I want to format a floating number, like this :
Input : 1.7
output : 01.70
I have already tried below function.
sprintf("%02.02f", 1.7);
Please help.
Try:
sprintf('%05.2f', 1.7);
Explanation
This forum post pointed me in the right direction: The first number does neither denote the number of leading zeros nor the number of total charaters to the left of the decimal seperator but the total number of characters in the resulting string!
Example
sprintf('%02.2f', 1.7); yields at least the decimal seperator "." plus at least 2 characters for the precision. Since that is already 3 characters in total, the %02 in the beginning has no effect. To get the desired "2 leading zeros" one needs to add the 3 characters for precision and decimal seperator, making it sprintf('%05.2f', 1.7);
Try this
sprintf('%05.2f', 1.7);
Are you tried with str_pad()? It's for strings, and that's what you need, because $var = 001 is an octal and $var = "001" is a string.
$input = 1.7;
$output = str_pad($input, "0", 2, STR_PAD_BOTH)
Related
I am working on a PHP-script that handles monetairy amounts, and therefore needs to be exact with 2 decimals. To do this, I convert the user-input to a number by multiplying it with 100, and then casting it to int. This works fine, untill I recently discovered a number that increases by 1 when cast to int.
the malfunctioning code:
$number = (int)(str_replace(',','.',$_POST["input"])*100);
The number that gives problems is 2509,22 (I live in the Netherlands, so we use comma's for decimals, hence the str_replace in the above line of code).
This value creates the integer $number 250921, which is obviously 1 too low.
I know that int has limits, but this number is well within those limits as far as I'm aware...
When you multiply the string by 100 you get a float and its representation is not always what you expect, in this case 250921.99999999997. See it with:
echo serialize(str_replace(',','.','2509,22')*100);
Then you cast to an integer which trucates the fraction to get 250921. See Is floating point math broken?.
The solution would be to remove the comma and use as is and optionally cast to an integer:
$number = (int)str_replace(',', '', '2509,22');
For the issue of users entering too many fractional numbers, you should either use two inputs, one for whole number and one for fraction and/or restrict/validate that the inputs are correctly formatted. However, you can format the number first:
echo $number = (number_format(str_replace(',', '.', '2509,22'), 2, '.', '')*100);
You can use regex to match the int and zero - two decimals.
This will not do any conversions and nothing is multiplied or casted.
It will be treated as a string and nothing changes but the number of decimals.
$input = "2509,2222222";
// Regex number comma number (zero - two)
Preg_match("/(\d+),*(\d{0,2})/", $input, $m);
Unset($m[0]); // remove full match
Echo implode("", $m); // implode parts
https://3v4l.org/MjcYV
Scenario:
To trim leading zeros from positive and negative floating point numbers
Input:
000.123
00.123
01.123
-001.123
-00.123
-040.123
Desired output:
0.123
0.123
1.123
-1.123
-0.123
-40.123
Question:
Is there an inbuilt function which will make this specific formatting easier and more efficient than running each number through combinations of substr(), strpos(), explode() and if statements?
I guess your numbers are saved as a string, so in order to get your output you just simple cast them to a float or double like this:
echo (float) $number;
For more information about casting see the manual: http://php.net/manual/en/language.types.type-juggling.php#language.types.typecasting
Just cast it as float
Like this example:
<?php
$number = '-000.220';
echo (float)$number;
This way you remove all leading zeros, either being a positive or negative number
I have been handling long numbers in PHP. Like the following examples.
12.020000
12.000000
To get rid of trailing zeros and the decimal point I have been using the following inside a function.
return rtrim(rtrim($str, "0"),".");
So the above turns out like.
12.02
12
It was a bit short sighted as when 1000 gets entered it gets turned into 1.
Can someone please help me with the code to remove trailing zeros after the decimal point only?
Bonus points if the code removes the decimal place but I can always feed it into rtim($str,".").
EDIT: To be clear, I am stripping the decimal place and zeros only when displaying to the screen. Also casting to float is not an option as I also handle numbers like 0.00000001 which come out like 1.0e-9 sort of thing.
Why are you using string to hold numbers? Cast it to float and it'll solve your problem.
$string = '12.020000';
$number = (float) $string; // will be 12.02
Then, if you want to use it as string (but why?)
$string = (string) $number;
The thing that perplexes me about your question is that extra zeros won't be included in a number variable without intentionally adding them with number_format. (This may be why someone down-voted it).
Normally you don't want to use string functions (meant for text) on variables that hold numbers. If you want to round off a number, use a function like round.
http://php.net/manual/en/function.round.php
There's also number_format, which can format numbers by adding zero padding: (it doesn't actuall round, just trims off excess numbers).
http://php.net/manual/en/function.number-format.php
Since your zeros are appearing, it's likely that you simply need to multiple the variable by 1, which will essentially convert a string to a number.
Good luck!
I would like to format numbers, so numbers woul format like this:
1=1
10=10
100=100
1000=1,000
10000=10,000
100000=100,000
1000000=1,000,000
I think it can be done with number_format(), but right now I`m having a problem, so if the number is 35679 it shows 35,679,000.
If you want 35679 to show up as 35,679:
number_format(35679,0,'',',');
First parameter is the input number. Second is the amount of decimals. Third is the decimal separator (not needed without decimals).
Last is the thousands separator.
(You probably set the number of decimals to 3)
Please see THIS for a complete explanation of number_format().
For example you would need number_format($number, 0) if the default settings are present or number_format($number, 0, '.', ',') for comma to be used as thousand seperator.
I now want to know that means this line:
printf("Answer: %00010.6f", 22);
He prints: 022.000000. But way? i know whar 6f means float.
thansk for answers
After initially thinking this was C (result of long habit), I realize this is for PHP. Mostly the same, but the constant seems to be handled differently.
Anyway, the parameters in your code break down as follows:
f = print the number as a floating point
10 = total field width of ten digits
000 = print up to 3 leading zeros when applicable (i.e. if there aren't 3 significant figures left of the decimal point)
. = use a dot as the decimal separator
6 = six places after the decimal
It seems the printing parameters for PHP's printf are actually on the sprintf page.
The printf() syntax and meanings are very well-documented. Look at the printf(3) man page or the Wikipedia printf entry.
The particular example you gave means: print a floating point number. Give it 6 characters after the decimal point. Then prefix it with zeros until it is at least 10 characters.
this format string means:
use 0 as filling character
fill to a minimum of 3 characters before the . ( 2 -> 002, 23 -> 023, longer numbers stay as they are)
display exactly 10 characters (including the delimiter)
use . as decimal delimiter
display 6 digits after the delimiter
type float
printf("Answer: %f", 22) would enter the number 22 to the string "Answer: %f" in the place of the "%f" and print it as a float ("f" is for "float").
The numbers between the "%" and the "f" are to set the format - the number of digits that the printout will have.