How can I echo out the selected date - php

Question

does anyone know how I would echo out the selected date as text with the date month and year separated outside of the form? I tried echoing out $date $month and $year outside of the form however this doesn't give me the correct date thankyou for the help
<?
$date = array('16-01-14','16-01-28','16-02-14','16-02-28','16-03-14','16-03-28','16-04-14','16-04-28',
'16-05-14','16-05-28','16-06-14','16-06-28','16-07-14','16-07-28','16-08-14','16-08-28','16-09-14','16-09-28','16-10-14','16-10-28',
'16-11-14','16-11-28','16-12-14','16-12-28');
$currentdate = date('y-m-d');
echo $currentdate;
?>
<form>
<select style="width:200px;">
<?php
foreach ($date as $i => $d) {
if ($currentdate >= $d && ($i == count($date)-1 || $currentdate < $date[$i+1])) {
$selected = "selected";
} else {
$selected = "";
}
list($year, $month, $day) = explode('-', $d);
echo "<option $selected>" . date("m/d/Y", strtotime($d)) . "</option>";
echo 'the current billing period is';
}
?>
</select>
</form>

Answer 1

Inside of your loop add a $selected_int variable like so:
foreach ($date as $i => $d) {
if ($currentdate >= $d && ($i == count($date)-1 || $currentdate < $date[$i+1])) {
$selected = "selected";
$selected_int = $i;
} else {
$selected = "";
}
list($year, $month, $day) = explode('-', $d);
echo "<option $selected>" . date("m/d/Y", strtotime($d)) . "</option>";
echo 'the current billing period is';
}
Then, you can reference it like:
echo date('Y-m-d', strtotime($date[$selected_int]));
Addition
I know you've already accepted the answer, but I also wanted to make a suggestion now that I see what you are using the $date for. Since you know the start date, and it is in 14-day periods, it would be easy to write that as part of the loop.
$start_date = date('Y-m-d', strtotime(date('Y').'-01-01'); //First day of the year, for the sake of argument.
$interval = 14;
for ($i = 0; date('Y') == date('Y', strtotime($start_date.' +'.($i * $interval).' days')); $i++) {//While this year is equal to the start date's year with the added interval [If I knew what your logic here was I could offer a better suggestion]
if ($currentdate >= date("Y-m-d", strtotime($start_date.' +'.($i * $interval).' days')) && (date('Y') < date("Y", strtotime($start_date.' +'.(($i + 1) * $interval).' days')) || $currentdate < date("m/d/Y", strtotime($start_date.' +'.(($i + 1) * $interval).' days')))) {
$selected = "selected";
$selected_int = $i;
} else {
$selected = "";
}
echo "<option $selected>" . date("m/d/Y", strtotime($start_date.' +'.($i * $interval).' days')) . "</option>";
}
Basically, this takes the start date, shows it as the first date option, then adds 14 days to it with each pass through. Your if/else statement should still be the same. It checks to see if you are on the last interval of the year, or if the current date is less than the next interval, and also that the current date is greater than the current interval.
After your loop, you can get the date by:
echo date("m/d/Y", strtotime($start_date.' +'.($selected_int * $interval).' days'));
I know it seems like a lot, but it would save you from having to make a date array to begin with.

Answer 2

Use strtotime instead list.
....
// list($year, $month, $day) = explode('-', $d);
echo "<option $selected>" . date("m/d/Y", strtotime($d)) . "</option>";
....
EDIT: Additional information - your code requires a lot modification and likely some structure changes but assuming this is for testing a method and "how to do" instead a final product.
You need to submit the selected date, catch it in the script and use the selected date to do what you need - i.e. retrieve data from database - and this should give you some idea.
<?php
// You need to create these dates by using another method. You cannot hard code these. You can create it with date functions easily.
$date = array('16-01-14','16-01-28','16-02-14','16-02-28','16-03-14','16-03-28','16-04-14','16-04-28','16-05-14','16-05-28','16-06-14','16-06-28','16-07-14','16-07-28','16-08-14','16-08-28','16-09-14','16-09-28','16-10-14','16-10-28','16-11-14','16-11-28','16-12-14','16-12-28');
// Checking if we have a posted form, with the button name user clicked
if (isset($_POST["btnSubmit"])) {
// This is your selected day - use it where you need:
$selectedDate = $_POST["selectedDate"];
// This is where your model start singing and gets necessary info for this date - just printing here as sample
print $selectedDate;
// I need dropDownDate to compare in the SELECT to preselect the appropriate date
$dropDownDate = strtotime($selectedDate);
} else {
// First time visit, preselect the nearest date by using current date
$dropDownDate = time();
}
?>
<form method="post">
<select name="selectedDate" style="width:200px;">
<?php
foreach ($date as $i => $d) {
if ($dropDownDate >= strtotime($d) &&
(!isset($date[$i+1]) || ($dropDownDate < strtotime($date[$i+1])))
) {
$selected = 'selected="selected"';
} else {
$selected = "";
}
list($year, $month, $day) = explode('-', $d);
echo "<option $selected>" . date("m/d/Y", strtotime($d)) . "</option>";
}
?>
</select>
<input type="submit" name="btnSubmit" value="Submit">
</form>
Note that I added a "submit" type input (to submit the form) and changed form method to "post", finally named SELECT as "selectedDate". I also changed your date comparison code line in the loop.
Hope this helps.