JSON Array of objects with MySql - php

Question

i am trying to get this output from a database of countries. i had use the mysqli_fetch_object() function but it does not work with me
"countries":[{"countryname":"India","flag":"http:\/\/wptrafficanalyzer.in\/p\/demo1\/india.png","language":"Hindi","capital":"New Delhi","currency":{"code":"INR","currencyname":"Rupee"}},{"countryname":"Pakistan","flag":"http:\/\/wptrafficanalyzer.in\/p\/demo1\/pakistan.png","language":"Urdu","capital":"Islamabad","currency":{"code":"PKR","currencyname":"Pakistani Rupee"}}]}
and i am use this php script
<?php
require 'config.php';
$con=mysqli_connect($servername,$username,$password,$db);
if(!$con)
{
die ("Erro in connection" . mysqli_connect_error);
}
else{ $encode = array();
$sql="select * from country ";
$res=mysqli_query($con,$sql);
if(mysqli_num_rows($res)>0)
{
$temp_array=array();
while($row=mysqli_fetch_object($res))
{
//$temp_array[]=$row;
$encode=$row;
}
//echo json_encode($temp_array);
echo json_encode($encode);
}
else
{
echo " 0 Rows";
}
}
?>
if anybody can help me ?

Answer 1

Your code should be something like below;
<?PHP
require 'config.php';
$con=mysqli_connect($servername,$username,$password,$db);
if(!$con)
die ("Error in connection" . mysqli_connect_error);
else{
$encode = array();
$sql = "select * from country ";
$res = mysqli_query($con,$sql);
if(mysqli_num_rows($res)>0)
{
$temp_array=array();
while($row=mysqli_fetch_object($res))
{
$encode[]=$row;
}
}
echo json_encode($encode);
}
?>
You do not need to write down 0 rows because you are returning a json object which has an array so when you check result.length it tells you the row count.
As an advice you may use something like below;
<?php
require 'config.php';
$con = mysqli_connect($servername,$username,$password,$db);
$resultArray = array();
$resultArray["error"] = true; //That will tell your javascript client if any error exits.
$resultArray["errorMessage"] = ""; //We will set this value if any error exits;
if(!$con)
{
$resultArray["error"] = true;
$resultArray["errorMessage"] = "Error in connection" . mysqli_connect_error();
}
else{
$resultArray["error"] = false;
$itemCollection = array();
$sql = "select * from country ";
$res = mysqli_query($con,$sql);
if(mysqli_num_rows($res)>0)
while($row = mysqli_fetch_object($res))
$itemCollection[]=$row;
$resultArray["itemCollection"] = $itemCollection;
}
echo json_encode($resultArray);
?>
In my sample you are going to get a json result something like below;
{"error":true,"errorMessage":"ErrorMessageIfExists","itemCollection":[yourObject,yourObject]}
Hope this helps you.