Count occurrence of words and only 1 in the same phrases - php

Question

I have a problem where I need to count the number of times a word occurs in a given array.
I want the code to increase the count of a word ('instagrammm') by 1 if the word is in the same phrases.
Here is my code:
$output = array();
$buzzes = ['instagramm some text instagramm', 'instagramm some text' , 'instagramm some text' , 'instagramm some text'];
foreach ($buzzes as $buzz) {
$flag = 0;
$words = explode(" ",$buzz);
foreach ($words as $word)
{
$word = mb_convert_case($word, MB_CASE_LOWER, "UTF-8");
$word = preg_replace('/^[^A-Za-z0-9\-]|[^A-Za-z0-9\-]$/', '', $word);
if(strlen($word) > 2){
if (array_key_exists($word, $output)){
$output[$word]++;
}else{
$output[$word] = 1;
}
}
}
}
Here is the expected result:
Array
(
[instagramm] => 4
[some] => 4
[text] => 4
)

Answer 1

Try this one. It will be faster with fewer comparisons and allocations:
foreach ($buzzes as $buzz) {
$words = array_unique(explode(' ',$buzz));
foreach ($words as $word) {
$word = mb_convert_case($word, MB_CASE_LOWER, "UTF-8");
$word = preg_replace('/^[^A-Za-z0-9\-]|[^A-Za-z0-9\-]$/', '', $word);
if(strlen($word) > 2){
if (array_key_exists($word, $output)){
$output[$word]++;
}else{
$output[$word] = 1;
}
}
}
}
take a look:
// My version
Took: 0.178099
Array
(
[instagramm] => 4
[some] => 4
[text] => 4
)
// accepted version
Took: 25.308847
Array
(
[instagramm] => 4
[some] => 4
[text] => 4
)

Answer 2

seems you are suppose to have another condition in your piece of code.
just modified your code with a condition.
$output = array();
$buzzes = array('instagramm some text instagramm', 'instagramm some text' , 'instagramm some text' , 'instagramm some text');
foreach ($buzzes as $buzz) {
$flag = 0;
$words = explode(" ",$buzz);
$wordArr = array();
foreach ($words as $word)
{
$word = mb_convert_case($word, MB_CASE_LOWER, "UTF-8");
$word = preg_replace('/^[^A-Za-z0-9\-]|[^A-Za-z0-9\-]$/', '', $word);
if(!in_array(strtolower($word),$wordArr)) {
if(strlen($word) > 2){
if (array_key_exists($word, $output)){
$output[$word]++;
}else{
$output[$word] = 1;
}
}
$wordArr[] = strtolower($word);
}
}
}
print_r($output);

Answer 3

Here's a simplified version of the code:
$output = array();
$buzzes = ['instagramm some text instagramm', 'instagramm some text' , 'instagramm some text' , 'instagramm some text'];
foreach( explode( ' ', implode( ' ', $buzzes ) ) as $word )
{
$word = strtolower( trim( $word ) );
if( !empty( $word ) )
{
if( isset( $output[ $word ] ) )
{
$output[ $word ]++;
}
else{ $output[ $word ] = 1; }
}
}
Output:
Array
(
[instagramm] => 5
[some] => 4
[text] => 4
)