Guys I have this php code to return the current time:
$time = date('m/d/Y h:i:s a', time());
I saw this time to my database using this code :
$query = "INSERT into `time` VALUES('', '$time')";
And the time row values update every transaction.
The question here is how I could return the most recent time?
I think i need an sql statement that return the time descendingly but I don't know what is it, so any help?
You can do a simple select, depending on what you want to do:
SELECT * FROM time ORDER BY <time> DESC LIMIT 1
I don't know the name of the column so I wrote <time>.
You just need to do an ORDER BY and a LIMIT 1:
SELECT `yourTimeColumn`
FROM `time`
ORDER BY `yourTimeColumn` DESC
LIMIT 1;
In addition, you could do your INSERT with the current time by just doing:
INSERT INTO `time` VALUES ('', NOW())
if your date is not in datetime format then It needs to be converted to datetime first.
Hope the following will help you.
SELECT * FROM time ORDER BY CONVERT(datetime, column) DESC LIMIT 1
column is the name of the time column.
Related
I have s MySQL Query where I want to pull data from my database but base it on the current month information
FROM lbs_trace_etrack WHERE (lbs_agent = '$slfirstname' AND DATE (lbs_date) = CURDATE()) ORDER BY lbs_date DESC LIMIT 0,50");
This string pulls out the information for the current day.
I have also tried the below string but get no results from it:
FROM lbs_trace_etrack WHERE (lbs_agent = '$slfirstname' AND MONTH(lbs_date) = (MONTH(NOW()) AND YEAR(lbs_date) = YEAR(NOW())
My table date format is as follow 2016-08-02
Or using PHP variables as so:
<?php
$start = date('Y-m-01'); // FIRST DAY OF CURRENT MONTH
$end = date("Y-m-t", strtotime(date("Y-m-d"))); // LAST DAY OF CURRENT MONTH
$sql = "SELECT * FROM lbs_trace_etrack WHERE lbs_agent = '".$slfirstname."' AND (lbs_date BETWEEN '".$start."' AND '".$end."')";
?>
I have done the following and it works
FROM lbs_trace_etrack WHERE lbs_agent = '$slfirstname' AND MONTH(lbs_date) = MONTH(CURDATE()) AND YEAR(lbs_date) = YEAR(CURDATE()) ORDER BY lbs_date ASC, lbs_time ASC
Thanks to all and Tijo for guidance
Assuming lbs_agent is a DATE field type as mentioned in comments, you could do this (note I am just showing the pertinent date part of your WHERE clause):
WHERE lbs_agent >= DATE_FORMAT(NOW() ,'%Y-%m-01')
It is important that you do not use a function call on the left (field definition) side of the WHERE comparison, as you will then not be able to leverage any index on that field. Doing this would require a full table scan with MySQL performing the function on this field for every row in the table such that the comparison can be made.
Feel free to use MySQL functions for the comparison value, as those would be calculated just once when the query is being planned. You would then be able to use an index on the field for quickly filtering the rows in the table that meet the criteria. From a query execution standpoint, this is basically that same as if your query has this WHERE clause:
WHERE lbs_agent >= '2016-08-01'
This is as compared to the examples in your question which would be executed as:
WHERE DATE(lbs_date) = '2016-08-03'
and
WHERE MONTH(lbs_date) = 8 AND YEAR(lbs_date) = 2016
Both of these would require full table scan since the values derived from the field are not able to be determined until the row is scanned.
You could try to extract the month, such as EXTRACT(MONTH from NOW())
you can use following code if it timestamp
MONTH(CURDATE())
In my database I stored date and time as a TIMESTAMP values. I want to retrive only today data from the database. This is code that I tried
$today = date("Y-m-d") . '00:00:00';
$last = date("Y-m-d") . '23:59:59';
$sql = "SELECT id, name, name2,some,some,submittimestamp,some FROM recs where submittimestamp Between $today AND $last";
$result = $conn->query($sql);
But I only get the 0 results message using this. There is more than 100 rows added today.
How can I solve this ? I cant change the database now. only way to solve this is change the PHP script
Do I need to convert PHP datetime to MYSQL timestamp ?
This is my sample database entry time-stamp value
2014-10-02 15:47:01
I only want to retrieve data for one day. time is not required !!
SELECT id, name, name2, submittimestamp
FROM recs WHERE submittimestamp > DATE_SUB(CURDATE(), INTERVAL 1 DAY);
Also you may try this, as DATE() ignores time part
SELECT id, name, name2, submittimestamp
FROM recs WHERE DATE(submittimestamp) = CURDATE();
can any one explain how i would display my table record according date, like any user of my website can see their activity of current date only...
while($data=mysql_fetch_array($rs))
{
$data["create_date"]=date("M d,y" , $data[create_date]);
i am using this but it displaying previous date result also
here is my code, i am fetching result from different tables
$SQL="select * from $tab where 1 $con ORDER BY id desc $_REQUEST[sort_mode] $con_limit";
while($data=mysql_fetch_array($rs))
{
$data["create_date"]=date("M d,y" , $data[create_date]);
gri("users","WHERE id='$data[op_id]' ","",$op_name);
gri("patient", " where id ='$data[patient_id]' order by id desc","",$patient);
$data[first_name]=$patient[first_name];
$data[last_name]=$patient[last_name];
$data[age]=$patient[age];$data[sex]=$patient[sex];
$data[mob]=$patient[mob];
$data[op_name]=$op_name[name];
$t->set_var($data);
$t->set_var(array("chk_status_$data[id]_$data[status]"=>"selected",));
$t->parse("ABlockList","AccessBlockList",true);
}
You can also use MySQL for this.
Example
select * from table_name where create_date >= NOW();
OR
SELECT * FROM table_name WHERE DATE(create_date) = CURDATE();
OR
SELECT * FROM table_name WHERE DATE(create_date) = DATE(NOW())
DATE() returns the date without time and NOW() returns the current date & time (note we’ve used the DATE() function in this query to remove the time)
Okay guys, this probably has an easy answer but has been stumping me for a few hours now.
I am using PHP/HTML to generate a table from a MySQL Table. In the MySQL table (TimeRecords) I have a StartTime and EndTime column. In my SELECT statement I am subtracting the EndTime from the StartTime and aliasing that as TotalHours. Here is my query thus far:
$query = "SELECT *,((EndTime - StartTime)/3600) AS TotalPeriodHours
FROM TimeRecords
WHERE Date
BETWEEN '{$CurrentYear}-{$CurrentMonth}-1'
AND '{$CurrentYear}-{$CurrentMonth}-31'
ORDER BY Date
";
I then loop that through an HTML table. So far so good. What I would like to do is to add up all of the TotalHours and put that into a separate DIV. Any ideas on 1) how to write the select statement and 2) where to call that code from the PHP/HTML?
Thanks in advance!
Try this
$query= "
SELECT ((EndTime - StartTime)/3600) AS Hours, otherFields, ...
FROM TimeRecords
WHERE
Date BETWEEN '{$CurrentYear} - {$CurrentMonth} - 1'
AND '{$CurrentYear}-{$CurrentMonth} - 31' ";
$records =mysql_query($query);
$sum= 0;
while($row=mysql_fetch_array($records))
{
echo"$row['otherFields']";
echo"$row['Hours']";
$sum+=$row['Hours'];
}
echo" Total Hours : $sum ";
Just use a single query with a Sum(). You could also manually calculate it if you're already displaying all rows. (If paginating or using LIMIT, you'll need a separate query like below.)
$query = "
SELECT Sum(((EndTime - StartTime)/3600)) AS SumTotalPeriodHours
FROM TimeRecords
WHERE
Date BETWEEN '{$CurrentYear} - {$CurrentMonth} - 1'
AND '{$CurrentYear}-{$CurrentMonth} - 31'
";
You can do this in the same query if you have a unique id using GROUP BY WITH ROLLUP
$query = "
SELECT unique_id,SUM((EndTime - StartTime)/3600) AS TotalPeriodHours
FROM TimeRecords
WHERE Date BETWEEN '{$CurrentYear}-{$CurrentMonth}-1'
AND '{$CurrentYear}-{$CurrentMonth}-31'
GROUP BY unique_id WITH ROLLUP
ORDER BY Date
";
In this instance the last result from your query with contain NULL and the overall total. If you don't have a unique ID you will need to do it in PHP as per Naveen's answer.
A few comments on your code:
Using SELECT * is not considered good practice. SELECT the columns you need.
Not all months have a day 31 so this may produce unexpected results. If you're using PHP5.3+, you can use
$date = new DateTime();
$endDate = $date->format( 'Y-m-t' );
The "t" flag here gets the last day of that month. See PHP docs for more on DateTime.
In my code, I am trying to find items in an activities table that are within the last day. This query is not returning any results, are there any problems with it? Is there a better query?
$curday = time() - (24*3600);
$query = "SELECT * FROM activities WHERE userid = '$userid' AND 'timestamp' > '$curday'";
There are two choices here, you can get and format the date through PHP or use SQL language to do it. I prefer to do it within the SQL, it also allows me to use the same query in a MySQL client.
This question is essentially the same thing: MySQL SELECT last few days?
This would be the new query:
$query = "SELECT * FROM activities WHERE userid = '$userid' AND 'timestamp' > DATE_ADD(CURDATE(), INTERVAL -1 DAY)";
you can try with unix function 'mktime' to get value of yesterday ..
as
$curday = mktime(0,0,0,date("m"),date("d")-1,date("Y"));
for reference
if your database will mysql only then you can extract yesterday in sql itself..
SELECT * FROM activities
WHERE userid = '$userid'
AND timestamp > DATE_SUB(CONCAT(CURDATE(), ' 00:00:00'), INTERVAL 1 DAY)
one more thing if timestamp is your column name don't put this column inside single quote ..
What you can use is DATE_SUB. This can be used as follows
SELECT * FROM activities
WHERE userid = '$userid'
AND timestamp > date_sub(current_date, interval 1 day)
This way you don't need to work with current date in PHP
in Informix it would be (TODAY - 1) if the column is type DATE