How to solve the key variable on $unset key - php

Question

I am running a PHP script, and keep getting errors like:
Notice: Undefined variable: key in D:\0-MYBLOG\SERVER-MYBLOG\InstantWP_4.3.1\iwpserver\htdocs\wordpress\wp-content\plugins\sama-author-review\admin\metabox.php on line 310
Line 310 looks like this:
unset( $new['items_review'][$key] );
Here the code:
if ( $new['items_review'] && is_array( $new['items_review'] )) {
foreach ( $new['items_review'] as $review ) {
if ( empty( $review['label'] ) ) {
unset( $new['items_review'][$key] );
} else {
$review['value'] = absint( $review['value'] );
$review['label'] = esc_attr( $review['label'] );
if ( empty( $review['slug'] )) {
$review['slug'] = sanitize_title( $review['label'] );
} else {
$review['slug'] = sanitize_title( $review['slug'] );
}
$review['style'] = esc_attr( $review['style'] );
$items_review[$i] = $review;
$i++;
}
}
}
Is there a quick fix to resolve these error?
Really appreciate for any help
Thank you

Answer 1

I think I get what the problem is, you have forgotten to put the key parameter on your foreach statement.
I admit its a bit of a guess as I have no idea what is in $new but it seams a logical possibility.
if ( $new['items_review'] && is_array( $new['items_review'] )) {
// foreach ( $new['items_review'] as $review ) {
// replace foreach with this line
foreach ( $new['items_review'] as $key => $review ) {
if ( empty( $review['label'] ) ) {
unset( $new['items_review'][$key] );
} else {
$review['value'] = absint( $review['value'] );
$review['label'] = esc_attr( $review['label'] );
if ( empty( $review['slug'] )) {
$review['slug'] = sanitize_title( $review['label'] );
} else {
$review['slug'] = sanitize_title( $review['slug'] );
}
$review['style'] = esc_attr( $review['style'] );
$items_review[$i] = $review;
$i++;
}
}
}