In mysql table table data, one column has multiple value like this,
code name
1,2,3 a
4 b
My desired output will be
code name
1 a
2 a
3 a
4 b
Here is my code:
$sql="SELECT * FROM hsc_sub group by sub_name order by sub_code";
$res = app_db_query($app,$sql);
while($row = mysqli_fetch_assoc($res)){
//enter code here
$subj[] = $row;
$subj[] = explode(",",$row['sub_code']);
}
Within the ForEach Loop, we can achieve your requirement.
$subCode[];
$name[];
echo("Code");
echo("\t");
echo("Name");
echo("\n");
$sql="SELECT * FROM hsc_sub group by sub_name order by sub_code";
$res = app_db_query($app,$sql);
while($row = mysqli_fetch_assoc($res)){
$nm = $row['sub_name']
$sub[] = explode(",",$row['sub_code']);
foreach($sub as $item)
{
$name.push($nm);
$subCode.push($item);
echo($item);
echo("\t");
echo($nm);
echo("\n");
}
}
Related
I created a settings table in my database and I would like to assign value to a variable based on the setting and I'm not sure how to go about doing it.
table: settings
id | setting | value
1 | setting_one | value_one
2 | setting_two | value_two
3 | setting_three | value_three
Query
if ($result = $db->query("SELECT * FROM settings")) {
while($row = mysqli_fetch_assoc($result)) {
$SettingOne = $row['setting_one'];
$SettingTwo = $row['setting_two'];
$SettingThree = $row['setting_three'];
}
}
The select will return you 3 rows, assuming your table has only 3 rows in it
that is why you process the result in a while lop.
Each $row will contain an Assoc array in the form of the columns that you selected in your query.
In this case as you use SELECT * the $row array will contain 3 occurances
id, setting, value
So your loop should look like
if ($result = $db->query("SELECT * FROM settings")) {
while($row = mysqli_fetch_assoc($result)) {
$id = $row['id'];
$setting = $row['setting'];
$value = $row['value'];
echo "The id = $id, the setting = $setting, the value is $value <br>";
}
}
This will produce you 3 lines of output, assuming you only have 3 rows in your table
I got it figured out and just echo the row['setting'] as $setting for each :)
if ($result = $db->query("SELECT * FROM settings")) {
while($row = mysqli_fetch_assoc($result)) {
$key = $row['setting'];
$$key = $row['value'];
}
$result->free();
$result->close();
}
I have 2 tables that look like this
table A table B
id | data id | features
--------- --------------
1 | blue 1A | 1;2
2 | red 2B | 1;2;3
3 | yellow 3B | 3;1
...... ......
What i plan to do is something like this, where i query one table. loop thru the array of results and explode the data with the semicolon delimiter. then loop thru that new array and query it to get the data (note code below not tested)
$sql = "SELECT * FROM `tableB` WHERE `id`= '2B' LIMIT 1";
$query = $db->query($sql);
while ($row = mysql_fetch_array($query)) {
$arr = explode(';', $row['features']);
for ($i = 0; $i < sizeof($arr); $i++)
{
$sql2 = "SELECT * FROM `tableA` WHERE `id`="'.$arr[$i].'"";
$query2 = $db->query($sql2);
while ($row2 = mysql_fetch_array($query2)) {
$r[] = $row2['data'];
}
}
}
print_r($r);
is there a way i can achieve this just in mysql, where i match the column in tableB with the ID's in tableA? or maybe by not using a nested loop? performance is key. coz both tables have more than 25k rows of data.
thanks in advance
Check out this code. Reduced few loops.
$sql = "SELECT * FROM `tableB` WHERE `id`= '2B' LIMIT 1";
$query = $db->query($sql);
$arr = explode(';', $row['features']);
$str = implode(",", $arr);
$sql2 = "SELECT * FROM `tableA WHERE id IN ({$str});";
$query2 = $db->query($sql2);
while ($row2 = mysql_fetch_array($query2)) {
$r[] = $row2['data'];
}
What you are looking for is the IN function
This will take an array of id's and give you every result in a single query.
So your code should look like this after you apply it
while ($row = mysql_fetch_array($query)) {
$new_query = str_replace(";", ",", $row['features']);
$sql2 = "SELECT * FROM `tableA` WHERE `id` IN ($new_query)";
$query2 = $db->query($sql2);
while ($row2 = mysql_fetch_array($query2)) {
$r[] = $row2['data'];
}
}
i have a table with staff_id and subjects, i want to display all staffs according to their subjects.
my table
result i want
Physics
-001
-004
-006
Chemistry
-002
-009
Biology
-003
-008
Mathematics
-005
My code
$q = mysql_query("Select staff_id from my_table");
while($row = mysql_fetch_array($q)){
echo $subject .'</br>';
echo $staff_id.'</br>';
}
but this doesn't give the result i want.
any help?
What you need is ORDER BY.
Change your query to:
SELECT STAFF_ID, SUBJECT FROM my_table ORDER BY SUBJECT, STAFF_ID
So you get the records in the right order to work with them.
Something like this?
$q = mysql_query("SELECT `staff_id`, `subject` FROM `my_table`;");
$data = array();
while($row = mysql_fetch_array($q)){
$data[$row['subject']][] = '-'.$row['staff_id'];
}
print_r($data);
Or to echo out the rows
foreach($data as $heading => $rows){
echo $heading.'<br>';
foreach($rows as $row){
echo $row.'<br>';
}
}
You can write your code like this below:
$q = mysql_query("SELECT * FROM my_table ORDER BY SUBJECT, STAFF_ID");
while($row = mysql_fetch_array($q)){
//Do staff
}
The following code should help. You should split each subject into a separate array within your query. Once your query is complete, you should iterate through the subject array, and then within each staff id.
$subjects = array();
$q = mysql_query("Select staff_id from my_table");
while($row = mysql_fetch_array($q)){
if ($subjects[$row['SUBJECT']] == nil) {
$subjects[$row['SUBJECT']] = array();
}
array_push($subjects[$row['SUBJECT']], $row['STAFF_ID']);
}
foreach ($subjects as $key=>$value) {
echo $key . '<br>;
foreach ($vaue as &$staff) {
echo $staff . '<br>';
}
}
$result=mysql_query("SELECT * from table GROUP BY subject");
while($ext=mysql_fetch_object($result)) {
$query=mysql_query(" SELECT * from table WHERE subject='".$ext->subject."'");
echo $ext->subject;
while($res=mysql_fetch_object($query)) {
echo $res->staff_id;
}
}
I have
$result = "";
if(someCondition)
$result = mysql_query("SELECT * FROM table1 WHERE column = '$value' ");
else
$result = mysql_query("SELECT * FROM table2 WHERE column = '$value' ");
$result could have 0 -> infinity rows returned
Table 1 and Table 2 have different amounts of columns with different names
I want to write 1 generic loop after the above else that will just print out all of the rows. Preferably 1 per line or deliminated.
To clarify, one of the two query calls will fill the $results variable with rows.
I wont know which one fills it at run time so I want to just do a print all contents to screen. Is there a method that does this? is there a fast loop that iterates through all of the rows without explicitly saying the column names?
bored enough to answer:
$result = "";
if(someCondition){
$result = mysql_query("SELECT * FROM table1 WHERE column = '$value' ");
}else{
$result = mysql_query("SELECT * FROM table2 WHERE column = '$value' ");
}
while ($row = mysql_fetch_array($result)) ) {
foreach($row as $key => $var)
{
echo $key . ' = ' . $var . '<br />';
}
}
Suppose I have a while loop like:
$sql = mysql_query("SELECT * FROM tablename");
while($row = mysql_fetch_array($sql)){
$id = $row["id"];
$sql_2 = mysql_query("SELECT * FROM secondtable WHERE id != $id ");
while($ro = mysql_fetch_array($sql_2)){
$id2 = $ro["id2"];
echo $id2;
}
}
then if first query return 5 results i.e 1-5 and second query returns 3 results than if i want to echo out second query it gives me like this..........
111112222233333
than how can i fix to 123 so that the second while loop should execute according to number of times allowed by me........!! how can i do that.........!!
I'm not sure I 100% understand your question - it's a little unclear.
It's possible you could solve this in the query with a GROUP BY clause
$sql_2 = mysql_query("SELECT id FROM secondtable WHERE id != $id GROUP BY id");
But that would only work if you need just secondtable.id and not any of the other columns.
When you say "number of time allowed by me" do you mean some sort of arbitrary value? If so, then you need to use a different loop mechanism, such as Greg B's solution.
Do you want to explicitly limit the number of iterations of the inner loop?
Have you considered using a for loop?
$sql = mysql_query("SELECT * FROM tablename");
while($row = mysql_fetch_array($sql)){
$id = $row["id"];
$sql_2 = mysql_query("SELECT * FROM secondtable WHERE id != $id ");
for($i=0; $i<3; $i++){
$ro = mysql_fetch_array($sql_2);
$id2 = $ro["id2"];
echo $id2;
}
}
Your first while loop is iterating over all 5 results, one at a time.
Your second while loop is iterating over each of the 5 results, producing it's own set of results (i.e. 3 results for each of the 5 iterations, totaling 15 results).
I believe what you are trying to do is exclude all IDs found in your first loop from your second query. You could do that as follows:
$sql = mysql_query("SELECT * FROM tablename");
$exclude = array();
while($row = mysql_fetch_array($sql)) {
array_push($exclude, $row['id']);
}
// simplify query if no results found
$where = '';
if (!empty($exclude)) {
$where = sprintf(' WHERE id NOT IN (%s)', implode(',', $exclude));
}
$sql = sprintf('SELECT * FROM secondtable%s', $where);
while($row = mysql_fetch_array($sql_2)) {
$id2 = $row["id2"];
echo $id2;
}
$sql = mysql_query("SELECT * FROM tablename");
$tmp = array();
while($row = mysql_fetch_array($sql)){
$id = $row["id"];
if(!in_array($id, $tmp)) {
$sql_2 = mysql_query("SELECT * FROM secondtable WHERE id != $id ");
while($ro = mysql_fetch_array($sql_2)){
$id2 = $ro["id2"];
echo $id2;
}
$tmp[] = $id;
}
}
Saving all queried $id's in an array to check on the next iteration if it has already been queried. I also think that GROUPing the first query result would be a better way.
I agree with Leonardo Herrera that it's really not clear what you're trying to ask here. It would help if you could rewrite your question. It sounds a bit like you're trying to query one table and not include id's found in another table. You might try something like:
SELECT * FROM secondtable t2
WHERE NOT EXISTS (SELECT 1 FROM tablename t1 WHERE t1.id = t2.id);