I want to update a unix timestamp and add x months.
This is a timestamp that i use 1456256866
strtotime("+1 month")
what i want to accieve is :
$time = '1456256866';
//update $time with x months something like
$time("+5 month");
Can someone put me in the right direction?
Much Thanks
You could do something like below. the function strtotime takes a second argument.
$time = 1456256866;
$time = strtotime('+5 month', $time);
For such operations You should use Datetime class, especially Add method:
$date = new DateTime('#1456256866');
$date->add(new DateInterval('P5M'));
echo $date->format('Y-m-d') . "\n";
Check more here: http://php.net/manual/pl/datetime.add.php
Related
just trying to create a variable where it outputs the exact current datetime and adding exactly one additional year. how do i add the days?
$expirationdate = date('Y-m-d H:i:s', .' + 1 year'));
Lets say the exact current date is 2019-01-23 17:11:25
the variable will be: 2020-01-23 17-11-25 (+365)
Also, if a person manually modifies the date on their PC/Phone, will that time be the start of the current date on the variable?
You can achieve your result by using strtotime() and date() function of php
$expirationdate = date('Y-m-d H:i:s', strtotime('+ 1 year'));
print_r($expirationdate);
You can read more about the strtotime() and date()
Try with below code:
$expirationdate = date('Y-m-d H:i:s', strtotime('+1 years'));
I hope it will help you.
Try This :
$date= date('Y-m-d H:i:s',strtotime('+1 years'));
I think the best way to work with dates and time in PHP is through the DateTime object. You can use modify method to add or subtract days, years or whatever you want, like this:
$d = new DateTime(); //current date
$d->modify('+10 days');
$d->modify('+1 year');
echo $d->format('Y-m-d H:i:s');
Regarding your second question if a person modifies date on his computer it won't change anything because PHP runs on the server and takes date from it (not from the user machine).
// to simplify $timestamp in this example is the unix timestamp of 2016-04-20
Consider this example:
strtotime('+1 year', $timestamp); // this returns 2017-04-19
How can I make it return 2017-04-20?
Another example:
strtotime('+1 month', $timestamp); // this returns 2016-05-19
How can I make it return 2016-05-20?
Basically, I want to relatively add time that ends up with the same date.
strtotime('+1 day', strtotime('+1 year', $timestamp));
?
$date = date("Y",$timestamp) + 1 //gives you the next year
$date .= "-" . date("m-d",$timestamp) //concantenates on the current month and day
I may be misunderstanding what you're asking but you're probably better of using the DateTime library built into PHP, it's a lot more flexible than the standard date() function.
So you could do:
$d = new DateTime();
$d->modify('+1 year');
echo $d->format('Y-m-d'); // Outputs: 2017-04-20
If you want to create a DateTime object from a specific date you can do so by:
$d = DateTime::createFromFormat('Y-m-d', '2016-01-01');
echo $d->format('Y-m-d'); // Outputs 2016-01-01
I believe that's what you're after, it's much cleaner than date() and easier to read in my personal opinion.
Im trying to add a certain amount of days to a timestmp using this in PHP:
$capturedDate = '2008-06-20';
$endDate = strtotime($capturedDate);
$endDate2 = strtotime('+1 day',$endDate);
echo $endDate2;
but its displaying: 1216526400
any ideas?
Try:
echo date("Y-m-d H:i:s",$endDate2);
Or (for just the date):
echo date("Y-m-d",$endDate2);
You can find documentation about how to format your string here: http://php.net/manual/en/function.date.php
You should be using DateTime for working with dates. It's timezone friendly.
$datetime = new DateTime('2008-06-20');
$datetime->modify('+1 day');
echo $datetime->getTimestamp();
strtotime() converts the date into a unix timestamp which is the number of seconds since January 1st 1970. If you want a date output you have to run the finished timestamp through date() first.
$capturedDate = '2008-06-20';
$endDate = strtotime($capturedDate.' +1 day');
echo date("Y-m-d", $endDate);
strtotime creates a Unix timestamp so if you want to be presented with a formatted date, you need to pass the timestamp as an argument to the date function as follows:
$capturedDate = '2008-06-20';
$endDate = strtotime($capturedDate);
$endDate2 = strtotime('+1 day',$endDate);
echo date('Y-m-d', $endDate2);
Additionally, there are a wide variety of parameters you can use in the date function if you want to display additional information.
e.g.: echo date('Y-m-d H:i:s', $endDate2); or echo date('Y-m-d h:i:s a', $endDate2);, etc.
Sooooo close, just take your timestamp and convert it back into date format using date("desired format",$endDate2);
DateTime is a very nice way to deal with dates. You can try like this:
$capturedDate = '2008-06-20';
$date = DateTime::createFromFormat('Y-m-d', $capturedDate)->modify('+1 day');
echo $date->getTimestamp();
I am trying to add minutes to current date but it returns strange results
date_default_timezone_set('Asia/Karachi');
$currentDate = date("m-d-Y H:i:s");
$currentDate_timestamp = strtotime($currentDate);
$endDate_months = strtotime("+10 minutes", $currentDate_timestamp);
$packageEndDate = date("m-d-Y H:i:s", $endDate_months);
echo " <br> " . $packageEndDate . " <br> ";
echo $currentDate;
I am getting Output
01-01-1970 05:50:00
07-19-2013 20:25:23
It should return
07-19-2013 20:35:23
07-19-2013 20:25:23
After this I need to query to database so date format should be same. Database column is of string type.
Your code is redundant. Why format a timestamp as a string, then convert that string back to a timestamp?
Try
$now = time();
$ten_minutes = $now + (10 * 60);
$startDate = date('m-d-Y H:i:s', $now);
$endDate = date('m-d-Y H:i:s', $ten_minutes);
instead.
Probably the minimalist way would be:
date_default_timezone_set('Asia/Baku');
$packageEndDate = date('Y-m-d H:i:s', strtotime('+10 minute'));
echo $packageEndDate;
Output (Current time in my city at the time of writing):
2017-07-20 12:45:17
Try this:
$now = time();
$tenMinFromNow = date("m-d-Y H:i:s", strtotime('+10 minutes', $time));
$tenMinsFromNow = (new \DateTime())->add(new \DateInterval('PT10M'));
Will leave you with a DateTime object representing a time 10 minutes in the future. Which will allow you to do something like:-
echo $tenMinsFromNow->format('d/m/Y H:i:s');
See it working
PHP version >= 5.4 I'm afraid, but you should be using at least that version by now anyway.
Pakistan, which is the localisation explicitly set, uses "DD-MM-YYYY" format dates so the problem occurs when you cast the date into a string of "MM-DD-YYYY". This American format of date is not parseable by the Pakistan localisation.
If you still want to keep the round-trip to a string and back, use DD-MM-YYYY or the ISO datetime format.
While this is the only (current) answer which actually explains your original issue, I recommend the code be refactored as others have demonstrated.
I'm really stuck with adding X minutes to a datetime, after doing lots of google'ing and PHP manual reading, I don't seem to be getting anywhere.
The date time format I have is:
2011-11-17 05:05: year-month-day hour:minute
Minutes to add will just be a number between 0 and 59
I would like the output to be the same as the input format with the minutes added.
Could someone give me a working code example, as my attempts don't seem to be getting me anywhere?
$minutes_to_add = 5;
$time = new DateTime('2011-11-17 05:05');
$time->add(new DateInterval('PT' . $minutes_to_add . 'M'));
$stamp = $time->format('Y-m-d H:i');
The ISO 8601 standard for duration is a string in the form of P{y}Y{m1}M{d}DT{h}H{m2}M{s}S where the {*} parts are replaced by a number value indicating how long the duration is.
For example, P1Y2DT5S means 1 year, 2 days, and 5 seconds.
In the example above, we are providing PT5M (or 5 minutes) to the DateInterval constructor.
PHP's DateTime class has a useful modify method which takes in easy-to-understand text.
$dateTime = new DateTime('2011-11-17 05:05');
$dateTime->modify('+5 minutes');
You could also use string interpolation or concatenation to parameterize it:
$dateTime = new DateTime('2011-11-17 05:05');
$minutesToAdd = 5;
$dateTime->modify("+{$minutesToAdd} minutes");
$newtimestamp = strtotime('2011-11-17 05:05 + 16 minute');
echo date('Y-m-d H:i:s', $newtimestamp);
result is
2011-11-17 05:21:00
Live demo is here
If you are no familiar with strtotime yet, you better head to php.net to discover it's great power :-)
You can do this with native functions easily:
strtotime('+59 minutes', strtotime('2011-11-17 05:05'));
I'd recommend the DateTime class method though, just posted by Tim.
I don't know why the approach set as solution didn't work for me.
So I'm posting here what worked for me in hope it can help anybody:
$startTime = date("Y-m-d H:i:s");
//display the starting time
echo '> '.$startTime . "<br>";
//adding 2 minutes
$convertedTime = date('Y-m-d H:i:s', strtotime('+2 minutes', strtotime($startTime)));
//display the converted time
echo '> '.$convertedTime;
I thought this would help some when dealing with time zones too. My modified solution is based off of #Tim Cooper's solution, the correct answer above.
$minutes_to_add = 10;
$time = new DateTime();
**$time->setTimezone(new DateTimeZone('America/Toronto'));**
$time->add(new DateInterval('PT' . $minutes_to_add . 'M'));
$timestamp = $time->format("Y/m/d G:i:s");
The bold line, line 3, is the addition. I hope this helps some folks as well.
A bit of a late answer, but the method I would use is:
// Create a new \DateTime instance
$date = DateTime::createFromFormat('Y-m-d H:i:s', '2015-10-26 10:00:00');
// Modify the date
$date->modify('+5 minutes');
// Output
echo $date->format('Y-m-d H:i:s');
Or in PHP >= 5.4
echo (DateTime::createFromFormat('Y-m-d H:i:s', '2015-10-26 10:00:00'))->modify('+5 minutes')->format('Y-m-d H:i:s')
If you want to give a variable that contains the minutes.
Then I think this is a great way to achieve this.
$minutes = 10;
$maxAge = new DateTime('2011-11-17 05:05');
$maxAge->modify("+{$minutes} minutes");
Use strtotime("+5 minute", $date);
Example:
$date = "2017-06-16 08:40:00";
$date = strtotime($date);
$date = strtotime("+5 minute", $date);
echo date('Y-m-d H:i:s', $date);
As noted by Brad and Nemoden in their answers above, strtotime() is a great function. Personally, I found the standard DateTime Object to be overly complicated for many use cases. I just wanted to add 5 minutes to the current time, for example.
I wrote a function that returns a date as a string with some optional parameters:
1.) time:String | ex: "+5 minutes" (default = current time)
2.) format:String | ex: "Y-m-d H:i:s" (default = "Y-m-d H:i:s O")
Obviously, this is not a fully featured method. Just a quick and simple function for modifying/formatting the current date.
function get_date($time=null, $format='Y-m-d H:i:s O')
{
if(empty($time))return date($format);
return date($format, strtotime($time));
}
// Example #1: Return current date in default format
$date = get_date();
// Example #2: Add 5 minutes to the current date
$date = get_date("+5 minutes");
// Example #3: Subtract 30 days from the current date & format as 'Y-m-d H:i:s'
$date = get_date("-30 days", "Y-m-d H:i:s");
one line mysql datetime format
$mysql_date_time = (new DateTime())->modify('+15 minutes')->format("Y-m-d H:i:s");
One more example of a function to do this: (changing the time and interval formats however you like them according to this for function.date, and this for DateInterval):
(I've also written an alternate form of the below function.)
// Return adjusted time.
function addMinutesToTime( $dateTime, $plusMinutes ) {
$dateTime = DateTime::createFromFormat( 'Y-m-d H:i', $dateTime );
$dateTime->add( new DateInterval( 'PT' . ( (integer) $plusMinutes ) . 'M' ) );
$newTime = $dateTime->format( 'Y-m-d H:i' );
return $newTime;
}
$adjustedTime = addMinutesToTime( '2011-11-17 05:05', 59 );
echo '<h1>Adjusted Time: ' . $adjustedTime . '</h1>' . PHP_EOL . PHP_EOL;
Without using a variable:
$yourDate->modify("15 minutes");
echo $yourDate->format( "Y-m-d H:i");
With using a variable:
$interval= 15;
$yourDate->modify("+{$interval } minutes");
echo $yourDate->format( "Y-m-d H:i");