I have an array that looks like this
"name" => array:3 [
1 => "Hello"
4 => "Test"
21 => "Test2"
]
"runkm" => array:3 [
1 => "100.00"
4 => "1000.00"
21 => "2000.00"
]
"active" => array:3 [
1 => "1"
4 => "0"
21 => "0"
]
Can i somehow combine the matching keys with a PHP function so that the array would look like this instead
1 => array:3 [
name => "Hello"
runkm => "100.00"
active => "1"
]
4 => array:3 [
name => "Test"
runkm => "1000.00"
active => "0"
]
21 => array:3 [
name => "Test2"
runkm => "2000.00"
active => "0"
]
EDIT: Thanks for all the answers guys. What i was really looking for was a PHP built in function for this, which i probably should have been more clear about.
$newArr=array();
foreach($array1 as $key => $value){
$newArr[$key]=>array(
'name' =>$value[$key];
'runkm' =>$array2[$key];
'active'=>$array3[$key];
);
}
this is how you make a new array and then print the $newArr and check you get what you want or not? Good Luck!
<?php
$resultarr = array();
for($i=0;$i<count($sourcearr['name']);$i++) {
$resultarr[] = array('name'=>$sourcearr['name'][$i], 'runkm'=>$sourcearr['runkm'][$i], 'active'=>$sourcearr['active'][$i]);
}
This works well. And also, doesn't use hard coded keys.
<?php
$arr = [
"name" => [
1 => "Hello",
4 => "Test",
21 => "Test2"
],
"runkm" => [
1 => "100.00",
4 => "1000.00",
21 => "2000.00"
],
"active" => [
1 => "1",
4 => "0",
21 => "0"
]
];
// Pass the array to this function
function extractData($arr){
$newarr = array();
foreach ($arr as $key => $value) {
foreach($value as $k => $v) {
if(!isset($newarr[$k]))
$newarr[$k] = array();
$newarr[$k][$key] = $v;
}
}
return $newarr;
}
print_r(extractData($arr));
?>
I'm not sure if there's a function that does that in PHP but maybe you can try this
$arr1 = array(
"name" => array(
1 => "hello",
4 => "test",
21 => "test2",
),
"runKm" => array(
1 => "100",
4 => "200",
21 => "300",
),
"active" => array(
1 => "1",
4 => "0",
21 => "0",
),
);
// declare another that will hold the new structure of the array
$nArr = array();
foreach($arr1 as $key => $val) {
foreach($val as $sub_key => $sub_val) {
$nArr[$sub_key][$key] = $sub_val;
}
}
what this does is simply loop thru each array and its values and assign it to another array which is the $nArr. I hope it helps.
Related
I have an array with fields
[
"house" => "30|30|30",
"street" => "first|second|third",
...
]
I want to get array
[
[
"house" => "30",
"street" => "first",
...
],
[
"house" => "30",
"street" => "second",
...
],
[
"house" => "30",
"street" => "third",
...
]
]
I know how I can solve this using PHP and loop, but maybe this problem has more beautiful solution
use zip
$data = [
"house" => "30|30|30",
"street" => "first|second|third",
];
$house = collect(explode('|',$data['house']));
$street = collect(explode('|',$data['street']));
$out = $house->zip($street);
$out->toarray();
Here's something I managed to do with tinker.
$original = [
"house" => "30|30|30",
"street" => "first|second|third",
];
$new = []; // technically not needed. data_set will instantiate the variable if it doesn't exist.
foreach ($original as $field => $values) {
foreach (explode('|', $values) as $index => $value) {
data_set($new, "$index.$field", $value);
}
}
/* dump($new)
[
[
"house" => "30",
"street" => "first",
],
[
"house" => "30",
"street" => "second",
],
[
"house" => "30",
"street" => "third",
],
]
*/
I tried using collections, but the main problem is the original array's length is not equal to the resulting array's length, so map operations don't really work. I suppose you can still use each though.
$new = []; // Since $new is used inside a Closure, it must be declared.
collect([
"house" => "30|30|30",
"street" => "first|second|third",
...
])
->map(fn($i) => collect(explode('|', $i))
->each(function ($values, $field) use (&$new) {
$values->each(function ($value, $index) use ($field, &$new) {
data_set($new, "$index.$field", $value);
});
});
$array = ["house" => "30|30|30","street" => "first |second| third"];
foreach($array as $key=> $values){
$explodeval = explode('|',$values);
for($i=0; $i<count($explodeval); $i++){
$newarray[$i][$key]= $explodeval[$i];
}
}
output:
Array
(
[0] => Array
(
[house] => 30
[street] => first
)
[1] => Array
(
[house] => 30
[street] => second
)
[2] => Array
(
[house] => 30
[street] => third
)
)
i have 1 array like below :
0 => array:4 [
"id" => "1"
"date" => "2021-08-03"
"from_time" => "09"
"to_time" => "14"
]
1 => array:4 [
"id" => "2"
"date" => "2021-08-03"
"from_time" => "09"
"to_time" => "14"
]
now what i want to do ?? as you can see the date and from_time and to_time have the same value . i want to merge them to 1 item like below :
0 => array:4[
"date" => "2021-08-03"
"from_time" => "09"
"to_time" => "14"
"id" => ["1" , "2"]
].
so i can have the same day ids in 1 index of array and if for example the same date and time got 4 ids i get the id key with 4ids . i used array_merge_recursive but it didnt help me with the same keys of an array
this is how i am building the array :
foreach ($arrays as $key => $array) {
$options[$key]['id'] = last(str_split($array['id']));
$options[$key]['date'] = substr($array['id'],0,-2);
$options[$key]['from_time'] = Carbon::createFromTimestamp($array['pickup']['from'])->format('H');
$options[$key]['to_time'] = Carbon::createFromTimestamp($array['pickup']['to'])->format('H');
}
. thanks in advance for help
<?php
//define items
$items = [
[
"id" => "1",
"date" => "2021-08-03",
"from_time" => "09",
"to_time" => "14",
],[
"id" => "2",
"date" => "2021-08-03",
"from_time" => "09",
"to_time" => "14",
]
];
$options = [];
//loop through the items
foreach ($items as $item) {
//set up the hashing key to use to locate if we hit dup entry
$key = "{$item['date']}-{$item['from_time']}-{$item['to_time']}";
//if indexing key not in options = never looked at it before
if (!array_key_exists($key, $options)) {
//have the key points to the current entry
$options[$key] = $item; //attach the whole item to it
//we want the id to be an array to initialize it to be one
$options[$key]['id'] = [];
}
//gets here then we know options[$key] exists
//if the item id not in the id array of our dict
if (!in_array($item['id'], $options[$key]['id'])) {
//add to it
$options[$key]['id'][] = $item['id'];
}
}
//array_values to get the values and not worry about the keys
print_r(array_values($options));
You can do something like this:
$arr = [
[
"id" => "1",
"date" => "2021-08-03",
"from_time" => "09",
"to_time" => "14"
],
[
"id" => "2",
"date" => "2021-08-03",
"from_time" => "09",
"to_time" => "14"
],
[
"id" => "3",
"date" => "2021-08-03",
"from_time" => "14",
"to_time" => "16"
]
];
$res = array_reduce($arr, function($carry, $entry) use(&$arr) {
$matches = array_filter($arr, function($item) use($entry) {
return $item['from_time'] === $entry['from_time'] && $item['to_time'] && $entry['to_time'];
});
//print_r([ $entry['id'], $matches ]);
foreach($matches as $match) {
unset($arr[array_search($match['id'], array_column($matches, 'id'))]);
}
if (!count($matches)) {
return $carry;
}
$carry[] = [
'id' => array_column($matches, 'id'),
'date' => $entry['date'],
'from_time' => $entry['from_time'],
'to_time' => $entry['to_time'],
];
return $carry;
}, []);
I am having three arrays
topicsSelected
relavantGroups
topicAssingned
$topicsSelected = [ "T-100","T-600"];
$relavantGroups = [
[ "id" => "G-001","name" => "3 A","active" => false ],
["id" => "G-002","name" => "3 B","active" => false]
];
$topicAssingned = [
"G-001" => [
"groupID" => "G-001",
"groupName" => "3 A",
"topics" => [
"T-100" => [
"topicID" => "T-100"
],
"T-200" => [
"topicID" => "T-200"
]
]
],
"G-002" => [
"groupID" => "G-002",
"groupName" => "3 B",
"topics" => [
"T-400" => [
"topicID" => "T-400"
],
"T-500" => [
"topicID" => "T-500"
]
]
],
];
$topicsSelected array values at least one value should present $topicAssingned means based on groupID, i have to push one value to $relavantGroups like disable : D suppose value not present means disable : A
Expected output:
[
"id" => "G-001",
"name" => "3 A",
"active" => false,
"disable" => "D"
],
[
"id" => "G-002",
"name" => "3 B",
"active" => false,
"disable" => "A"
]
<?php
$topicsSelected = [ "T-100","T-600"];
$relavantGroups = [
[ "id" => "G-001","name" => "3 A","active" => false ],
["id" => "G-002","name" => "3 B","active" => false]
];
$topicAssigned = [
"G-001" => [
"groupID" => "G-001",
"groupName" => "3 A",
"topics" => [
"T-100" => [
"topicID" => "T-100"
],
"T-200" => [
"topicID" => "T-200"
]
]
],
"G-002" => [
"groupID" => "G-002",
"groupName" => "3 B",
"topics" => [
"T-400" => [
"topicID" => "T-400"
],
"T-500" => [
"topicID" => "T-500"
]
]
],
];
$topic_selected_map = [];
foreach($topicsSelected as $each_topic){
$topic_selected_map[$each_topic] = true;
}
$relevant_group_map = [];
foreach($relavantGroups as $each_group){
$relevant_group_map[$each_group['id']] = $each_group;
}
$result = [];
foreach($topicAssigned as $each_assigned_topic){
if(!isset($relevant_group_map[$each_assigned_topic['groupID']])) continue;
$topics_not_found = true;
foreach($each_assigned_topic['topics'] as $each_topic => $topic_details){
if(isset($topic_selected_map[$each_topic])){
$topics_not_found = false;
break;
}
}
$result[] = [
'id' => $each_assigned_topic['groupID'],
'name' => $each_assigned_topic['groupName'],
'active' => $relevant_group_map[$each_assigned_topic['groupID']]['active'],
'disable' => ($topics_not_found === true ? 'A' : 'D')
];
}
print_r($result);
Output:
Array
(
[0] => Array
(
[id] => G-001
[name] => 3 A
[active] => false
[disable] => D
)
[1] => Array
(
[id] => G-002
[name] => 3 B
[active] => false
[disable] => A
)
)
First, make a map(associative array) of values of $topicsSelected. Same goes for $relavantGroups. This is to make the check more efficient. See more on Hash Table.
Now, iterate over $topicAssigned and then iterate over each group's topics inside it. Now, check if a topic exists inside $topicsSelected using a simple isset function. If yes, we disable them, else we don't.
It's not very clear what you are asking and the code is a bit weird but I'll give it a try.
First fix your array declaration - you should use => and not :;
You have to Iterate over the $relavantGroups and for each element iterate the $topicAssingned array. Then perform a simple comparison to see if the group Id is present and you are done!
Here is my solution (quick and dirty): You can see it here
foreach ($relavantGroups as &$g) {
$found = false;
foreach ($topicAssingned as $key => $assigned) {
if ($key === $g["id"] && is_array($assigned["topics"])) {
foreach ($assigned["topics"] as $topic) {
if (in_array($topic["topicID"], $topicsSelected)) {
$found = true;
break;
}
}
}
}
$g["disable"] = $found ? "D" : "A";
}
var_dump($relavantGroups);
Updated the solution - note that I'm using in_array() to determine if the topicID is present. That mean that any value that is in the $topicsSelected array will affect the result.
Hope I helped.
This will output (based one your example):
array(2) {
[0]=> array(4) {
["id"]=> string(5) "G-001"
["name"]=> string(3) "3 A"
["active"]=> bool(false)
["disable"]=> string(1) "D"
}
[1]=> array(4) {
["id"]=> string(5) "G-002"
["name"]=> string(3) "3 B"
["active"]=> bool(false)
["disable"]=> string(1) "A"
}
}
This question already has answers here:
Merge two 2d arrays by shared column value
(6 answers)
Closed 5 months ago.
i want to join two arrays where 1 key should join them.
array:1 [
0 => array:2 [
"MONAT" => "AUG"
"MAIL_CNT" => "2"
]
1 => array:2 [
"MONAT" => "JUL"
"MAIL_CNT" => "1"
]
]
array:2 [
0 => array:2 [
"MONAT" => "AUG"
"ORDER_CNT" => "18"
]
1 => array:2 [
"MONAT" => "JUL"
"ORDER_CNT" => "1"
]
]
The result should be something like
array:1 [
0 => array:2 [
"MONAT" => "AUG"
"MAIL_CNT" => "2"
"ORDER_CNT" => "18"
]
1 => array:2 [
"MONAT" => "JUL"
"MAIL_CNT" => "1"
"ORDER_CNT" => "1"
]
]
I cant figure out what to do.
Thanks in advance and greetings !
use array_replace_recursive
$array = array_replace_recursive($a1, $a2);
you should use php array_replace_recursive() for this
$arr1=array(
0 =>array(
"MONAT" => "AUG",
"MAIL_CNT" => "2"
),
1 => array(
"MONAT" => "JUL",
"MAIL_CNT" => "1"
)
);
$arr2=array(
0 => array(
"MONAT" => "AUG",
"ORDER_CNT" => "18"
),
1 => array(
"MONAT" => "JUL",
"ORDER_CNT" => "1"
)
);
$array = array_replace_recursive($arr1, $arr2);
echo"<pre>"; print_r($array);
$mergedArray = array();
foreach( $arr1 as $key => $row) {
$mergedArray[$key] = array_merge($arr2[$key], $row)
}
hope this helps
1st : simple use array_merge
2nd : & means it is passed by reference instead of value
foreach( $array1 as $key => &$val) {
$val = array_merge($val,$array2[$key]);
}
print_r($array1);
Note : Above code will work only if both array count is same otherwise it will throw the error .
I have the following 2D array and I would like to get the key of the smalest value in the [0] column if done is equal to no
$graph= array(
"CityA" => array(
"0" => "1",
"1" => "CityC",
"done" => "no",
),
"CityB" => array(
"0" => "4",
"1" => "CityA",
"done" => "no",
),
"CityC" => array(
"0" => "5",
"1" => "CityA",
"done" => "no",
),
);
Try this,
$arr = array_map(function($v){return $v[0];}, $graph);
$key = array_keys($arr, min($arr));
Here you go.
$tes = min( array_column( $graph, 0 ) );
$key = array_search( $tes, array_column( $graph, 0 ) );
$array_keys = array_keys($graph);
echo $array_keys[$key];
You should perform all of your checks in a single pass through your array.
My snippet will provide the first qualifying (contains the lowest [0] value AND has a done value of no) row's key.
Code: (Demo)
$graph = [
"CityB" => ["0" => "1", "1" => "CityA", "done" => "no"],
"CityA" => ["0" => "1", "1" => "CityC", "done" => "no"],
"CityD" => ["0" => "1", "1" => "CityD", "done" => "yes"],
"CityC" => ["0" => "5", "1" => "CityA", "done" => "no"]
];
$result = [];
foreach ($graph as $key => $row) {
if ($row['done'] === 'no' && (!isset($result[$key]) || $row[0] < $result[$key])) {
$result[$key] = $row[0];
}
}
echo key($result) ?? 'No "done => no" rows';
Output:
CityB