Most efficient way to perform query - php

My goal is to get all records from tables where foreign key values match with IDs returned by a subquery from another table.
I have tried several combinations of but they don't even compile.
To clarify, consider following query:
SELECT *
FROM `news`
WHERE IDFIRM IN (SELECT ID FROM firm WHERE Block=0)
AND Actual=1
This is a simple query, but besides the ID in this subquery, I need to also retrieve other columns and return them in response.
Something like this (but of course this doesn't work):
SELECT news.*, sub.name
FROM `news`,
(SELECT * FROM firm WHERE Block=0) AS sub
WHERE news.IDFIRM IN (SELECT sub.ID FROM sub)
AND news.Actual=1
I have an idea how to implement this using joins, but the problem is that there can be multiple IN statements (from different tables), like this:
SELECT *
FROM `news`
WHERE IDFIRM IN (SELECT ID FROM firm WHERE Block=0)
AND Actual=1
AND id_publisher IN (SELECT ID FROM publisher WHERE Block=0)
So this query can become quite different, depending on the request.
How can I create the most efficient query to solve this task? Or it is possible only with multiple queries?
Thanks.

You should definitely use JOIN instead of IN (SELECT ...):
Query 1:
SELECT *
FROM `news`
WHERE IDFIRM IN (SELECT ID FROM firm WHERE Block=0)
AND Actual=1
Replace this by:
SELECT news.*
FROM news
INNER JOIN form ON news.IDFIRM = form.ID
WHERE news.Actual=1
Query 2:
SELECT news.*, sub.name
FROM `news`,
(SELECT * FROM firm WHERE Block=0) AS sub
WHERE news.IDFIRM IN (SELECT sub.ID FROM sub)
AND news.Actual=1
Replace by:
SELECT news.*,
firm.name
FROM news
INNER JOIN firm ON news.IDFIRM = firm.ID
WHERE news.Actual=1
AND firm.Block=0
Query 3:
SELECT *
FROM `news`
WHERE IDFIRM IN (SELECT ID FROM firm WHERE Block=0)
AND Actual=1
AND id_publisher IN (SELECT ID FROM publisher WHERE Block=0)
Replace by:
SELECT news.*
FROM news
INNER JOIN firm ON news.IDFIRM = firm.ID
INNER JOIN publisher ON news.id_publisher = publisher.ID
WHERE news.Actual=1
AND firm.Block=0
AND publisher.Block=0
Adding tables and conditions
So the idea is that you add all the tables you need with clauses like this:
INNER JOIN table1 ON news.<foreign-key> = table1.ID
and that you add the conditions all in the WHEREclause, like this:
WHERE table1.field = <literal>
AND table2.field = <other literal>
AND ...

Assuming your your indexes are sane on both sides of the JOIN they will actually be leveraged, whereas subqueries might use one side.
SELECT [column_list]
FROM news n
INNER JOIN firm f
ON n.idfirm = f.id
INNER JOIN publisher p
ON n.idpublisher = p.id
WHERE n.actual = 1
AND f.block = 0
AND p.block = 0

You are already suggesting a JOIN.
You can use multiple JOIN's to get what you want.
SELECT * FROM news
JOIN firm ON IDFIRM = firm.ID
WHERE Block = 0
JOIN publisher ON id_publisher = publisher.ID
WHERE Block = 0
I'm doing this from memory but should get you close I think.

Related

Error joining 3 tables php/sql

I'm new to this, so I know I'm missing something simple, but I can't figure it out. I'm trying to join 3 tables together and I've got it working with 2 joins, but when combined in the same query, there ends up being an error.
My 3 tables are:
TBL_Authors
Author_ID
Author_Name
TBL_Publishers
Publisher_ID
Publisher_Name
TBL_Books
Title
Author_ID
Publisher_ID
ISBN
Genre
Price
Cost
Rating
What I have that isn't working:
$query = 'SELECT * FROM TBL_PUBLISHERS
JOIN TBL_BOOKS ON TBL_PUBLISHERS.Publisher_ID = TBL_BOOKS.Publisher_ID
SELECT * FROM TBL_AUTHORS
JOIN TBL_BOOKS ON TBL_AUTHORS.Author_ID = TBL_BOOKS.Author_ID
ORDER BY TBL_BOOKS.Title ASC;';
This query assumes that each book was published.
SELECT
*
FROM
TBL_Books b
INNER JOIN TBL_Publishers p ON b.Publisher_ID = p.Publisher_ID
INNER JOIN TBL_Authors a ON b.Author_ID = a.Author_ID
ORDER BY
b.Title
Book will always have an Author, but not necessarily a Publisher, if it's not published. If you need to fetch all the books irrespective of whether published or not, you will have to change INNER join on TBL_Publishers to LEFT.
This Query Will show you the result of all details of book, publisher name, author name.
SELECT
t1.* , t2.Publisher_Name , t3.Author_Name
FROM
TBL_Books as t1
INNER JOIN TBL_Publishers as t2 ON t1.Publisher_ID = t2.Publisher_ID
INNER JOIN TBL_Authors as t3 ON t1.Author_ID = t2.Author_ID
ORDER BY
t1.Title
Check This and update if this query helps you.

Combine two mysql group queries

I'm making a web app to create tournaments and as i have learned PHP in the course of this project, so my skills aren't probably the best.
I have an identifier in my database day2_semifinal or day2_additional which basically identifies the type of semifinal.
So my first query is:
$numberquery = mysql_query("
SELECT *
FROM tourneyplayers
INNER JOIN results
on (resultid=r_id)
INNER JOIN players
ON (p_id=playerid)
INNER JOIN tourneys
on (T_Id=tourneyid)
WHERE tourneyid='$tourneyid' and
in_day2 = 1 and
day2_semifinal IS NOT NULL
GROUP BY day2_semifinal
ORDER BY agegroupid",$connection);
This will get me all the semifinal groups, i'll iterate over them and query all the players in group:
$semigroup = $group['day2_semifinal'];
$playerQuery = mysql_query("
SELECT *
FROM tourneyplayers
INNER JOIN results
on (r_id=resultid)
INNER JOIN players
on (p_id=playerid)
WHERE tourneyid='$tourneyid' AND
day2_semifinal = '$semigroup' and
in_day2 = 1
ORDER BY day2startplace",$connection);
Now after i've created tables and echoed all the data from player queries for day2_semifinal, i run another query:
$numberquery = mysql_query("SELECT * FROM tourneyplayers INNER JOIN results on (resultid=r_id) INNER JOIN players ON (p_id=playerid) WHERE tourneyid='$tourneyid' and in_day2 = 1 and day2_additional_nosemi IS NOT NULL AND day2_additional_nosemi <> 0 GROUP BY day2_additional_nosemi ORDER BY agegroupid",$connection);
Which is fairly similar to the first one, only thing different is day2_semifinal identifiers have changed to day2_additional. After that query, i'll again, iterate over the day2_additional_nosemi groups and query the players inside of them:
$additionalgroup = $group['day2_additional_nosemi'];
$playerQuery = mysql_query("SELECT * FROM tourneyplayers INNER JOIN results on (r_id=resultid) INNER JOIN players on (p_id=playerid) WHERE tourneyid='$tourneyid' AND day2_additional_nosemi = '$additionalgroup' and in_day2 = 1 ORDER BY day2startplace",$connection);
Now this works, but this creates an issue with ordering, since the first query orders them by agegroupid but only for players in day2_semifinal (and i'd like to have day2_additional players ordered together with day2_semifinal). If i run another query the previous data has already been echoed and ordering is not right. How could i concatenate two $numberquery queries in order to select players after them as well?
I'm answering my own question as i figured out a way to do this. What i did, was removed ORDER BYfrom both queries and created a new query which concatenated the two with UNION:
SELECT * FROM (
SELECT *
FROM tourneyplayers as tp1
INNER JOIN results as r1
on (tp1.resultid=r1.r_id)
INNER JOIN players as p1
ON (p1.p_id=tp1.playerid)
WHERE tp1.tourneyid=96 and
tp1.in_day2 = 1 and
r1.day2_semifinal IS NOT NULL
GROUP BY r1.day2_semifinal
UNION ALL
SELECT *
FROM tourneyplayers as tp2
INNER JOIN results as r2
on (tp2.resultid=r2.r_id)
INNER JOIN players as p2
ON (p2.p_id=tp2.playerid)
WHERE tp2.tourneyid=96 and
tp2.in_day2 = 1 and
r2.day2_additional_nosemi IS NOT NULL AND
r2.day2_additional_nosemi <> 0
GROUP BY r2.day2_additional_nosemi
) t ORDER BY t.agegroupid;

UNION SELECT tables with inner join and GET values with "ALIAS"

So I have 2 tables, Matches and Teams, what I want to do is get some values from the match and Inner join "Teams" to get the names of both teams and add them to a php array later on (getting it all in one sql)
Matches
- IDMatch
- IDLocalTeam
- IDVisitorTeam
- Time
- Half
- Stopped
Teams
- IDTeam
- name
What I have by now is
$query = "SELECT * FROM `Matches`
INNER JOIN `Teams` ON `Matches`.IDLocalTeam = `Teams`.IDTeam
UNION SELECT * FROM `Matches` INNER JOIN `Teams`
ON `Matches`.IDVisitorTeam = `Teams`.IDTeam
ORDER BY IDMatch DESC;";
If someone could help me it would be great! Thanks alot
Wouldn't it be easier to use INNER JOIN twice? It's definitely quicker way of doing joins anyway.
SELECT
*
FROM
`Matches` m
INNER JOIN `Teams` t1
ON m.IDLocalTeam = t1.IDTeam
INNER JOIN `Teams` t2
ON m.IDVisitorTeam = t2.IDTeam
ORDER BY
m.IDMatch DESC;
Also start using aliases instead of table names to identify fields in query, it will SQL much smaller.

MySQL Using SUM with multiple joins

I have a projects table and a tasks table I want to do a query that gets all projects and the sum of the time_spent columns grouped by project id. So essentially list all projects and get the total of all the time_spent columns in the tasks table belonging to that project.
With the query posted below I get the latest added time_spent column and not the sum of all the columns.. :S
Below is the query I have at the moment:
SELECT `projects`.`id`, `projects`.`description`, `projects`.`created`,
`users`.`title`, `users`.`firstname`, `users`.`lastname`, `users2`.`title`
as assignee_title, `users2`.`firstname` as assignee_firstname,
`users2`.`lastname` as assignee_lastname,
(select sum(tasks2.time_spent)
from tasks tasks2
where tasks2.id = tasks.id)
as project_duration
FROM (`projects`)
LEFT JOIN `users`
ON `users`.`id` = `projects`.`user_id`
LEFT JOIN `users` as users2
ON `users2`.`id` = `projects`.`assignee_id`
LEFT JOIN `tasks` ON `tasks`.`project_id` = `projects`.`id`
GROUP BY `projects`.`id`
ORDER BY `projects`.`created` DESC
Below is my projects table:
Below is my tasks table:
Thanks in advance!
Usually this query will help you.
SELECT p.*, (SELECT SUM(t.time_spent) FROM tasks as t WHERE t.project_id = p.id) as project_fulltime FROM projects as p
In your question, you don't say about users. Do you need users?
You are on right way, maybe your JOINs can't fetch all data.
This query should do it for you.
Note, whenever you do a group by you must include every column that you select from or order by. Some MySql installations don't prevent you from doing this, but in the end it results in an incorrect result set.
As well you should never do a query as part of your SELECT statement, known as a sub-query, as it will result in an equal amount of additional queries in relation to the number of rows returned. So if you got 1,000 rows back, it would result in 1,001 queries instead of 1 query.
SELECT
p.id,
p.description,
p.created,
u.title,
u.firstname,
u.lastname,
a.title assignee_title,
a.firstname assignee_firstname,
a.lastname assignee_lastname,
SUM(t.time_spent) project_duration
FROM
projects p
LEFT JOIN
users u ON
u.id = p.user_id
LEFT JOIN
users a ON
a.id = u.assignee_id
LEFT JOIN
tasks t ON
t.project_id = p.id
GROUP BY
p.id,
p.description,
p.created,
u.title,
u.firstname,
u.lastname,
a.title,
a.firstname,
a.lastname
ORDER BY
p.created DESC

write mysql query using inner joins for three tables

I have the following query which works perfectly:
SELECT *
FROM contacts
WHERE id in (
SELECT DISTINCT contacts.id
FROM contacts
INNER JOIN contacts2tags
ON contacts.id = contacts2tags.contactid
WHERE tagid in(7,4)
)
Here contacts table contains id, first_name, last_name, ..and tags table contains id, name. contacts2tags table contains contactid and tagid which are same as contacts.id and tags.id respectively
Now, what I want is, to display only the contacts which have both a tagid 7 and a tagid 4.
I tried something like this:
SELECT *
FROM contacts
WHERE id IN
(
SELECT CT1.contactid
FROM
tags T1, contacts2tags CT1, tags T2, contacts2tags CT2
WHERE CT1.contactid = CT2.contactid
AND CT1.tagid = T1.id
AND CT2.tagid = T2.id
AND (T1.id = 7 AND T2.id = 4)
and it works too.
My problem is, I want to convert the above second query to one using inner joins.
I have an array of ids stored in $tmp in php
I want to use those ids and write the above query for them.
How do I do that? I am not comfortable with sql. Might be its a very simple thing to ask.
Thanks in advance
EDIT:
The answer below solved the problem. But the sql runs very slow for 10k records. Any suggestions to optimise it? Pasting the updated query as given in the answer.
SELECT c.id
FROM contacts c
inner join contacts2tags t on c.id = t.contactid
where t.tagid in (7,4)
group by c.id
having count(distinct t.tagid) = 2
This should work
SELECT c.id
FROM contacts c
inner join contacts2tags t on c.id = t.contactid
where t.tagid in (7,4)
group by c.id
having count(distinct t.tagid) = 2

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