Displaying SQL-data in a table - php

Question

A few months ago, I made a system where people could upload a picture and then those pictures would be displayed in a table with 4 columns.
Now I am working on a project (to practice my php, I am still learning it) and I would like to use a similar system as below but it should display data from a database.
The result I was trying to achieve is the data being displayed in 2 columns.
if ($handle = opendir('images/')) {
$bool = true;
while ($bool) {
$td = 1;
echo '<tr>';
while ($td < 4) {
$file = readdir($handle);
if ($file != '.' && $file != '..' && $file != '.DS_Store') {
echo '<td>';
if ($file) {
echo '<img src="images/'.$file.
'">';
} else {
$bool = false;
}
echo '</td>';
$td++;
}
}
echo '</tr>';
}
}
closedir($handle);

Answer 1

For anyone looking for the answer:
$query = "SELECT * FROM webshop";
if($query_run = mysql_query($query)) {
$bool = true;
echo '<table>';
while($bool) {
$td = 0;
echo '<tr>';
while($td < 2) {
if($fetch = mysql_fetch_assoc($query_run)) {
echo '<td>';
$title = $fetch['title'];
$info = $fetch['info'];
/* Commented out for now, will be implemented later
$image = $fetch['image'];
$price = $fetch['price'];
*/
echo $title;
} else {
$bool = false;
}
echo '</td>';
$td++;
}
echo '</tr>';
}
echo '</table>';
}