Retrieving data from database using prepared statement - php

Question

I'm having problem retrieving my data from my database. Here's my code:
function login($email, $password) {
$stmt = $this->conn->prepare("SELECT id FROM lms_admin_users WHERE email=?");
$stmt->bind_param('s', $email);
$stmt->execute();
$stmt->store_result();
if($stmt->num_rows == 1) {
while ($stmt->fetch()) {
// echo data from table like $data["name"]; <----
}
}
else {
echo "Failed";
}
}
What I want to know is the equivalent of while($data=mysqli_fetch_assoc($result)) to replace my existing code (in OOP way) while ($stmt->fetch()) and make it fetch the datas using $data["name"]

Answer 1

You need to tell PHP in which variable(s) to store the result. There are two ways to do this:
with bind_result, and then fetch on the statement object, or
with get_result, and then fetch_assoc (or other fetch_* variant) on the result object
1. bind_result
With this solution you bind variable(s) to the SELECT list, and while looping with fetch PHP will put the new data in those variable(s):
$stmt = $this->conn->prepare("SELECT id FROM lms_admin_users WHERE email=?");
$stmt->bind_param('s', $email);
$stmt->execute();
$stmt->store_result();
$stmt->bind_result($id, $name); // <- Add; #args = #cols in SELECT
if($stmt->num_rows == 1) {
while ($stmt->fetch()) {
echo $id, $name; // <-- then you can do this.
}
}
2. get_result
Instead of bind_result you can use get_result, which will give a result object which you can fetch each row from as an associative array:
//...
// $stmt->store_result(); // <- Remove: does not work together with next statement
$result = $stmt->get_result(); // <--- add this instead
if($result->num_rows == 1) { // <--- change to $result->...!
while ($data = $result->fetch_assoc()) {
echo $data['id'], $data['name']; // <--- available in $data
}
}