Warning: mysql_close(): 4 is not a valid MySQL-Link resourc - php

Question

Friends please help me out here
My Config File config.php
**<?php
define('DB_SERVER', 'localhost'); // Mysql hostname, usually localhost
define('DB_USERNAME', 'gani'); // Mysql username
define('DB_PASSWORD', 'gani'); // Mysql password
define('DB_DATABASE', 'gani'); // Mysql database name
$connection = mysql_connect(DB_SERVER, DB_USERNAME, DB_PASSWORD) or die(mysql_error());
$database = mysql_select_db(DB_DATABASE) or die(mysql_error());
?>
My php file
**function instcount($updateid,$position)
{
include "config.php";
global $connection;
$sel=mysql_query("select * from register where regid='$updateid'");
$getcount=mysql_num_rows($sel);
$rowss=mysql_fetch_array($sel);
//print_r($rowss);
if($getcount==0)
{
$insert=mysql_query("insert into register (regid,dtentered) values ('$updateid',CURDATE())");
}
else
{
$update=mysql_query("update dailycount set net=100 where regid='$updateid'");
}
$selw=mysql_query("select sid,position from register where regid='$updateid'");
$rowd=mysql_fetch_array($selw);
if($rowd['sid']!='admin' && $rowd['sid']!="")
{
instcount($rowd['sid'],$rowd['position']);
}
//return 0;
mysql_close($connection);
}
$updated="10000";
$upfun=instcount($updated,$position);**
When i run above script I am getting below error
Warning: mysql_close(): 4 is not a valid MySQL-Link resource
Any one please help me out....

Answer 1

The problem is the
global $connection;
line of the code. You include the file within the function and according to php manual on include:
When a file is included, the code it contains inherits the variable
scope of the line on which the include occurs.
This means, that the $connection variable becomes a local variable, since the include is within the function.
Either move the include out of the function or delete the global $connection; line from your code.