SQL query in php function 500 server error [duplicate] - php

Question

This question already has answers here:
Giving my function access to outside variable
(6 answers)
Closed 7 years ago.
I ran into a very strange thing.
This throws an 500 server error:
function writeMsg() {
$id='0000000625';
$translation = 'word';
try {
$stmt = $conn->prepare("UPDATE table SET HUN=? WHERE ID=?");
$stmt->execute(array($translation,$id));
$response["success"] = 1;
} catch(PDOException $e) {
echo 'ERROR: ' . $e->getMessage();
$response["success"] = 0;
}
echo 'RESPONSE: '.$response["success"];
}
writeMsg();
This runs fine:
$id='0000000625';
$translation = 'word';
try {
$stmt = $conn->prepare("UPDATE table SET HUN=? WHERE ID=?");
$stmt->execute(array($translation,$id));
$response["success"] = 1;
} catch(PDOException $e) {
echo 'ERROR: ' . $e->getMessage();
$response["success"] = 0;
}
echo 'RESPONSE: '.$response["success"];
I only removed the first and the last 2 lines.
Does anyone has an explanation to this?

Answer 1

You've probably missed the $conn variable scope
function writeMsg() {
global $conn;
$id = '0000000625';
$translation = 'word';
try {
$stmt = $conn->prepare("UPDATE table SET HUN=? WHERE ID=?");
$stmt->execute(array($translation, $id));
$response["success"] = 1;
} catch(\PDOException $e) {
echo 'ERROR: ' . $e->getMessage();
$response["success"] = 0;
}
echo 'RESPONSE: ' . $response["success"];
}
writeMsg();
Just use global $conn to retrieve the $conn variable from the global scope. Check more at http://php.net/manual/en/language.variables.scope.php for global keyword