I am trying to configure Yii2 url manager in a manner that if a controller name is skipped in url it should call the default controller for action. I have managed to achieve this without action parameter. But got stuck when using parameters in action name.
Here is my route config:
return [
'catalog/category/<alias:[\w-]+>' => 'catalog/default/category',
'catalog/<action:\w+>' => 'catalog/default/<action>',
];
Controller File:
namespace app\modules\catalog\controllers;
use yii\base\Controller;
use app\modules\catalog\models\Categories;
class DefaultController extends Controller
{
public function actionShopbydepartment()
{
$data['categories'] = Categories::findParentSubHierarchy();
return $this->renderPartial('shopbydepartment', $data);
}
public function actionCategory($alias = null)
{
die(var_dump($alias));
$data['category'] = Categories::findCategoryBySlug($alias);
return $this->render('category', $data);
}
}
when I access the following url it loads perfectly.
http://domain.com/index.php/catalog/shopbydepartment
But when i access the below url it called the right function but did not pass the $alias value:
http://domain.com/index.php/catalog/category/appliances
UPDATE:
I have used the following approach for module wise url rules declaration:
https://stackoverflow.com/a/27959286/1232366
Here is what i have in the main config file:
'rules' => [
[
'pattern' => 'admin/<controller:\w+>/<action:[\w-]+>/<id:\d+>',
'route' => 'admin/<controller>/<action>'
],
[
'pattern' => 'admin/<module:\w+>/<controller:\w+>/<action:[\w-]+>/<id:\d+>',
'route' => 'admin/<module>/<controller>/<action>'
],
],
the admin is working fine and this is my first module so rest of the rules are mentioned already
Well just to help other fellows I have retrieve the value of $alias using the following approach:
$alias = \Yii::$app->request->get('alias');
But definitely this is not an accurate answer of the question. I still didn't know what i am doing wrong that i didn't get the value using the approach mentioned in question.
It wirk!
[
'name' => 'lang_country_seller_catalog',
'pattern' => '<lang:\w+>-<country:\w+>/seller/catalog/<module>/<controller>/<action>',
'route' => 'seller/catalog/<module>/<controller>/<action>',
],
[
'name' => 'lang_country_seller_catalog_attributes',
'pattern' => '<lang:\w+>-<country:\w+>/seller/catalog/attributes/<module>',
'route' => 'seller/catalog/attributes/<module>',
],
Related
I have the ability for users to define URLs for some of their items so, for example:
http://x.com/mynewobject
mynewobject would be defined by the user in a form and I need to be able to say in the UrlManager to math that, but also match everything else.
Problem is the default rules in the UrlManager will try and catch the mynewobject controller and throw a 404 when it cannot.
What is the way to make a UrlManager catch user defined URLs?
The best way I have found of doing this, without manually declaring your URLs, is to actually take a closer look at the Yii 2 documentation.
It actually shows a good example here of user generated URLs http://www.yiiframework.com/doc-2.0/guide-runtime-routing.html#creating-rules which I used to complete my task.
The configuration I used was:
'urlManagerFrontend' => [
'class' => 'yii\web\UrlManager',
'enablePrettyUrl' => true,
'showScriptName' => false,
'cache' => null,
'baseUrl' => '/',
'rules' => [
[
'class' => 'common\components\ObjectUrlRule',
'pattern' => '<slug:.*>',
'route' => 'site/index'
],
'<controller:[\w-]+>/<id:\d+>'=>'<controller>/view',
'<controller:[\w-]+>/<action:[\w-]+>/<id:\d+>'=>'<controller>/<action>',
'<controller:[\w-]+>/<action:[\w-]+>'=>'<controller>/<action>',
// your rules go here
]
],
And a rule class of:
<?php
namespace common\components;
use Yii;
use yii\web\UrlRule;
use common\models\ObjectUrl;
class ObjectUrlRule extends UrlRule
{
public function parseRequest($manager, $request)
{
$pathInfo = trim($request->getPathInfo());
if(!$pathInfo){
return false;
}
$controller = Yii::$app->createController($pathInfo);
if($controller){
return false;
}
$objectUrl = ObjectUrl::find()->where(['url' => $pathInfo])->one();
if(!$objectUrl){
return false;
}
return $objectUrl->getUrl($pathInfo);
}
}
Where ObjectUrl is the model (table) which contains the map of user generated URLs.
The good thing about this class, as well, is that it will not run the database call unless the controller does not exist and there is a pathinfo.
I have the following code where I want to find a model using a field called link instead of id. However, it doesn't seem to produce any results. Where could I be getting it wrong? It returns 404
public function actionView($link)
{
$model = News::find()->where(['link'=>$link])->all();
return $this->render('view', [
'model' => $model,
]);
}
NB: in the search model, I have tried adding this:
$query->andFilterWhere([
'id' => $this->id,
'link'=>$this->link,
'category' => $this->category,
'date' => $this->date,
'userid' => $this->userid,
'featured' => $this->featured,
]);
If you want a single model you need one() and not all()
public function actionView($link)
{
$model = News::find()->where(['link'=>$link])->one();
return $this->render('view', [
'model' => $model,
]);
}
With one() method you retrive just a model and in your $model you have the data you need ..
If you sue all() lie you did you retrive a collection of models and for accessing a single model you must set a proper index eg:
$my_model = $model[0];
In UrlManager config you propably have:
'<controller>/<action>/<id:\d+>' => '<controller>/<action>',
It means default rewrite rules use id as param and it has to be digit, so you can't use controller/view/link. Just to be sure, change action name from actionView to actionTest and then call URL controller/test?link=linklink.
Other solution is to use URL like this: controller/view?link=linklink
The problem is in your url
case 1)
http://localhost/projectName/backend/web/controllerName/actionName/username/rushil
Gives output : Not Found (#404)
case 2)
http://localhost/projectName/backend/web/controllerName/actionName/rushil
Gives output : Not Found (#404)
case 3)
http://localhost/projectName/backend/web/controllerName/actionName?username=rushil
this will work.
Solution : check your url and pass link parameter in url as shown in case 3
404 means your action was not found by url manager. link parameter must be in the url (http://yourapp/controller/view?link=something) because you definded it as actionView($link)
Requesting http://yourapp/controller/view will give you 404 error.
For anyone who may encounter such an error, the problem is after using pretty urls, you need to add rules to map the url format.
C:\xampp\htdocs\your_project\frontend\config\main.php under urlManager add the rules like so:
'urlManager' => [
'class' => 'yii\web\UrlManager',
// Disable index.php
'showScriptName' => false,
// Disable r= routes
'enablePrettyUrl' => true,
'rules' => array(
'<controller:\w+>/<id:\d+>' => 'news/view',
'<controller:\w+>/<link>' => 'news/latestnews', // This is required for $link parameter
'<controller:\w+>/<action:\w+>/<id:\d+>' => '<controller>/<action>',
'<controller:\w+>/<action:\w+>/<link>' => 'news/latestnews',
'<controller:\w+>/<action:\w+>' => '<controller>/<action>',
),
],
],
Working with Yii 2.0.4, I'm trying to use urlManager Rule to preload an object based on a given ID in the URL.
config/web.php
'components' => [
'urlManager' => [
[
'pattern' => 'view/<id:\d+>',
'route' => 'site/view',
'defaults' => ['client' => Client::findOne($id)],
],
[
'pattern' => 'update/<id:\d+>',
'route' => 'site/update',
'defaults' => ['client' => Client::findOne($id)],
],
]
]
If this works, it will not be necessary to manually find and object each time, for some CRUD actions:
class SiteController extends Controller {
public function actionView() {
// Using the $client from the urlManager Rule
// Instead of using $client = Client::findOne($id);
return $this->render('view', ['client' => $client]);
}
public function actionUpdate() {
// Using $client from urlManager Rule
// Instead of using $client = Client::findOne($id);
if ($client->load(Yii::$app->request->post()) && $client->save()) {
return $this->redirect(['view', 'id' => $client->id]);
} else {
return $this->render('edit', ['client' => $client]);
}
}
}
NOTE: The above snippets are not working. They're the idea of what I want to get
Is it possible? Is there any way to achieve this?
If you look closer: nothing actually changes. You still call Client::findOne($id); but now doing it in an unexpected and inappropriate place, and if you look at the comment about default parameter it says:
array the default GET parameters (name => value) that this rule provides.
When this rule is used to parse the incoming request, the values declared in this property will be injected into $_GET.
default parameter is needed when you want to specify some $_GET parameters for your rule. E.g.
[
'pattern' => '/',
'route' => 'article/view',
'defaults' => ['id' => 1],
]
Here we specify article with id = 1 as default article when you open main page of site e.g. http://example.com/ will be handled as http://example.com/article/view?id=1
I can suggest to you add property clientModel in to your controller and then in beforeAction() method check if its update or view action then set
$this->clientModel = Client::findOne($id);
and in your action:
return $this->render('view', ['client' => $this->clientModel]);
I have a problem with Yii2's urlManager. I have an action with url category/index, where I pass ?par=test as param.
I want to create an alias for my url so that when par is not specified the url will be /test, but when it is specified the url should be /test/some-value. Here is my config for now:
'rules' => [
[
'pattern' => 'test',
'route' => 'category/index',
],
'<subcats: (val|some-value)>' => 'test/<subcats>',
If you need url like category/index/test/some-value. Use that
'category/index/test/<val:\w+>' => 'category/index'
In controller in method index use that:
public function actionIndex($val){
Yii2 automatically provide parameter $val in action.
Can we rename routing resource path names in Laravel like in Ruby on Rails?
Current
/users/create -> UsersController#create
/users/3/edit -> UsersController#edit
..
I want like this;
/users/yeni -> UsersController#create
/users/3/duzenle -> UsersController#edit
I want to do this for localization.
Example from Ruby on Rails;
scope(path_names: { new: "ekle" }) do
resources :users
end
I know this is an old question. I'm just posting this answer for historical purposes:
Laravel now has the possibility to localize the resources. https://laravel.com/docs/5.5/controllers#restful-localizing-resource-uris
Localizing Resource URIs By default, Route::resource will create
resource URIs using English verbs. If you need to localize the create
and edit action verbs, you may use the Route::resourceVerbs method.
This may be done in the boot method of your AppServiceProvider:
use Illuminate\Support\Facades\Route;
/**
* Bootstrap any application services.
*
* #return void
*/
public function boot() {
Route::resourceVerbs([
'create' => 'crear',
'edit' => 'editar',
]); }
Once the verbs have been customized, a resource route registration such as Route::resource('fotos', 'PhotoController') will
produce the following URIs:
/fotos/crear
/fotos/{foto}/editar
It ain't pretty, but you could define multiple routes that use the same controller function. For example:
Route::get("user/create", "UsersController#create");
Route::get("user/yeni", "UsersController#create");
The only (glaringly obvious downside) being that you're routes will get quite cluttered quite quickly. There is a setting in app/config/app.php where you can set/change your locale, and it could be possible to use that in conjunction with a filter to use the routes and then group those routes based on the current local/language, but that would require more research.
As far as I know, there isn't a way to rename resource routes on the fly, but if you get creative you can figure something out. Best of luck!
You can't change the resource url's.
For this you will need to define/create each route according your needs
Route::get("user/yeni", "UsersController#create");
and if you need more than one languages you can use the trans helper function, which is an alias for the Lang::get method
Route::get('user/'.trans('routes.create'), 'UsersController#create');
I just had the same issue. And managed to recreate some sort of custom resource route method. It probably could be a lot better, but for now it works like a charm.
namespace App\Helpers;
use Illuminate\Support\Facades\App;
class RouteHelper
{
public static function NamedResourceRoute($route, $controller, $named, $except = array())
{
$routes = RouteHelper::GetDefaultResourceRoutes($route);
foreach($routes as $method => $options) {
RouteHelper::GetRoute($route, $controller, $method, $options['type'], $options['name'], $named);
}
}
public static function GetRoute($route, $controller, $method, $type, $name, $named) {
App::make('router')->$type($named.'/'.$name, ['as' => $route.'.'.$method, 'uses' => $controller.'#'.$method]);
}
public static function GetDefaultResourceRoutes($route) {
return [
'store' => [
'type' => 'post',
'name' => ''
],
'index' => [
'type' => 'get',
'name' => ''
],
'create' => [
'type' => 'get',
'name' => trans('routes.create')
],
'update' => [
'type' => 'put',
'name' => '{'.$route.'}'
],
'show' => [
'type' => 'get',
'name' => '{'.$route.'}'
],
'destroy' => [
'type' => 'delete',
'name' => '{'.$route.'}'
],
'edit' => [
'type' => 'get',
'name' => '{'.$route.'}/'.trans('routes.edit')
]
];
}
}
Use it like this in the routes.php:
\App\Helpers\RouteHelper::NamedResourceRoute('recipes', 'RecipeController', 'recepten');
Where the first parameter is for the named route, second the controller and third the route itself.
And something like this to the view/lang/{language}/route.php file:
'edit' => 'wijzig',
'create' => 'nieuw'
This results in something like this:
This is not possible in Laravel as they use code by convention over configuration. A resources uses the RESTfull implementation
Therefore you have to stick to the convention of
GET /news/create
POST /news
GET /news/1
GET /news/1/edit
...