My product can have many categories. In one part of the object however, I need to get a specific Category. So instead of getting all the categories and then in a for loop search for specific one, I need to get only this specific category. For that I am using query builder.
public function findProduct($id) {
$qb = $this->createQueryBuilder('p')
->addSelect(array('p', 'cat')) // many to many table
->addSelect(array('p', 'category')) // the category entity
->leftJoin('p.category', 'cat')
->leftJoin('cat.category', 'category')
->andWhere("category.id = 15") // error here
->SetParameter('id', $id);
return $qb->getQuery()->getOneOrNullResult();
}
With this query I am easily able to do $product->getCategory[0]([] since array) and get only the category that I need(in this example category with id=15)
THE PROBLEM:
However if the product doesnt have a category with a specific id.. It returns whole product null..
So If i do:
$product = $em->getRepository('MpShopBundle:Product')->findProduct($id); = null
But instead it should be like this:
$product = $em->getRepository('MpShopBundle:Product')->findProduct($id); = object
$product->getCategory() = null
How can I make this work in query builder? Is that even possible?
This should work. Instead of constraining your whole query (which is what that does) just constrain the join).
leftJoin('cat.category', 'category', 'WITH', 'category.id = 15')
This way you should get your product always & category only if id == 15.
Related
Let's say I have Category model with hasMany relation to Product model. Product has color column.
I want to return all categories with all colors that exists in this category, so I tried:
return Category::with(['products' => function ($query) {
$query->distinct('color');
}])->get();
Thanks to this I could later foreach or pluck category->products to get unique colors list. I know I can just get all products in every category, and then filter unique colors, but by doing this I would have to query for example 1000 products per category, instead just 5, which is unnecessary resource heavy. That's why I'm trying to do this on SQL level not PHP.
But this code does not work. There are no errors, it just still returns all products with duplicated colors. Why?
Edit:
Not sure why but my code works if I add select() with used columns before discrinct, and then distinct is making unique rows by all choosed columns. No "color" param required in distinct. Not sure why it works that way, need to dive deeper into SQL docs.
Have you tried this code? Somehow, this will reduce your unnecessary query.
$categories = Category::with([
'products'=> fn($q) => $q->select(['category_id', 'color'])->distinct('color')
])
->select('id') // select required column in categories table
->whereHas('products')
->get();
$colors = $categories->map(function($category) {
return $category->products->pluck('color');
})->toArray();
$color = [];
for ($i=0; $i < count($colors); $i++) {
$color = array_merge($color, $colors[$i]);
}
$uniqueColor = array_unique($color);
return $categories;
I need to make pagination in Laravel, and as I read laravel documentation here is a several way to do it. but in my cases it is a little bit complexity. So let say I've two table in my DB, table1 and table2(many to many relationship), I want to paginate table1 with specific ids. So I mean if table1 contains ids 1,2,3,4,5 ... n, I want to paginate only rows which id is 2 and 3
I have tried :
private function check_wear($type){
$products_id = array(); //here is ids which $type is set as 'ON'
$wears = DB::select("SELECT prod_id FROM wears WHERE ".$type." = 'on' "); //Select specific products ids. (in our case it is **table1**)
foreach ($wears as $wr){
array_push($products_id,$wr->prod_id);
}
return $products_id; //return array with ids which should be paginate
}
public function hat($locale){
$hat_prod_ids = $this->check_wear('coat');
$p=12;
$products = DB::table('products')->paginate($p); // 12 per page
dd($products);
my code only paginate one table with all data, is there any built-in function to somehow write a logic condition? for pagination
If you need to filter your pagination with elements which you've in $hat_prod_ids, you're able to use WhereIn() method, that one checks if your elements (in our case ids) exist in your $hat_prod_ids and returns true or false
$products = DB::table('products')
->whereIn('id',$hat_prod_ids)
->paginate($p);
add that code and now you will be able to paginate only that ids which is matched in your array
I want to get 2 result from a filter query in Laravel version 6. I want to get product table information that user can change item exist in page by a select box with name of pageitemcount and can search by a field with name of select. when user select pageitemcount and also search for an name, submit a form and below query is run . When user search anything, available filter of category must be limited to available categories. I want to show distinct product category in additional to product list.
public function productIndex(Request $request)
{
$take = 10;
$query = Product::query();
if ($request->has('pageitem')){
$take = $request->input("pageitem");
}
// Search
if ($request->has('search')){
$query = $query->where('name', $request->input("search"));
}
$availableCategoriesQuery= $query;
// Get product unique product category to show them to user
// that exist in prodcut list that show to user
$availableCategories = $availableCategoriesQuery->select("category_id")->distinct()->get();
// Get product list by pagination
$productList = $query->paginate($take);
return view('admin.manage_product', ['productList' => $productList, 'availableCategories' => $availableCategories]);
}
but when $availableCategories is executed, affected $query variable, and i cant get right result from next line, i get result of $availableCategories in $productList variable. i do'nt want to repeat my code again, how can i deal with?
the result of $availableCategories is completely true, but result of productList is $availableCategories that is paginated.
OK, I think I see the problem. You are trying to reuse the $query variable. You probably want something like this:
I assume that product_categories is the table for your product categories. You can also use the model if you want.
Also, Since the DB has no intrinsic order, you should specify an OrderBy() as well.
$take = $request->input("pageitem", 10);
$productList = Product::paginate($take)->get();
$availableCategories = DB::table('product_categories')->distinct()->get("category_id");
I'm trying to access the parent value, the posts date, in a nested function.
In my application, a user has many posts, with each post being associated to a product (textbook). Each time someone views a page with the product, a new row is added to the product-views table.
I want to return the cumulative amount of times the users products have been seen. I've been able to get all the users posts, then the associated product, and then the count of all the views of that product.
Now I'd like to add another where() condition to only return views that have occured after the post was created. To do so, I need to get the posts date, e.g. views->product->post, while constructing the query like user->posts->product->views.
// getting all of the users available posts
$user = $request->user()->posts()->available()->with([
// with the textbook (product) associated with the post
'textbook' => function ($q) {
// get the count of textbook-page views
return $q->withCount([
// from the related table views
'views' => function ($q) {
// ===!!! Q !!!=== How do I access the posts (parent (grandparent?)) date, so that I only select the rows that have been viewed after the post was created ===!!!===
->where('date-viewed', '>=', 'posts.date');
},
]);
//some cleanup
}])->distinct()->get()->unique('isbn')->pluck('textbook.views_count')->sum();
How do I go backwards in a nested function to access the posts date?
It looks like as Jonas said in the comments, each with() relationship was a new query, so I ended up creating a hasManyThrough() relationship between the posts and views through the product.
// getting all of the users available posts
$user = $request->user()->posts()->available()->withCount([
'views' => function ($q) {
// ===!!! A !!!=== Fixed ===!!!===
->whereRaw('`date-viewed` >= posts.date');
},
])->distinct()->get()->unique('isbn')->pluck('views_count')->sum();
I have a query as:
$Category = DB::table('food')
->select('food.Food_id','food.FoodName','categories.CategoryName')
->join('categories','categories.Category_id','=','food.Category_id')
->where('categories.CategoryName', '=','Breakfast')
->get();
But I want query based on if condition,meaning that if Category is Breakfast then only food items related to Breakfast are shown or IF Category is Lunch then only food items related to that category are shown.I am using laravel 5.2
Try something like this. You don't have to make a query all at once. You can combine it through several steps. Until you perform get(), find() or something similar in the end, it won't return query results, but only kind of query builder object if I'm not wrong.
// You should probably send this as a method parameter so you can determine if you should get one, or the other category
$cat = 1;
$Category = DB::table('food')
->select('food.Food_id','food.FoodName','categories.CategoryName')
->join('categories','categories.Category_id','=','food.Category_id');
if($cat == 0){
$Category = $Category->where('categories.CategoryName', '=','Breakfast');
}
if($cat == 1){
$Category = $Category->where('categories.CategoryName', '=','Lunch');
}
$Category = $Category->get();