Hi so I have a JS file with a function for my button, this button get value from different checkbox in a table. But now i want to get these value on another page (for invoice treatement).
Here is my Script :
$("#boutonfacturer").click(function () {
var checked = $('input[name="id_commande[]"]:checked');
var tab = [];
var jsonobj = {};
checked.each(function () {
var value = $(this).val();
jsonobj.value = value;
tab.push(jsonobj);
});
var data= { recup : tab };
console.log(data);
$.ajax({
type: 'POST',
url: 'genererfacture-facture_groupee.html',
data: data,
success: function (msg) {
if (msg.error === 'OK') {
console.log('SUCCESS');
}
else {
console.log('ERROR' + msg.error);
}
}
}).done(function(msg) {
console.log( "Data Saved: " + msg );
});
});
i use an MVC architecture so there is my controller :
public function facture_groupee() {
$_POST['recup'];
var_dump($_POST['recup']);
console.log(recup);
$this->getBody()->setTitre("Facture de votre commande");
$this->getBody()->setContenu(Container::loader());
$this->getBody()->setContenu(GenererFacture::facture_groupee());
and for now my view is useless to show.
I have probably make mistake in my code.
Thank you.
Nevermind after thinking, I have used my ajax.php page which get my another page thanks to a window.location :
my JS :
$("#boutonfacturer").click(function () {
var checked = $('input[name="id_commande[]"]:checked');
var tab = [];
checked.each(function () {
var value = $(this).val();
tab.push(value);
});
var data = {recup: tab};
console.log(data);
$.ajax({
type: 'POST',
url: 'ajax.php?action=facture_groupee',
data: data,
success: function (idfac) {
console.log("Data Saved: " + idfac);
var id_fac = idfac;
window.location = "ajax.php?action=facture_groupee=" + id_fac;
}
});
});
my php :
public function facture_groupee() {
foreach ($_POST['recup'] as $p){
echo $p; }
Related
My PHP is returning this data to Ajax...
echo $data6['favorite_properties_id'];
I am updating it in one function and trying to send it to another using following html and jquery .
<img class="<?php if($favorite == 1){ echo 'alreadyfavorite';} else { echo 'addtofavorite';} ?>" pid="<?php echo $propertyid; ?>" fpid="<?php while($data5=$select5->fetch()){echo $data5['favorite_properties_id'];} ?>" src="../images/system/addtofavorite.png">
This is my jquery...
$('.alreadyfavorite1').click(function() {
event.preventDefault();
var del_id = $(this).attr('fpid');
var $ele = $(this).parent().parent().parent();
var reference = this;
$.ajax(
{
type: 'POST',
url: '../controllers/favoritesaddremove.php',
data:
{
del_id: del_id
},
success: function(data)
{
$ele.fadeOut(1000).delay(1000).remove(1000);
}
});
});
// On Search Property Results Page - Add to Favorite Button (Heart)
$('.addtofavorite').click(function() {
event.preventDefault();
var ins_id = $(this).attr('pid');
var del_id = $(this).attr('fpid');
var reference = this;
/* alert(del_id);
alert(ins_id); */
$.ajax(
{
type: 'POST',
url: '../controllers/favoritesaddremove.php',
data:
{
ins_id: ins_id
},
success: function(data)
{
$(reference).toggleClass("addtofavorite alreadyfavorite");
$('.alreadyfavorite').attr('fpid', data);
}
});
});
The second function is not working, but if i refresh the page then the second function is working...
First assign some id to the image and change fpid to data-fpid(data-attribute):
<img class="asdasd" id="aid" data-fpid="something">
In your success try:
success: function(data)
{
$('#aid').data('fpid', data); //this should update the value in data-fpid
}
Hello overflowers!
I can't seem to manage to send my ajax data over to my php page correctly, it has worked perfectly fine before but now it is not working.
I'm getting the correct data via console.log but on my php page i'm getting Undefined index error.
Jquery
var task_takers_pre = [];
var task_takers = [];
var i = 1;
$(".new-task-takers ul.select_takers li").on('click', function(){
$(this).each(function(){
$(this).toggleClass("active");
if($(this).find('.fa').length > 0){
$(this).find('.fa').remove();
i -= 1;
var removeItem = $(this).data("id");
task_takers_pre.remove(removeItem);
console.log(task_takers_pre);
}else{
$('<i class="fa fa-check" aria-hidden="true"></i>').insertBefore($(this).find("div"));
i += 1;
task_takers_pre[i] = $(this).data("id");
console.log(task_takers_pre);
}
$.each(task_takers_pre, function (index, value) {
if ($.inArray(value, task_takers) == -1) {
task_takers.push(index, value);
}
});
});
});
$("#new-task").on('submit', function(){
console.log(task_takers_pre);
$.ajax({
type: 'POST',
url: '',
cache: false,
data: {task_takers_pre : task_takers_pre },
success: function(data) {
//console.log(data)
}
});
});
PHP
if(isset($_POST['task_submit'])){
$task_takers = $_POST['task_takers_pre'][0];
var_dump($task_takers);
}
EDIT
jQuery
var task_takers_pre = [];
var task_takers = [];
var i = 1;
$(".new-task-takers ul.select_takers li").on('click', function(){
$(this).each(function(){
$(this).toggleClass("active");
if($(this).find('.fa').length > 0){
$(this).find('.fa').remove();
i -= 1;
var removeItem = $(this).data("id");
task_takers_pre.remove(removeItem);
console.log(task_takers_pre);
}else{
$('<i class="fa fa-check" aria-hidden="true"></i>').insertBefore($(this).find("div"));
i += 1;
task_takers_pre[i] = $(this).data("id");
console.log(task_takers_pre);
}
$.each(task_takers_pre, function (index, value) {
if ($.inArray(value, task_takers) == -1) {
task_takers.push(index, value);
}
});
});
});
$(".assign").on('click', function(){
console.log(task_takers_pre);
$.ajax({
type: 'POST',
url: './core/includes/new_task.php',
cache: false,
data: {task_takers_pre : task_takers_pre},
success: function(data) {
//console.log(data)
}
});
$.ajax({
type: 'POST',
url: '',
cache: false,
data: {'task_takers_pre' : task_takers_pre},
success: function(data) {
//console.log(data)
}
});
});
PHP
if(isset($_POST['task_takers_pre'][0])){
$task_takers = $_POST['task_takers_pre'][0]; // Just for testing
var_dump($task_takers); // Just for testing
}
if(isset($_POST['task_takers_pre'])){
$task_takers2 = $_POST['task_takers_pre']; // Just for testing
var_dump($task_takers2); // Just for testing
}
What you are attempting to do is use the same PHP code to handle the Button Press from the Form AND the AJAX Call. Don't!
(note: This answer is Only based upon the code that has been provided and what is trying to achieved with this code.)
So your current PHP is, which I am guessing is what you call when you click the submit button... In that case $_POST['task_takers_pre'] will not exist as you are generating that from the JS and sending it in the AJAX Call.
Write a separate AJAX Call.
You need to create a separate file to handle your AJAX calls and have it perform what duties it needs to perform.
// This is just for testing my AJAX Call
public function ajax_post(){
if(isset($_POST['task_takers_pre'])){
$task_takers = $_POST['task_takers_pre'][0]; // Just for testing
var_dump($task_takers); // Just for testing
die();
}
else {
// Illegal access/entry do something...
echo 'Error - I had better check what I am posting.';
die();
}
}
If you juse want to send some data in the AJAX Call when you click the submit button,you could return false to prevent form submission in the submit event.
$("#new-task").on("submit", function(){
$.ajax({
type: "POST",
url: "",
cache: false,
data: {task_submit:1, task_takers_pre: task_takers_pre},
success: function(data){
console.log(data);
}
});
return false;
});
here is my ajax request :
$(".colorme").on("click", function () {
var c = $(this);
var b = "id=" + c.attr("id");
$.ajax({
type: "POST",
url: "../../colorme",
data: b,
success: function (a) {
$.when(c.fadeOut(300).promise()).done(function () {
if (c.hasClass("btn")) {
c.removeClass("btn-default").addClass("btn-success").text(a).fadeIn()
} else {
c.replaceWith('<span class="notice_mid_link">' + a + "</span>")
}
})
}});
return false
})
so here is what I receive as a response :
{"f0d8c0":0.3269616519174,"d8d8d8":0.22377581120944,"181818":0.10926253687316,"d8a890":0.091268436578171,"303030":0.054454277286136}
I would like to be able display each one of those values as a pair.Right now it returns :[object OBJECT]
Use,
data = $.parseJSON(JSON.stringify(a));
Try this.
var obj = jQuery.parseJSON(a);
alert( obj.f0d8c0);
alert( obj.d8d8d8);
You can assign your response value in var a =$.parseJSON(RESPONSE VALUE)
For more Details Read this LINK
$.ajax({type: "POST", url: "../../colorme", data: b, success: function (a) {
resp = jQuery.parseJSON(a);
alert(resp.f0d8c0);
alert(resp.d8d8d8); //maybe you need to use a better way to name the data?
$.when(c.fadeOut(300).promise()).done(function () {
if (c.hasClass("btn")) {
c.removeClass("btn-default").addClass("btn-success").text(a).fadeIn()
} else {
c.replaceWith('<span class="notice_mid_link">' + a + "</span>")
}
})
}});
I am trying to make an ajax call on click on anchor tag dynmically generated from $.each loop for a JSON response.
For Information : #records is my table and .update is the class of anchor tag in that table.
Please be informed that the table is generated dynamically.
Now the problem is that my ajax call is returning nothing even i have checked it error: but no response received. I have tried alerting my var data just before the ajax call and it worked.So the problem starts from the ajax call. Moreover, my server side code is running fine.
// Update existing customers
$("#records").on('click', ".update", function() {
var data = '?'+ $(this).attr('id');
$.ajax({
type: "GET",
url: "viewcustomers.php",
data: data,
success: function(response) {
console.log(response);
}
});
});
Thanks in advance.
For reference below is the code that generates the table.
// Function to make datagrid
function getRecords() {
$.getJSON("viewcustomers.php", function(data) {
var items = [];
var xTd = '';
var xTr = '';
$.each(data, function(key, val) {
var c = 0;
var id = 0;
$.each(val, function(key1, val1) {
if (c == 0)
{
id = val1;
}
c++;
xTd += '<td>' + val1 + '</td>';
});
xTd += '<td>Edit</td>';
xTd += '<td>Delete</td>';
xTr = '<tr>' + xTd + '</tr>';
items.push(xTr);
xTd = '';
xTr = '';
});
$("#records").append(items);
});
}
Updated the server side code:
page url : localhost/hotel/viewcustomers.php
/**
* Fetch single row for the purpose of update / delete.
*/
if(isset($_GET['update'])){
$customer = new Customers;
$Id = $_GET['update'];
$customer_single = $customer->View_Single_Customer($Id);
echo json_encode($customer_single);
unset($customer);
}
This line is not used the right way var data = '?'+ $(this).attr('id');
Change it like this: var my_id = $(this).attr('id');
Then update the line data: data with data : {id:my_id}
Complete code :
$("#records").on('click', ".update", function() {
var my_id = $(this).attr('id');
$.ajax({
type: "GET",
url: "viewcustomers.php",
data : {id : my_id},
success: function(response) {
console.log(response);
}
});
});
Or do it like this:
$("#records").on('click', ".update", function() {
var param = '?id='+ $(this).attr('id'); /*notice that I have added "id=" */
$.ajax({
type: "GET",
url: "viewcustomers.php" + param,
/* remove the data attribute */
success: function(response) {
console.log(response);
}
});
});
Modify it as
$("#records").on('click', ".update", function() {
var request = '?id='+ $(this).attr('id');
$.ajax({
type: "GET",
url: "viewcustomers.php" + request,
success: function(response) {
console.log(response);
}
});
});
For some reason ajax is not sending data.
On the PHP I have this code:
if (isset($_POST['submit'])) {
echo "submit";
} else {
echo "not submit";
}
And I get not submit.
This is JS code:
$(function () {
$('#submit').click(function () {
var length = $('#number').val();
var small = $('#small').val();
var big = $('#big').val();
var number = $('#numero').val();
var special = $('#special').val();
var submit = 'submit';
var url = 'public/php/codegenerator.php';
var data = "length=" + length + "&small=" + small + "&big=" + big +
"&number=" + number + "&special=" + special + "&submit=" + submit;
$.ajax({
type: "POST",
url: url,
data: data,
success: function () {
$('#code').load(url, function () {
$(this).fadeIn(1000)
});
}
});
return false;
});
});
You can try this approach
$(function(){
$('#submit').click(function(){
//YOUR CODE
var param = {
length:length,
small:small,
big:big,
number:number,
special:special,
submit:submit
}
$.ajax({
type: "POST",
url: url,
data: param,
//EDITED LINE
success: function (data) {
$('#code').hide().html(data).fadeIn(1000);
}
});
return false;
});
});
// REVISED ANSWER
// IN YOUR PHP FILE
if (isset ($_POST['submit'])) {
echo json_encode(array('result'=>"submit"));
}
else {
echo json_encode(array('result'=>"not submit"));
}
//IN YOUR JQUERY CODE
$.ajax({
type: "post",
url: url,
data: param,
dataType:'json';
//EDITED LINE
success: function (data) {
// alert(data.result);
$('#code').hide().html(data.result).fadeIn(1000);
}
});
You are getting Not submit, because it comes from the .load() call and not from .ajax - and in the load call you just load the URL without passing any POST data. So why you are running .load inside the success callback of .ajax with the same url?