All the examples and documentation didnt really help or even offer an example for this so I m gonna ask here:
$db = new SQLite3(database.db);
$stmt = $db->prepare('SELECT COUNT(uid) FROM kunden WHERE date = :date');
$stmt->bindValue(':ldate',$today,SQLITE3_TEXT);
$result = $stmt->execute;
How can I get the result from that prepared statement? I know execute is not supposed to return a result. I tried using query and query_single but that didnt work. var_dump($result->fetchArray()); also didnt work. Help is much appreciated.
SQLite3Stmt::execute() is a function, and needs to be called as such:
$db = new SQLite3('database.db');
$stmt = $db->prepare('SELECT COUNT(uid) FROM kunden WHERE date = :date');
$stmt->bindValue(':ldate',$today,SQLITE3_TEXT);
$result = $stmt->execute();
You can then fetch the result like this:
$array = $result->fetchArray();
echo $array['COUNT(uid)'];
Related
When I run the code below, it returns nothing. When I explicitly type a string in the place of the '?', it will return the expected result but using the prepared version has not worked for me thus far. I do not believe there is any kind of versioning issue as using prepared statements for INSERT queries has worked for me in the past. What might be the problem here with the prepared statement?
$pdo = new PDO("mysql:host=localhost;dbname=database", $user, $pass);
$sql = "SELECT * FROM table WHERE column LIKE '%?%';";
$stmt = $pdo->prepare($sql);
$stmt->execute(array($_GET['searchterm']));
$results = $stmt->fetchAll();
print_r($results);
You are preparing the value so it isn't behaving as if you just put the string inside of the query.
When preparing a string you don't need to add " or ', that is done for you. You need to add the %'s into the value that you are escaping.
$pdo = new PDO("mysql:host=localhost;dbname=database", $user, $pass);
$sql = "SELECT * FROM table WHERE column LIKE ?;";
$stmt = $pdo->prepare($sql);
$stmt->execute(array("%{$_GET['searchterm']}%"));
$results = $stmt->fetchAll();
print_r($results);
I want to change MySQL to PDO:
$mapa = mysql_fetch_array(mysql_query("select * from mapa where id = ".$postac['mapa']." limit 1"));
$mapa_d = mysql_query("select * from mapa_d where mapa = ".$mapa['id']." ");
PHP:
$_SESSION['postac'] = $_POST['postac'];
try like this so far:
$stmt = $pdo->prepare("SELECT * FROM mapa WHERE id=:mapa");
$stmt->bindValue(':mapa', $postac, PDO::PARAM_STR);
$stmt->EXECUTE();
$postac = $stmt->fetchAll(PDO::FETCH_ASSOC);
mysql update:
mysql_query("update postac set logged = 1 where id = ".$_SESSION['postac']." limit 1");
PDO:
$stmt = $pdo->prepare("update postac set logged = 1 where id:postac");
$stmt->bindValue(':postac', $_SESSION, PDO::PARAM_STR);
$stmt->EXECUTE();
$_SESSION = $stmt->fetchAll(PDO::FETCH_ASSOC);
Does not work.
Pre-Answer Note:
I assume you have already set up a PDO connection construct ($pdo) before trying to run your PDO queries.
$mapa = mysql_fetch_array(
mysql_query("select * from mapa WHERE id = ".$postac['mapa']." limit 1"));
$mapa_d = mysql_query("select * from mapa_d WHERE mapa = ".$mapa['id']." ");
PHP:
$_SESSION['postac'] = $_POST['postac'];
try like this so far:
$stmt = $pdo->prepare("SELECT * FROM mapa WHERE id=:mapa");
$stmt->bindValue(':mapa', $postac, PDO::PARAM_STR);
$stmt->EXECUTE();
$postac = $stmt->fetchAll(PDO::FETCH_ASSOC);
PART 1:
Be Consistent
Your original statement uses a value $postac['mapa'] as an id reference in the MySQL_ query, but then your PDO statement you are passing the whole array as a value into the PDO query.
First, MySQL: id ==> $postac['mapa']
Second, PDO: id ==> $postac
So this is causing an immediate issue as you're passing a whole array in to PDO which is somehow expected to extract one value from this array. This array is being classed as a string with your PDO::PARAM_STR declaration so this is preventing the query from using this value, as it doesn't fit what it's told to expect.
Therefore this returns a NULL query.
So to fix it,
$stmt = $pdo->prepare("SELECT * FROM mapa WHERE id=:mapa");
$stmt->bindValue(':mapa', $postac['mapa'], PDO::PARAM_STR);
$stmt->execute();
$postac = $stmt->fetchAll(PDO::FETCH_ASSOC);
Part 2:
Syntax
$stmt = $pdo->prepare("update postac set logged = 1 where id:postac");
$stmt->bindValue(':postac', $_SESSION, PDO::PARAM_STR);
$stmt->EXECUTE();
$_SESSION = $stmt->fetchAll(PDO::FETCH_ASSOC);
As above, you're passing the whole $_SESSION array as a PARAM_STR value, so it's returning VOID /NULL. You also have a syntax fault that you're using WHERE id:postac, but you really mean WHERE id = :postac be careful of missing out syntax such as = !!.
PART 3:
Error Checking
It is well worth exploring and learning how to get useful error feedback on PHP PDO, as it will save you posting to StackOverfow X times a day (hopefully!)!
There is a good answer here about how to setup PDO to output errors. It is also well worth browsing the PHP Manual for PDO error checking details.
I'm having a problem running prepared queries on a MSSQL database using PDO. I can connect to the database and run SELECT queries with no parameters, but now I'm trying to run a simple SELECT query with one parameter, :user. However, the code does not return any values, despite the fact that there definitely is a database row with that value in. Here's the code I'm using:
$db = new PDO('dblib:host='.$dbHost.';dbname='.$dbName.';charset=utf8mb4',$dbUser, $dbPass);
$stmt = $db->prepare('SELECT * FROM customer WHERE email_address = :user ');
$stmt->bindValue(":user", $_SESSION["username"], PDO::PARAM_STR);
$result = $stmt->fetchAll(PDO::FETCH_ASSOC);
var_dump($result);
I receive no output from the var_dump. I know that in the database there is a correct row, so I tried:
$stmt = $db->prepare("SELECT * FROM customer WHERE email_address = 'the#email.com'");
$result = $stmt->fetchAll(PDO::FETCH_ASSOC);
var_dump($result);
And yet still no value was returned. Am I doing something wrong with PDO? If I type this exact query into the query bar it runs.
you forgot to execute your query.
right after the paramter binding, put this code:
$stmt->execute();
Ok, I'm an idiot. Forgot to execute the query. Amended code for people in the same predicament:
$db = new PDO('dblib:host='.$dbHost.';dbname='.$dbName.';charset=utf8mb4',$dbUser, $dbPass);
$stmt = $db->prepare('SELECT * FROM customer WHERE email_address = :user ');
$stmt->bindValue(":user", $_SESSION["username"], PDO::PARAM_STR);
$stmt->execute();
$result = $stmt->fetchAll(PDO::FETCH_ASSOC);
var_dump($result);
I am totally new to this PHP.
I am just practicing Prepared statements.
I know there few questions which is related to mine.
But nothing Helped me.
This is my php code Which returns always num_rows equal to Zero.
But there is a data in my table
if (isset($_POST['submit'])) {
$my_id = 49;
$content = $_POST['cont'];
$content_date = date('d-m-y');
$check = "SELECT * FROM post WHERE user_id = ?";
$stmt = $con->prepare($check);
$stmt->bind_param("i",$my_id);
$stmt->execute();
$stmt->fetch();
$numberofrows = $stmt->num_rows;
$stmt->close();
echo '<h1>'.$numberofrows.'</h1>';
}
Use () look like this... $numberofrows = $stmt->num_rows(); and try.
Guys Thanx For your Ans
Finally My friend helped me to solve this.
We have to store the result before we calling num_rows
$stmt->store_result();
It works fine now
I have the following PDO statement:
$stmt = $db->prepare("SELECT MAX(RID) FROM TEMP_ROUTE");
$stmt->execute();
$rid = $stmt->fetch(PDO::FETCH_ASSOC);
$rid = (int) $rid["MAX(RID)"];
Is there any way so that I don't have to do the last statement there. In other words I want it to fetch $rid["MAX(RID)"] when doing the fetch.
Have a look at http://www.php.net/manual/en/pdostatement.bindcolumn.php and try using PDO::FETCH_BOUND instead perhaps? This won't make it shorter though. Or try something like this, from http://www.php.net/manual/en/pdostatement.fetch.php:
$stmt = $db->prepare("SELEXT MAX(RID) AS max FROM TEMP_ROUTE");
$stmt->execute();
$rid = $stmt->fetch(PDO::FETCH_OBJ)->MAX;