Been having trouble with a form not submitting data to a page (Change Password) when on any page of the website apart from the index page (Which is working as it should). The website is built using CodeIgniter.
The code currently used on all pages for the form is the following:
<div class="modal-body">
<form role="form" id="change_password_form" action="<?php echo base_url('auth/change_password')?>" method="post">
<fieldset>
<div class="form-group">
<input class="form-control" placeholder="Old Password" name="old" type="password" autofocus>
</div>
<div class="alert alert-danger" id="old" role="alert" style="display:none"></div>
<div class="form-group">
<input class="form-control" placeholder="New Password - minimum 8 characters" name="new" type="password" value="">
</div>
<div class="alert alert-danger" id="new" role="alert" style="display:none"></div>
<div class="form-group">
<input class="form-control" placeholder="Confirm New Password" name="new_confirm" type="password" value="">
</div>
<div class="alert alert-danger" id="new_confirm" role="alert" style="display:none"></div>
<input type="hidden" name="user_id" value="<?php echo $user_id;?>" id="user_id" />
</fieldset>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
<button type="button" class="btn btn-primary" id="changepassword" value="Submit">Submit</button>
</form>
</div>
On the index page, this successfully goes to the change_password function and will check the details to see if they meet the rules. An error message is shown below the text box when submit is clicked. However on other pages using the same code, nothing happens when submit is clicked. when I go into Main.php and change the page of index.php in the index function to any other page (view_inventory.php for example), The change password works correctly on the new index page, but will not work on the old index page.
I can get the change password to work on other pages if I replace the submit button with the code below (Doesn't show the results under the text boxes, but on a new blank page), but I didn't really want to have to edit so many pages if it can be fixed in a smaller amount.
<input type="submit" value="Submit" class="btn btn-primary">
Any help would be gratefully appreciated.
I had the same error last week. you have to use a Submit inside form instead of button.
You can use form_submit for example:
echo form_submit('mysubmit', 'Submit');
// Would produce: <input type="submit" name="mysubmit" value="Submit" />
Here is the documentation:
http://www.codeigniter.com/user_guide/helpers/form_helper.html
Regards.
Related
I have a sample log in/log out module. It's inside a form that accesses a separate php file for verification and database access. I want to use sweetalert2 to display the success or denied modal. How can I do that?
HTML:
<div class="modal-body">
<div class="text-danger"><?php echo isset($_GET['error']) ? $_GET['error']: "" ?></div>
<form action="login.php" method="POST" enctype="multipart/form-data">
<div class="form-group">
<label for="email">Email address</label>
<input type="email" class="form-control" name="email" placeholder="Enter email" required>
</div>
<div class="form-group">
<label for="password">Password</label>
<input type="password" class="form-control" name="password" placeholder="Password" required>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-secondary" data-dismiss="modal">Close</button>
<button type="submit" class="submit_btn btn btn-primary">Submit</button>
</div>
</form>
</div>
As you can see, it's accessing a separate php file. Don't worry about ^this modal, it can be closed. How do I replace this modal with another modal made of sweetalert2 when the php is in another file?
PHP: (login.php)
if (empty($email)) {
header("Location: index.php?error = You need to enter your email.");
} else if (empty($password)) {
header("Location: index.php?error = You need to enter your password.");
A sample of my php code. I know it's bad form to just...redirect like that, but the main problem here is how to pass that error into a sweetalert2. I've tried calling swwetalert2 inside the login.php file, but it doesn't work.
<form method="POST">
<div class="form-outline form-white mb-4">
<input type="password" name="password" class="form-control" required/>
<label class="form-label" for="form">Pass</label>
</div>
<button type="Submit" value="send" class="btn transparent btn-block" style="color: white;">Submit</button>
</form>
if (isset($_POST['submit'])) {
$password=$_POST['password'];
if ($password=='password') {
header("location:ari.html");
exit();
}
else
echo "Incorrect.";
}
I'm beginning php currently and I'm trying to use a login method, but whenever I press my submit button my code refreshes and doesn't move onto the next page I indicated. (location:ari.html)
If I could get help on what I did wrong that would be great thanks.
you should consider using action attribute in form tag and point into some POST url that retrieve your data
use action line this
<form method="POST" action="/ari.php">
submit button refresh the page without action attribute it just point to current URL if you dont fill it
<form method="POST" >
<div class="form-outline form-white mb-4">
<input type="password" name="password" class="form-control" required/>
<label class="form-label" for="form">Pass</label>
</div>
<button type="Submit" name="submit" value="send" class="btn transparent btn-block" style="color: white;">Submit</button>
</form>
<?php
if (isset($_POST['submit'])) {
echo $password=$_POST['password']=='password'?header("location:ari.html"):"Incorrect.";
}
?>
have updated this code and working fine for me...hope u got the answer
Take a look at this line:
<form method="POST">
What happening is that when you are submitting the form it is sending data to the same page.
In this line:
if (isset($_POST['submit']))
I found no tag with name='submit' attribute. You should put this in your submit button.
If you want to send it to another page then use the action attribute in form tag and point your data to that page like action=yourpage.php
Here is my html:
<form id="quant" method="POST" action="/portfolio" name="trans">
<div class="modal-body">
Shares : <input autocomplete="off" type="text" name="quantity">
<input type="hidden" value="<?= htmlspecialchars($_GET['q']); ?>" name="stock">
<input type="submit" name="val" value="Confirm Transaction" class="btn btn-primary">
<div id="slider-range-max"></div>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
</div>
</form>
Here is an image of my web inspector showing that in fact that data was requested:
I have been trying to figure out why this has not been working for a long time, any suggestions would be appreciated.
The Code:
if(isset($_POST["quantity"])) {
var_dump($_POST);
which returns nothing
Then you need a slash after it to let it know it is a folder and not a file: action="/portfolio/"
If you're using something like AngularJS to submit your form, it doesn't send POST data the typical way. Check out this post.
I have a login form inside a fancybox popup and for some reason the submit button doesn't work.
I tried using different html input types as show below.
With type="button" the form works but when i click enter is doesnt submit form
With type="submit" the form doesnt work at all when i click submit or press enter it just redirects me to mysite.com/?login=&pass=&submit=SIGN+IN+TO+YOUR+ACCOUNT closing the fancy box
This below is form code
<div style="display:none">
<div id="sign_in" class="fancybox_message sign_in_popup">
<div class="login_form_container">
<h1 class="semibold">SIGN IN TO YOUR ACCOUNT</h1>
<form>
<input type="text" name="login" id="login" class="regular" autocomplete="off" placeholder="Username or Email" />
<input type="password" name="pass" id="pass" class="regular" autocomplete="off" placeholder="Password" />
<div class="clear"></div>
<div class="squaredFour">
<input style="display: none;" type="checkbox" value="None" id="squaredFour" name="check" />
<label for="squaredFour"></label>
</div>
<span class="regular remember">Remember me</span>
Forgot your username/password?
<div class="errorHolder" style="float: left;margin-top:5px;color:red"></div>
<input type="button" name="submit" id="ajaxLogin" class="semibold submit" value="SIGN IN TO YOUR ACCOUNT" />
</form>
</div>
<div class="login_social_container">
<!--<img src="<?php echo $website_domain; ?>/assets/images/login_facebook.png" alt="Login from facebook" />-->
Login with Facebook
Login with Twitter
Login with Linkedin
Login with Google+
</div>
</div>
</div>
You should add
onclick="submitMyForm()"
to the submit button, then implement your ajax operation in a function called submitMyForm.
If you're not sure about ajax or don't want to juggle with the fields, you can use a hidden iframe and make your <form> target point there. This way you get the submitted info just as you normally would but no page reload will happen.
I'm a newbie programmer trying to utilize Twitter Bootstrap to build out a concept. I'm using PHP and assigning actions within HTML tags to POST data and essentially take a user through the navigation. This has been pretty straightforward when using forms: i.e. here is a snippet that does work. For example, for this snippet of HTML:
<form action="?viewnotes" method="post">
<input type="hidden" name="id" value="<?php htmlout($note['id']); ?>">
</form>
It successfully triggers the following if statement in my index.php:
if (isset($_GET['viewnotes']))
However, I'm trying to do the same thing in my registration page, using a Twitter Bootstrap class for buttons. Here is the HTML:
<a class="btn btn-primary btn-large" action="?register">Sign Up Free!ยป</a></p>
The PHP code is:
if (isset($_GET['register']))
{
include 'register.html.php';
}
Clicking on the Sign Up button is not invoking the PHP code. If I hard code the URL it works, but then I have a similar issue on the register.html.php page. HTML on the register page has:
<form class="form-horizontal" action="?storeuser" method="post">
<fieldset>
<legend>It's quick and easy...</legend>
<div class="control-group">
<label class="control-label">First Name</label>
<div class="controls">
<input type="text" name="fname" class="input-xlarge" id="fname">
</div>
</div>
<div class="control-group">
<label class="control-label" name="lname">Last Name</label>
<div class="controls">
<input type="text" name="lname" class="input-xlarge" id="lname">
</div>
</div>
<div class="control-group">
<label class="control-label" name="email">Email Address</label>
<div class="controls">
<input type="text" name="email" class="input-xlarge" id="email">
</div>
</div>
<div class="control-group">
<label class="control-label" name="password">Password</label>
<div class="controls">
<input type="password" name="password" class="input-xlarge" id="password">
</div>
</div>
</fieldset>
<button type="submit" name="action" class="btn btn-primary btn-large">Complete Registration</button>
</form>
However, when clicking on the button, the index file does not trigger the following, which would store the fields into the DB.
if (isset($_GET['storeuser']))
If I hardcode the URL to register.html.php, then the resulting URL looks like localhost/register.html.php?storeuser instead of localhost/?storeuser. I'm not sure if that's affecting the behavior here.
Thank you for the help!
I think you're approaching this the wrong way, and it's not Twitter Bootstrap's fault.
Usually, you'd use POST, not GET, to handle user registrations. Your form would look like this:
<form action="register.php" method="post">
<!-- your form -->
<fieldset>
<input type="submit" name="register" value="Register" class="btn btn-primary" />
</fieldset>
</form>
You can then build register.php as follows:
<?php
if (isset($_POST['register'])) {
// handle user registration
}
// display form
?>
This will display the form when the user visits register.php, but will try and process the user registration first if the form's been POSTed.
try passing a value with your GET variable
<form action="?viewnotes=1" method="post">