I'm trying to echo $_POST with $.ajax in PHP with no success. In Xdebug I see the $_POST get the right value and executing the echo $_POST line, but I keep getting the else output clause. Also in chrome I see the headers that are sent valid. All the code is in the same page index.php.
<!doctype html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>jQuery.post demo</title>
<script src="https://code.jquery.com/jquery-2.2.0.min.js"></script>
</head>
<body>
<button type="button" id="but">Click Me!</button>
<script>
$('#but').click(function() {
$.ajax({
type: "POST",
url: "index.php",
data: {name: "John"},
success: function() {
alert('success');
}
});
});
</script>
</body>
</html>
<?php
if ($_SERVER['REQUEST_METHOD'] == "POST") {
echo $_POST['name'];
} else {
echo "Nothing to Show";
}
?>
At the moment the whole page is being returned in response to your AJAX request; HTML and all. You're also not retrieving the value returned from the request in your JS code, to do that you just need to accept a parameter on your success handler. Try this:
In it's own file, say foo.php:
<?php
if ($_SERVER['REQUEST_METHOD'] == "POST") {
echo $_POST['name'];
} else {
echo "Nothing to Show";
}
?>
Then in your HTML:
<script>
$('#but').click(function() {
$.ajax({
type: "POST",
dataType: 'text', // to ensure jQuery doesn't try to deserialise the repsonse
url: "foo.php",
data: { name: "John" },
success: function(response) {
console.log(response.trim()); // = 'John'
}
});
});
</script>
Ajax will return a response and you can use that response to display. It will not work on the same page.
Try as below :
main.php
<!doctype html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>jQuery.post demo</title>
<script src="https://code.jquery.com/jquery-2.2.0.min.js"></script>
</head>
<body>
<button type="button" id="but">Click Me!</button>
<div id="result"></div>
<script>
$('#but').click(function() {
$.ajax({
type: "POST",
url: "test.php",
data: {name: "John"},
success: function(data) {
alert('success');
$('#result').html(data);
}
});
});
</script>
</body>
</html>
test.php
<?php
if ($_SERVER['REQUEST_METHOD'] == "POST") {
echo $_POST['name'];
} else {
echo "Nothing to Show";
}
?>
Related
I'm trying message application. My goal is get sender id and receiver id with a click on one button.
After then post this datas with ajax or ajax(json) to php in same page.
I will use the incoming data in php with mysql_query. I tryed many examples. But never get result. My example code at below.
Little Note: Success alert comes but doesn't print any data on screen.
<html>
<head>
<script src="https://code.jquery.com/jquery-3.1.1.min.js"></script>
</head>
<body>
<button type="button" onclick="myFunc()">Get ID</button>
<script>
function myFunc()
{
var id = 'example';
jQuery.ajax({
url:'index.php',
type: "POST",
data: {'name':id},
success: function(data)
{
alert("success");
}
});
};
</script>
<?php
if(isset($_POST['name']))
{
$value = $_POST['name'];
echo $value;
}
else
{
echo "don't work.";
}
?>
</body>
</html>
<?php
if(isset($_POST['name']))
{
echo json_encode(array(
'value' => $_POST['name']
));
exit();
}
?>
<html>
<head>
<script src="https://code.jquery.com/jquery-3.1.1.min.js"></script>
</head>
<body>
<button type="button" onclick="myFunc()">Get ID</button>
<script>
function myFunc()
{
var id = 'example';
jQuery.ajax({
url:'index.php',
type: "POST",
data: {'name':id},
dataType : 'json',
success: function(data)
{
alert("success");
}
});
};
</script>
</body>
</html>
I'm going to create a page that user can input something in textarea (index.php). When user click on Tweet, it will get all text that user typed to page tweet.php (I used jQuery Ajax method). After that, it will redirect to page show.php
Here is my code
index.php
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<title>Tweet</title>
<script type="text/javascript" src="js/jquery.js"></script>
<script type="text/javascript">
$(document).ready(function(){
function save_tweet(text_tweet){
$.ajax
({
type: "POST",
url: "tweet.php",
data: "text="+text_tweet,
success: function(msg)
{
if(msg==1){
window.location.href="show.php";
}else{
alert("Error");
}
}
});
}
$("#tweet").bind('click', function(){
var text_tweet = $("#text_tweet").val();
if(text_tweet==""){
$("#show").html("Blank text");
return;
}else{
$("#show").html("");
save_tweet(text_tweet);
}
});
});
</script>
</head>
<body>
<center>
<textarea name="text_tweet" cols="61" rows="5" id="text_tweet"></textarea>
<br/>
<div id="show"></div>
<br/>
Tweet
</center>
</body>
</html>
tweet.php
<?php
session_start();
if(isset($_POST['text'])){
$_SESSION['text_tweet'] = $_POST['text'];
}
?>
show.php
<?php
session_start();
echo $_SESSION['text_tweet'];
?>
The problem is when i input some text in textarea and click Tweet, it will alert Error. Can anyone know what is the problem?
Thank in advance.
Why are you checking if msg is 1 ? Are you returning 1 in your response body ? Looking at the JQuery docs it the success function callback is described as:
Type: Function( PlainObject data, String textStatus, jqXHR jqXHR )
You could log the value of msg and see what is actually contains.
Try changing your code to:
$.ajax
({
type: "POST",
url: "tweet.php",
data: {text: text_tweet},
success: function(msg)
{
if(msg==1 || msg=="1"){
window.location.href="show.php";
}else{
alert("Error");
}
}
});
tweet.php
<?php
session_start();
if(isset($_POST['text'])){
$_SESSION['text_tweet'] = $_POST['text'];
echo 1;
}
?>
try
if(msg.length){
window.location.href="show.php";
}else{
alert("Error");
}
Add the dataType in your ajax:
dataType: 'text',
Add above line in your ajax code.
And change your below line:
var text_tweet = $("#text_tweet").val();
with the:
var text_tweet = $("#text_tweet").text();
And in your tweet.php file add this line:
echo "1";
This is my code and i want to pass javascript variable with ajax to php when i click submit button then the result doesn't show var_data variable from javascript What code is wrong?
This is edit order one before everybody help me
<!DOCTYPE html>
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.5/jquery.min.js"></script>
<script>
$(document).ready(function() {
$('#sub').click(function() {
var var_data = "Hello World";
$.ajax({
url: 'http://localhost/ajax/PassVariable.php',
type: 'GET',
data: { var_PHP_data: var_data },
success: function(data) {
// do something;
}
});
});
});
</script>
</head>
<body>
<input type="submit" value="Submit" id="sub"/>
<?php
$test = $_GET['var_PHP_data'];
echo $test;
?>
</body>
</html>
and this is source code now
<?php
if (isset($_GET['var_PHP_data'])) {
echo $_GET['var_PHP_data'];
} else {
?>
<!DOCTYPE html>
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.7/jquery.js"></script>
<script src="http://malsup.github.com/jquery.form.js"></script>
<script>
$(document).ready(function() {
$('#sub').click(function() {
var var_data = "Hello World";
$.ajax({
url: 'http://localhost/test.php',
type: 'GET',
data: { var_PHP_data: var_data },
success: function(data) {
// do something;
$('#result').html(data)
}
});
});
});
</script>
</head>
<body>
<input type="submit" value="Submit" id="sub"/>
<div id="result">
</body>
</html>
<?php } ?>
this statement if(isset($_GET['var_PHP_data'])) output false and then show Hello World What should i do to do for isset($_GET['var_PHP_data']) is true?
Your solution has PHP issues: you don't check if the data exists, and also, you don't do anything with the result. I've modified the script to do the following:
Check if the var_PHP_data var is set (in PHP, on the server).
If yes, just send a blank text response containing that data.
If no, then draw the form and everything else.
In the form, I've created a #result div.
Ajax response will be shown in this div.
Also make sure that you host the script at localhost and that it is called test.php. To make sure this is resilient, you can change the Ajax URL to
<?php echo $_SERVER['PHP_SELF'];?> to make sure that you'll hit the correct script.
<?php
if (isset($_GET['var_PHP_data'])) {
echo $_GET['var_PHP_data'];
} else {
?>
<!DOCTYPE html>
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.5/jquery.min.js">
<script>
$(document).ready(function() {
$('#sub').click(function() {
var var_data = "Hello World";
$.ajax({
url: 'http://localhost/test.php',
type: 'GET',
data: { var_PHP_data: var_data },
success: function(data) {
// do something;
$('#result').html(data)
}
});
});
});
</script>
</head>
<body>
<input type="submit" value="Submit" id="sub"/>
<div id="result">
</body>
</html>
<?php } ?>
Try jQuery Form its this will help to solve many problems.
For you question: try url without domain name, add tags 'form', change event click to submit, add data type
what are the contents of PassVariable.php ? if is the same where you have they jquery bit wont work coz php will print all the page again, if the file is different try
success: function(data) {
alert('databack = '+ data);
}
Try placing your input into a form and attaching the ajax call to the form onsubmit event. The way it happens in the provided happen is when you click in the field, in which case it submits before you can write anything really.
$(document).ready(function() {
$('#brn').click(function() {
var var_data = "Hello World";
alert("click works");
$.ajax({
url: 'http://localhost/ajax/PassVariable.php',
type: 'GET',
data: { x: var_data },
success: function(data) {
alert(data);
}
});
});
});
change it to this code
then in PassVariable.php put
make button
<input type="button" id="btn" value="click me" />
it should work because it is very basic example. If it doesn't work check your console if there are any JavaScript errors and remove them.
Problem 1: My content overlaps itself twice after I post some data back to the same page using jQuery.ajax(). The reason why I'm posting data back to the same page is because I need to pass my JavaScript values to the PHP side.
Question: How do I edit my code such that there will only be 1 copy of my content, before and after posting of data to the same page?
Problem 2: You may have noticed there is a $("#test").html(data); in my bingo function and a <span id="test"></span> in my body. I can't seem to remove them if not the passing of Javascript values to the PHP side would not work as shown by my print_r().
Question: Is there any way I can remove them but still pass my values from JavaScript to PHP using jQuery.ajax()?
bingo.php
<html>
<head>
<script type="text/javascript" src="js/jquery-1.7.2.min.js"></script>
<?php
if (!isset($_POST['varA']) && !isset($_POST['varB']))
{
?>
<script type="text/javascript">
$(document).ready(bingo);
function bingo()
{
jQuery.ajax({
type: "POST",
data: {varA: "123", varB: "456"},
success: function(data)
{
alert("POST to self is successful!");
$("#test").html(data);
}
});
}
</script>
<?php
}
else
{
print_r($_POST['varA']);
echo " - ";
print_r($_POST['varB']);
}
?>
</head>
<body>
<input type="text" value="meow"/>
<span id="test"></span>
</body>
</html>
Omg that is so messy! Try the following code anyway:
<?php
if (isset($_POST['varA']) && isset($_POST['varB'])) {
print_r($_POST['varA']);
echo " - ";
print_r($_POST['varB']);
} else {
?>
<html>
<head>
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(bingo);
function bingo()
{
jQuery.ajax({
type: "POST",
data: {varA: "123", varB: "456", ajax: true},
success: function(data)
{
alert("POST to self is successful!");
$("#test").html(data);
}
});
}
</script>
</head>
<body>
<input type="text" value="meow"/>
<span id="test"></span>
</body>
</html>
<?php
}
?>
If you wish to keep your ! in your conditions, you can do it the other way round also.
<?php
if (!isset($_POST['varA']) && !isset($_POST['varB'])) {
?>
<html>
<head>
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(bingo);
function bingo()
{
jQuery.ajax({
type: "POST",
data: {varA: "123", varB: "456"},
success: function(data)
{
alert("POST to self is successful!");
$("#test").html(data);
}
});
}
</script>
</head>
<body>
<input type="text" value="meow"/>
<span id="test"></span>
</body>
</html>
<?php
}
else {
print_r($_POST['varA']);
echo " - ";
print_r($_POST['varB']);
}
?>
I'm using jQuery's .ajax() to post to a PHP file called process.php. Process.php has a lot of code in it, but for simplicity's sake, let's just say it contains <?php echo 'hello'; ?>.
Is this the proper jQuery to insert process.php's results into div.results? :
$.get('process.php', function(data) {
$('.results').html(data);
});
So far it doesn't seem to be working.
Here's the HTML/Javascript file
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8" />
<script type="text/javascript" src="http://code.jquery.com/jquery-1.5.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$("form#form").submit(function() {
var username = $('#username').attr('value');
$.ajax({
type: 'POST',
url: 'process.php',
data: 'username=' + username,
success: function() {
$('form#form').hide(function() {
$.get('process.php', function(data) {
$('.results').html(data);
});
});
}
});
return false;
});
});
</script>
</head>
<body id="body">
<form id="form" method="post">
<p>Your username: <input type="text" value="" name="username" id="username" /></p>
<input type="submit" id="submit" value="Submit" />
</form>
<div class="results"></div>
</body>
</html>
Here's process.php (greatly simplified):
<?php
/* get info from ajax post */
$username = htmlspecialchars(trim($_POST['username']));
echo $username;
?>
If you simply want to place the resulting string back into an element, use load().
$('.results').load('process.php');
However, looking at your code...
$.ajax({
type: 'POST',
url: 'process.php',
data: 'username=' + username,
success: function() {
$('form#form').hide(function() {
$.get('process.php', function(data) {
$('.results').html(data);
});
});
}
});
...shows you have misunderstood something. The correct anonymous function to assign to the success callback would be...
function(data) {
$('form#form').hide()
$('.results').html(data);
}
You could try something like this.
function ajax_login() {
if ($("#username").val()) {
$.post("/process.php", { username : $("#username").val() }, function(data) {
if (data.length) {
$("#login_form").hide();
$("#login_result").html(data);
}
})
} else {
$("#login_result").hide();
}
Then in process.php just echo out some text if the post sucesses.
process.php =>
if (isset($_POST['username'])
{
echo 'hello '.$_POST['username'];
}