Gather a row of tableB from buttons row of table A - php

Question

I am working in php and bootstrap with tables.
I have a tableA that for each row contains a button.
Each button has a value assigned equal to the row number. (see below)
$job_id = $row['id'];
<td> <a class='btn btn-primary btn-sm' data-toggle='modal' data-target='#myModal' name='job_id' value=$job_id id='job_id'>Info</a></td>
I cannot achieve this:
- Each button open a modal pop-up that contains the row of a tableB
So if I click on the button of the second row of tableA I want to show in the popup all the data that row2 of the tableB contains and so on.
Basically I cannot find out how to connect the button with a specific row of another table.
With this code in my modal I can only gather the entire tableB, but not the single row.
$sql = "SELECT * from tableb WHERE id=job_id ";
With this code in my modal I gather always the row 3 of tableB for all the buttons...
$sql = "SELECT * from tableb WHERE id=3 ";
With this code in my modal I gather for every button the last row I inserted
$sql = "SELECT * from tableb WHERE id='$job_id' ";
(TableA and TableB are connected with foreign key)
TableB has (id, job_id) with job_id= id of tableA
TableA has (id)
Any suggestion that can help me with what I want to achieve?
UPDATE 1 -> File xxx.php containts the script that load TableA and the script that load the Modal pop up
script that load TableA
<?php
include("../includes/connection.php");
if ($link->connect_errno > 0) {
die('Unable to connect to database [' . $link->connect_error . ']');
}
$sql = "SELECT * from TableA";
if (!$result = $link->query($sql)) {
die('There was an error running the query [' . $link->error . ']');
}
echo "
<table class='table'>
<thead>
<tr>";
/* Get field information for all columns */
...
while ($row = $result->fetch_assoc()) {
$job_id = $row['id'];
echo "<form action='' method=post>";
echo "<tr class='info'>
<input type=hidden name=hidden value=" . $row['id'] . ">
<td>" . $row['id'] . "</td>
<td>" . $row['device'] . "</td>
<td>" . $row['model'] . "</td>
<td>" . $row['problem'] . "</td>
<td> <a class='btn btn-primary btn-sm' data-toggle='modal' data-target='#myModal' name='job_id' value=[$job_id] > Info</a></td>
</tr>";
echo "</form>";
} echo " </tbody> </table>"; ?>
script that load the modal popup with tableB
<?php
include("../includes/connection.php");
if ($link->connect_errno > 0) {
die('Unable to connect to database [' . $link->connect_error . ']');
}
$sql = "SELECT * from TableB WHERE job_id=$job_id ";
if (!$result = $link->query($sql)) {
die('There was an error running the query [' . $link->error . ']');
}
echo "
<table class='table'>
<thead>
<tr>";
/* Get field information for all columns */
while ($finfo = $result->fetch_field()) {
echo "
<th>" . $finfo->name . "</th>";
}
echo "
</tr>
</thead>
<tbody>";
while ($row = $result->fetch_assoc()) {
echo "<tr class='info'>
<td>" . $row['id'] . "</td>
<td>" . $row['name'] . "</td>
<td>" . $row['mail'] . "</td>
<td>" . $row['number'] . "</td>
<td>" . $row['price'] . "</td>
<td>" . $row['paymenttype'] . "</td>
<td>" . $row['faktura'] . "</td>
<td>" . $row['date'] . "</td>
</tr>";}echo " </tbody></table>";?>

Answer 1

You can use JOIN instruction to link your two tables with one single request.
// For the third button the SQL request will be :
$sql="SELECT * FROM tableA A INNER JOIN tableb B ON B.job_id=A.id WHERE B.id=3";
// For the fourth button the SQL request will be :
$sql="SELECT * FROM tableA A INNER JOIN tableb B ON B.job_id=A.id WHERE B.id=4";
Note that here I use aliases on my request. For instance A is the alias of table A. Thus, A.id is the id column of tableA.
Look at this link for more infos about SQL Joins : http://www.w3schools.com/sql/sql_join.asp.

Answer 2

To get the rows in tableB corresponding to an id of tableA you should write:
$sql = "SELECT * from tableb WHERE job_id = $jobId ";
Note that I put 'WHERE job_id = ', and not 'WHERE id = '.
There's an answer that recommends a JOIN. With a JOIN you'll get the row in tableA and the data in tableB