Can't display image PHP - php

Question

My problem is, when I upload a picture to a database, the upload is successful but the picture isn’t displayed. This is my code:
SQL file:
CREATE TABLE `images` (`id` int(11) NOT NULL auto_increment,`name` varchar(100) default NULL,`size` int(11) default NULL,`type` varchar(20) default NULL,`content` mediumblob,PRIMARY KEY (`id`)) ENGINE=MyISAM;
Index.php
<?php if (!empty($uploadOk)): ?>
<div>
<h3>Image Uploaded:</h3>
</div>
<div>
<img src="image.php?id=<?=$imageId ?>" width="150px">
<strong>Embed</strong>: <input size="25" value='<img src="image.php?id=<?=$imageId ?>">'><br>
</div>
<hr>
<? endif; ?>
<form action="index.php" method="post" enctype="multipart/form-data" >
<div>
<h3>Image Upload:</h3>
</div>
<div>
<label>Image</label>
<input type="hidden" name="MAX_FILE_SIZE" value="500000">
<input type="file" name="image" />
<input name="submit" type="submit" value="Upload"><br>
</div>
</form>
</tr>';}mysql_close();?>
image.php
<?php
// verify request id.
if (empty($_GET['id']) || !is_numeric($_GET['id'])) {
echo 'A valid image file id is required to display the image file.';
exit;
}
$imageId = $_GET['id'];
//connect to mysql database
if ($conn = mysqli_connect('localhost', 'username', 'pass', 'db_name')) {
$content = mysqli_real_escape_string($conn, $content);
$sql = "SELECT type, content FROM images where id = {$imageId}";
if ($rs = mysqli_query($conn, $sql)) {
$imageData = mysqli_fetch_array($rs, MYSQLI_ASSOC);
mysqli_free_result($rs);
} else {
echo "Error: Could not get data from mysql database. Please try again.";
}
//close mysqli connection
mysqli_close($conn);
} else {
echo "Error: Could not connect to mysql database. Please try again.";
}
if (!empty($imageData)) {
// show the image.
header("Content-type: {$imageData['type']}");
echo $imageData['content'];
} ?>
getImage.php
<?php
$id = $_GET['id'];
$link = mysql_connect("localhost", "username", "pass");
mysql_select_db("db_name");
$sql = "SELECT content FROM images WHERE id=$id";
$result = mysql_query("$sql");
$row = mysql_fetch_assoc($result);
mysql_close($link);
header("Content-type: image/jpeg");
echo $row['content'];
?>
This code worked. I think the SQL database is incorrect or has problems to display images.

Answer 1

In order to display the image, you should use AJAX from JavaScript.