How to find specific day from years given PHP? - php

Question

I am looking on how to get specific day from time given :
let's say I have 2 dates : 1 Jan 2016 until 1 Jan 2017, I will need to know how many Mondays are there, or Tuesdays or any days that I select on the input I gave.
Is there any best way to achieve this ?

Answer 1

UPDATED ANSWER
<?php
$count = 0;
$days = array("Monday", "Friday");
foreach ($days as $day) {
$startDate = '1 Jan 2016';
$endDate = '1 Jan 2017';
$endDate = strtotime($endDate);
$i = '';
for ($i = strtotime($day, strtotime($startDate)); $i <= $endDate; $i = strtotime('+1 week', $i)) {
echo date('l Y-m-d', $i) . '<br>';
$count++;
}
}
echo $count;

Answer 2

Try modify this example:
<?php
//http://php.net/manual/en/class.dateperiod.php#109846
$begin = new DateTime( '2012-08-01' );
$end = new DateTime( '2012-08-31' );
$end = $end->modify( '+1 day' );
$interval = new DateInterval('P1D');
$daterange = new DatePeriod($begin, $interval ,$end);
foreach($daterange as $date){
//HERE ADD YOUR CONDITIONS...
echo $date->format("Ymd") . "<br>";
}
?>
You can reviewer this solution PHP create range of dates

Answer 3

get all days and loop through them all, get the first Monday after the start date and then iterate 7 days at a time:
$endDate = strtotime($endDate);
for($i = strtotime('Monday', strtotime($startDate)); $i <= $endDate; $i =strtotime('+1 week', $i))
echo date('l Y-m-d', $i);