] . '/page/common/foot.php);
?>
</header>
include will bring content from head.php and foot.php and will put in index.php file
Another possible solution to avoid multiple head tags which also makes it possible to add additional css files:
<?php
// head.php
$html = <<< EOF
<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml" dir="ltr" lang="en-US">
<head>
<title>{$title}</title>
{$meta}
<link href="../../css/headermenu.css" rel="stylesheet" type="text/css"/>
{$additional_style}
</head>
<body>
<ul id="menu">
<li>Home<span></span></li>
</ul>
{$mainbody}
{$footer}
{$javascript}
</body>
</html>
EOF;
?>
<?php
// page1.php
$title = 'some title';
$meta = '';
$additional_style = '';
$mainbody = 'your body';
$footer = '';
$javascript = '';
include_once("head.php");
echo $html;
?>
<?php
// page2.php
$title = 'some other title';
$meta = '';
$additional_style = '<link href="../../css/page2.css" rel="stylesheet" type="text/css"/>';
$mainbody = 'your body';
$footer = '';
$javascript = '';
include_once("head.php");
echo $html;
?>
It also allows for multiple levels of inheritance (for example, you could define the same footer for a couple of pages). This principle can also be used without EOF, but I think that it looks nicer this way.
The main downside is that you will get a warning if you do not set all the variables of head.php in the pages including it.
I have my footer.php with admin button in it and when i include it at the end of my page the button doesn't appear.. But if i put it before this code:
<?php if ($row["rights"]=="2"):?>
<div id='cssmenu-admin'>
<ul>
<li name='admin' class='active'><a href='administration.php'><span>Admin</span></a></li>
</ul>
</div>
<?php endif; ?>
from footer.php before while cycle it works like it should.
This my footer.php file:
<div id="footer">
<hr>Copyrighted (C) 2014 by djdanas#gmail.com<br>
<?php if ($row["rights"]=="2"):?>
<div id='cssmenu-admin'>
<ul>
<li name='admin' class='active'><a href='administration.php'><span>Admin</span></a></li>
</ul>
</div>
<?php endif; ?>
</div>
<br><hr>
And this is my page file:
<!DOCTYPE HTML>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8"/>
<title>Pagrindinis</title>
<link href="CSS/stilius.css" rel="stylesheet" type="text/css"/>
<link href="CSS/menu.css" rel="stylesheet" type="text/css"/>
</head>
<body>
<?php require("includes/validate.php");?>
<?php require("includes/stilius.php");?>
<?php
require("includes/connection_to_db.php");
$sql = "SELECT prekės.* , CONCAT(vartotojai.name) as v_name
FROM prekės
LEFT JOIN vartotojai
ON vartotojai.V_ID=prekės.V_ID
ORDER BY prekės.date
DESC LIMIT 8";
$result = mysql_query("$sql");
?>
<?php mysql_close(); ?>
<?php while ($row = mysql_fetch_assoc($result)) : ?>
<?php $image = '<td><img src="data:image/jpeg;base64,'.base64_encode($row['image']).'" name="pix" width="270" height="200"/></td>' ?>
<table class="two">
<th><?php echo $row['name'] ?></th>
<th>Prekės savininkas: <?php echo $row['v_name']?></th>
<th><input type="button" value="Mainyti"></th>
<tr>
<?php echo $image?>
<td><textarea disabled style="resize:none; background-color:white" name="about" rows="12" cols="65"><?php echo $row['specs']?></textarea><td>
</table>
<?php endwhile; ?>
<?php require("includes/footer.php");?>
</body>
</html>
EDIT:
Ok, i solved my problem by adding new variable
$rights = $row['rights'];
right after
<!DOCTYPE HTML>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8"/>
<title>Pagrindinis</title>
<link href="CSS/stilius.css" rel="stylesheet" type="text/css"/>
<link href="CSS/menu.css" rel="stylesheet" type="text/css"/>
</head>
<body>
<?php require("includes/validate.php");?>
<?php require("includes/stilius.php");?>
in my page file and changed 1 line in my footer.php file from
<?php if ($row['rights']=="2"):?>
to
<?php if ($rights="2"):?>
now it's working like a charm :)
I'll take a stab in the dark here and say that your test
if ($row["rights"]=="2")
means you are checking to see if the user logged in has the "rights" of 2?
Then when you loop through your query...
while ($row = mysql_fetch_assoc($result))
You are overwriting your $row variable. So whatever you thought was in there to begin with, isn't anymore. You should use a different variable for either your user or looping through the query.
EDIT:
It's also possible that the variable isn't in scope once you get to where you are testing it. You could try using a print_r($row) in footer.php to see what is currently inside of $row -- that should help.